Re: [Vo]:Toyota puts 24,000 hybrid car patents into the public domain

[Terry Blanton]

This is not unprecedented:

https://www.tesla.com/blog/all-our-patent-are-belong-you

YMMV and reasons might differ.

RE: [Vo]:A backdoor to proton annihilation?

[JonesBeene]

Hi Robin

> In order to flip the charge, you probably need to add the difference in 
> energy,
i.e. 2 proton masses worth, or about 2 GeV.
[snip]

It is very doubtful that the entire mass-energy of a proton is to be found in 
charge alone which is the implication of what you are saying. 

For instance, a neutron with no charge has about the same mass-energy as a 
charged proton. I suspect the energy needed to conjugate charge in the proton  
is about the same as the difference in mass between the neutron and proton. Far 
less.

Jones

Re: [Vo]:Toyota puts 24,000 hybrid car patents into the public domain

[Jed Rothwell]

Terry Blanton  wrote:

This is not unprecedented:
>
> https://www.tesla.com/blog/all-our-patent-are-belong-you
>
>
Whaddya know! That document is titled "All Our Patent Are Belong To You."
That's an inside joke based on a video game. That is a flippant way to put
it for a billion-dollar corporation. If I were a stockholder, it would make
me uneasy. Elon Musk's subsequent behavior made stockholders uneasy.

Toyota's decision to put their patents in the public domain seems more in
tune with a conventional business strategy. I guess they are saying:

"The patents are now free but if you want to use them soon in industrial
scale production quantities, why not buy the equipment from us? It would be
cheaper."

It is a good faith gesture.

- Jed

RE: [Vo]:A backdoor to proton annihilation?

[JonesBeene]

A  yellow-green laser pulse  – according to Holmlid and replicated by Olafsson 
in Iceland and Zeiner-Gunderson in Norway – produces a large number of muons 
per pulse. They have performed sophisticated measurements to ascertain this.

The photons of the laser which provides the input for the Holmlid effect have  
an individual mass-energy of less than  one MeV. The Holmlid effect  only works 
if there is a “target” of dense hydrogen, so somehow the interaction of 
coherent low energy photons with dense hydrogen performs a  kind of magic. 
Input energy seems to be multiplied by a factor of a million to one.

No one knows the exact details of  how that initial laser energy is able  to be 
 multiplied to produce a massive number of muons but there could be a 
“backdoor” mechanism. The Holmlid effect output  represents s more net gain  
per nucleon than nuclear fusion.  One possibility to explain the situation is 
if  “flipping the charge of protons” (conjugation) is done without brute force. 
That is the premise of the previous post. 

Specifically, by applying low energy photons to dense hydrogen, antimatter is 
first produced by charge conjugation - which  antimatter then annihilates with 
matter, resulting in  the subatomic debris called “quark soup” which then 
decays to mostly muons which are relatively long lived.

Otherwise one needs brute force and a billion dollar particle accelerator  in 
order to produce the same flux of muons which is measured by Holmlid et al. 
Since muon decay produces mostly neutrinos the actual useful net energy of this 
complete reaction is not huge, despite the large amount of mass which is 
involved.

The best approach  for achieving  decent net gain is use the  muons to produce 
“muon catalyzed fusion” before they decay. In fact, Holmlid suggest that this 
is already what has been happening in cold fusion – and researchers never 
thought to look for muons – which were there.

Jones

Hi Robin

> In order to flip the charge, you probably need to add the difference in 
> energy,
i.e. 2 proton masses worth, or about 2 GeV.
[snip]

It is very doubtful that the entire mass-energy of a proton is to be found in 
charge alone which is the implication of what you are saying. 

For instance, a neutron with no charge has about the same mass-energy as a 
charged proton. I suspect the energy needed to conjugate charge in the proton  
is about the same as the difference in mass between the neutron and proton. 

RE: [Vo]:A backdoor to proton annihilation?

