when I use size, it sets the global size of the whiskers (I'd rather say the
thickness of the line) but for sure it does not set the width of the
whisker.
Try to use the option 'width' with errorbar() not errorbarh(), you'll see
that it works perfectly, it sets the width of the whisker. It just do
Hello,
I tried this pseudo-generator style experiment (see below). The "<<-"
operator assigns to in the calling environment which would be the
environment of "getN".
Yet when the function incr is returned, isn't this environment lost?
Also the print displays GlobalEnv, yet the globalenv does not h
Milton,
On 16 July 2009 at 18:08, milton ruser wrote:
| I'm trying to compile R 2.9.1 on my home directory under debian,
| and as I need to play with RPy, I tryed compile R using:
To use RPy on Debian (or Ubuntu) you can also just try
sudo apt-get install python-rpy
which has been available
Hi Mehdi,
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
I don't mean to rude, but you seem to lack basic knowledge regarding the
use of spatial data in R. Starting to use R is hard, but please ask
On Fri, Jul 17, 2009 at 9:15 AM, Saptarshi Guha wrote:
> Hello,
> I tried this pseudo-generator style experiment (see below). The "<<-"
> operator assigns to in the calling environment which would be the
> environment of "getN".
Yes.
> Yet when the function incr is returned, isn't this environme
Professor Harrell,
Thanks for your lightning-fast reply. It was extremely helpful, and
pointed me exactly to where I needed to go to solve my problem.
For others reading, my problem was that I was incorrectly dealing with
the validation data.
I tried to do this to generate predictions from a pre
'startgiven' is in the environment of your function 'incr' (which is what your
function 'a' becomes). It might be more transparent to define your function
with an enclosing local environment explicitly, for example:
> b <- local({
+ startgiven <- 0
+ function(n) {
+ if(!missing(n)) {
+
Hi,
I'm trying to evaluate a character vector within pnorm. I have a vector
with values and names
x = c(2,3)
names(x) = c("mean", "sd")
so that i tried the following
temp = paste(names(x), x, sep = "=")
#gives
#> temp
#[1] "mean=2" "sd=3"
#Problem is that both values 2 and 3 are taken as v
Thanks to all for the helpful explanation.
Regards
Saptarshi
On Fri, Jul 17, 2009 at 12:42 AM, wrote:
> 'startgiven' is in the environment of your function 'incr' (which is what
> your function 'a' becomes). It might be more transparent to define your
> function with an enclosing local environ
Dear Thomas,
You don't need parse()
X <- c(mean = 2, sd = 3)
pnorm(0, mean = X["mean"], sd = X["sd"])
Have a look at
library(fortunes)
fortune(106)
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en boso
Here is one way:
x <- c(2,3)
names(x) <- c("mean", "sd")
do.call(pnorm, c(list(0), as.list(x)))
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Thomas Roth (geb. Kaliwe
Dear R users,
I have two nonlinear equations, f1(x1,x2)=0 and f2(x1,x2)=0. I try to use optim
command by minimize f1^2+f2^2 to find x1 and x2. I found the optimal solution
changes when I change initial values. How to solve this?
BTW, I also try to use grid searching. But I have no information o
yhsu6 wrote:
>
> Dear R users,
>
> I have two nonlinear equations, f1(x1,x2)=0 and f2(x1,x2)=0. I try to use
> optim command by minimize f1^2+f2^2 to find x1 and x2. I found the optimal
> solution changes when I change initial values. How to solve this?
>
> BTW, I also try to use grid search
Hi,
It works perfectly! Though I'm still stuck on the height of the whiskers
with errorbarh() :)
Regards/Cordialement
Benoit Boulinguiez
-Message d'origine-
De : hadley wickham [mailto:h.wick...@gmail.com]
Envoyé : dimanche 12 juillet 2009 11:09
À : Benoit Boulinguiez
Cc : r-help@r-
Hello,
I apologize if an answer to my questions is available, or if I
submitted this question incorrectly. I have read the mailing lists, as
well as the R Project and CRAN homepages. However, I may have missed
something.
