SELECT DATE_FORMAT(dato, '%e/%c/%Y') AS dato FROM transportdokument WHERE
dato = '2013-07-20' AND dato = '2013-07-24' GROUP BY dato DESC is working
perfect in my PHP file.
But I need to transfer the date back from my norwegian formatted date to
the origin date format in WHERE dato
...@gmail.com]
Sent: Wednesday, July 24, 2013 7:02 AM
To: MySQL Mailinglist
Subject: From DATE_FORMAT and back to origin date in mysql date column
SELECT DATE_FORMAT(dato, '%e/%c/%Y') AS dato FROM transportdokument WHERE
dato = '2013-07-20' AND dato = '2013-07-24' GROUP BY dato DESC is
working perfect
Good Afternoon All
following the documentation available at
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
i wish to select a date using DD-MON-YY format but my format of '%y-%b-%d'
appears to be incorrect
mysql select DATE_FORMAT('11-10-09','%y-%b-%d') from DUAL
Basicay, your date_format works like:
select DATE_FORMAT('YY-MM-DD','%y-%b-%d') from DUAL;
Martin Gainty mgai...@hotmail.com escreveu na mensagem
news:blu142-w2137936b18ae273dbd6cb1ae...@phx.gbl...
Good Afternoon All
following the documentation available at
http://dev.mysql.com/doc/refman
To: mysql@lists.mysql.com
From: j...@consultorweb.cnt.br
Subject: Re: DATE_FORMAT parameter question
Date: Fri, 9 Apr 2010 12:56:46 -0300
Basicay, your date_format works like:
select DATE_FORMAT('YY-MM-DD','%y-%b-%d') from DUAL;
Martin Gainty mgai...@hotmail.com escreveu na mensagem
If you'll excuse the shameless plug: I once created a tool to help find
the exact parameters to use for PHPs date() and MySQLs DATE_FORMAT().
Please see
http://bitbybit.dk/php/date_format/
(Yes, it looks horrible. But it works)
/ Carsten
Martin Gainty skrev:
Good Afternoon All
following
que les email peuvent facilement
être sujets à la manipulation, nous ne pouvons accepter aucune responsabilité
pour le contenu fourni.
Date: Fri, 9 Apr 2010 19:02:33 +0200
From: cars...@bitbybit.dk
To: mgai...@hotmail.com
CC: mysql@lists.mysql.com
Subject: Re: DATE_FORMAT parameter
Hello mysql,
I have a PHP script that is running the following query:
SELECT `Messages`.`ID`,
`Messages`.`Sender`,
`Messages`.`Subject`,
DATE_FORMAT( `Messages`.`Date`, '%D %M %Y' ) AS Date,
LEFT(`Messages`.`Text`, 200 ) AS Preview,
`Messages`.`New`,
`Profiles`.`NickName`,
`Profiles`.`RealName
Hello mysql list,
As is very often the case, five minutes after I posted this, I found
the problem or solution, not sure it was the problem as I am not
convinced that mysql ought to get confused so easily. I changed
DATE_FORMAT( `Messages`.`Date`, '%D %M %Y' ) AS Date,
DATE_FORMAT( `Messages
RE: Import Access Data...
I'll try and import using ODBC. Is there any good web sites
about ODBC and its operations that I can learn about it?
Scott
If you haven't found this by now:
http://forums.mysql.com/list.php?65 - MySQL forum for Access conversion.
Many people use ODBC to migrate
date_format('2004-10-03 15:06:14','%m/%d/%y %T');
How do I create a table using:
date_format('2004-10-03 15:06:14','%m/%d/%y %T');
That way I can import Access Data?
--
Power to people, Linux is here.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http
Thanks! I'll try and import using ODBC. Is there any good web sites
about ODBC and its operations that I can learn about it?