[JonesBeene]

… correction… meant to say the photons of the laser which provides the input 
for the Holmlid effect have  an individual mass-energy of less than  one eV. To 
put that into the context of charge conjugation  – there are a few papers out 
there such as
“Direct, Resonant Production of States with Positive Charge Conjugation in 
Electron-Positron Annihilation”
By Czyż, et al
https://arxiv.org/abs/1710.08161

which indicate that charge conjugation can be a relatively low energy 
transformation

RE: [Vo]:A backdoor to proton annihilation?

[bobcook39...@hotmail.com]

Philippe Hatt’s physical model for neucleons (potons and neutrons) and Bill 
Stubb’s evaluations of old and new high energy scattering experiments 
valadiating Hatt’s model are pertinent to explaining the disintegration of H 
into muons.  Muons appear to be quasi stable constitutents of nucleons when 
existing outside the a nucleon’s coherent system of primary 
particldes—electrons, positrons and neutrinos.

“Hidden in plain sight… as it were.”

Jones assessment is right on IMHO.

The role of neutrinos in a complete nucleon is not addressed  by Hatt’s model 
noted above, but may be pertinent in understanding nucleon stability when 
irradiated by a laser such as used by Holmlid in his experiments.

Bob Cook
-


From: JonesBeene 
Sent: Thursday, April 4, 2019 11:19:47 AM
To: vortex-l@eskimo.com
Subject: [Vo]:A backdoor to proton annihilation?

One of the big knocks about the Holmlid effect – where the claim is that 
hydrogen
is completely annihilated- showing up primarily as muons, which then decay (but
can catalyze fusion before decay) is the low input energy used by Holmlid.

This annihilation process is well known in beamlines at the big labs and 
normally
requires a massive amount of energy to smash protons into “quark soup”…

Because of the disparity in applied energy – many experts think Holmlid is 
delusional.

But wait…the problem here could be that the critics’ only tool is the beamline 
and
the geniuses have not carefully looked elsewhere. In fact, there could be 
another
way to approach annihilation – the antineutron. But where would  they coming 
from?

Hidden in plain sight… as it were.

The following research confirms the theory that the antiproton is the exact 
mirror
image of the proton. There is absolutely no difference other than the charge 
has been
flipped. This is important for an alterative understanding of annihilation.

“Protons and antiprotons appear to be true mirror images”
https://phys.org/news/2015-08-protons-antiprotons-true-mirror-images.html
Thus the question is this: can coherent photons of the correct energy and 
resonance flip
a proton into an antiproton by simply reversing the charge? Clearly the answer 
implies
a backdoor to proton annihilation if Holmlid is correct.

Charge conjugation is a transformation that switches particles with their 
corresponding
antiparticles, and it is well studied as C-symmetry. Sooner or later if the 
Holmlid effect
continues to be validated as Norront has done, the experts will realize that 
proton
annihilation is simply the surprising result of charge-flipping following laser 
irradiation …

AT LOW ENERGY …and massive  input from a proton beam is not required.

The critics may end  looking like fools unless they jump onboard the Holmlid 
express,
which is leaving the station soon. Next stop – Stockholm.

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

I think that what is going on is a change of state condition in the cloud
of electrons that cover the positive core of the ultra-dense hydrogen (UDH)
when the laser light hits the UDH. The Laser pulse greatly increases the
density of the polariton population in the electron cloud so that a Bose
condensate of polaritons forms. This condensate generates two chiral
polarized magnetic vortex flux tubes that just so happen to be compatible
with the flux tubes that bind quarks together. These UDH magnetic flux
tubes destabilize these valance quarks that these flux tunes touch and
produce a proton decay reaction that transforms protons to mesons (kaons).

It is not a matter of raw power, but more like a key that exactly fits in a
sub nuclear particle lock, where the magnetic flux tune exactly fits the
mechanism that keeps protons and neutrons together.



