Hi,
How can we check the SQL string created by select?
for example:
given this
$select-where ( conditions);
$select-orwhere ( conditions);
$select-order ( conditions);
I want to check the complete SQL statement it has created
Zend_Debug::Dump($select) doesn't provide what I wanted to know.
On Tue, Feb 17, 2009 at 2:31 PM, Deepak Shrestha d88...@gmail.com wrote:
Hi,
Although related to my previous post on paginator, this is separate
from what is being discussed before.
Documentation on Zend_Paginator
http://framework.zend.com/manual/en/zend.paginator.usage.html (In the
last
Hi all,
When trying to access the totalItemCount property of Paginator, I am
getting this error:
==
Notice: Undefined property: Zend_Paginator::$totalItemCount
==
Is this bug?
Problem elaboration
===
before using paginator, my
2009/2/17 Paweł Chuchmała pawel.chuchm...@gmail.com:
In mypaginator.phtml, you have something like that:
a href=?= $this-url(array('page' = $page)); ?
?= $page; ?
/a
You must cznge parameters for $this-url(). For example:
a href=?= $this-url(array_merge(array('page' =
Hi,
Although related to my previous post on paginator, this is separate
from what is being discussed before.
Documentation on Zend_Paginator
http://framework.zend.com/manual/en/zend.paginator.usage.html (In the
last para of 36.2.2. Rendering pages with view scripts) suggests that
it accepts four
On Sat, Feb 14, 2009 at 7:14 PM, PHPScriptor cont...@phpscriptor.com wrote:
Would be nice if you told us what your (stupid :-D) blunder was... In case
someone has the same problem, he would not have to ask again...
Sorry I forgot about it.
Actually it was really stupid :-)
Basically I have a
Hi,
I need some hint on using paginator with search form.
If I have following code in my controller
=
if($request-isPost())
{
if ($form-isValid($request-getPost()))
{
$req = $form-getValues();
$pageno
On Sun, Feb 15, 2009 at 8:49 PM, PHPScriptor cont...@phpscriptor.com wrote:
Well there are some sollutions:
1. put the form values in a session.
2. put your form values in the url
Got that. :-)
I was thinking other way round. Actually my question should be does
paginator retains the
2. put your form values in the url
but anyway I got the answer already.
Not really
My question is how to modify the view partial script of paginator
control (mypaginator.phtml) so that it will send the form data along
with requested page number
Initially my url is
hi,
Tracing my previous problem on why I cannot paginate with paginator, I
found out that the value I passed from controller to model is not
interpreted properly.
supposing clicking next button in paginator control, i got this url
http://myweb/index/index/page/2
In my controller
Hi
How do I preserve the hard return (CR CR/LF) entered in textarea in
zend_form? Currently my filter for textarea is StringTrim and
NotEmpty.
I thought I am getting this because $this-escape is used in my view
script. I tried removing it but I am still getting the same output
(everything in one
On Fri, Feb 13, 2009 at 2:54 PM, Deepak Shrestha d88...@gmail.com wrote:
Let me explain a bit so that it will be clear about
1. what I am trying to do
2. where I am doing wrong and
3. where I need to fill up the missing pieces.
My front page is where all the records are shown so I wanted
On Tue, Feb 10, 2009 at 11:58 PM, keith Pope mute.p...@googlemail.com wrote:
Heres what I do, this is within a model resource Model has Resource -
Zend_Db_Table.
public function getProductsByCategory($categoryId, $paged=null,
$order=null)
{
$select = $this-select();
this file structure
in the same place as the view script?
===
views
scripts
index
index.phtml
mypagintor.phtml
using this I got file not found error.
and this modification solved the problem
===
div id=pgcontrol
Hi,
So far I am able to use the Zend_Paginator to display the limited
results but I cannot forward through pages yet. I guess I need to
track the page number request from paginator control (either through
URL or using Zend_Controller_Router_Interface) but before doing that
I have some questions.
You are PHPScriptor. Arn't you? I like your answering style :-)
In the same directory I think you mean.
Yes. so that means what I am doing is fine.
public function setupRoutes(Zend_Controller_Front $frontController)
{
$router = $frontController-getRouter();
$router-addRoute(
Let me explain a bit so that it will be clear about
1. what I am trying to do
2. where I am doing wrong and
3. where I need to fill up the missing pieces.
My front page is where all the records are shown so I wanted to use
the paginator. For the simplicity I want to fetch all the records from
On Wed, Feb 11, 2009 at 4:39 PM, Moritz Mertinkat mor...@mertinkat.net wrote:
Hi there,
the problem is that array_splice doesn't care about your string keys.
The manual states that array_splice($input, 0, 0, array($x, $y)) is identical
to array_unshift($input, $x, $y) which should make it
Hi,
Short and quick question:
I need some background and hint on how to use Paginator in strict Zend
Framework MVC convention? (no customization) also some insight on
Zend_Controller_Router_Interface. I cannot find enough information
in documentation to grasp this.
On Tue, Feb 10, 2009 at 7:31 PM, PHPScriptor cont...@phpscriptor.com wrote:
I don't know if this will answer your question, but this is how I do it:
The paginator is set in the controller. I think you could do it in the
model, but that would make things a lot complicater.
