bro try to send a intended code
On Tue, Jul 28, 2020 at 5:16 PM Harvindar Singh Garcha <
garchaama...@gmail.com> wrote:
> I am new to Django, and trying to paginate a dictionary objects,
> However I am unable to so and not getting what's wrong with my code,
> Its still printing whole data on a si
I am new to Django, and trying to paginate a dictionary objects,
However I am unable to so and not getting what's wrong with my code,
Its still printing whole data on a single page. Above I have posted my View
along with template code.
class Search(ListView):
paginate_by = 5
def get(self, re
I am new to Django, and trying to paginate a dictionary objects, I am
calling stackoverflow API where I want the result to get paginated. However
I am unable to so and not getting what's wrong with my code. Above I have
posted my View along with template code.
>
>
> class Search(ListView):
> p
I think there might be a way around, below is the code modified for views.py
@login_required
def home_view(request):
"""Display all the post of friends and own posts on the dashboard"""
posts = Post.objects.order_by('-date_posted')
media: MEDIA_URL
# 'post':Post.objects.filter(Q(author=request.use
Dear Sir,
it shows all the text on all the pages.
if there are total 5 posts, then it shows all the 5 posts on all the pages.
Thanks,
Akshat Zala
On Saturday, 30 May 2020 20:54:35 UTC+5:30, maninder singh Kumar wrote:
>
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at
Hi,
if I change the template to:
{% if not is_paginated %}
{% if page_obj.has_previous %}
First
arrow_left
{% endif %}
{% for num in page_obj.paginator.page_range %}
{% if page_obj.number == num %}
{{ num }}
{% elif num > page_obj.number|add:'-4' and num < page_obj.number|add:'4' %}
{{ num }}
{%
Hi akshat,
What is the difficulty?
Where have you defined the variable is_paginated? Is it present in the
context?
On Sat, May 30, 2020, 8:53 PM maninder singh Kumar <
maninder.s.ku...@gmail.com> wrote:
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at 7:22 PM Akshat Zal
Views.py looks fine !
regards
willy
On Sat, May 30, 2020 at 7:22 PM Akshat Zala wrote:
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
On Saturday, 30 May 2020 19:20:47 UTC+5:30, Akshat Zala wrote:
>
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
> posts = Post.objects.
Hello,
I am finding it difficult to paginate through all the posts
My views.py :
@login_required
def home_view(request):
"""Display all the post of friends and own posts on the dashboard"""
posts = Post.objects.all().order_by('-date_posted')
media: MEDIA_URL
# 'post':Post.objects.filter(Q(author
_staff`, `auth_user`.`is_active`, `auth_user`.`date_joined`
FROM `auth_user` WHERE `auth_user`.`username` LIKE BINARY %alpha%
1:
https://docs.djangoproject.com/en/2.2/topics/db/sql/#performing-raw-queries
--
Regards
Deep L Sukhwani
On Wed, 25 Sep 2019 at 00:47, leb dev wrote:
> I now how
I now how to use django pagination with ORM django after filtering the
required data and put in into *pagination div*
*queryset_list = employee.objects.all()*
*query=request.GET.get("q")*
*if query:*
*queryset_list=queryset_list.filter(*
* Q(name__icont
er
>> scroll the browser another batches will be append to the browser.
>> Below are the 3 ways am aiming to achieve this:
>>
>> 1. Using django pagination feature.
>>
>> 2. Everytime records need to be appended to the browser , an ajax call is
>> made to the view, t
can take minutes. I have experienced that issue with two different
> project.
>
> Django pagination by itself won't give you the infinite scroll you are
> expecting. But it should give you an easy interface for slicing the
> data from your db.
>
> An easier way might be
following
> issues.
> I have a database table consist of about 1000 record. I need to be
> displaying like 20 records at a time on a page such that when the user
> scroll the browser another batches will be append to the browser.
> Below are the 3 ways am aiming to achieve t
I would use 1 + 2 from your list.
3 might work on 1000 record, depending on how much data there is per
record. But if you grow to more than 10,000 record, the page loading
can take minutes. I have experienced that issue with two different
project.
Django pagination by itself won't give yo
the 3 ways am aiming to achieve this:
1. Using django pagination feature.
2. Everytime records need to be appended to the browser , an ajax call is
made to the view, then the queryset is slice using appropriate lower and
upper band. Then the returned record is appended to the browser.