I noticed the package 'norm' has been removed. Its page
http://cran.r-projec
The package is ORPHANED (i.e. no active maintainer) and does not pass
the checks for recent versions of R anymore.
If you think the package is very useful for you, you may want to become
its new active maintainer. Just take the sources from the archive, fix
and update the package as you like and
Don MacQueen wrote:
As others noted, you can use the built in function colSums, but you said
you're writing your own. Given what you've got so far, that makes the
issue one of structuring the output.
Try
csum <- function(m)
{
a = data.frame(m)
s = lapply(a,sum)
unlist(s)
}
lapp
I appreciate the info!
I am mostly interested with ML missing data imputation. Is there
another R module which has such a function that is well regarded?
Thank you.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEAS
On Fri, 17 Jul 2009, Daniel Abbott wrote:
Hello,
I apologize if an answer to my questions is available, or if I
submitted this question incorrectly. I have read the mailing lists, as
well as the R Project and CRAN homepages. However, I may have missed
something.
I noticed the package 'norm' ha
On Fri, Jul 17, 2009 at 10:29 AM, Andriy Fetsun wrote:
> I want to perform some sort of transformation on all the
> elements in the matrix I have posted and that I have only presented
> those 3 elements as an example of how the transformation will affect
> those 3 elements.
>
> Do you see the prob
I am still failing to understand exactly what you want to set. Maybe
you want to set the height of the whiskers?
Hadley
On Fri, Jul 17, 2009 at 9:07 AM, Benoit
Boulinguiez wrote:
> when I use size, it sets the global size of the whiskers (I'd rather say the
> thickness of the line) but for sure
Achim Zeileis wrote:
On Fri, 17 Jul 2009, Daniel Abbott wrote:
Hello,
I apologize if an answer to my questions is available, or if I
submitted this question incorrectly. I have read the mailing lists, as
well as the R Project and CRAN homepages. However, I may have missed
something.
I not
On Jul 17, 2009, at 12:52 AM, Sean Brummel wrote:
> This conversation is digressing... Here is my question, what does
> the value from the predict function mean? AS STATED IN MY CODE. Try
> running the example that I gave.
>
> predict(model,type=c("response"))[1]=?
Look at the help
That what i was looking for :-)
bill.venab...@csiro.au schrieb:
Here is one way:
x <- c(2,3)
names(x) <- c("mean", "sd")
do.call(pnorm, c(list(0), as.list(x)))
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto
Hi, All,
Many thanks for letting me know there is no references and dereferencing in R,
but I saw a library called (ref) on cran, but when I use library(ref), I was
told there is no such library in R.
So if I can not passing an array from a perl script to a R script by its
reference, how to
Hi there,
I have a relatively simple question, though, I couldn't find a solution for
it so far. I have a table with 1000 entries and columns containing
information about different parameters for each entry.
What I want to do is group all parameters from one of the columns [e.g. if
all 1000 entri
On 17-Jul-09 12:12:01, Uwe Ligges wrote:
> Achim Zeileis wrote:
>> On Fri, 17 Jul 2009, Daniel Abbott wrote:
>>> Hello,
>>> I apologize if an answer to my questions is available, or if I
>>> submitted this question incorrectly. I have read the mailing lists,
>>> as well as the R Project and CRAN ho
On Jul 17, 2009, at 5:47 AM, Miroslav Nikolov wrote:
Hi there,
I have a relatively simple question, though, I couldn't find a
solution for
it so far. I have a table with 1000 entries and columns containing
information about different parameters for each entry.
What I want to do is group al
Follow-up:
On 17-Jul-09 12:38:27, Ted Harding wrote:
> On a point of information: The licence in question:
>
> License: The software may be distributed free of charge and used
> by anyone if credit is given. It has been tested fairly
> well, but it comes with no guarantees and t
On Jul 17, 2009, at 4:44 AM, xin liu wrote:
Hi, All,
Many thanks for letting me know there is no references and
dereferencing in R, but I saw a library called (ref) on cran, but
when I use library(ref), I was told there is no such library in R.