On Fri, Apr 5, 2019 at 10:36 AM JonesBeene  wrote:

>
>
> A  yellow-green laser pulse  – according to Holmlid and replicated by
> Olafsson in Iceland and Zeiner-Gunderson in Norway – produces a large
> number of muons per pulse. They have performed sophisticated measurements
> to ascertain this.
>
>
>
> The photons of the laser which provides the input for the Holmlid effect
> have  an individual mass-energy of less than  one MeV. The Holmlid effect
> only works if there is a “target” of dense hydrogen, so somehow the
> interaction of coherent low energy photons with dense hydrogen performs a
> kind of magic. Input energy seems to be multiplied by a factor of a million
> to one.
>
>
>
> No one knows the exact details of  how that initial laser energy is able
> to be  multiplied to produce a massive number of muons but there could be a
> “backdoor” mechanism. The Holmlid effect output  represents s more net
> gain  per nucleon than nuclear fusion.  One possibility to explain the
> situation is if  “flipping the charge of protons” (conjugation) is done
> without brute force. That is the premise of the previous post.
>
>
>
> Specifically, by applying low energy photons to dense hydrogen, antimatter
> is first produced by charge conjugation - which  antimatter then
> annihilates with matter, resulting in  the subatomic debris called “quark
> soup” which then decays to mostly muons which are relatively long lived.
>
>
>
> Otherwise one needs brute force and a billion dollar particle accelerator
> in order to produce the same flux of muons which is measured by Holmlid et
> al. Since muon decay produces mostly neutrinos the actual useful net energy
> of this complete reaction is not huge, despite the large amount of mass
> which is involved.
>
>
>
> The best approach  for achieving  decent net gain is use the  muons to
> produce “muon catalyzed fusion” before they decay. In fact, Holmlid suggest
> that this is already what has been happening in cold fusion – and
> researchers never thought to look for muons – which were there.
>
>
>
> Jones
>
>
>
> Hi Robin
>
>
>
> > In order to flip the charge, you probably need to add the difference in
> energy,
>
> i.e. 2 proton masses worth, or about 2 GeV.
>
> [snip]
>
>
>
> It is very doubtful that the entire mass-energy of a proton is to be found
> in charge alone which is the implication of what you are saying.
>
>
>
> For instance, a neutron with no charge has about the same mass-energy as a
> charged proton. I suspect the energy needed to conjugate charge in the
> proton  is about the same as the difference in mass between the neutron and
> proton.
>
>
>
>
>

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

More support for the magnetic flux tube posit on matter distruction as
follows:

This matter distruction issue is common to most LENR reactor designs. It
becomes apparent when the reactor is pushed to high energy production
levels.


For example, in an interview that Dennis Cravens had with Host Ruby Carat,
he describes these pin holes seen in his reactor at 2:00 and states that
his reactor fails when the power level produced get high. Cravens just
ignores these holes and what causes them. This issue is a show stopper when
it comes to producing a useful LENR reactor.


Hear at between 2:00 and 3:30 into this interview.



https://disq.us/url?url=https%3A%2F%2Fwww.coldfusionnow.com%2Fpodcast%2FRuby-Carat-Dennis-Cravens-Cold-Fusion-Now-015.mp3%3A6HpHKlYZLvP-Yz_ofy8wHVRV9rs&cuid=2168707


We have seen these magnetic vortex flux tube generated pin holes develop in
the meltdown of the LION reactor. This damage is a product of the inherent
nature of the LENR active agent which is excited ultra dense hydrogen.


This behavior of the active agent has been seen in about a half dozen
reactor designs that have been analyzed by MFMP and is the basis of the O
day presentation that Bob Greenyer will give ...sooner or later...