Where to define
On Tue, Feb 10, 2009 at 9:15 PM, PHPScriptor cont...@phpscriptor.com wrote:
You always come back in your controller. The zend paginator add's the param
'page' in the url.
So you always do a requery. (if that's what you wanted to say).
http://localhost/news become http://localhost/news/page/1
Hi,
I got confused on why this is not working.
I have an array of locations stored in $location variable which is
fetched using fetchPairs(). I wanted to add and element Any = Any
at the beginning of this $location.
so my $locations is [from Zend_Degug::Dump($locations)]:
=
On Sun, Feb 8, 2009 at 2:03 AM, A.J. Brown fynw...@gmail.com wrote:
Hi Deepak,
Can you pastebin both the controller and the form (in seperate pastes)?
Attaching would be fine too. I'll help you debug it.
--
A.J. Brown
web | http://ajbrown.org
phone | (937) 660-3969
Hi,
here are the
On Sun, Feb 8, 2009 at 9:22 PM, PHPScriptor cont...@phpscriptor.com wrote:
your viewscript:
? $this-searchstr ?
does that work?
try something like this:
?php echo $this-searchstr; ?
or
?= $this-searchstr; ?
-
visit my website at http://www.phpscriptor.com/
plus I noticed something.
I tried to enter the string What da Hell and it gives me invalid
string error? why I can't type a sentence? what's wrong with the
validation? Does this have something to do with the problem?
Thank you for your patience.
Plus I noticed that it is causing by my
Hi,
One quick question. How to set the option for 'Alnum' validator to
accept white space?
Thanks
--
===
Registered Linux User #460714
Currently Using Fedora 8, 10
===
On Sat, Feb 7, 2009 at 7:10 PM, Deepak Shrestha d88...@gmail.com wrote:
Hi,
One quick question. How to set the option for 'Alnum' validator to
accept white space?
Thanks
Hi found the solution after digging inside Alnum.php itself:
including the third parameter like this solved the problem
Hi,
I am trying to implement a simple search function. For the test
purpose I am trying to display the search string in my view. This is
how it looks like:
my form
--
class Form_Search extends Zend_Form
{
public function init()
{
//create search text input
On Fri, Feb 6, 2009 at 7:01 PM, PHPScriptor cont...@phpscriptor.com wrote:
Try this:
$this-getPost('qsearch');
It gives me:
=
Application error
Exception information:
Message: Method getPost does not exist and was not trapped in __call()
===
Trying
On Fri, Feb 6, 2009 at 10:43 PM, PHPScriptor cont...@phpscriptor.com wrote:
I'm assuming that if your method getPost does not exist that your
$request-isPost() and isValid($request-getPost()) will also not work. Try
to do a var_dump of $request-getPost(); and your $request.
Hi,
I agree with
Hi,
It looks like you're not setting post as the method.
$form-setMethod( 'post' );
$this-view-form = $form;
The form's method is set to post now (sorry I forgot; my bad) but I am
still getting the same result.
It's not the best way but you can do it like this maybe:
$data =
On Thu, Feb 5, 2009 at 10:08 PM, A.J. Brown fynw...@gmail.com wrote:
On Wed, Feb 4, 2009 at 9:44 PM, Deepak Shrestha d88...@gmail.com wrote:
Thanks. How about assigning specific error message to each validator?
Use the options array (3rd parameter). The key should be 'messages
Hi,
I have text element in the form with two validators
+---
$mytext= New Zend_Form_Element_Text('mytext');
$mytext-setLabel('Enter Text:');
$mytext-setAttrib('size', '40');
$mytext-setRequired(true);
What I actually wanted to do is:
*
Empty string will be checked first and shown error message ignoring
other validators. So if the string is empty show the error message for
empty string validator and exit from validator chain ignoring other
validators
Hmm, I tried it, and seems to be working fine... You didn't use decorators?
Did you look at your html source output? Did you try cleaning up your
browser history?
Everything is default from ZF.
No decorators.
Yes html source shows the previous order of elements.
Yes in my firefox setting it
Yes, add a setter method for attaching the model to the form and then do
this in the controller. The form will then have access to the model to
retrieve any data it needs.
You can also populate the element directly in your controller by retrieving
it from the form and manipulating it e.g.
hi,
I am not sure if this is related to ZF but anyway I am asking it here.
I have a one column table (called location) in my database.
++
| locname | this is also the primary key
++
| location 1 |
++
| location 2
Just for confirmation, is this what I am getting?
array('location1' = 'location1', 'location2' = 'locatino2' ...)
This is what I desired
instead of
===
array('somevalue' = 'location1', 'somevalue' = 'location2' ...)
===
I got he desired result
Hi,
I changed the order of few elements inside the Form but whenever I
access the form it is showing me the same Form from previous layout.
My update didn't get reflected.
I tried clearing the browser cache and all still the same.
Is cache working behind the scene somewhere?