An error from that function may indicate t
On Fri, Jul 17, 2009 at 8:54 AM, Ted
Harding wrote:
> Follow-up:
>
> On 17-Jul-09 12:38:27, Ted Harding wrote:
>> On a point of information: The licence in question:
>>
>> License: The software may be distributed free of charge and used
>> by anyone if credit is given. It has been tested f
On 17-Jul-09 13:01:46, Gabor Grothendieck wrote:
> On Fri, Jul 17, 2009 at 8:54 AM, Ted
> Harding wrote:
>> Follow-up:
>>
>> On 17-Jul-09 12:38:27, Ted Harding wrote:
>>> On a point of information: The licence in question:
>>>
>>> License: The software may be distributed free of charge and used
>>>
aggregate?
Something like this should work although it is not very elegant.
mydata <- data.frame(aa=rep(letters[1:10],2), bb=rnorm(20, 5,1))
ss <- aggregate(mydata[,2],list(aa=mydata$aa), sum)
pie(ss[,2])
===
I think the problem here is that you seem to be trying to specify a
non-innovations form model, for which both Q and R need to be specified,
but you have only specified Q.
The code guesses whether you are specifying an innovations model or an
non-innovations model based on whether you specify
Kel Lam wrote:
> My institute has been heavily dependent on SAS for the past while, and
> SAS is starting to charge us a very deep amount for license renewal.
> Since we are a non-profit organization that is definitely not
> sustainable. The team is brainstorming possibility of switching to R,
>
--- Begin Message ---
My question is as follows
Y~N(mu2,sigma2^2), i.e. Y has cdf F2
X generates from:
X=F2^{-1}(u)+a*|u-tau|^b*I(u>0.75), where u~U(0,1)
Given tau=0.75, I want to find a and b such that
E(X)-E(Y)=2 and Var(X)/Var(Y)=3
I try optim and grid seaching and get different results,
My question is as follows
Y~N(mu2,sigma2^2), i.e. Y has cdf F2
X generates from:
X=F2^{-1}(u)+a*|u-tau|^b*I(u>0.75), where u~U(0,1)
Given tau=0.75, I want to find a and b such that
E(X)-E(Y)=2 and Var(X)/Var(Y)=3
I try optim and grid seaching and get different results, any solution?
T
Thanks everyone for your suggestions, they've been very helpful. I think I've
just about solved my problem, but not quite yet. As suggested, I've used
sys.call and match.call. Here is what I have so far:
fun.tester <- function(abc,def,ghi,jkl,...){
mf <- match.call(expand.dots = FALSE)
sc <- sy
Dear useRs and developeRs,
I am struggling with a simple but not obviously solvable issue. Suppose I
have the following list of data.frames called 'tmp':
a <- data.frame(a=rnorm(10),b=letters[1:10])
(tmp <- list(a,a[1:4,],a[1:7,]))
It is known that all data.frames in this list have the same numb
Question 2a)
I am also working with arules package and I have the following problem
let suppose the matrix b like:
b<-matrix(c(1,1,1,1,1,1,0,0,1,1,1,1,0,0,1,1,0,1,1,1,1,1,1,1),nrow=6)
rownames(b)=c("T1", "T2", "T3", "T4", "T5", "T6")
colnames(b)=c("It1", "It2", "It3", "It4")
bt<-as(b, "transactions
Yep, it's my mistake while manipulating the data. Now it works fine
except there is a warning message coming out:
Warning message:
In zoo(rval, ix) :
some methods for “zoo” objects do not work if the index entries in
‘order.by’ are not unique
I checked the faq and some other documents, it seems
Hello R gurus,
I am biologist doing biomarker research and I have a data set where I have 6
proteins and close to 3000 samples, i have to look for differences between
disease(Y) and controls(N) along with genetic risk, genotypes, sex and other
demographic info available. however i do not know any
try this,
do.call(rbind, tmp)
baptiste
2009/7/17 Angel Spassov
> Dear useRs and developeRs,
>
> I am struggling with a simple but not obviously solvable issue. Suppose I
> have the following list of data.frames called 'tmp':
>
> a <- data.frame(a=rnorm(10),b=letters[1:10])
> (tmp <- list(a,a[1
do.call(rbind, tmp)
On Fri, Jul 17, 2009 at 10:55 AM, Angel Spassov wrote:
> Dear useRs and developeRs,
>
> I am struggling with a simple but not obviously solvable issue. Suppose I
> have the following list of data.frames called 'tmp':
>
> a <- data.frame(a=rnorm(10),b=letters[1:10])
> (tmp <- l
1Rnwb wrote:
Hello R gurus,
I am biologist doing biomarker research and I have a data set where I have 6
proteins and close to 3000 samples, i have to look for differences between
disease(Y) and controls(N) along with genetic risk, genotypes, sex and other
demographic info available. however i d
I should elaborate the situation a bit more. We store our data in UNIX and
have been using UNIX SAS for our work. My Biostat dept has 40 SAS users
from which at most 10 also use R. The Epi/Grad Students/Investigators
combine for another 30-40 not-so-frequent SAS users let alone R. So we are
ta
Right on target! Very appreciated. Thanks.