Also see the holes rendered in this Russian paper on the first page


https://translate.google.com/translate?hl=de&sl=ru&tl=en&u=http%3A%2F%2Fwww.trinitas.ru%2Frus%2Fdoc%2F0231%2F004a%2F02311041.htm


Investigation of the characteristics of MagnetoToroElectric Emanations with
the help of photographic film detectors

On Fri, Apr 5, 2019 at 4:07 PM Axil Axil  wrote:

> I think that what is going on is a change of state condition in the cloud
> of electrons that cover the positive core of the ultra-dense hydrogen (UDH)
> when the laser light hits the UDH. The Laser pulse greatly increases the
> density of the polariton population in the electron cloud so that a Bose
> condensate of polaritons forms. This condensate generates two chiral
> polarized magnetic vortex flux tubes that just so happen to be compatible
> with the flux tubes that bind quarks together. These UDH magnetic flux
> tubes destabilize these valance quarks that these flux tunes touch and
> produce a proton decay reaction that transforms protons to mesons (kaons).
>
> It is not a matter of raw power, but more like a key that exactly fits in
> a sub nuclear particle lock, where the magnetic flux tune exactly fits the
> mechanism that keeps protons and neutrons together.
>
>
>
> On Fri, Apr 5, 2019 at 10:36 AM JonesBeene  wrote:
>
>>
>>
>> A  yellow-green laser pulse  – according to Holmlid and replicated by
>> Olafsson in Iceland and Zeiner-Gunderson in Norway – produces a large
>> number of muons per pulse. They have performed sophisticated measurements
>> to ascertain this.
>>
>>
>>
>> The photons of the laser which provides the input for the Holmlid effect
>> have  an individual mass-energy of less than  one MeV. The Holmlid effect
>> only works if there is a “target” of dense hydrogen, so somehow the
>> interaction of coherent low energy photons with dense hydrogen performs a
>> kind of magic. Input energy seems to be multiplied by a factor of a million
>> to one.
>>
>>
>>
>> No one knows the exact details of  how that initial laser energy is able
>> to be  multiplied to produce a massive number of muons but there could be a
>> “backdoor” mechanism. The Holmlid effect output  represents s more net
>> gain  per nucleon than nuclear fusion.  One possibility to explain the
>> situation is if  “flipping the charge of protons” (conjugation) is done
>> without brute force. That is the premise of the previous post.
>>
>>
>>
>> Specifically, by applying low energy photons to dense hydrogen,
>> antimatter is first produced by charge conjugation - which  antimatter then
>> annihilates with matter, resulting in  the subatomic debris called “quark
>> soup” which then decays to mostly muons which are relatively long lived.
>>
>>
>>
>> Otherwise one needs brute force and a billion dollar particle
>> accelerator  in order to produce the same flux of muons which is measured
>> by Holmlid et al. Since muon decay produces mostly neutrinos the actual
>> useful net energy of this complete reaction is not huge, despite the large
>> amount of mass which is involved.
>>
>>
>>
>> The best approach  for achieving  decent net gain is use the  muons to
>> produce “muon catalyzed fusion” before they decay. In fact, Holmlid suggest
>> that this is already what has been happening in cold fusion – and
>> researchers never thought to look for muons – which were there.
>>
>>
>>
>> Jones
>>
>>
>>
>> Hi Robin
>>
>>
>>
>> > In order to flip the charge, you probably need to add the difference in
>> energy,
>>
>> i.e. 2 proton masses worth, or about 2 GeV.
>>
>> [snip]
>>
>>
>>
>> It is very doubtful that 

Re: [Vo]:A backdoor to proton annihilation?

[mixent]

In reply to  JonesBeene's message of Fri, 5 Apr 2019 06:50:07 -0700:
Hi Jones,

You may be right. I was thinking in terms of conservation of energy, but upon
further consideration, I am forced to admit, that it might be possible with the
addition of zero energy. 
When a proton and an anti-proton annihilate one another, the energy released is
equal to the mass-energy of both particles, which should be the same as that of
two protons, so there shouldn't be any energy required to flip a proton to an
anti-proton. It just violates conservation of charge, unless one can
simultaneously flip the charge of an electron, which would be the equivalent of
getting a proton and an electron to swap charges.