Scott
On Mon, 07 Mar 2005 09:26:56 +1100, Daniel Kasak
[EMAIL PROTECTED] wrote:
Scott Hamm wrote:
How do I create a table using:
date_format('2004-10-03 15:06:14
Scott Hamm wrote:
How do I create a table using:
date_format('2004-10-03 15:06:14','%m/%d/%y %T');
That way I can import Access Data?
Can't do that.
You can import Access data via ODBC - that way the driver figures out
how to send the data to MySQL.
I assume you are trying to export to a text
How do I create a table using:
date_format('2004-10-03 15:06:14','%m/%d/%y %T');
That way I can import Access Data?
--
Power to people, Linux is here.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
BY fixturedate
which works fine, and I'm able to output the result of the SQL without
problem.
If that query is changed to:
SELECT DISTINCT fixturedate,
MONTH(fixturedate) AS CalMonth,
DATE_FORMAT(fixturedate, '%d a%') AS testing
FROM Fixtures
ORDER BY fixturedate
Coldfusion tells me
I have the following query where the user will put in a date. They will
put it in like '01/01/04'. I use this date in my WHERE clause but MySQL
needs the date like '2004/01/01'. I tried using Date_Format('04/01/01',
'%Y-%m-%d') to change the way it is formatted but I don't get the
correct data
If you need the date like, '2004/01/01', then shouldn't it be '%Y/%m/%d'?
You still ahve the dashes (the '-' character) in your date-format, and you
need a forward-slash (the '/' character) instead.
Here's what I ran on MySQL:
mysql select date_format(NOW(), '%Y/%m/%d
Hello all,
I have a query that for some reason is now returning the incorrect year. First here is
my server configuration.
Windows 2003 Advanced server
MySQL version 4.0.15-nt
Here is my SQL statement:
SELECT
DATE_FORMAT(E.DateTime, '%X-%m-%d %h:%i:%s %p' ) AS DateTime,
E.SendCount
Try %Y instead of %X
-Original Message-
From: PAUL MENARD [mailto:[EMAIL PROTECTED]
Sent: Monday, January 05, 2004 10:08 AM
To: [EMAIL PROTECTED]
Subject: Issue with DATE_FORMAT() call returning wrong
year
Hello all,
I have a query that for some reason is now returning
the incorrect
: Issue with DATE_FORMAT() call returning wrong
year
Hello all,
I have a query that for some reason is now returning
the incorrect year. First here is my server
configuration.
Windows 2003 Advanced server
MySQL version 4.0.15-nt
Here is my SQL statement:
SELECT
DATE_FORMAT(E.DateTime, '%X-%m
Hi, i have a problem with getting the right return values from field purrdato.
All records exept a few are set with date and the rest is NULL. The field allows Null
values. when using: DATE_FORMAT(purrdato, '%d.%m.%Y') AS purrdato ...it even
returns '00.00.' on null values
Okay, here's an interesting one. Here's the query:
SELECT distinct date_format(auditdate, %Y%M ) as listUrl, date_format(
auditdate, %Y%m ) as blank
FROM quality_history
WHERE auditdate Now()
ORDER BY listUrl desc
LIMIT 6
auditdate is a DATE datatype
When I run
Hello,
I have read and searched the internet, but I cannot find much on getting
mysql to return German and other languages months. Is there codes you use?
I really would prefer to use the English MySQL (if there is such a one) as I
don't know much German, and need the error messages in English!
Look in your my.ini file.
There's maybe an entry:
language=f:/mysql/share/german
Set it to your favourit language!
Bernhard
- Original Message -
From: Steve Vernon [EMAIL PROTECTED]
To: Mysql List [EMAIL PROTECTED]
Sent: Wednesday, October 22, 2003 4:47 PM
Subject: date_format
Hello Steve,
Steve Vernon wrote on 22.10.2003 16:47
I suppose I could return the month as a number, and then output the text
from that, but this seems a bit tacky!
I think that's the most reliable way, imagine you move to a new server
or install your software somewhere else . . . I
I am trying to format a TIMESTAMP column on output by using the
DATE_FORMAT() function:
Can someone tell me why this does not change the format - no error
message - just does not do anything?
