* Carlos Vazquez
> I get this error when I try to execute the following select statement:
> "All Parts of a PRIMARY KEY must be NOT NULL; if you need null in
> a key, use UNIQUE instead."
>
> CREATE TEMPORARY TABLE IF NOT EXISTS
> CashVariances
> (PRIMARY KEY(sUnit))
> SELECT
> sUnit,
$query = "SELECT date, AES_DECRYPT('cardnumber1','jmbjd'),
AES_DECRYPT('cardnumber2','jmbjd'), AES_DECRYPT('cardnumber3','jmbjd'),
AES_DECRYPT('cardnumber4','jmbjd'), upload_type, z_errors, a_errors,
db_errors FROM customers WHERE refrence_number = '$refnum'";
If 'cardnumber1' is the name of the c
On 6 Feb 2004, at 14:38, Erich Beyrent wrote:
This seems really efficient, since the only large number of rows to
search against is the main listings table, if I read this right. Is
there any further optimization that I can do, or this as good as it
gets? Believe me, I am NOT complaining!!!
Yes,
the WHERE clause, right?
>
> Thanks!
>
> -Erich-
>
>
> -Original Message-
> From: Schwartz, Evelyn [mailto:[EMAIL PROTECTED]
> Sent: Friday, February 06, 2004 8:53 AM
> To: [EMAIL PROTECTED]; [EMAIL PROT
From: Erich Beyrent [mailto:[EMAIL PROTECTED]
Sent: Fri 2/6/2004 9:00 AM
To: [EMAIL PROTECTED]
Cc:
Subject: RE: Help with query
Hi Evelyn,
How would I do that - would something like this be what you had in mind?
, February 06, 2004 8:53 AM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: Help with query
You will need parentheses around the 'or' clauses of your where clause.
You also don't seem to join the categories table with any other tables. If
you don't join tables you
You will need parentheses around the 'or' clauses of your where clause.
You also don't seem to join the categories table with any other tables. If you don't
join tables you will create what is called a 'cross product' query. If table A has 10
rows and table B has 20 rows then querying A and
-Original Message-
> From: Bernard Clement [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 29, 2004 1:19 PM
> To: Howell, Scott; Mysql (E-mail)
> Subject: Re: HELP! Select queries for tables that has fields with #
> characters
>
>
> Hello Howell,
>
> See URL: http
select * from emp where `file#` = 1332;
returns
ERROR 1054: Unknown column 'file' in 'where clause'
-Original Message-
From: Bernard Clement [mailto:[EMAIL PROTECTED]
Sent: Thursday, January 29, 2004 1:19 PM
To: Howell, Scott; Mysql (E-mail)
Subject: Re: HELP! Selec
Hello Howell,
See URL: http://www.mysql.com/doc/en/Legal_names.html for the solution.
Basically enclose FILE# with `, e.g. where `FILE#` = 1332
Bernard
On Thursday 29 January 2004 12:55, Howell, Scott wrote:
> I am trying to query a table that has field names with # characters in
> them. For ex
From: Howell, Scott [mailto:[EMAIL PROTECTED]
> I am trying to query a table that has field names with #
> characters in them.
> For example a table emp_earn has a field called FILE#
>
> I need to do a query where FILE# = 1332, but anything I try
> errors out.
I can't seem to even create a
* jalil
> I need to get total number of all rows in a table and also select some
> rows from the same table. I know how to do this
> using two queries, but was wondering if there is any way to do it in one
> query (one trip to the database).
>From version 4 you can use the SQL_CALC_FOUND_ROWS opti
Hi Li,
If you want to see the implementation portion of C coding for mysql_real_connect, U
can see open
the mysql.h header file in any C++ editor.
I don't know Why do you want to see those iplementation?
libmysql.lib is a library file used to permit dynamic calls from it's clients.
libmysqld.lib
Try single quotes around instead of double quotes.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Jay Blanchard wrote:
[snip]
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as
timein FROM emp2 where mo
nth(hdate)=$mymonth and empnum < "" order by timein";
[/snip]
Change to single quotes around data
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEA
[snip]
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as
timein FROM emp2 where mo
nth(hdate)=$mymonth and empnum < "" order by timein";
[/snip]
Change to single quotes around data
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as timein FR
: Don Matlock [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 04, 2004 11:32 AM
To: [EMAIL PROTECTED]
Subject: RE: Help:)
Thank you very much for the prompt reply.