>
>Hi Robin
>
>> In order to flip the charge, you probably need to add the difference in 
>> energy,
>i.e. 2 proton masses worth, or about 2 GeV.
>[snip]
>
>It is very doubtful that the entire mass-energy of a proton is to be found in 
>charge alone which is the implication of what you are saying. 
>
>For instance, a neutron with no charge has about the same mass-energy as a 
>charged proton. I suspect the energy needed to conjugate charge in the proton  
>is about the same as the difference in mass between the neutron and proton. 
>Far less.
>
>Jones
Regards,


Robin van Spaandonk

local asymmetry = temporary success

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

https://en.wikipedia.org/wiki/CP_violation

There are mesons that change change. This is how there is a case put forth
about why the universe holds only matter and not any antimatter.

Holmlid got in trouble with particle physics for violating the conservation
of baryon number. Protons and neutrons don't decay into mesons. But they
should. This is called the Strong CP problem
.

Particle physics has been looking for proton decay for years and when they
find it courtesy of Holmlid they say that proton decay is impossible. These
Physics professionals are hard to figure out.

On Fri, Apr 5, 2019 at 4:50 PM  wrote:

> In reply to  JonesBeene's message of Fri, 5 Apr 2019 06:50:07 -0700:
> Hi Jones,
>
> You may be right. I was thinking in terms of conservation of energy, but
> upon
> further consideration, I am forced to admit, that it might be possible
> with the
> addition of zero energy.
> When a proton and an anti-proton annihilate one another, the energy
> released is
> equal to the mass-energy of both particles, which should be the same as
> that of
> two protons, so there shouldn't be any energy required to flip a proton to
> an
> anti-proton. It just violates conservation of charge, unless one can
> simultaneously flip the charge of an electron, which would be the
> equivalent of
> getting a proton and an electron to swap charges.
>
> >
> >Hi Robin
> >
> >> In order to flip the charge, you probably need to add the difference in
> energy,
> >i.e. 2 proton masses worth, or about 2 GeV.
> >[snip]
> >
> >It is very doubtful that the entire mass-energy of a proton is to be
> found in charge alone which is the implication of what you are saying.
> >
> >For instance, a neutron with no charge has about the same mass-energy as
> a charged proton. I suspect the energy needed to conjugate charge in the
> proton  is about the same as the difference in mass between the neutron and
> proton. Far less.
> >
> >Jones
> Regards,
>
>
> Robin van Spaandonk
>
> local asymmetry = temporary success
>
>

RE: [Vo]:A backdoor to proton annihilation?

[JonesBeene]

Hi Robin,

➢  It violates conservation of charge unless one can simultaneously flip the 
charge of an electron, which would be the equivalent of getting a proton and an 
electron to swap charges.

Hmmm… Perhaps that is exactly what happens on a transient basis. Some kind of 
double charge reversal occurs on irradiation -  which could be transient since 
the UDH hydrogen is very compact and annihilation would be almost  
instantaneous.

Consequently, one suspects that the Holmlid effect does not scale up well – but 
large size is not needed in this case since so many muons are produced per 
pulse and each will catalyze dozens of fusion reactions. He seems to be looking 
at a megawatt as the thermal capacity limit in a muon catalyzed fusion 
implementation. 

It could be possible that the frequency/wavelength of Holmlid’s laser  was a 
lucky choice and is somehow spatially resonant with a cluster of dense 
hydrogen. His  papers list the wavelength at 1064 or 532 nm so there is 
probably a frequency doubling feature. That wavelength would imply  a very 
large cluster of UDH if there was spatial resonance.

 The pulse energy is listed as miniscule - only .2J to .5J which works out to 
about e^18 coherent photons per pulse. This is incredibly low energy input 
-billions of times lower than a beamline - and  yet many muons appear, as if by 
magic. I hope he is correct on this because it would be the most important 
finding in LENR since the beginning, in 1989.

Almost certainly there is a backdoor mechanism of some kind at work here. The  
formation of antimatter via charge conjugation in dense hydrogen could be the 
best explanation.

