index and it returned successful. So that was
the problem all along.
Thanks for your suggestions.
Best regards
Alugo Abdulazeez.
> From: defati...@hotmail.com
> To: spa...@googlemail.com
> CC: mysql@lists.mysql.com
> Subject: RE: PHP-MYSQL Question
> Date: Tue, 7 Apr 2009 15:32
I've done that but it still gives the same error message.
Date: Tue, 7 Apr 2009 16:25:15 +0200
Subject: Re: PHP-MYSQL Question
From: spa...@googlemail.com
To: defati...@hotmail.com
CC: mysql@lists.mysql.com
it is not the ENGINE as Eugene mentioned above, is that you need to use
UNS
ble2
> remains unsuccessful.
>
> > Date: Tue, 7 Apr 2009 17:56:49 +0400
> > From: evge...@kosov.su
> > To: defati...@hotmail.com
> > CC: mysql@lists.mysql.com
> > Subject: Re: PHP-MYSQL Question
> >
> > I suppose the problem is that table1.table1_id and tab
l@lists.mysql.com
> Subject: Re: PHP-MYSQL Question
>
> I suppose the problem is that table1.table1_id and table2.table1_id are
> of different types. The first one is INT UNSIGNED and the second is just
> INT.
>
>
> abdulazeez alugo wrote:
> > Table1 is as below:
>
Hi guys,
Please can anyone tell me what I'm doing wrong with the code below? It keep
returning unsuccessful.
$result=mysql_query("CREATE TABLE table2(table2_id INT NOT NULL PRIMARY KEY
AUTO_INCREMENT,
table1_id INT NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment T
mail.com
> CC: mysql@lists.mysql.com
> Subject: Re: PHP-MYSQL Question
>
> # perror 150
> MySQL error code 150: Foreign key constraint is incorrectly formed
>
> What does table1 look like?
>
> abdulazeez alugo wrote:
> >
> > Yeah I used the mysql_error
that be the problem?
> Date: Tue, 7 Apr 2009 17:48:16 +0400
> From: evge...@kosov.su
> To: defati...@hotmail.com
> CC: mysql@lists.mysql.com
> Subject: Re: PHP-MYSQL Question
>
> # perror 150
> MySQL error code 150: Foreign key constraint is incorrectly formed
&g
Apr 2009 17:38:59 +0400
From: evge...@kosov.su
To: defati...@hotmail.com
CC: mysql@lists.mysql.com
Subject: Re: PHP-MYSQL Question
Perhaps you don't have permissions to create tables?
It would have been much clearer if your script was like this:
$result=mysql_query($your_create_table_st
Yeah I used the mysql_error and it returned Can't create table
'.\website\table2.frm' (errno: 150). So what does that say?
> Date: Tue, 7 Apr 2009 17:38:59 +0400
> From: evge...@kosov.su
> To: defati...@hotmail.com
> CC: mysql@lists.mysql.com
> S
Perhaps you don't have permissions to create tables?
It would have been much clearer if your script was like this:
$result=mysql_query($your_create_table_statement);
if($result){ print"Successful";}
else {print "Unsuccessful: ".mysql_error()}
abdulazeez alugo wrote:
Hi guys,
Please can anyo
I just started working with mysql and I'm very novice
Created a simple database and programmed php to connect as follows...
$link= mysql_connect($hostname,$user,$password)or die ("_something is
whong");
mysql_select_db($db,$link);
$query ="SELECT * FROM projects";
$result = mysql_query($query);
$
vious" value of Topic from
the previous record, and only output the Topic part when it changes.
HTH,
Tore.
- Original Message -
From: "Mike Walth" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, February 21, 2003 5:34 AM
Subject: PHP / MYSQL Question
Not sure if this can be done with just a MYSQL Query or if it needs to be
done in conjunction with a PHP script. What I am trying to do is build a
dynamic FAQ section with PHP. Here are the two tables
Topics
===
TopicID
TopicTitle
TopicDESC
FAQS
===
FAQID
Question
Answer
Topic
Luie,
> Wouldn't replace change all the entries in your table row, same effect as update?
> I believe the question is how to test which entry in a form has a new value and
>replace/update only that value
in the table.
> If I have a form...
>
> __
> |Employee Reco
Wouldn't replace change all the entries in your table row, same effect as update?
I believe the question is how to test which entry in a form has a new value and
replace/update only that value in the table.
If I have a form...
__
|Employee Record Update|
|
ginal Message-
> From: Rick Emery [mailto:[EMAIL PROTECTED]]
> Sent: Friday, 15 February 2002 11:10 a.m.
> To: [EMAIL PROTECTED]
> Cc: '[EMAIL PROTECTED]'
> Subject: FW: [PHP] MySQL question...not sure if this is the correct
> forum to ask.
>
>
> -Origi
-Original Message-
From: Peter Ruan [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 14, 2002 4:04 PM
To: [EMAIL PROTECTED]
Subject: [PHP] MySQL question...not sure if this is the correct forum to
ask.
Hi,
Can the UPDATE statement have conditional check embedded in it? I
have a
Dave Lake wrote:
>
> Hi Folks
>
> I have used MySQL for some time and am just getting my head around PHP. I
> looked across a number of PHP sites for some input on this but failing to
> find an answer thought I would ask some MySQL users (surely many of you are
> using PHP right? ;-) ) for help.