Yes you were correct, it was the fact that the password had not been
entered at all...I did the
mysql -u root -p
when prompted for the
pe in the command for the pass wrong?
Don
-Original Message-
From: Michael Stassen [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 04, 2004 2:40 AM
To: robert_rowe
Cc: [EMAIL PROTECTED]; Don Matlock
Subject: Re: Help:)
robert_rowe wrote:
Issuing this command:
mysql>SET PASSWORD
try...
update user set password=PASSWORD('xx') where user='root' and
host='localhost';
(replacing the x's with the password)
Larry
-Original Message-
From: Don Matlock [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 04, 2004 11:32 AM
To:
sage-
From: Michael Stassen [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 04, 2004 2:40 AM
To: robert_rowe
Cc: [EMAIL PROTECTED]; Don Matlock
Subject: Re: Help:)
robert_rowe wrote:
> Issuing this command:
>
>
>>mysql>SET PASSWORD FOR 'root'@'localhost'
robert_rowe wrote:
Issuing this command:
mysql>SET PASSWORD FOR 'root'@'localhost' = PASSWORD xx
set your password to xx
I'm not so sure. PASSWORD is a function which expects a string. The
correct syntax is
SET PASSWORD FOR 'root'@'localhost' = PASSWORD('new_password')
so I
Issuing this command:
> mysql>SET PASSWORD FOR 'root'@'localhost' = PASSWORD xx
set your password to xx
You will need to use
mysql -u root -p xx
from the local machine to get access with the root user.
This:
mysql -u root -p
is specifying a blank password.
I beli
Dear all,
thank you very much for the fast and numerous responses. The idea of Roger
Baklund does exactly what I want. Thank you very much Roger.
I oversee the possibility to use IF conditions on MySQL server, this is what
I wanted to do programmatically but to do in the DB server is ok. Let's s
on 12/29/03 12:00 PM, Bjoern Wuest wrote:
> Hello
>
> I have the following problem:
>
> Table1 'pl':
> +---+---+
> | p | o |
> +---+---+
>
> Table2 'ln':
> +---+--+---+
> | p | l | v |
> +---+--+---+
>
> Now my problem: how to write a statement to select all 'p' and 'v' from 'pl'
>
--- rmck <[EMAIL PROTECTED]> wrote:
> mysql> SELECT start,ID FROM table ORDER BY id DESC
> LIMIT 1;
>
> ++---+
> | start | ID|
> ++---+
> | 10726035
* Bjoern Wuest
> I work on this problem for three days now and could not find any
> tip in any manual, book, tutorial or search engine.
>
> I have the following problem:
>
> Table1 'pl':
> +---+---+
> | p | o |
> +---+---+
> | 1 | 1 |
> | 2 | 1 |
> | 3 | 2 |
> +---+---+
>
> Table2 'ln':
> +---
>
> -Message d'origine-
> De : Carlos André Moura de Amorim [mailto:[EMAIL PROTECTED]
> Envoyé : vendredi 19 décembre 2003 14:55
> À : Chris Elsworth
> Cc : [EMAIL PROTECTED]
> Objet : Re: Help me - please
>
>
>
> i added ulimit -n 1024 in mysql_insta
what distro are you using? what is running on this server? another
server is runnin' on the same machine? what hardware are you using? is
it heavy loaded?
On Fri, 2003-12-19 at 09:54, Carlos Andrà Moura de Amorim wrote:
> i added ulimit -n 1024 in mysql_install_db, i can't to install. Appear th
You must be 'root' to do a "ulimit -n 1024".
Marc.
-Message d'origine-
De : Carlos André Moura de Amorim [mailto:[EMAIL PROTECTED]
Envoyé : vendredi 19 décembre 2003 14:55
À : Chris Elsworth
Cc : [EMAIL PROTECTED]
Objet : Re: Help me - please
i added ulimit -n
i added ulimit -n 1024 in mysql_install_db, i can't to install. Appear the
error again. Please again!!!