Thanks
--
On Mon, Feb 2, 2009 at 2:54 PM, PHPScriptor cont...@phpscriptor.com wrote:
Not that I know. But if you post your code, we can have a closer look...
my Form code:
?php
class Form_PostInfo extends Zend_Form
{
public function init()
{
//create title element
Hi,
I am confused on how to populate the Select element from database. In
the Select element I need to fill it with location data which is
stored in database as single field table (each item is unique)
location
--
location1
location2
location3
...
... etc.
--
There is
On Sat, Jan 31, 2009 at 9:23 PM, Daniel Latter dan.lat...@gmail.com wrote:
shoudnt $adlocation be $location?
Thank You
Daniel Latter
sorry for that, it is all $location (typo).
When form renders I can see the error message that Invalid argument
supplied for foreach() in TestForm.php at line
It looks like your doing it correct except for the array of data that you're
using to populate the form. You're not actually populating the select
element with options, you only want the current Or selected option to be
selected in the select list on display.
So in your case it's probably a
On Sat, Jan 31, 2009 at 10:37 PM, gerardroche bullfrogbl...@live.com wrote:
you would just do this
try this first:
$data = array(
'location' = 'location1'
);
$form-populate($data);
when the form is displayed it should show a select list of location options
with location1 selected.
On Sat, Jan 31, 2009 at 10:48 PM, Daniel Latter dan.lat...@gmail.com wrote:
Are you sure your setting $this-data variable in the form class?, and
if so var_dump it to see what it contains?
My sample trial code
in my controller
==
$data = array('location1' = 'location1');
$form
no.
Change in my controller to the following
in my controller
==
$data = array('location' = 'location1');
$form= $this-_getTestForm();
$form-populate($data);
...
==
all i did was change the array
from
$data = array('location1' =
On Sat, Jan 31, 2009 at 11:46 PM, gerardroche bullfrogbl...@live.com wrote:
you keep moving the goal posts.
put this in your form, to the letter:
$location= New Zend_Form_Element_Select('location');
$location-setLabel('*Location:');
$location-setMultiOptions(array('location1' =
On Sun, Feb 1, 2009 at 12:37 AM, Daniel Latter dan.lat...@gmail.com wrote:
a) Do I need to declare global variable in my form class plus getter,
setter methods so that Controller can set that variable through those
methods and I can use the data provided in that variable?
yes.
so what is the
On Wed, Jan 28, 2009 at 3:23 PM, Deepak Shrestha d88...@gmail.com wrote:
Ok,
I found a Warning displayed at top of my form after validation.
The Message:
=
Warning: htmlspecialchars() expects parameter 1 to be string, array
given in C:\WEB\myweb\library\Zend\View\Abstract.php
Hi, me again
it is solved now by doing this
==
$captchaimg-setMessage(My Custom Message, 'badCaptcha');
==
This came to my mind only after I did some digging around and had a
look at the code
'Zend/captcha/Word.php' (ancestor class)
Where the message template
Hi,
Breaking from previous post, I am posting this as a new subject.
I am using Zend_From to display captcha with custom error message.
When I make a wrong entry (intentionally), my custom error message is
not shown when form validates.
Sample code:
//first create an
Ok,
I found a Warning displayed at to of my form after validation.
The Message:
=
Warning: htmlspecialchars() expects parameter 1 to be string, array
given in C:\WEB\myweb\library\Zend\View\Abstract.php on line 804
What does this mean?
Thanks
--
Hi,
I found out that image is being generated. Also because of
$captchaimg-generate(); command its being generated twice.
So I replaced the 'generate()' with $captchaimg-setWordlen('5');
Now I can see that every time I display the form page, new image is
generated in the 'captcha/images' folder
Hi,
Didn't get any help from my last post so I went through documentation
and tried to understand as much I can but can't find a way to display
captcha image in Zend_Form using default behavior of Zend Framework's
MVC. AFAIK (with my current knowledge), my code is correct.
This is the code
On Tue, Jan 27, 2009 at 3:24 PM, Deepak Shrestha d88...@gmail.com wrote:
Hi,
Didn't get any help from my last post so I went through documentation
and tried to understand as much I can but can't find a way to display
captcha image in Zend_Form using default behavior of Zend Framework's
MVC
Hi,
I am absolutely new to ZF. Right now I am playing around with the
Quickstart files. So far I am bit comfortable with the concepts. Now
I want to change the provided zend captcha (figlet) into image type
but can't find any example of this in the zend documentation.
This is what I came up with
After reading the list archive
http://www.nabble.com/Zend_Captcha-td20300142.html#a20300142 , I
figured out my mistake. Now I have made changes and code looks like
this
...
...
...
//first create an image type captcha
$captchaimg = New
Hi,
I am completely new to ZF and following the quickstart guide. It was
doing OK until I reached the part Create Layout section
(http://framework.zend.com/docs/quickstart/create-a-layout) my page
start to show something unusual. I cannot understand this yet.
Things that might help:
On Wed, Jan 7, 2009 at 4:48 PM, keith Pope mute.p...@googlemail.com wrote:
Looks like you dont have short tags enabled for your php install. In
your .htaccess use
php_value short_open_tag on
It works now. Can move on with tutorials
Thanks
--
===
Registered Linux User
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