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

Holmlid uses  a crystal frequency doubler (  1064 to 532 nm ) which
polarizes the laser light to a single handedness. The chirality of the EMF,
both fields and particles, are very important to the LENR reaction. The
strong force is a chiral force.

https://en.wikipedia.org/wiki/Optical_frequency_multiplier

https://formulatrix.com/protein-crystallization-systems/sonicc-protein-crystal-detection/how-it-works/

[image: image.png]



On Fri, Apr 5, 2019 at 6:32 PM JonesBeene  wrote:

> Hi Robin,
>
>
>
>- It violates conservation of charge unless one can simultaneously
>flip the charge of an electron, which would be the equivalent of getting a
>proton and an electron to swap charges.
>
>
>
> Hmmm… Perhaps that is exactly what happens on a transient basis. Some kind
> of double charge reversal occurs on irradiation -  which could be transient
> since the UDH hydrogen is very compact and annihilation would be almost
>  instantaneous.
>
>
>
> Consequently, one suspects that the Holmlid effect does not scale up well
> – but large size is not needed in this case since so many muons are
> produced per pulse and each will catalyze dozens of fusion reactions. He
> seems to be looking at a megawatt as the thermal capacity limit in a muon
> catalyzed fusion implementation.
>
>
>
> It could be possible that the frequency/wavelength of Holmlid’s laser  was
> a lucky choice and is somehow spatially resonant with a cluster of dense
> hydrogen. His  papers list the wavelength at 1064 or 532 nm so there is
> probably a frequency doubling feature. That wavelength would imply  a very
> large cluster of UDH if there was spatial resonance.
>
>
>
> The pulse energy is listed as miniscule - only .2J to .5J which works out
> to about e^18 coherent photons per pulse. This is incredibly low energy
> input -billions of times lower than a beamline - and  yet many muons
> appear, as if by magic. I hope he is correct on this because it would be
> the most important finding in LENR since the beginning, in 1989.
>
>
>
> Almost certainly there is a backdoor mechanism of some kind at work here.
> The  formation of antimatter via charge conjugation in dense hydrogen could
> be the best explanation.
>
>
>
>
>

Re: [Vo]:A backdoor to proton annihilation?

[mixent]

In reply to  JonesBeene's message of Fri, 5 Apr 2019 15:31:57 -0700:
Hi Jones,
[snip]

If such a mechanism exists, then it implies the relatively easy conversion of
matter into anti-matter, and probably also the reverse. A slight asymmetry in
the ease of conversion from one to the other may also explain the preponderance
or ordinary matter in the universe. I.e. if it's easier for anti-matter to
convert to ordinary matter than the reverse, then in the early universe, before
the formation of elements higher than Hydrogen, when it was still very dense,
almost all anti-matter would convert to ordinary matter. 
Perhaps the dense H where the electrons and protons are close enough, makes the
reverse reaction to anti-matter possible with a little prodding?
Regards,


Robin van Spaandonk

local asymmetry = temporary success

Re: [Vo]:A backdoor to proton annihilation?

[mixent]

In reply to  mix...@bigpond.com's message of Sat, 06 Apr 2019 10:34:09 +1100:
Hi,

If all baryons are indeed composed of positron electron pairs, with an excess of
a single positron in a proton, then all it would take to convert the proton into
an anti-proton would be for an electron to replace the additional positron in
the proton, causing the proton to acquire an overall negative charge, and the
original positron to be ejected. This effectively describes a charge swap
mechanism.
Regards,


Robin van Spaandonk

local asymmetry = temporary success

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

https://www.forbes.com/sites/startswithabang/2019/03/29/no-physicists-still-dont-know-why-matter-and-not-antimatter-dominates-our-universe/#4a6e2cd25826


As per Andrei Sakharov

We've known how to create more matter than antimatter in theory since the
late 1960s, when physicist Andrei Sakharov identified the three conditions

necessary
for baryogenesis. They are as follows:

   1. The Universe must be an out-of-equilibrium system.
   2. It must exhibit *C*- and *CP*-violation.
   3. There must be baryon-number-violating interactions.