On Thu, 18 Dec 2003, Chris Elsworth wrote:
> On Thu, Dec 18, 2003 at 05:28:30PM -0200, Carlos Andr? Moura de Amorim wrote:
>
> > 031217 14:32:34 Warning: setrlimit couldn't increase number o
"xian ting" <[EMAIL PROTECTED]> wrote:
> in sql: insert into table select from ...
> can select from a remote data base server such as sqlserver using odbc
> as 'SELECT * into test01 FROM Fund IN [ODBC] [ODBC;Driver=SQL
> Server;UID=admin;PWD=;Server=(lacal);DataBase=CMBXMDM;]'in access.
> thanks
On Thu, Dec 18, 2003 at 05:28:30PM -0200, Carlos Andr? Moura de Amorim wrote:
> 031217 14:32:34 Warning: setrlimit couldn't increase number of open files
> to more than 256 (request: 510)
It might be worth putting a "ulimit -n 1024" (or some other decent
number) in the rc.d script that starts my
- Original Message -
From: "Andy (da man) Rosenblatt" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, November 29, 2003 4:05 PM
Subject: HELP!
> hi
> I bought a book with your mySQL program and seemed to have installed it
worng and i cant stop it. I never set a user name or
Hi Greg,
> Here's my situation. I'm implementing radiusd on a solaris box using
> a mysql database that's on a remote windows host. I've managed to get
> a user authenticaed (still with the CLID unknown message, but I'll
> move on. Hope that's OK to do.)
It's OK. Moreover, since that message i
Hi Dominic,
> I think everyone is misunderstanding my problem as perhaps I didnt phrase
it very well.
>
> I need to add a new autonumber field to my db, but I need to make sure
when the numbers go into the field they are in the order of one of my other
fields that is a date field.
>
> i.e. I have
Hi,
(please reply to the list only)
> Yes thanks but how do I then add a new auto number field and still keep
the order?
What order? What has an auto-number have to do with what order?
Please explain your problem in detail - it might be completely clear to you,
but we're outsiders :-)
With reg
Hi,
> I need to add a new auto field to my db, but I need to make sure the
records are listed in order of one of the other fields first which is a date
field.
>
> Any ideas how I do this would be greatly appreciated!
"listing records" is in no particular order, unless you ask for an order.
SELEC
>From MySQL Manual:
"If you want to change the number or the size of your InnoDB log files,
you have to shut down MySQL and make sure that it shuts down without
errors. Then copy the old log files into a safe place just in case
something went wrong in the shutdown and you will need them to recover
003 10:06 AM
To: [EMAIL PROTECTED]
Cc: Admin-Stress
Subject: Re: help on my query statement
* Admin-Stress
> I have a table called TRANSACTION, it has some fields :
>
> REGDATE - date of the transaction
> WHAT - a string (NOT UNIQUE)
> CUSTOMER - customer code
>
> I want to q
* Admin-Stress
> I have a table called TRANSACTION, it has some fields :
>
> REGDATE - date of the transaction
> WHAT - a string (NOT UNIQUE)
> CUSTOMER - customer code
>
> I want to query all WHAT that the date of the transaction was 15
> days before.
>
> So, my sql query is :
>
> SELECT WHAT FROM
www.cpan.org
or
www.rpmfind.net comes in a package.
Most perl distributions have this installed by default.
- Dathan Vance Pattishall
- Sr. Programmer and mySQL DBA for FriendFinder Inc.
- http://friendfinder.com/go/p40688
-->-Original Message-
-->From: Daniel [mailto:[EMAIL PRO
* Unnar
> I have a problem with this query
>
> Version MySQL 4.0.15-nt
>
> The query gets all articles written by author but excludes those articles
> which are related to products
>
> SELECT DISTINCT
> post.post_id,
> post.title
> FROM
> c_posts post,
> c_post_produ
SELECT *
FROM
WHERE value > 915
-Original Message-
From: delz [mailto:[EMAIL PROTECTED]
Sent: Friday, October 17, 2003 9:46 AM
To: [EMAIL PROTECTED]
Subject: Help in querying
Hi All,
I'm using mysql as my database. I have a table which has the following
colums:
idx
productname
value
Shaun
Not a 100 % sure if this is what you're looking for or if somebody's already
suggested it also do not know how practical it is for your application
If a booking spans more than one day (e.g. two) split it into two days - and
write two records to the table one for each daythis fi
I'm under the impression that your over thinking the problem.
