Hi!
I'm struggling to understand why the shard_chooser gets called for
this query:
SELECT count(users.uid) AS count_1 FROM users WHERE users.external_id
= %s
I would have thought this query_chooser should be called instead?
shard_chooser gets set a mapper, a clause but the instance is None.
I've figured out why it doesn't work. The scalar method on Session
doesn't deal with sharding.
On Apr 11, 11:55 am, Geoff [EMAIL PROTECTED] wrote:
Hi!
I'm struggling to understand why the shard_chooser gets called for
this query:
SELECT count(users.uid) AS count_1 FROM users WHERE
Hi,
I need to use substring function into sql statement. For it, I define
the next sql:
_sql = select([func.substring(planilladet.c.msg_debug, 1,
40).label('msg_debug'), func.sum(planilladet.c.cant).label('cant'),
func.sum(planilladet.c.cant * planilladet.c.importe).label('importe')],
\
(ProgrammingError) (-104, 'isc_dsql_prepare: \n Dynamic SQL Error\n
SQL error code = -104\n Token unknown - line 1, column 39\n ,')
'SELECT substring(planilladet.msg_debug, ?, ?) AS msg_debug,
sum(planilladet.cant) AS cant, sum(planilladet.cant *
planilladet.importe) AS importe \nFROM
Also what would be a syntax to make a same selection using
session.query(th)?
what would you like the ORM query to return ? Object instances ?
currently, using group_by() and such with Query implies you're getting
individual column tuples back using _values(), in which case its
On Apr 10, 2008, at 8:46 PM, Steve Zatz wrote:
I am not sure when the change was introduced but the following mapper,
which previously worked:
mapper(Section, section_table, properties = {'items': relation(Item,
backref='section'), 'keywords':relation(Keyword,
primaryjoin
Hello All,
I have a session object, for instance:
my_object = session.query(Person).filter_by(name='MYSELF').first()
I know I can access to its attributes to modify the database:
my_object.name = 'YOURSELF'
my_object.town = 'PARIS'
Is there a way to access its attributes on another way ?
The
On Apr 10, 2008, at 8:46 PM, Steve Zatz wrote:
I am not sure when the change was introduced but the following mapper,
which previously worked:
mapper(Section, section_table, properties = {'items': relation(Item,
backref='section'), 'keywords':relation(Keyword,
primaryjoin
On Apr 11, 2008, at 10:41 AM, Lukasz Szybalski wrote:
So I tried instead of doing:
s
=
sqlalchemy
.select
([th
.RECORD_NO
,sqlalchemy
.func
.count
(th
.RECORD_NO
)],sqlalchemy
.and_
(th
.APPLIED_TEST
==1,th.CODING_DATE=='20080404')).group_by(th.RECORD_NO).execute()
do this:
On Apr 11, 2008, at 11:45 AM, [EMAIL PROTECTED] wrote:
Hello All,
I have a session object, for instance:
my_object = session.query(Person).filter_by(name='MYSELF').first()
I know I can access to its attributes to modify the database:
my_object.name = 'YOURSELF'
my_object.town = 'PARIS'
Magic ! It works perfectly.
Thanks a lot Michael for your help and all your work.
Dominique
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File sqlalchemy/databases/mssql.py, line 499, in do_execute
cursor.execute(SET IDENTITY_INSERT %s OFF %
self
.identifier_preparer.format_table(context.compiled.statement.table))
SystemError: 'finally' pops bad exception
This seems to be some weird error either with pyodbc or with
I.e., *all* columns from th are being added to the columns clause of
the select. According to the SQL standard, these names all need to
be added to the GROUP BY as well - if MS-SQL is allowing only a
partial GROUP BY list, thats just poor behavior on the part of MS-SQL
(MySQL has this
On Apr 11, 2008, at 12:51 PM, Lukasz Szybalski wrote:
Is there a way to get this ?
SELECT RECORD_NO, count(RECORD_NO) FROM table GROUP BY RECORD_NO
(primary key is RECORD_ID)
The only way I know how to do it is via sqlalchemy.select
but I would like the query type of the return where my
This is probably not a SQLAlchemy issue, but thought I should share with
the group in case there were other Pydev+Eclipse users out there.
I recently came across an issue that when debugging code using Pydev,
the code would hang whenever I tried to step over a statement of
SQLAlchemy code. I
ok, I don't think we are on a same page. So let me explain what I
want and maybe unconfused myself on what is a proper way to get data
out of database via sqlalchemy orm style.
Query class should not be confused with the Select class, which
defines database SELECT operations at the SQL
On Apr 11, 2008, at 2:51 PM, Lukasz Szybalski wrote:
Above statements should result in query like: 'select a,count(a) from
x where b=5,c=6 group by a'
In order to get ORM object I need to use query. (That is what I get
from reading the sentence I quoted)
From the above, what ORM object
my hat's off to you for coming up with that relation(), it works again
in rev 4486.
Ah the irony ... check out http://tinyurl.com/6kqv94
And thanks as always for your remarkable responsiveness and for
sqlalchemy. It is indispensible.
Steve
Above statements should result in query like: 'select a,count(a) from
x where b=5,c=6 group by a'
In order to get ORM object I need to use query. (That is what I get
from reading the sentence I quoted)
From the above, what ORM object would you like ? the one which has
a as
On Apr 11, 2008, at 4:40 PM, Lukasz Szybalski wrote:
It makes sense now. I assumed that ORM object will only return 1
column I group by, and a count. When it returns the full row then my
group_by makes no sense.
Thanks
Lucas
ps. The links were really helpful !
greatglad that
On Fri, 11 Apr 2008 07:00:42 -0700 (PDT)
maxi [EMAIL PROTECTED] wrote:
The problem is with substring function, in SQL (I'm using Firebird
2.x) substring funcition sintax is:
SUBSTRING(planilladet.msg_debug 1 FROM 40)
How can do it in sqlalchemy ? (I use sqlalchemy 0.3.11)
It's been
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