Holmlid has discovered the CP-violating condition that violates
baryon-number-conservation,
Holmlid just does not know the details of what that mechanism is.

On Fri, Apr 5, 2019 at 7:43 PM  wrote:

> In reply to  mix...@bigpond.com's message of Sat, 06 Apr 2019 10:34:09
> +1100:
> Hi,
>
> If all baryons are indeed composed of positron electron pairs, with an
> excess of
> a single positron in a proton, then all it would take to convert the
> proton into
> an anti-proton would be for an electron to replace the additional positron
> in
> the proton, causing the proton to acquire an overall negative charge, and
> the
> original positron to be ejected. This effectively describes a charge swap
> mechanism.
> Regards,
>
>
> Robin van Spaandonk
>
> local asymmetry = temporary success
>
>

RE: [Vo]:A backdoor to proton annihilation?

[bobcook39...@hotmail.com]

There should be 9 muons produced for each reaction of a photon with a  H in the 
dense hydrogen material.  If the incoming photon has enough energy to exceed 
the binding energy holding one muon to the other 8 in a nucleon, then the 
dissassembly of the entire neucleon may happen spontaneously.



Hatt’s model may allow prediction of that energy and a validation via the 
number of muons produced by an interaction of 1 photon and one nucleon.  A 
threshold energy for the incident laser photons , necessary to produce muons, 
should be expected, if the reaction is  as suggested above.



I may be that Holmlid already has the data on minimal energies for the photon 
flux need for production of muons.



Asssuming a nucleon structure that can be aligned in a magnetic field, and a 
direction of the photon beam, the suggested reaction may be significantly 
enhanced and otherwise controlled.



Bob Cook










From: mix...@bigpond.com 
Sent: Friday, April 5, 2019 4:34:09 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:A backdoor to proton annihilation?

In reply to  JonesBeene's message of Fri, 5 Apr 2019 15:31:57 -0700:
Hi Jones,
[snip]

If such a mechanism exists, then it implies the relatively easy conversion of
matter into anti-matter, and probably also the reverse. A slight asymmetry in
the ease of conversion from one to the other may also explain the preponderance
or ordinary matter in the universe. I.e. if it's easier for anti-matter to
convert to ordinary matter than the reverse, then in the early universe, before
the formation of elements higher than Hydrogen, when it was still very dense,
almost all anti-matter would convert to ordinary matter.
Perhaps the dense H where the electrons and protons are close enough, makes the
reverse reaction to anti-matter possible with a little prodding?
Regards,


Robin van Spaandonk

local asymmetry = temporary success

RE: [Vo]:A backdoor to proton annihilation?

[bobcook39...@hotmail.com]

Robin—

I think you are close to what happens in the photon-nucleon reaction.

I would be interesting to measure the muon energy spectrum to see if it 
suggests a nucleon structure and a disintegration pattern.

Bob Cook


From: Axil Axil 
Sent: Friday, April 5, 2019 4:50:55 PM
To: vortex-l
Subject: Re: [Vo]:A backdoor to proton annihilation?

https://www.forbes.com/sites/startswithabang/2019/03/29/no-physicists-still-dont-know-why-matter-and-not-antimatter-dominates-our-universe/#4a6e2cd25826

As per Andrei Sakharov


We've known how to create more matter than antimatter in theory since the late 
1960s, when physicist Andrei Sakharov identified the three 
conditions
 necessary for baryogenesis. They are as follows:

  1.  The Universe must be an out-of-equilibrium system.
  2.  It must exhibit C- and CP-violation.
  3.  There must be baryon-number-violating interactions.

Holmlid has discovered the CP-violating condition that violates  
baryon-number-conservation, Holmlid just does not know the details of what that 
mechanism is.

