Please suggest any good book for Java (for beginners)
Thanks in advance :)
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+1
On Mon, Jun 13, 2011 at 4:47 AM, Supraja Jayakumar suprajasank...@gmail.com
wrote:
Hi All
Can someone suggest a simple application that I can develop and host on
Azure.
I have very little web based programming experience and have some knowledge
with
.net but nothing major.
I am
*Probability Riddle Loaded Revolver - 13* June
*
*
**
*Henry has been caught stealing cattle, and is brought into town for
justice. The judge is his ex-wife Gretchen, who wants to show him some
sympathy, but the law clearly calls for two shots to be taken at Henry from
close range. To make
Pull the Trigger Again ??
On Mon, Jun 13, 2011 at 1:01 PM, Lavesh Rawat lavesh.ra...@gmail.comwrote:
*Probability Riddle Loaded Revolver - 13* June
*
* * ***
**
*Henry has been caught stealing cattle, and is brought into town for
justice. The judge is his ex-wife Gretchen, who wants to
should rotate again..
On Mon, Jun 13, 2011 at 1:12 PM, sunny agrawal sunny816.i...@gmail.comwrote:
Pull the Trigger Again ??
On Mon, Jun 13, 2011 at 1:01 PM, Lavesh Rawat lavesh.ra...@gmail.comwrote:
*Probability Riddle Loaded Revolver - 13* June
*
*
**
*Henry has been caught
ignore the above answerit shouldn't rotate again...
On Mon, Jun 13, 2011 at 1:37 PM, Piyush Sinha ecstasy.piy...@gmail.comwrote:
should rotate again..
On Mon, Jun 13, 2011 at 1:12 PM, sunny agrawal sunny816.i...@gmail.comwrote:
Pull the Trigger Again ??
On Mon, Jun 13, 2011 at 1:01
You can go for Thinking in Java by Bruce Eckel or books authored
by Hortsman...both are equally good!!
On Mon, Jun 13, 2011 at 11:35 AM, Anurag Gupta anurag.gupta...@gmail.comwrote:
Please suggest any good book for Java (for beginners)
Thanks in advance :)
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@sunny agarwal:
Yes, it would be considered constant space.. even if it required 1MB
of space .
By big oh notation of space, we mean cases where input size, 'n' tends
to infinity and
the space requirement of the algorithm proposed does not approach
infinity.
here, even if n-infinity, input size
@howtechstuffworks:
Your question seems to be - why 'k+1' and not 'k+2' or 'k+3' or
something else.
The simple reason is that,
Given that P('k') and P('k+1') is true, we can extend it for ANY value
of k.
(ie) k+2 , can be derived from 'k+1' by substituting k=k+1.
similarly k+3 can be
@ross
thanks for clarification...
On Mon, Jun 13, 2011 at 2:46 PM, ross jagadish1...@gmail.com wrote:
@sunny agarwal:
Yes, it would be considered constant space.. even if it required 1MB
of space .
By big oh notation of space, we mean cases where input size, 'n' tends
to infinity and
amit it is working fine in gcc complier and giving out too i.e
10
what's error in it??
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char *a[10];
a++;//lvalue reqd error..
i knw dt base address f array cnt be incremented.
bt following code compiles succesfully
int main(int argc, char *argv[])
{
printf(%s, *++argv);
}
can some one xplain why this is happening
similarly
int foo(int *blah[10])
{
int *f[10];
Hi
Sorry. What does that mean ?
Thanks
Supraja J
On Jun 13, 12:45 am, Akash Mukherjee akash...@gmail.com wrote:
+1
On Mon, Jun 13, 2011 at 4:47 AM, Supraja Jayakumar suprajasank...@gmail.com
wrote:
Hi All
Can someone suggest a simple application that I can develop and host on
This is a standard shortest path problem. Use Dijkstras. Make a graph with
edge costs based on the square's nature - Harmful or Deadly. Mark edge costs
for Deadly as infinity. Find the cost of the shortest path. You can also use
Bellman Ford algorithm which would be simpler to implement in this
You could also use a priority queue based search (A*) where you explore all
vertices with cost 0 before exploring all vertices with cost 1 etc.
Essentially, that is the same as Dijkstra's in this case.
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DK
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Question:
An array is of size N with integers between 0 and 1024(repetitions allowed).
Another array of integers is of size M with no constraints on the numbers.
Find which elements of first array are present in the second array. (If you
are using extra memory, think of minimizing that still,
Use a hash table of size 1025 with bits per table entry = 2.
