Yep, just mysqldump although that 's only half the story.
After export, you need to import. Beste way to do this is with
command line.
Add following code to your export SQL file:
USE `db_name`;
Run following command:
mysql --user=username -p /location/of/export/file.sql
This will
No that does not work either.
Even if it did, from the manual: As opposed with isset(),
property_exists() returns TRUE even if the property has the value
NULL.
Nulls exceptions / notices are exactly what I am trying to prevent.
It's kind of verbose, but the best compromise I have found is to
Did you cleared the cache folder?
In which file ddid you find the sort_order (as you said you have
found it in internal symfony files...)
On 4 ún, 09:29, michael hodges mhodg...@gmail.com wrote:
Hello all,
I'm new to Symfony. While I've been able to figure things out as I go
along, this
Where did this form come from? Is it an admin generated form? Filter
form?
On 4 ún, 01:20, Darren884 darren...@gmail.com wrote:
I ran into a form with this customer[amount[text]
What is that [text]? And how do I apply it to other fields? I have
been having issues with other fields and I
hi, i like first create my schema on my DB with pgAdmin III and after
with symfony doctrine:build-schema , build-model, build-forms.
build-filters and i dont have problem :-) try.
and this generate relations with other tables on your schema.
On Mon, Jan 25, 2010 at 7:15 PM, webasker
Hi everyone!
I'm getting a problem with forms on Symfony 1.4, using Doctrine. I'm trying
to create a form to represent this relationship on the database:
Fact - FactPerson - Person
As you can see, this table schema represents a many-to-many association. The
problem with this association, in
Right now I have two form widgets which are of the class
sfWidgetFormPropelChoice.
The second field has about 20 choices, but can be filtered by the
first one.
Is it possible in a quick and neat way to replace the all the options
of the second form field by the filtered options (about 5) when a
Hi Augusto,
Thanks for your advises, I will just begin this module.
Regards,
JoJo
2010/2/4 Augusto Flavio afla...@gmail.com
Hi Yang,
you said the you need two modules based on the same model class. One for
display a graph a other to i have not idea. But ok. I, in your
Hi list,
I have a doubt on the content of this file:
in sf_lib_dir/i18n/data/fr_FR.dat
there is no NegativePattern definition to handle a negative value in
the format_currency function/helper
ie: format_currency(-120.3, '€', 'fr_FR'); // -returns -120,30 but
should return -120.30 €
What do
Hi,
I'v you tried the embedRelation function ?
in FactPersonForm, try something like
configure()
{
$this-embedRelation('Fact');
$this-embedRelation('Person');
}
And if you do so, remember to add only one primary key on the
FactPerson table. Ie. you should have in you schema :
FactPerson:
On 5 Feb., 15:24, Cainã cainan.co...@gmail.com wrote:
[...] The problem with this association, in special, is that the
FactPerson table has
some extra fields, apart from the fact_id and the person_id
fields. How
could i create such form? [...]
Assuming that you did define FactPerson
non-french users can answer too :)
On 5 fév, 16:40, Florian sideral.undergro...@gmail.com wrote:
Hi list,
I have a doubt on the content of this file:
in sf_lib_dir/i18n/data/fr_FR.dat
there is no NegativePattern definition to handle a negative value in
the format_currency function/helper
Hello, I have a question, is there some way to define a variable in
the url part of the routing joined to a literal? An example:
my_route:
url: /:variable1/:variable2/literal:variable3.html
When Symfony reads this, it prints literal:variable3.html as it is. Is
there some other way to do it?
I'm having this error when I call this kind of route:
my_route:
url: /:variable1-:variable2.html
param: { module: my_module, action: index }
The error:
500 | Internal Server Error | Exception
sfRoute::serialize() must return a string or NULL
I'm using Symfony 1.4.1 (I have also tried
Hi Augusto
I've the same problem. When run on a Windows Xp enviroment
symfony project:deploy production
or
symfony project:deploy production --go
the task show
exec rsync --dry-run -azC --force --...www/vhosts/mysite.com/
and stays in a loop or something, without showing anything else.
At
Hi,
the .html must be defined on setting.yml as suffix and then the route
would be
my_route:
url: /:variable1/:variable2/literal/:variable3
and the url show
http://www.yoursite.com/variable1/variable2/literal/variable3.html
but i hope that this variables are not so variable otherwise google
I think symfony can't know what you want to display If you don't tell
it... ;)
Show me your schema.yml file (at least part with Empressas
specification)
On 4 ún, 16:09, wueb webmaster@gmail.com wrote:
On 4 Fev, 14:52, Tom Ptacnik to...@tomor.cz wrote:
1 st problem
try to do:
Do you have got all sfGuardDoctrine tables definitions in your project
schema.yml file?