On Sun, 10 Jun 2001 19:13:01 -0700, "Vladimir Kravtsov" <[EMAIL PROTECTED]>
wrote:
>>
>>
>>
>>>connectdb();
>>mysql_select_db(xtopsites);
>>$validated=1;
>>$sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>//
On Sun, Jun 10, 2001 at 07:13:01PM -0700, Vladimir Kravtsov wrote:
> $sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>// Line 8
Actually, using '$validated' might work better - one or the other.
Whit
-
On Sun, Jun 10, 2001 at 07:13:01PM -0700, Vladimir Kravtsov wrote:
> $sql = "select id, siteurl, sitename, from sitesats where validated = "$validated"";
>// Line 8
> What's wrong here?
Try \"$validated\" - you need to escape the quoted quotes.
Whit
---
On 11-Jun-01 Vladimir Kravtsov wrote:
>
>
>
> connectdb();
> mysql_select_db(xtopsites);
> $validated=1;
> $sql = "select id, siteurl, sitename, from sitesats where validated =
> "$validated""; // Line 8
^ ^ - escape your quotes, \"$validated\";
change to sin
You have a problem with "...
" is reserved word, put \ before it...
try this:
$sql = "select id, siteurl, sitename, from sitesats where validated =
\"$validated\"";
regards,
Augusto
On Sun, 10 Jun 2001, Vladimir Kravtsov wrote:
>
>
>
> connectdb();
> mysql_select_db(xtopsites);
> $valid
When I run this I get: Parse error: parse error in
c:\inetpub\wwwroot/php/X-TopSites/admin/admin.php on line 8
I want it to select the id, siteurl, sitename (in a table called sitesats) of any site
which is not validated (I made it so validated=1 and not validated=2)
What's wrong here?
T
you can use fetch_array:
$data = mysql_query("select * from Categories");
$aux="";
while ($row = mysql_fetch_array($data)) {
$aux.="".$row['Name']."";
}
$aux.="";
echo $aux;
this code will print in html a combobox with the options, in php, the
variable "$catagorie" will have the "id" number o
Have a look at the PHP mysql_fetch_array and mysql_fetch_row functions and
associated documentation...
";
}
?>
On Sun, 10 Jun 2001, Vladimir Kravtsov wrote:
> Here is my db hierarchy:
> Database: xtopsites
> Table: Categories
> idName
> 1Name1
> 2Name2
> 3Name3
> 4Name4
>
Here is my db hierarchy:
Database: xtopsites
Table: Categories
idName
1Name1
2Name2
3Name3
4Name4
5Name5
6Name6
I would like the user to get to a sign up form and have all the names of the
categories displayed.is this possible to do using fetch_array? If it i
Hello Adrian,
Friday, June 08, 2001, 8:59:51 AM, you wrote:
ADC> Hi,
ADC> I am not sure whether this relates to this list or the (not working) php
ADC> list.
ADC> For simplicity: I have a form that displays data from a table. I will
ADC> take just one field that displays a name
ADC>
ADC> T
database,sql,query
On Fri, 8 Jun 2001, Gabriele Bartolini wrote:
>
> >magic_quotes_gpc = On ; magic quotes for
> >incoming GET/POST/Cookie data
>
> And, what about: magic_quotes_runtime ?
Off.
Adrian
--
On Fri, 8 Jun 2001, Rolf Hopkins wrote:
> What you wrote here and what you wrote below are not the same
>
> update vusers set name="Adrian D'Costa" where id=3;
>
> update vusers set name='Adrian D\'Costa' where id=3;
>
> will both work. Look up the section on escaping special characters in the
- Original Message -
From: "Adrian D'Costa" <[EMAIL PROTECTED]>
To: "Rolf Hopkins" <[EMAIL PROTECTED]>
Cc: "Mysql Mailing List" <[EMAIL PROTECTED]>
Sent: Friday, June 08, 2001 17:47
Subject: Re: php/mysql question
> On Fri,
On Fri, 8 Jun 2001, Rolf Hopkins wrote:
>
> - Original Message -
> From: "Adrian D'Costa" <[EMAIL PROTECTED]>
> To: "Mysql Mailing List" <[EMAIL PROTECTED]>
> Sent: Friday, June 08, 2001 13:59
> Subject: php/mysql question
>
>
On Fri, 8 Jun 2001, Gabriele Bartolini wrote:
>
> >$tname =urldecode($name);
> >$tname1 = stripslashes($tname1);
> >$updtStmt = "update vusers set orgname='$tname1' where id=$tid";
>
> It all depends on these 2 variables settings:
>
> magic_quotes_gpc= On
> magic_quotes_runtime=
[EMAIL PROTECTED]>
Sent: Friday, June 08, 2001 7:59 AM
Subject: php/mysql question
> Hi,
>
> I am not sure whether this relates to this list or the (not working) php
> list.
>
> For simplicity: I have a form that displays data from a table. I will
> take just one field that
Hi,
I am not sure whether this relates to this list or the (not working) php
list.
For simplicity: I have a form that displays data from a table. I will
take just one field that displays a name
This allow a user to update the changes when the submit button is pressed.
On the next php file I
- Original Message -
From: "Adrian D'Costa" <[EMAIL PROTECTED]>
To: "Mysql Mailing List" <[EMAIL PROTECTED]>
Sent: Friday, June 08, 2001 13:59
Subject: php/mysql question
> Hi,
>
> I am not sure whether this relates to this list or the (n
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