1. Go through the N sized array and set bit 0 of the hash table entry to 1
if it is present in the first array.
2. Go through the M sized array and set bit 1 of the hash table entry to 1
if the element belongs to 0 to 1024.
3. Go
It means that he's supporting your motion.
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Follow me on Twitter:
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why do we need 2 bits at all ??
i think single bit per table entry will do.
say table is T[1025], and array is A[M]
1. Go through the N sized array and set bit 0 of the hash table entry to 1
if it is present in the first array.
2. Go through the M sized array and if T[a[i]] is set then this
Friends..read more about *SaaS* aka Software as a Service...where you can
host your software on cloud as a service.It's better to start making a small
SaaS app...hosting is a cake walk!!
On Mon, Jun 13, 2011 at 5:29 PM, Divye Kapoor divyekap...@gmail.com wrote:
It means that he's supporting
can sme body tell me..?
1)
#include stdio.h
int main()
{
int i= -3, j=2 ,k=0, m;
m= ++i ++j || ++k;
printf(%d %d %d %d\n,i,j,k,m);
return 0;
}
output:
-2 3 0 1
2)#include stdio.h
int main()
{
int i= -3, j=2 ,k=0, m;
m= ++i || ++j ++k;
printf(%d %d %d %d\n,i,j,k,m);
return 0;
}
The Complete Reference By Herbert Shildt is comprehensive.
You can also look up some tutorials on youtube :)
On Jun 13, 11:05 am, Anurag Gupta anurag.gupta...@gmail.com wrote:
Please suggest any good book for Java (for beginners)
Thanks in advance :)
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Your boss asks you to do a program that maintains the database of
customers updated. You need to dotNet using MVC.
For you, what may be the best way to create a control class to access
and update data from customers?
Luciano Pinheiro.
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we can take care of the duplicate entries, but then that would cost more
space(int), as of now we are working with bool
On Mon, Jun 13, 2011 at 5:51 PM, sunny agrawal sunny816.i...@gmail.comwrote:
that will report duplicate entries multiple times :(
On Mon, Jun 13, 2011 at 5:38 PM, sunny
the expression involving and and or operator is evaluated from left to right
uptill the point from where the value of the expression can be determined.
On Mon, Jun 13, 2011 at 6:17 PM, Shachindra A C sachindr...@gmail.comwrote:
|| and operators are called short circuit operators and need not
no we can take care of duplicates without any extra memory
modify 2nd step of my previous solution as follows
if T[a[i]] is set then this element is there in second array so report this
element and Reset T[a[i]].
now no duplicates will be reported. and only 1025 bits will be required.
any
A1.bitmap.
A2.xor.
On Thu, Jun 09, 2011 at 02:45:48AM -0700, Dumanshu wrote:
Q1. I have a file in which there are supposed to be 4 billion
numbers,
starting from 1 to 4,000,000,000 but unfortunately one number is
missing,
i.e there are only 3,999,999,999 numbers, I need to find the
suppose numbers are 11,12,13,15 then you get some xor_val for xor of all
these numbers
after this
for (int i=11;i=15;i++) xor_val ^=i;
now xor_val is 14
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Sun, Jun 12, 2011 at 9:24 PM, Supraja
The best book is effective java ...but it is not for beginners but SCJP
java book is marvellous !!!
On Mon, Jun 13, 2011 at 5:59 AM, naivenow black.b...@gmail.com wrote:
The Complete Reference By Herbert Shildt is comprehensive.
You can also look up some tutorials on youtube :)
On Jun
ok i got the values of i ,j ,k ,.in all the 3 codes but can u please
explain me how we get the value of m =1 in all the 3 program.?
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because in all expression is evaluated to true.
On Mon, Jun 13, 2011 at 10:02 PM, sahil sharma sahil18...@gmail.com wrote:
ok i got the values of i ,j ,k ,.in all the 3 codes but can u
please explain me how we get the value of m =1 in all the 3
program.?
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Java in 60 Minutes A Day..
by Rich Raposa..
its a good book for begginers...
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Assuming everything is unbiased:
probability of the next slot to contain a bullet (given, first was empty)
would be (1/4) = 0.25
After spinning: prob(bullet) = (2/6) = 0.334...
We want to minimize the probability...
thus answer should be just to pull the trigger again..
On Mon, Jun 13, 2011 at
Six-chambered revolver, so 2 bullets in sequence is the same as 1
bullet in Five-chambered.