$sql = SELECT * from arviContacts WHERE fid=$zz AND
DATE_FORMAT(date_rec,'%Y-%m-%d %T');
I have also
Thanks very much Robert, that worked. I was surprised at the effect of
the '*'.
Best regards,
Nicole
Robert Kostko wrote:
Hi, Nicole
IMHO after * all additional field statements DATE_FORMAT(date_rec,'%Y-%m-%d %T') are ignored. Try to list all neccessary fields after SELECT and give
):
SELECT DATE_FORMAT('2001-12-25', '%v-%y');
++
| DATE_FORMAT('2001-12-25', '%v-%y') |
++
| 52-01 |
++
SELECT DATE_FORMAT('2001-12-31', '%v-%y
year ( xx-01
is right )
Here's the an example (the second one is not what I'd expect):
SELECT DATE_FORMAT('2001-12-25', '%v-%y');
++
| DATE_FORMAT('2001-12-25', '%v-%y') |
++
| 52-01
you increment the year as well? SELECT
DATE_FORMAT('2001-12-31', '%v-%y'); returning '01-01' is inaccurate to say
the least.
%x and %X have the same problem as %v (since they use it).
Don't really know how you would use them with each other to get the right
date, but you must be able to do
it would be '01', but if you wrap
the week number, you shouldn't you increment the year as well? SELECT
DATE_FORMAT('2001-12-31', '%v-%y'); returning '01-01' is inaccurate to say
the least.
mysql select DATE_FORMAT('2001-12-31', '%v-%y');
+---+
| DATE_FORMAT
Hello All,
I want to convert the string '18 October 2002' to the date format
'2002-10-18' using MySQL.
Essentially this is the reverse of the DATE_FORMAT(date,format) function.
I'm pretty sure it can't be done but does anyone out there have any ideas?
Thanks,
Andrew
sql,query
, d1.width, DATE_FORMAT(d1.created,
'%d-%m-%Y'), DATE_FORMAT(d1.amended, '%d-%m-%Y'), d2.extdescr from decheader
as d1, decextdescr as d2 where d1.code = d2.code and d1.code = '00042'
The problem I am having is with the DATE_FORMAT. Running the above query
returns the following for the width
On 3 Oct 2002, at 15:33, Mark Colvin wrote:
The problem I am having is with the DATE_FORMAT. Running the above query
returns the following for the width column.
94.40 DATE_FORMAT(d1.created, '%d-%m-%Y'): NULL DATE_FORMAT(d1.amended,
'%d-%m-%Y'): 03-10-2002
Show your PHP code. How
Hi,
This might be a strange question, but can you do date_format when you do a
myrow? Or does date_format as always have to be done in a sql statement?
Does anyone have an easy of doing dates?
Chuck Payne
Magi Design and Support
Radoslaw,
Thursday, June 13, 2002, 4:03:08 PM, you wrote:
RK I run mysql3.23.49/myisam with linux 2.4.18/libc2.2.5.
RK Some time ago I've hardware crash. Myisamchk didn't report
RK any problems but after some time mysql got SIGSEGV.
[skip]
Can you send me binary files of your table for
Hi
I run mysql3.23.49/myisam with linux 2.4.18/libc2.2.5.
Some time ago I've hardware crash. Myisamchk didn't report
any problems but after some time mysql got SIGSEGV.
From that time mysql finished with SIGSEGV in the same place
a few times.