On Fri, Apr 5, 2019 at 7:43 PM mailto:mix...@bigpond.com>> 
wrote:
In reply to  mix...@bigpond.com's message of Sat, 06 
Apr 2019 10:34:09 +1100:
Hi,

If all baryons are indeed composed of positron electron pairs, with an excess of
a single positron in a proton, then all it would take to convert the proton into
an anti-proton would be for an electron to replace the additional positron in
the proton, causing the proton to acquire an overall negative charge, and the
original positron to be ejected. This effectively describes a charge swap
mechanism.
Regards,


Robin van Spaandonk

local asymmetry = temporary success

Re: [Vo]:A backdoor to proton annihilation?

[mixent]

In reply to  bobcook39...@hotmail.com's message of Sat, 6 Apr 2019 03:39:40
+:
Hi,

A minor variation is the possibility that it's the excess positron that is
responsible for the stability of the whole proton. If an intruding electron were
to annihilate that positron, then the whole proton might lose coherence.

However I suspect it's all a it more complicated, because otherwise protons
bombarded with electrons would be disintegrating all over the place.


[snip]
Regards,


Robin van Spaandonk

local asymmetry = temporary success

Re: [Vo]:A backdoor to proton annihilation?

[Axil Axil]

The key to the Holmlid effect is the creation of CP violation. What can
produce this condition?

There is a upcoming version of QM that uses complex numbers and
four-dimensional Riemann space. It's used to handle open systems.

It is called PT-symmetric quantum mechanics.

PT-symmetric quantum mechanics is an extension of conventional quantum
mechanics into the complex domain. (PT symmetry is not in conflict with
conventional quantum theory but is merely a complex generalization of it.)
PT-symmetric quantum mechanics was originally considered to be an
interesting mathematical discovery but with little or no hope of practical
application, but beginning in 2007 it became a hot area of experimental
physics.

http://www.europhysicsnews.org/articles/epn/pdf/2016/02/epn2016472p17.pdf

If  PT symmetry is broken, so is CP symmetry.

The polariton condensate can produce PT symmetry breakage via  the
transformation of its dipole whispering gallery waves (WGW) as predicted
by  PT-symmetric quantum mechanics.

A critical clue to the role of symmetry breaking in LENR is the observation
that the application of an electrostatic field (a laser flash) catalyzes
spontaneous symmetry breaking in the WGW via the Kerr effect.



The result of the application of a KERR stimulus is a monopole where just a
single rotating polariton spin current remains. This current is an
amplified sum of the initial double counter rotating polariton dipole
currents. The chiral handedness of the two counter rotating polariton
currents also merge into a single much more amplified polariton current.

In more detail, it looks like the index of refraction of the vacuum changes
under the influence of EMF.

This idea is the basis for the activation signal in the LENR reaction. The
nature of the vacuum that the polaritons reside in is changed by B and/or E
fields to induce a change of state in the circulation patterns of the
polariton in the cavity. This is the KERR effect. This reorganization of
polariton flow is what focuses the spin components of the polaritons into a
monopole magnetic flux tube beam.

After the laser flash, the polaritons that comprise the condensate
transform into a tachyonic field and thereby acquire  imaginary mass. This
puts the polariton condensate into a dark mode state that may also add
something to the Holmlid effect.

Ken Shoulders called this dark mode state a "black EVO."

On Sat, Apr 6, 2019 at 12:10 AM  wrote:

> In reply to  bobcook39...@hotmail.com's message of Sat, 6 Apr 2019
> 03:39:40
> +:
> Hi,
>
> A minor variation is the possibility that it's the excess positron that is
> responsible for the stability of the whole proton. If an intruding
> electron were
> to annihilate that positron, then the whole proton might lose coherence.
>
> However I suspect it's all a it more complicated, because otherwise protons
> bombarded with electrons would be disintegrating all over the place.
>
>
> [snip]
> Regards,
>
>
> Robin van Spaandonk
>
> local asymmetry = temporary success
>
>