LOOK-UP the functions DATE_SUB / INTERVAL / TIME_TO_SEC / TO_DAYS and
the arithmetic should be easy.
- Dathan Vance Pattishall
- Sr. Programmer and mySQL DBA for FriendFinder Inc.
- http://friendfinder.com/go/p40688
-->-Or
On Wed, 2003-10-08 at 09:52, shaun thornburgh wrote:
> Hi,
>
> I have a table called Bookings which has two important columns;
> Booking_Start_Date and Booking_End_Date. These columns are both of type
> DATETIME. The following query calculates how many hours are available
> between the hours of 09
s one is my .02... :-)
-Original Message-
From: shaun thornburgh [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 07, 2003 3:51 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: Help With a DATETIME Query
Thanks for your reply, but its not an option!
>From: "Dan Greene&q
Thanks for your reply, but its not an option!
From: "Dan Greene" <[EMAIL PROTECTED]>
To: "shaun thornburgh" <[EMAIL PROTECTED]>,
<[EMAIL PROTECTED]>
Subject: RE: Help With a DATETIME Query
Date: Tue, 7 Oct 2003 16:41:04 -0400
I know it's not the a
I know it's not the answer you're looking for... :( but dealing with overnights has
caused me so much aggravation in past apps I've written, I've tended to make the
client create two (or more) 'bookings' for the covered time... don't know if it's an
option for you, but it's my $0.02.
> -
Hi,
I would do this in the application layer something like this:
$list_of_days_you_want_to_look_at = ('mon','tue','wed'..); Foreach ($day
in $list_of_days_you_want_to_look_at) {
use a similar query to below but geared to only look at $day instead; }
You should get an output like this:
Hi,
I would do this in the application layer something like this:
$list_of_days_you_want_to_look_at = ('mon','tue','wed'..);
Foreach ($day in $list_of_days_you_want_to_look_at) {
use a similar query to below but geared to only look at $day instead;
}
You should get an output like this:
At 3:08 PM +0200 9/19/03, Daniele Tagliavini wrote:
Hi,
I have a question for the LIMIT clause.
I have two table with relation 1:n and a query like this :
SELECT tableA.id, tableB.name FROM tableA INNER JOIN tableB ON
tableA.id=tableB.id WHERE something LIMIT x, 20
I want to restrict the result
Here is the corrected version:)
Take a look at Paul DuBois book. Don't use gets. Instead use fgets. That's
safe. I didn't change your gets call:)
hth,
Ganbold
#include
#include
#include
#if defined(_WIN32) || defined(_WIN64)
#include
#endif
#ifdef WIN32
#pragma comment(lib,"ws2_32")
#inc
Thanks Martin,
No I do not have that option unfortunately. I really do suspect that it has
nothing to do with mysql and that rather it is the router/IPs configuration
and called them upon this, but they said all is fine. So I frankly have no
clue where to go from here.
thanks again for any sug
At 11:25 -0400 9/6/03, Roger Davis wrote:
I am having a bit of trouble with the "IN" operator. I am thinking that it
just may be my misunderstanding.
Situation.
I have a table (ZipCounty) that I want to pull vendors from based on
zipcode. So I have a Vendor like field declared as TEXT. T
You are misunderstanding the 'IN' operator
Try and think of it this way
SELECT value from table where field in (1,2,3)
is the same as
SELECT value from table where field = 1 or field = 2 or field = 3
So in you case
SELECT Count(ID) FROM ZipCounty WHERE '528' IN (VendorLink);
is
SELECT Count(ID)
I'd bump up these two settings.
innodb_buffer_pool_size=32M
innodb_additional_mem_pool_size=16M
I'm not sure what the max is on innodb_buffer_pool_size,
but that is where innodb caches data. The more that is in cache
means less disk reads which equals speed.
walt
K Old wrote:
>
> Hello ever
Hi!
Try this:
SELECT TD.project_id, P.project_manager,
SUM( TD.time_hours_worked ) as hours
FROM time_daily TD
INNER JOIN projects P ON P.project_id = TD.time_project_id
WHERE TD.time_user_id = 'xpt'
HAVING hours <> '0.00'
Hope this helps!
