Re: Help me an idiot

2001-05-01 Thread Reg Jordan
ay 01, 2001 7:32 AM Subject: Re: Help me an idiot > On Mon, 30 Apr 2001 20:25:36 -0700, James H. Steiger > wrote: > > >If you read my post carefully, (assuming it made > >your server), you will see that > >it, indeed, gives the combinations solution you gave > &g

Re: Help me an idiot

2001-05-01 Thread Gary Carson
On Mon, 30 Apr 2001 20:25:36 -0700, James H. Steiger wrote: >If you read my post carefully, (assuming it made >your server), you will see that >it, indeed, gives the combinations solution you gave >below, and shows that it is equivalent to >another, more elegant way of arriving at the same >ans

Re: Help me an idiot

2001-04-30 Thread James H. Steiger
If you read my post carefully, (assuming it made your server), you will see that it, indeed, gives the combinations solution you gave below, and shows that it is equivalent to another, more elegant way of arriving at the same answer, i.e., 2^N = (in this case) 2^5 = 32 Jim Steiger On 30 A

Re: Help me an idiot

2001-04-30 Thread J. Williams
On 30 Apr 2001 12:18:55 -0700, [EMAIL PROTECTED] (Robert R Johnson) wrote: >Several have written to this thread and I believe there has been some >misleading information passed along and intermixed with correct >information. Possibly, you missed it, but I posted the correct answer last Saturday

Re: Help me an idiot

2001-04-30 Thread Robert R Johnson
Several have written to this thread and I believe there has been some misleading information passed along and intermixed with correct information. On Sun, 29 Apr 2001 11:26:11 -0400 "Zina Taran" <[EMAIL PROTECTED]> writes: > I believe, the thrust of the "fries" reply was the overcount in the > 5*

Re: Help me an idiot

2001-04-29 Thread J. Williams
; all would have been right with the world. Possibly, my attempt at humor in the response eluded you. How any one likes their "Big Mac" is beyond the scope of this newsgroup :-)) > >- Original Message - >From: J. Williams >To: <[EMAIL PROTECTED]> >Sent: Sunda

Re: Help me an idiot

2001-04-29 Thread Zina Taran
I believe, the thrust of the "fries" reply was the overcount in the 5*4*3*. response rather than an expression of culinary preferences. - Original Message - From: J. Williams To: <[EMAIL PROTECTED]> Sent: Sunday, April 29, 2001 10:33 AM Subject: Re: Help me an idi

Re: Help me an idiot

2001-04-29 Thread J. Williams
On 29 Apr 2001 04:09:05 GMT, [EMAIL PROTECTED] (Eric Bohlman) wrote: >"I wanted that with *fries* and *ketchup*! *Not* ketchup and fries!" We hear you, but fries were not included in the original problem...only the 5 condiments. But you're right, fries would be good with that! Order me one.

Re: Help me an idiot

2001-04-29 Thread Jay Warner
Abdul Rahman wrote: > Please help me with my statistics. > > Question: > > If you order a burger from McDonald's you have a choice of the following > condiments:ketchup, mustard , lettuce. pickles, and mayonnaise. A > customer can ask for all thesecondiments or any subset of them when he > or she

Re: Help me an idiot

2001-04-29 Thread James H. Steiger
On Sat, 28 Apr 2001 20:48:03 +0800, Abdul Rahman <[EMAIL PROTECTED]> wrote: >Please help me with my statistics. > >Question: > >If you order a burger from McDonald's you have a choice of the following >condiments:ketchup, mustard , lettuce. pickles, and mayonnaise. A >customer can ask for all the

Re: Help me an idiot

2001-04-28 Thread Eric Bohlman
W. D. Allen Sr. <[EMAIL PROTECTED]> wrote: > Five different condiments, plus no condiments, means 6*5*4*3*2*1 = 720 > distinct combinations. "I wanted that with *fries* and *ketchup*! *Not* ketchup and fries!" = Instructions for

Re: Help me an idiot

2001-04-28 Thread J. Williams
On Sat, 28 Apr 2001 20:35:05 GMT, "W. D. Allen Sr." <[EMAIL PROTECTED]> wrote: >Five different condiments, plus no condiments, means 6*5*4*3*2*1 = 720 >distinct combinations. >WDA > Correct me if I am wrong, but aren't you thinking of the number of permutations, i.e., all the condiments plus the

Re: Help me an idiot

2001-04-28 Thread Donald Burrill
Interesting response, Bill. But I don't believe it. Can you enumerate the combinations you perceive? -- DFB. On Sat, 28 Apr 2001, W. D. Allen Sr. wrote: > Five different condiments, plus no condiments, means 6*5*4*3*2*1 = 720 > distinct combinati

Re: Help me an idiot

2001-04-28 Thread W. D. Allen Sr.
Five different condiments, plus no condiments, means 6*5*4*3*2*1 = 720 distinct combinations. WDA end "Abdul Rahman" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Please help me with my statistics. > > Question: > > If you order a burger from McDonald's you

Re: Help me an idiot

2001-04-28 Thread Donald Burrill
On Sat, 28 Apr 2001, Abdul Rahman wrote: > Please help me with my statistics. > > If you order a burger from McDonald's you have a choice of the > following condiments: ketchup, mustard , lettuce. pickles, and > mayonnaise. A customer can ask for all these condiments or any subset > of them

Help me an idiot

2001-04-28 Thread Abdul Rahman
Please help me with my statistics. Question: If you order a burger from McDonald's you have a choice of the following condiments:ketchup, mustard , lettuce. pickles, and mayonnaise. A customer can ask for all thesecondiments or any subset of them when he or she orders a burger. How many differen