3. Fetch
d think how to
> refactor it
> if you want only paginate posts, i'll recommend you to use
> django-pagination app of some sort, it's can be used in template
>
> On Monday, January 25, 2016 at 5:16:31 PM UTC+3, Xristos Xristoou wrote:
>>
>> i want to using Pag
i foolow the steps but i have again error my new view :
def index(request):
try:
page = request.GET.get('page', 1),
except PageNotAnInteger:
page = 1,
objects = ['john', 'edward', 'josh', 'frank']
p = Paginator(objects,request=request)
people = p.page(page)
that method is Confusing,i try to understand,i create new view or i work
with current?i not understand it the using 'people' and object on they view
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post l
are you using python 3?
that's actually what i talking about - it's too old
try another one, like
this https://github.com/jamespacileo/django-pure-pagination - follow
the instructions and i hope you'll be fine
On Tuesday, January 26, 2016 at 5:09:29 PM UTC+3, Xristos Xristoou wrote:
>
> i follow
i follow the simpe steps but i take error invalid syntax
(pagination_tags.py, line 225)
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my probl
thnx you i try to use that now
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i have two Querys
s for
package you choose
but i'm afraid that this particular app is too old and you can experience
some troubles with it
anyways, you can try: pip install django-pagination
On Tuesday, January 26, 2016 at 4:44:05 PM UTC+3, Xristos Xristoou wrote:
>
> one more question how to install this
one more question how to install this ?autopagination ?i dont see anything
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specif
you can read the usage doc i sent linked, but yes - you don't need to do
anything with you queryset in view only pass it to template
On Tuesday, January 26, 2016 at 4:39:17 PM UTC+3, Xristos Xristoou wrote:
>
> if i use {autopagination} i dont need quyre on my view ?
>
> Τη Δευτέρα, 25 Ιανουαρίου
if i use {autopagination} i dont need quyre on my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my
if you'll decide to use some app for pagination, you can do it in template,
like
so https://github.com/ericflo/django-pagination/blob/master/docs/usage.txt
({% autopaginate posts 10 %})
or you can choose one of
these https://www.djangopackages.com/grids/g/pagination/
there is no actual ne
can you show me one examples with my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i hav
you want to paginate both querysets at the same page?
i believe it's a pretty strange idea and if so, you should think how to
refactor it
if you want only paginate posts, i'll recommend you to use
django-pagination app of some sort, it's can be used in template
On Monday, Januar
i want to using Paginator in my main page for my post list. i see docs and
examples for that but i thing my problem is a specific, because on my view
i have two Querys not one.
def index(request):
return render_to_response("blog/posts_list.html", {
'categories': Category.objects.all
Thanks for the help guys, I managed to solve, so I did:
* queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*try: *
* page = int(request.POST.get('page','1')) *
*except ValueError: *
* page = 1 *
*try:
thus still giving the same error
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On 10/03/2013 04:13 PM, Roberto López López wrote:
> *return HttpResponse(json.dumps([players]) ,
> content_type='application/json')*
better without the square brackets
*return HttpResponse(json.dumps(players) ,
content_type='application/json')*
--
Roberto López López
System Developer
Paral
doing so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*page = request.GET.get('page')*
*try:*
*players = paginator.page(page)*
*except PageNotAnInteger:*
*players = paginator.page(1)*
*exc
Try this (I have not tried the code myself, but I think that it should
work):
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotA
Better to say:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotAnInteger:
players = paginator.page(1)
excep
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 1)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
I'm doing this:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 20)*
*return json.dumps([item.get_json() for item in paginator.object_list])*
And my Document is thus:
http://plnkr.co/edit/FHH2hZh26OiLMKTk2ToO
But it gives me the following error:
'st
Hi Hélio,
It looks like you're applying pagination to the rendered JSON string itself.
You want to be paginating the queryset itself.
queryset = Player.objects.filter(name=namepost)
paginator = Paginator(queryset, 20)
return json.dumps([item.to_dict() for item in paginator.object_list
Hi guys.
I'm here with a problem that does not quite know how to solve.
I have this query:
result = json.dumps([a.get_json() for a in
Player.objects.filter(name=namepost)])
But now I want to return the result with paging, and do not really know how
to do ... I've been seeing in the documentatio
On Sun, May 6, 2012 at 10:56 PM, coded kid wrote:
> I'm trying to paginate a page in order to display five statuses per
> page. After inputting these codes, it fails to paginate. Below are the
> codes for pagination and updating of status in my django app.
>
>
> Views:
>
> def qask(request):
>
I'm trying to paginate a page in order to display five statuses per
page. After inputting these codes, it fails to paginate. Below are the
codes for pagination and updating of status in my django app.
Views:
def qask(request):
extra_data_context={}
#if there's nothing in
Is it possible to split articles manually with some sort of a pagination tag
in the text?
Whole text:
Part 1:
Lorem ipsum dolor sit amet, consectetur adipiscing elit.
{{ split_tag.page1 }}
Part 2:
Vivamus sit amet odio a turpis congue tincidunt.
{{ split_tag.page2 }}
etc.
--
You received thi
Nevermind, it is a SQL Server problem. (I hate SQL Server. There, I
said it.)
I had to first filter manually by the m2m objects, then apply the
pagination to the results.
Thanks!
On Feb 18, 2:53 pm, David De La Harpe Golden
wrote:
> On 18/02/11 17:38,diogobaederwrote:
>
> > Hi,
> > Any ideas of
On 18/02/11 17:38, diogobaeder wrote:
> Hi,
> Any ideas of what might be happening?