On Wed, 2003-09-03 at 17:24, Cory Hicks wrote:
Hi,
Paul DuBois said:
> At 11:24 -0500 9/3/03, Cory Hicks wrote:
>>Hey folks,
>>
>>I am trying to run the following sql query in mysql:
>>
>>SELECT TD.project_id, P.project_manager
>>FROM time_daily TD
>>INNER JOIN projects P ON P.project_id = TD.time_project_id
>>WHERE TD.time_user_id = 'xpt' AND
Sorry,
I think it should be
GROUP BY TD.project_id, P.project_manager
Cory Hicks said:
> Hey folks,
>
> I am trying to run the following sql query in mysql:
>
> SELECT TD.project_id, P.project_manager
> FROM time_daily TD
> INNER JOIN projects P ON P.project_id = TD.time_project_id
> WHERE TD.
Cory,
Cory Hicks said:
> Hey folks,
>
> I am trying to run the following sql query in mysql:
>
> SELECT TD.project_id, P.project_manager
> FROM time_daily TD
> INNER JOIN projects P ON P.project_id = TD.time_project_id
> WHERE TD.time_user_id = 'xpt' AND (
> SUM( TD.time_hours_worked ) <> '0.00'
>
At 11:24 -0500 9/3/03, Cory Hicks wrote:
Hey folks,
I am trying to run the following sql query in mysql:
SELECT TD.project_id, P.project_manager
FROM time_daily TD
INNER JOIN projects P ON P.project_id = TD.time_project_id
WHERE TD.time_user_id = 'xpt' AND (
SUM( TD.time_hours_worked ) <> '0.00'
[EMAIL PROTECTED] wrote:
>
> In a normal case, to install Mysql in windows we need to run setup.exe and
> it's launch a wizard when we define some things like a destination
> directory.
>
> I want to know (if somebody can help me) if it is possible to install mysql
> and the wizard not be lau
On Sat, Aug 23, 2003 at 10:42:45AM -0400, March, Kristopher (Contractor) (DSCR) wrote:
> I'm trying to install DBI perl modules on a SUN 8 box.
>
> I can't seem to find a make utilitity for building the components. Is it
> called something else or will I have to go out and install it?
Is /usr/u
Hi,
try this:
SELECT * FROM your_table
WHERE StartDate > NOW()
AND EndDate < NOW()
> Hello,
>
> I am having a problem when doing a SELECT. Here is the
> scenerio:
>
> I have a table that has an event StartDate and
> EndDate, based on the current Date "NOW()" I need to
> know which records are
SELECT * FROM table_name WHERE EndDate < now();
Is this what you need?
-Original Message-
From: Rob Sirota [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 19, 2003 4:12 AM
To: [EMAIL PROTECTED]
Subject: Help with SELECT statement for date range
Hello,
I am having a problem when doing a
On Tue, 19 Aug 2003 04:11:32 -0700 (PDT)
Rob Sirota <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I am having a problem when doing a SELECT. Here is the
> scenerio:
>
> I have a table that has an event StartDate and
> EndDate, based on the current Date "NOW()" I need to
> know which records are curren
what ever happend to a unique primary key like userID ?
>>> "gord barq" <[EMAIL PROTECTED]> 08/11/03 11:15am >>>
I have a table I'm using for logging purposes with a schema like:
create table results (
user varchar(255)
);
Where user is not a unique field and I want to find out how
select count(distinct(user)) from results;
Cheers,
Jan
--
Janice Wright
Ingenta plc
[EMAIL PROTECTED]
Tel: +44 (0) 01865 799114
http://www.ingentaselect.com/
Sometime recently Daniel Rossi said:
> what ever happend to a unique primary key like userID ?
>
> >>> "gord barq" <[EMAIL PROTECTED
On Mon, 11 Aug 2003, gord barq wrote:
> I have a table I'm using for logging purposes with a schema like:
>
> create table results (
> user varchar(255)
>
> );
>
> Where user is not a unique field and I want to find out how many unique
> users there are in the table.
>
> I want to do
AIL PROTECTED]
> Sent: August 11, 2003 2:21 PM
> To: Aaron Wolski
> Cc: [EMAIL PROTECTED]
> Subject: Re: Help debugging this Query?