.. because you don't need to have them there .. they are in the
schema.yml file in the plugin directory.
On 5 ún, 07:07, Alter Ego sharif.she...@gmail.com wrote:
I've installed sfGuardDoctrine plugin and
I'm trying to use embedded forms on such a schema as :
News:
actAs: { Timestampable: ~ }
columns:
titre: { type: string(125), notnull: true }
texte: { type: string() }
date_News: { type: date(25), notnull: true }
actif: { type: boolean, notnull: true, default: true }
Book:
I'm trying to set a value in my form, before validation, and running
into problems.
The value I'm setting is an account_id, which should never be known to
the user, thus I don't use a hidden_input form value.
I want to preserve the form validation (a sfValidatorDoctrineChoice
validator that
I would pass the id as an option to the form (if the id is decided in
the action, and cannot be derived from the object itself) then add the
value using the updateObject() method. Since the value never enters
userland, there is no real need to run it through the validators in
this case, so I'd
You could also of course (instead of using a form option) populate the
object before passing it to the form, or after you have bound the
form, before calling save. (if you want to keep the account_id logic
completely out of the form class).
Russ.
On Feb 5, 10:30 pm, rooster (Russ)
Hi,
I have a project which consists of one base (skeleton) application and
for every new application we create we just want to duplicate the
skeleton app and customize from there.
Will symfony ever ship a task for cloning apps? I thought perhaps
something like
./symfony app:clone base target
What's the best way to add a doctrine listener from a plugin?
Doctrine_Manager is being reported as not being found (which i found
strange in the first place), and, to my limited understanding, the
method that sfDoctrinePlugin calls, configureDoctrine, only gets
called on your main project
I don't think a task is required. Can't you just do:
cp -r apps/frontend apps/new_app
- Jon
On Fri, Feb 5, 2010 at 4:33 PM, bkuberek bkube...@gmail.com wrote:
Hi,
I have a project which consists of one base (skeleton) application and
for every new application we create we just want to
On Feb 5, 1:30 pm, rooster (Russ) russmon...@gmail.com wrote:
value using the updateObject() method. Since the value never enters
This is the method I'm using atm. You're right, I was expecting too
much from the validators. Letting FK restraints maintain sanity
further down the chain seems
Hi:
I need to know if a user is logged in or not from my layout.php file, is
this possible? How?
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To
$sf_user-isAuthenticated()
On Fri, Feb 5, 2010 at 23:34, ReynierPM rper...@uci.cu wrote:
Hi:
I need to know if a user is logged in or not from my layout.php file, is
this possible? How?
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ReynierPM
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Hi,
2010/2/5 ReynierPM rper...@uci.cu:
Hi:
I need to know if a user is logged in or not from my layout.php file, is
this possible? How?
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ReynierPM
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On 2/5/2010 5:38 PM, Michał Piotrowski wrote:
I'm using something like this
?php if ($sf_user-isAuthenticated()): ?
li
?php echo link_to('Wyloguj', '@sf_guard_signout') ?
/li
?php else: ?
li
?php echo
On Fri, 5 Feb 2010, ReynierPM wrote:
Hi:
I need to know if a user is logged in or not from my layout.php file, is
this possible? How?
http://www.symfony-project.org/jobeet/1_2/Propel/en/13#chapter_13_sub_authentication
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Adrianrz, look again my question please. The problem I have is in
literal:variable3.
On Feb 5, 7:20 pm, adrianrz adrianrz2...@hotmail.com wrote:
Hi,
the .html must be defined on setting.yml as suffix and then the route
would be
my_route:
url: /:variable1/:variable2/literal/:variable3
Does anyone have any simple example code I can place into my objects
model to override this function? I need to add some stuff into it.
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Hi Adrian,
Try to run the deployment manually. Works fine.
Bye.
Augusto Morais
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I am trying to create a portfolio website and have a few questions
about routing.
On this site there will be 3 pages, Welcome, Projects, Contact. The
Projects page will reference the projects table and models. I am
cabable of creating the routing for this, however, The welcome and
contact pages
Routing does not need table and model, it refers to module and action.
For example for url www.mywebsite.com/welcome, in your routing.yml
you would have something like:
welcome:
url: /welcome
param: { module: default, action: welcome }
On Sat, Feb 6, 2010 at 5:21 PM, Shawn
# In which file did you find the sort_order
database_interface.lib.php
# Did you clear the cache
First I cleared the cache, but that didn't work
Second I renamed the app directory and recreated it from scratch using
just my schema and fixture
Even with the classes and generator files back to
Hi,
usually I write .htaccess rewrites or overload error404 action in the
default module. Overloading error404 is better when you need a bit
more processing to calculate the target URL.
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