Cheers,
AS
On Fri, Jul 17, 2009 at 4:39 PM, Henrique Dallazuanna wrote:
> do.call(rbind, tmp)
>
> On Fri, Jul 17, 2009 at 10:55 AM, Angel Spassov
> wrote:
>
>> Dear useRs and developeRs,
>>
>> I am struggling with a simple but not obviously solvable is
Need reproducible code and data to respond.
As per the last line to every message in r-help, reduce the file to the
smallest subset that exhibits the error and post it with self contained
code that will read it in and reproduce the error message.
On Fri, Jul 17, 2009 at 10:29 AM, Keith wrote:
> Y
On Thu, 16 Jul 2009, Noah Silverman wrote:
Thanks for the quick reply.
I found that page and do have the survival package installed.
My problem is that I don't understand a few things:
1) What do I input for the "formula" field? (In RapidMiner, the
functions don't have this input.)
2)
Thanks for your suggestions, they were quite helpful. I've just about solved
the problem, but now I just need to know where the additional arguments
passed through '...' are stored (in order to make my own matching scheme I
need to be able to change the value of those to the correct values upon
en
It usually gets uploaded within a day if it passes all the checks run by
Kurt Hornik. Then the Windows version gets built within the next 24
hours as well. Vik Jim Lemon wrote:
> Gates, Michael wrote:
>> ...
>> Members,
>> I recently submitted my first package to the submissions ftp site o
On Fri, 17 Jul 2009, escher2079 wrote:
Thanks for your suggestions, they were quite helpful. I've just about solved
the problem, but now I just need to know where the additional arguments
passed through '...' are stored (in order to make my own matching scheme I
need to be able to change the va
Hi,
I'm trying to run Fisher's Exact test on the data below, but I'm not
sure how interpret the data shown. Can someone tell me what this is
saying? Looking at the numbers it should be that there's no significant
difference between the HDL and LDL, but a p-value of 1 seems high. Is
the low value in
Fair enough. I'm not going to post all the code because it's distracting, but
the following example function is demonstrative of the problem:
exfun<-function(...){
print(x)
}
I'm aware that leaving making the only inputs additional arguments is bad
form, but this is merely an example. So here i
Hi,
I am new to R plot. I am trying to scale my y axis in log. When I
do this I receive the following error
Error in axis(side = side, at = at, labels = labels, ...) :
CreateAtVector [log-axis()]: axp[0] = 0 < 0!
In addition: Warning messages:
1: In plot.window(...) :
nonfinite axis lim
James Allsopp-2 wrote:
>
> Hi,
> I'm trying to run Fisher's Exact test on the data below, but I'm not
> Bound Unbound
> HDL27 9
> LDL 8 2
>> fisher.test(data)
>
>
At odds of 3 and 4 with one count =2, even the best test won't help.
Dieter
--
View this message in co
Kate,
This is a difficult problem, mainly because your function is not
deterministic. Run the function a couple of times with the same parameter
values and you will get a different value each time. Obviously, you cannot
optimize such functions in the ususal sense.