>
> Aaron,
> It sounds like the join has duplicates on both sides. If you join a->b
> where a is unique (like a primary key) then you will
Aaron,
It sounds like the join has duplicates on both sides. If you join a->b
where a is unique (like a primary key) then you will get count(b)
records (where b is the rows that match a). Or if b is unique then you
will get count(a) records. However if neither a or b is unique you get
count(a) * co
>
> what ever happend to a unique primary key like userID ?
>
User is not the primary key. This is a logging table so the primary key is
likely to be a timestamp of some sort.
Read the question.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:htt
At 08:15 PM 8/10/2003, you wrote:
I have a table I'm using for logging purposes with a schema like:
create table results (
user varchar(255)
);
Where user is not a unique field and I want to find out how many unique
users there are in the table.
I want to do something like:
select co
2003年 8月 2日 土曜日 15:11、あなたは書きました:
> Hi frnd.
>
> I am also using mysql and facing problems regarding access to
> the
> db using odbc from visual basic.
>
> i have made a table under mysql default db and
>
> used ms ado to connect to the db.
>
> what will be the server name in such a case(that will b
* Petre Agenbag
> The distinct clause will return only one occurrance of the
> implicated field.
> distinctrow would do the same, but for an entire row. what I am
> looking for
> is something like distinctset(field1,field2,field7) , is this what the
> MAX-CONCAT "trick" attempts to do?
Not exactly
t to make sure that you (or anyone else
interested in this thread) understands exactly what the question is (
believe me, after a while thinking of it myself, I sometimes lose the entire
question completely inbetween all the "if" "and" and "or"'s flying through
my
* Petre Agenbag
[...]
> This works:
>
> select distinct name, max(id) as mid from table group by name
>
> but it only returns the name and the highest id for such a name.
>
> if I try this:
>
> select distinct name, max(id) as mid, anything_else from table group by
> name
>
> it returns the FIRST
ailto:[EMAIL PROTECTED]
Sent: jeudi 31 juillet 2003 15:52
To: [EMAIL PROTECTED]
Subject: RE: Help!!! Need to backup mysql using - MYSQL Second Edition?
Thank you once again, so the correct thing is:
C:\mysql\bin\>mysqldump -u ola -p --opt --databases --complete-insert
--flush-logs >
Hi,
rapid correction !!
in the backup command, retrieve the word mysql placed just after
--flush-logs .
Thierno 6C
-Original Message-
From: Thierno Cissé [mailto:[EMAIL PROTECTED]
Sent: jeudi 31 juillet 2003 15:40
To: 'Ola Ogunneye'
Cc: [EMAIL PROTECTED]
Subject: RE: Help!
iginal Message-
From: Ola Ogunneye [mailto:[EMAIL PROTECTED]
Sent: jeudi 31 juillet 2003 15:15
To: [EMAIL PROTECTED]
Subject: RE: Help!!! Need to backup mysql using - MYSQL Second Edition?
Hi, sorry to bother you, but from what you recommended, am I typing
everything just the way you typed
hi,
> Still a newbie, and running mysql on windows 2000 Advanced Server. I
am trying to backup
> mysql and was confused as to which command to use. I see the following
options
use mysqldump .
If you want backup whole database(s) , proceed to next :
mysqldump -u username -p --opt --databases --com
On 25-Jul-2003 Vikram Vaswani wrote:
> mysql> SELECT * FROM branches;
> +--+-++--+
>| bid | cid | bdesc | bloc |
> +--+-++--+
>| 1011 | 101 | Corporate HQ | CA |
Try this ...
Delete from clients where 0 = (select count(*) from branches where branches.cid =
clients.cid)
Cheers
FattShin
-Original Message-
From: Vikram Vaswani [mailto:[EMAIL PROTECTED]
Sent: Friday, July 25, 2003 9:51 PM
To: Nils Valentin; [EMAIL PROTECTED]
Subject: Re: Help with
Estoy tomando el sol
.
q
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Hey,
Thanks for the help. I dont think this is possible, because MySQL will not
let you delete from the same table you are reading. Is there an alternative
way to do this using a subquery, you think?
>ignore both previous posts. Both don't work as wanted. I just realized that
>and I will come ba
Hi Vikram,
ignore both previous posts. Both don't work as wanted. I just realized that
and I will come back to you after I created the tables and made it sure.