0x80cb554 handle_segfault__Fi + 428
0x40021f54 _end +
Hi,
I have a quick question concerning date/time functions. If I query
MySQL:
SELECT date_format(date, '%W %M %e %Y') FROM experiments where
expid=3706
It returns: Wednesday May 2 1979
Are there existing methods for determining whether to add st, nd or
rd after the %e?
e.g
Subject: date_format question
Hi,
I have a quick question concerning date/time functions. If I query
MySQL:
SELECT date_format(date, '%W %M %e %Y') FROM experiments where
expid=3706
It returns: Wednesday May 2 1979
Are there existing methods for determining whether to add st, nd or
rd
Neil,
I appear to be having an error with the following update that I am
submitting to my database. I am using mysql's DATE_FORMAT function to pull
the date out and insert in a user friendly form. Upon submission of the
modified data, I use the below SQL to update the table information
I appear to be having an error with the following update that I am
submitting to my database. I am using mysql's DATE_FORMAT function to pull
the date out and insert in a user friendly form. Upon submission of the
modified data, I use the below SQL to update the table information.
Everything
find no mention. Am I searching
for the wrong thing? I searched for AS in the documentation
thanks again Jules
You may want to try:
$result = mysql_query(SELECT title, description, url, author,
date_format(datefield, '%M %D %Y') AS datefield FROM documents
- Original Message -
From: julian haffegee [EMAIL PROTECTED]
To: MySQL General List [EMAIL PROTECTED]
Sent: Monday, December 31, 2001 2:55 PM
Subject: Re: date_format
Thanks this works
the difference was the 'AS datefield'
what is this bit doing? I searched for AS (in the SELECT
on the web/books suggests that this is what to do
$result = mysql_query (SELECT title, description, url, author,
date_format(datefield, %M %D %Y') FROM documents);
This just leaves out all dates.
Can anyone see where I'm going wrong
Thank you so much
Jules
#2 All I have read on the web/books suggests that this is what to do
$result = mysql_query (SELECT title, description, url, author,
date_format(datefield, %M %D %Y') FROM documents);
This just leaves out all dates.
You may want to try:
$result = mysql_query(SELECT title, description
-07-16 14:00:00'
^
exactly this is the bug!
the date at this time was: '2001-07-19 14:00:00' and now() correctly
reports this, but a date_format(now(), '%Y%m%d%H') says '2001071614' with
16 as the month-day instead of 19 which would be right !?
--
Florian Schmidt
Hi!
i've mysql-3.23.39-nt on winnt with a client running under SCO 3.2
i've a simple querry with date_format in it, but date_format isn't doing
what i expect...
sql_string: select date_format(c.hour, '%Y%m%d%H'), c.hour from count c
c.hour is DATETIME
okay, i see this output on my sco
At 09:25 19.07.2001 -0400, you wrote:
Probably due to timezone setting differences between the two
client machines.
i also thought about that, but there are 2 DAYs difference... can this be a
timezone issue ?
okay, i see this output on my sco-machine:
'2001071614' '2001-07-19 14:00:00'
if i
At 09:40 19.07.2001 -0400, you wrote:
You're correct, likely not a timezone problem.
Have you confirmed that the clocks on these machines are
synchronized? That they aren't really three days off?
yep, again and agein :)
the clocks are in sync +/- 5 secs
okay, i see this output on my
Hi,
I've developed a simple search engine for a site I'm working on. Its
purpose is to display community events based on the users input criteria.
The problem is, if I use the DATE_FORMAT command to alter the appearance of
the events dates and times - then MySQL begins at the top of the list
I think your doing FAR more work than you need to. I'm also not getting
what you mean by it not paying attention to the initial query.
I suggest you combine those 3 queries into one, just like this:
SELECT somefield1, somefield2, DATE_FORMAT(EventStartDate, '%W %M %D %Y
like to
display them in a more user friendly format. For example, there is an
event taking place this Wednesday, in ISO 2001-05-30 - I'd like it to
display as May 30th, 2001.
Through the command line, I know I do this by typing:
select DATE_FORMAT(EventStartDate, '%M %D %Y');
My question
Hi Tim!