So, pull the trigger again = 1/5 + 1/5 = 2/5 (to die)
Rotate again = 2/6 + 1/6 = 1/3 (to die)
So, is better to rotate again
On Mon, Jun 13, 2011 at 2:35 PM, Kunal Patil kp101...@gmail.com wrote:
@Divye Kapoor : It was interesting...use of inheritance concept to print
that...
On Mon, Jun 13, 2011 at 12:09 AM, Divye Kapoor divyekap...@gmail.comwrote:
This will probably be the best solution yet ;)
Compile time template metaprogramming:
templateint N
class X : public XN-1 {
public:
Bt y k=0, in 2nd code???
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For more options,
m= ++i || ++j ++k;
++i will evauate to 3 and which is true so as next is ||
so next part will not be evaluated and m = true
On Mon, Jun 13, 2011 at 11:34 PM, udit sharma sharmaudit...@gmail.comwrote:
Bt y k=0, in 2nd code???
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@Sunny: Thn y k=1 in 2nd code???
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hmm. Sry yr... Got it.. Thanx.. :) :)
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For
+1 to Kunal's post
i think if you rotate again prob. of getting shot is 1/3 and not 1/2
On Mon, Jun 13, 2011 at 11:56 PM, sunny agrawal sunny816.i...@gmail.comwrote:
@Douglas
i don't understand your probablity analysis
but still for Rotate again as in your analysis 2/6+1/6 = 1/2
pull the
sams teach yourself JAVA in 21 days is a book that gives idea about every
topic and then you can study in detail.
On Mon, Jun 13, 2011 at 11:16 PM, vaibhav shukla vaibhav200...@gmail.comwrote:
@monty 1987 : can u plss send me the book u'r talking of .Thank you!!
On Mon, Jun 13, 2011 at
http://geeksforgeeks.org/?p=9057
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For more
hi,
we try to implement many programs using Recursion
and its said that this is better than iterative procedure.
if i am right then
i cant understand why is it so?
can anybody explain ...
and are there situations when iterative procedure is better than recursion.
Snehi
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its always better to have iterative program than recursive
since iterative program doesn't rely on system stack..
but recursive program are easy to write and gives a clear view of program
On Tue, Jun 14, 2011 at 1:13 AM, snehi jain snehijai...@gmail.com wrote:
hi,
we try to implement many
just a small doubt.
if x=10 and y=20
thn wht wud b the value of (x ^ y)?
acc to meit has to be 1 bt if the value is 1 , thn how wud the method
using XOR operations work?.plz xplain
On Mon, Jun 13, 2011 at 3:18 AM, KK kunalkapadi...@gmail.com wrote:
@kunal
Actually its not same
On 06/13/2011 05:22 PM, tech rascal wrote:
just a small doubt.
if x=10 and y=20
thn wht wud b the value of (x ^ y)?
acc to meit has to be 1 bt if the value is 1 , thn how wud the
method using XOR operations work?.plz xplain
On Mon, Jun 13, 2011 at 3:18 AM, KK
Is it right to say iteration is resource(time) intensive and recursion is
not. On
the other hand, recursion is space intensive (with stacks) and iteration is
not ?
Thanks
On Mon, Jun 13, 2011 at 2:08 PM, ADITYA KUMAR aditya...@gmail.com wrote:
its always better to have iterative program than
@Wladimir:
Can you kindly explain the overflow and underflow you mentioned.
Thanks
Supraja J
On Fri, Jun 10, 2011 at 9:58 PM, Wladimir Tavares wladimir...@gmail.comwrote:
Swapping two variables without using a temporary variable using the + and
-:
x = a;
y = b;
x = x + y / / x = a + b;
Recursion is the best way to write compact programs for what might
seem as tedious tasks to do.
Dynamic Programming is an alternate to recursion when problems possess
characteristics like suboptimal substructures and overlapping
subproblems.
Dynamic Programming is a iterative way of doing tasks
Hello,
I would really appreciate if someone can help me get an intuitive
understanding of XOR over a range of numbers.
I have seen it's usage is a couple of problems where duplicates are involved
and though ultimately i can see how it is solving the problem, i still feel
like checking the
@tech rascal
10 = 01010
20 = 10100
--
xor = 0
= 30
why r u getting 1 ??
On Tue, Jun 14, 2011 at 2:28 AM, Supraja Jayakumar suprajasank...@gmail.com
wrote:
@Wladimir:
Can you kindly explain the overflow and underflow you mentioned.
Thanks
Supraja J
On Fri, Jun 10,
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