However, you can rewrite the f
yhsu6 wrote:
>
> I have two nonlinear equations, f1(x1,x2)=0 and f2(x1,x2)=0. I try to use
> optim command by minimize f1^2+f2^2 to find x1 and x2. I found the optimal
> solution changes when I change initial values. How to solve this?
>
> BTW, I also try to use grid searching. But I have no i
Hi Group,
I have a question about obtaining the bias-corrected c-index using
validate from the Design library.
As an example, consider the example from help page:
library(Design)
?validate.lrm
n <- 1000
age<- rnorm(n, 50, 10)
blood.pressure <- rnorm(n, 120, 15)
cholesterol<- rno
yhsu6 wrote:
>
>
> ##
> #R code:
> mu2=0.4
> sigma2=4
> tau=0.75
> mean.diff=2
> var.ratio=3
>
> #Use optim:
> parameter<-function(c)
> {
> a<-c[1]
> b<-c[2]
> u<-runif(1)
> Y<-qnorm(u,mean=mu2,sd=sigma2)
> u<-runif(1)
> X<-qnorm(u,mean=mu2,sd=sigma2)+a*abs(u-ta
On Fri, 17 Jul 2009, escher2079 wrote:
Fair enough. I'm not going to post all the code because it's distracting, but
the following example function is demonstrative of the problem:
exfun<-function(...){
print(x)
}
I'm aware that leaving making the only inputs additional arguments is bad
form,
Dear UseRs,
I just learnt that the number of columns of a data frame is not always what
I thought it to be, and I wonder where I should have learnt about this.
Consider the following example:
dat <- data.frame(X1=1:10, X2=LETTERS[1:10])
ncol(dat) ## evaluates to 2 (of course)
dat$X1poly
On 7/17/2009 12:13 PM, James Allsopp wrote:
Hi,
I'm trying to run Fisher's Exact test on the data below, but I'm not
sure how interpret the data shown. Can someone tell me what this is
saying? Looking at the numbers it should be that there's no significant
difference between the HDL and LDL, but
The question is: you have your data in MySQL, build your model in R,
but now want to use the model to score your MySQL data on an on-going
basis, what to do?
MySQL users frequently use R for data mining and to build statistical
models. They benefit from the RMySQL package which builds an in
then what will be the other factors needed to be adjusted and whether I
should adjust or use them as covariates. Finally how these analysis will be
done in R
Harrell, Frank E wrote:
>
> 1Rnwb wrote:
>> Hello R gurus,
>>
>> I am biologist doing biomarker research and I have a data set where I
>
I'm trying to wean myself off the very limited capabilities of Excel and Oo.
Currently, I am trying to make a plot showing several values for 2
categories in a dot blot (see
http://www.nabble.com/file/p24538360/Picture%2B1.png Picture+1.png except
that the x axis should contain the category not
On Jul 17, 2009, at 9:57 AM, Kelvin Lam wrote:
I should elaborate the situation a bit more. We store our data in
UNIX and
have been using UNIX SAS for our work. My Biostat dept has 40 SAS
users
from which at most 10 also use R. The Epi/Grad Students/Investigators
combine for another 30-
Dataframes are lists. Look at dat with str and you will see that the
third column (actually the third list element) is a matrix. It's not
hard to find the documentation. If you read the documentation on the
help page for data.frame you should see this:
"If a list or data frame or matrix is
I thought that I wanted the non-innovations form but wanted R and w(t) to be
zero. I
thought leaving out R would give that. What I'm trying to do is estimate a
transfer function
noise model. I noticed that you suggested to another person to use ARMA()
and one can estimate the forecast function of
On Fri, Jul 17, 2009 at 7:17 PM, jaregi wrote:
> I'm trying to wean myself off the very limited capabilities of Excel and Oo.