You could do something like this:
$sqlstr = select date_format(EventStartDate, '%M %D %Y') as mydate, (rest of your
SQL string here) ;
$result = mysql(mydb, $sqlstr, $connect) ;
$myformatteddate = mysql_result($result, 0, 'mydate') ;
This should do it for you :) HTH
$Result = @mysql_query (SELECT DATE_FORMAT(EventStartDate,'%M %D %Y') AS
EventStartDate FROM EventsTable);
$Row = mysql_fetch_array($Result);
printf(Event Date:%s, %Row['EventStartDate'];
Hope this helps :o)
--Patrick
# -Original Message-
# From: Tim Thorburn [mailto:[EMAIL PROTECTED
in my database are ISO format, so -MM-DD, I'd like
to display them in a more user friendly format. For example, there
is an event taking place this Wednesday, in ISO 2001-05-30 - I'd
like it to display as May 30th, 2001.
Through the command line, I know I do this by typing:
select DATE_FORMAT
to do:
SELECT whatever FROM tbl1, tbl2
WHERE ( tbl1.registration_date =
DATE_FORMAT(now(),'%Y-%m-)DATE_FORMAT(tbl2.registration_date,'%d')
AND tbl1.registration_date = DATE_FORMAT(now(),'%Y-%m-%d') ) AND
tbl2.id=1000
So both tables have their own registration_date,
and I am trying to display rows
Paul Schreiber writes:
Sinisa Milivojevic wrote:
cut
Column start is of type TIME. The actual values are illustrated above in
the example.
Paul
Hi!
Then it is not a bug. As our manual clearly points out, date_format
can be used only on date and datetime column types.
Regards
Sinisa Milivojevic wrote:
[EMAIL PROTECTED] writes:
Description:
date_format is setting times to 12:00 AM; time_format works fine
How-To-Repeat:
mysql select start,TIME_FORMAT(start, '%l:%i %p') AS start2 FROM time;
+--+--+
| start| start2
Description:
date_format is setting times to 12:00 AM; time_format works fine
How-To-Repeat:
mysql select start,TIME_FORMAT(start, '%l:%i %p') AS start2 FROM time;
+--+--+
| start| start2 |
+--+--+
| 12:00:00 | 12:00 PM |
| 14:00:00 | 2:00 PM
with the name
ID and a datetime column named DATE..
But you are right that it is probably reserved for some stuff..
The DATE_FORMAT can indeed be left out, but I once understood that this was
more save to do..???
I never asked why, but also never had any problems..
I found the source of my problem
((perfect_customer_productorders.date) = DATE_FORMAT( DATE_SUB( NOW() ,
INTERVAL 30 DAY ) , '%Y-%m-%d' ) and perfect_customer_productorders.ordernr
= 'te-004' and perfect_customer_orders.status != 2) GROUP BY
perfect_customer_productorders.ordernr ORDER BY quantity desc
- This is the trouble maker
On Wednesday 17 January 2001 00:20 Cindy wrote:
OK. I went to the documentation at www.mysql.com and typed in
DATE_FORMAT in the search box, hopefully find a list of the %M's, etc
rules that may be used (I'd like December to become Dec, etc). No
dice. Randomly looking through sections
Jan 2001, Pavel Kveton wrote:
On Wednesday 17 January 2001 00:20 Cindy wrote:
OK. I went to the documentation at www.mysql.com and typed in
DATE_FORMAT in the search box, hopefully find a list of the %M's, etc
rules that may be used (I'd like December to become Dec, etc). No
dice
,
etc.
I would really like a complete list of the available %'s in this
function. I thank you all for your help, but I still think that
entering DATE_FORMAT in the documentation search box at www.mysql.com
should have been successful.
(I'm specifically looking for a way to display Dec for 12
Hello Cindy,
I posted this in response to another date formatting question, hope it
helps.
The link should be helpful if you haven't found it already.
SELECT fields, DATE_FORMAT(datefield, '%M %d, %Y');
I just looked it up myself...It's all in the manual at:
http://www.mysql.com/doc/D
Try the manual contents, linked from the documentation page
http://www.mysql.com/documentation/mysql/bychapter
OK. I went to the documentation at www.mysql.com and typed in
DATE_FORMAT in the search box, hopefully find a list of the %M's, etc
rules that may be used (I'd like December
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