Sorry for the confusion.
Best regards
Nils Valentin
Tokyo/Japan
2003年 7月 25日 金曜日 14:42、Nils Valentin さんは書きました:
> Hi Vikram,
>
> just
Hi Vikram,
just read the post once more. I made a mistake. You want to delete the
clients with no branches you said, so the command should look like
mysql> delete from clients where cid = (select clients.cid from clients
left join branches using (cid) WHERE ISNULL(clients.cid);
Note that cid
Hi Vikram,
NULL is a special data type and requires special procedures.
Try this:
> mysql> delete from clients where cid = (select clients.cid from clients
> left join branches using (cid) WHERE ISNULL(bid);
Please make NO SPACE betwen ISNULL and (bid) as otherwise wit will give you
an syntax
Hi Michael,
I a not 100% sure if I understood you correctly, but what you want to do seems
to be better made in the application itself, rather then the SQL code.
However you can use ALIASES together with the GROUP BY function and specify 2
columns (Cars and COUNT(Monthofyear) which should list
!
-Original Message-
From: Ryan Schefke [mailto:[EMAIL PROTECTED]
Sent: Friday, July 18, 2003 11:05 AM
To: 'Jason k Larson'
Subject: RE: * HELP * MySQL Connection Issue - Access Denied!!
Hey Jason - Thanks a ton for your help! You're a lifesaver!
When I use 'localhost&#x
CREATE TABLE NAME (
SELECT name, work
FROM A
UNION ALL
SELECT name, home
FROM A
WHERE home IS NOT NULL
);
CREATE TABLE ADDRESS (
SELECT work
FROM A
UNION ALL
SELECT home
FROM A
WHERE home IS NOT NULL
);
Cheers
/rudy
-Original Message-
From: Colt Br
Matthias,
I, like everyone else on the list it appears, have no idea how to help you
as you have provided no example of what you are trying to do, no output and
no error messages.
Remember everyone gives help here for free, so people tend to help people
who make it clear what the problem is.
I k
Egor,
It says 'update command denied to user: 'any user i put here' for table
'test2'
No matter what user/host combination I use I ALWAYS get this error.
-Original Message-
From: Egor Egorov [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 01, 2003 5:13 AM
To: [EMA
"Twibell, Cory L" <[EMAIL PROTECTED]> wrote:
>
> I have the user table which contains user record
> | Host | User| Pass | Select...|
> ---
> |% || | N... |
>
> The db record is
> | Host | Db| User | Select...|
> --
IL PROTECTED]
> Subject: RE: Help with privilege tables - IMPORTANT
>
>
> Yes, I have the UPDATE for table B. I belive this is a bug.
>
> -Original Message-
> From: Mike Hillyer [mailto:[EMAIL PROTECTED]
> Sent: Monday, June 30, 2003 4:47 PM
> To: Twibell, Cory L
Yes, I have the UPDATE for table B. I belive this is a bug.
-Original Message-
From: Mike Hillyer [mailto:[EMAIL PROTECTED]
Sent: Monday, June 30, 2003 4:47 PM
To: Twibell, Cory L; [EMAIL PROTECTED]
Subject: RE: Help with privilege tables - IMPORTANT
Hmm, if you have UPDATE privilege on
, June 30, 2003 4:26 PM
> To: Mike Hillyer; Twibell, Cory L; [EMAIL PROTECTED]
> Subject: RE: Help with privilege tables - IMPORTANT
>
>
> Ok, the user has the appropriate privileges in the db table.
> The user can select, insert, update, deletewhatever.
> What he CAN'
003 4:22 PM
To: Twibell, Cory L; [EMAIL PROTECTED]
Subject: RE: Help with privilege tables - IMPORTANT
Well, with that in mind, does the user have the appropriate INSERT
privileges?
Regards,
Mike Hillyer
www.vbmysql.com
> -Original Message-
> From: Twibell, Cory L [mailto:[EMAI
IL PROTECTED]
> Subject: RE: Help with privilege tables - IMPORTANT
>
>
> My user in the user table has NO privileges. All privileges
> for that user
> are done in the db table. Using MySQL 4.1.0-alpha
>
> -Original Message-
> From: Mike Hillyer [mailto:[EMAIL PROTEC
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