> Currently, I am trying to make a plot showing several values for 2
> categories in a dot blot (see
> http://www.nabble.com/file/p24538360/Picture%2B1.png Picture+1.png e
Hi,
On Jul 17, 2009, at 1:17 PM, jaregi wrote:
I'm trying to wean myself off the very limited capabilities of Excel
and Oo.
Currently, I am trying to make a plot showing several values for 2
categories in a dot blot (see
http://www.nabble.com/file/p24538360/Picture%2B1.png Picture+1.png
We use SAS and R here (a biostat department and consulting unit), in
part because there are some things SAS does that R doesn't. In
particular, we use SAS proc nlmixed with custom likelihood functions. R
has similar capability but does not allow custom likelihood; the authors
say adding it would
NDC/jshipman wrote:
Hi,
I am new to R plot. I am trying to scale my y axis in log. When I
do this I receive the following error
Error in axis(side = side, at = at, labels = labels, ...) :
CreateAtVector [log-axis()]: axp[0] = 0 < 0!
In addition: Warning messages:
1: In plot.window(...)
On Jul 17, 2009, at 11:27 AM, NDC/jshipman wrote:
Hi,
I am new to R plot. I am trying to scale my y axis in log. When I
do this I receive the following error
Error in axis(side = side, at = at, labels = labels, ...) :
CreateAtVector [log-axis()]: axp[0] = 0 < 0!
In addition: Warning mess
I reworked this using the innovations form and it seems to work. But none of
the parameters were changed after estimation.
summary lists:
$counts
function gradient
1 1
It guess it calculates the function but doesn't optimize the parameters.
I just used: tfn.est <- estMaxLik(
David,
thanks. Your explanation does not quite fit, though, as it refers to using
function data.frame, while I assigned the new column with $<-. poly() does
return an object of classes poly and matrix, not model.matrix, and handing a
poly object to function data.frame does behave like I would ex
Thanks a lot Berend and Ravi!!!
I am thinking to use integrate command to get theoretical E(X), E(Y), Var(X),
and Var(Y). Then the result will not depend on u anymore. After that, I will
use dfsane command in BB package.
Kate
Original message
>Date: Fri, 17 Jul 2009 09:51:34 -0700 (P
On Jul 17, 2009, at 3:24 PM, Ulrike Grömping wrote:
David,
thanks. Your explanation does not quite fit, though, as it refers to
using
function data.frame, while I assigned the new column with $<-.
poly() does
return an object of classes poly and matrix, not model.matrix,
But model.matr
I differ with Marc in one way. It is amazing what people can learn when
you create an emergency for them to do so.
Frank
Marc Schwartz wrote:
On Jul 17, 2009, at 9:57 AM, Kelvin Lam wrote:
I should elaborate the situation a bit more. We store our data in
UNIX and
have been using UNIX
Juliet Hannah wrote:
Hi Group,
I have a question about obtaining the bias-corrected c-index using
validate from the Design library.
As an example, consider the example from help page:
library(Design)
?validate.lrm
n <- 1000
age<- rnorm(n, 50, 10)
blood.pressure <- rnorm(n, 120, 15
I wrote a function with some loops and avoided a third loop by using the "by"
function. The output object is an array (or list) of class "by" that looks
like this:
>StationCover.df
Empirical.df$Quadrat: VFFF9-21
Station Shrub Tree Woody Invasive Herb Litter Bare
[1,] 0.0 11
David Winsemius wrote:
>
>
> On Jul 17, 2009, at 3:24 PM, Ulrike Grömping wrote:
>
>>
>> David,
>>
>> thanks. Your explanation does not quite fit, though, as it refers to
>> using
>> function data.frame, while I assigned the new column with $<-.
>> poly() does
>> return an object of classe
Hi there,
I have a dataset from a longitudinal study with a lot of drop-out. I
want to implement the inverse probability weighting method by Robins
1995 JASA paper "Analysis of semiparametric regression models for
repeated outcomes in the presence of missing data". Does anyone know
if there i
Hi! I'm trying to learn about object oriented R, as it seems like it
would be very useful.