>
Have you set a Meta.ordering on your Model (or applied an .order_by()
to the QuerySet?)
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Hi,
I have this weird pagination bug in Django: using object_list as a
return of a view, but passing a "paginate_by" argument to it, it's
repeating some of the results; Otherwise, if I remove the argument or
set as "paginate_by=None", the results are correct.
If using pagination, the quantity of
I don't have time to watch your code, but...
Take a look here http://www.tummy.com/Community/Articles/django-pagination/
I set up this cool pagination in 15 minutes without errors!
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I can't find a mistake :-(( {{ autopaginate product 2 }} is working,
because of only two products I see, but {{ paginate }} is NOT, its
returns just nothing
Here my template:
{% load i18n %}
{% load pagination_tags %}
{% autopaginate product 2 %}
Delete All | Another Action
{
22, 3:39 am, Jx wrote:
> > Hi,
> >
> > i recently encountered a problem due to inefficient performance of
> > django pagination. After researching, i realized that there is a need
> > to use django database queries when dealing with django-pagination as
> > &q
hips).
Then you should be able to do:
teachers = Teacher.objects.filter(student__name="Jonny")
I think the ORM should take care of this query for you and select only
those teachers.
Euan
On Jun 22, 3:39 am, Jx wrote:
> Hi,
>
> i recently encountered a problem due to inefficie
Hi,
i recently encountered a problem due to inefficient performance of
django pagination. After researching, i realized that there is a need
to use django database queries when dealing with django-pagination as
"LIMIT" will automatically be added. This is useful especially when
dealing
You can paginate whatever you want. From the docs:
"Note that you can give Paginator a list/tuple, a Django QuerySet, or
any other object with a count() or __len__() method. "
On Dec 19, 3:33 am, Continuation wrote:
> In the django-pagination, it uses the example:
> {% autopagi
> would I still be able to paginate over the entire list of 1 objects?
Or my list would be shortened to 5 objects?
Its the latter. Your query set will loop only for the size of it's length.
On Sat, Dec 19, 2009 at 12:03 PM, Continuation wrote:
> In the django-pagination,
In the django-pagination, it uses the example:
{% autopaginate object_list %}
My question is does object_list have to be the **entire** list over
which I want to paginate, or can I limit the length of object_list? If
I limit the length of object_list, will autopaginate still go through
the entire
gt; > On Aug 30, 2:47 pm, tezro wrote:
>
> > > > > > Anyone?
>
> > > > > > On Aug 14, 8:29 am, tezro wrote:
>
> > > > > > > The question is that
> > > > "django.views.generic.date_based.
> The question is that
> > > "django.views.generic.date_based.archive_index()"
> > > > > > takes an optional argument "num_latest" which is 15 by default.
> > > > > > Setting it manually to num_latest=10 is way off to
>
tezro wrote:
>
> > > > > The question is that
> > "django.views.generic.date_based.archive_index()"
> > > > > takes an optional argument "num_latest" which is 15 by default.
> > > > > Setting it manually to num_l
yone?
> >
> > > On Aug 14, 8:29 am, tezro wrote:
> >
> > > > The question is that
> "django.views.generic.date_based.archive_index()"
> > > > takes an optional argument "num_latest" which is 15 by default.
> > > &g
ent "num_latest" which is 15 by default.
> > > Setting it manually to num_latest=10 is way off to correct to
> > > me. It works. I suppose that it even doesn't retrieve all the tons of
> > > data from the DB, but what if I have 10 + 1 record :)
It works. I suppose that it even doesn't retrieve all the tons of
> > data from the DB, but what if I have 10 + 1 record :)
>
> > What's the right way to use "django-pagination" and the "archive_index
> > ()" or am I missing something?
On Sat, Sep 5, 2009 at 4:52 PM, Michael Ralan wrote:
>
> Hi,
>
> Apologies if this question has been asked before but I was not able to
> find a satisfactory answer.
>
> In the django admin app there is a capability to have a pagination
> object that lists the number of pages that can be paged.
>
Hi,
Apologies if this question has been asked before but I was not able to
find a satisfactory answer.
In the django admin app there is a capability to have a pagination
object that lists the number of pages that can be paged.
I have found code that uses the django Paginator object which builds
It works. I suppose that it even doesn't retrieve all the tons of
> data from the DB, but what if I have 10 + 1 record :)
>
> What's the right way to use "django-pagination" and the "archive_index
> ()" or am I missing something?
>
> Example co
of
data from the DB, but what if I have 10 + 1 record :)
What's the right way to use "django-pagination" and the "archive_index
()" or am I missing something?
Example code.
___
def index(request):
qs = News.objects.filter(is_published=
Simple Pagination in Django is great but I'm having some trouble with
the best way to design pagination with querysets derived from Search
Forms.
I'm currently using the Django-Pagination middleware and it works
great but there's really pretty bad documentation on it (as with man
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