I'm going over an example from the documentation, and I'm very confused:
http://www1.maths.lth.se/help/R/R.oo/
[assume you've called library (R.oo)]
setConstructorS3("SavingsAccount", function(balance=
Paul,
Thank you very much for your explanation. I have only been using R for GIS
purposes for about a week, so my expertise in the field is shallow. Your
explanation helped me out and I was able to plot the tif file simply by
using the spplot command.
The reason I was projecting it was that I a
On Jul 17, 2009, at 5:25 PM, Ulrike Grömping wrote:
David Winsemius wrote:
On Jul 17, 2009, at 3:24 PM, Ulrike Grömping wrote:
David,
thanks. Your explanation does not quite fit, though, as it refers to
using
function data.frame, while I assigned the new column with $<-.
poly() does
retu
On Fri, Jul 17, 2009 at 11:41 PM, Jim Nemesh wrote:
> Hi! I'm trying to learn about object oriented R, as it seems like it
> would be very useful.
>
> I'm going over an example from the documentation, and I'm very confused:
>
> http://www1.maths.lth.se/help/R/R.oo/
>
> [assume you've called librar
On Sat, Jul 18, 2009 at 3:21 AM, Henrik Bengtsson wrote:
> On Fri, Jul 17, 2009 at 11:41 PM, Jim Nemesh wrote:
>> Hi! I'm trying to learn about object oriented R, as it seems like it
>> would be very useful.
>>
>> I'm going over an example from the documentation, and I'm very confused:
>>
>> http:
Hello ,everyone.
I am a fresh user of R. I wrote several several R script in R with the
version 2.9.1 in Windows XP. But I only can run these scrpit via R-GUI.
Can anyone tell me how to run the scripts in background without openning
R-gui.In another word, run the R-script and get the result
Hi,
Is it possible to make something like the following code actually
work? My goal in this example would be that I'd see results like
1 1 10100
2 10100 10200
3 10200 10300
4 10300 10400
In real usage the function would obviously do a lot more work, but the
question I canno
See ?Reduce
On Fri, Jul 17, 2009 at 11:10 PM, Mark Knecht wrote:
> Hi,
> Is it possible to make something like the following code actually
> work? My goal in this example would be that I'd see results like
>
> 1 1 10100
> 2 10100 10200
> 3 10200 10300
> 4 10300 10400
>
> In r
Check out:
?Rscript
On Fri, Jul 17, 2009 at 10:14 PM, Jie TANG wrote:
> Hello ,everyone.
>
> I am a fresh user of R. I wrote several several R script in R with the
> version 2.9.1 in Windows XP. But I only can run these scrpit via R-GUI.
>
> Can anyone tell me how to run the scripts in backgr
On Fri, 17 Jul 2009, 1Rnwb wrote:
then what will be the other factors needed to be adjusted
It is NOT an exaggeration to say that hundreds of research
papers, dozens of books, and many dissertations have been written on how
to go about answering that question in one context or another.
Gi
Hi,
1. I want 95% not 99% confidence intervals in my summary.Design plot using the
Design package. Putting conf.int=.95 as an argument in plot does not work. The
default appears to be .99 not .95 as stated in the package Design manual (p.
164).
2. My sweave chuck is below and my output is
I am stumped. I have a data set with multiple columns and about 65,000 case.
Some of the cases have a "#NULL!" value so for dataframe "Props_":
access_emp pct_vacant TAVAIL park PARKACRES totlandare
4538 52.15 #NULL! 01 22.9974,129.70400
4539 52.
Hello,
I'm having a problem in R with repeated use of the "load", "save", and
"close" commands. I'm getting an error message that reads, "Too many
open files". I'm opening files and closing them (and unlinking them),
but when I go through that process 509 times, the program halts and I
get th
On Fri, Jul 17, 2009 at 10:37 PM, PDXRugger wrote:
> So i need to replace the the #NULL! with 0. I have tried:
>
> Props_pct_vacant<-Props_pct_vacant[Props_$pct_vacant !="#NULL!"]
Try this instead:
Props_$pct_vacant[which(Props_$pct_vacant=="#NULL!")] = 0
--
Michael Knudsen
micknud...@gmail.c
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