In reply to Eric Walker's message of Thu, 11 Sep 2014 21:01:27 -0700:
Hi,
[snip]
One thing that could be happening is that the when there is a capture of a
single deuteron (assuming this is what is going on), the daughter is
short-lived in the case of the specific isotopes under investigation,
Dear Readers,
Today I have published :
http://egooutpeters.blogspot.ro/2014/09/the-true-lenr-experts.html
It is an friendly to invitation to discuss a subject sensitive, seious and
senseless in some extent.
Peter
--
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com
Eric etal.--
It is not to hard to imagine 2 D's or 2 H's inside a face centered cubic metal
matrix reacting at the same time with Ni or Pd nuclei of the same cell they
share. Magnetic fields will increase the chances of interactions by reducing
the allowable positions the D or H can occupy.
that transmutation seems to be the fusion with an even number of
deuteron (2-4-6), with preference to stable isotopes.
IMHO, the reason for the even deuteron rule is the requirement from zero
spin in the groping of nuclei that will enter into the LENR reaction.
A pairing of protons that result
In reply to Axil Axil's message of Fri, 12 Sep 2014 11:20:18 -0400:
Hi,
[snip]
A pairing of protons that result in a total nuclear spin result of zero are
required for the fusion reaction to be successful.
A zero spin final nucleus will certainly have a lower energy than an odd spin
nucleus,
Sounds crazy. But published in Science today. That lends credence.
http://m.phys.org/news/2014-09-hydrogen-production-breakthrough-herald-cheap.html
http://www.gla.ac.uk/news/headline_358595_en.html
You guys know anything about this?
Thanks.
In reply to Bob Cook's message of Fri, 12 Sep 2014 07:38:24 -0700:
Hi Bob,
You may well be correct, however Eric was talking about short lived
intermediates. I was simply suggesting that he find out what they would be.
Robin--
I worry that your concern about simultaneous capture is based on
In reply to Bob Cook's message of Fri, 12 Sep 2014 07:09:59 -0700:
Hi,
[snip]
Robin--
How does a 6.-- Mev proton give up its energy without some gammas x-rays
showing up?
Bob
It probably doesn't, however I only said that such reactions might be possible,
not that they would explain
It’s actually not that surprising, and not really a breakthrough - since it
is platinum catalyzed. Which is the same as saying “dead in the water.”
Since only the production rate increases and not the electrical efficiency -
the cost of electrical input per unit of H2 is the same. The overhead is
If the reaction energy of 6 MeV is mostly transferred to the lattice
(soliton) via EMF strong coupling, the second proton of the He2 pair can
drift out of the reaction zone with a energy of just a few KeV.
With strong EMF coupling, an expelled particle need not be the primary
carrier of the
In reply to Axil Axil's message of Fri, 12 Sep 2014 20:33:47 -0400:
Hi,
If the reaction energy of 6 MeV is mostly transferred to the lattice
(soliton) via EMF strong coupling, the second proton of the He2 pair can
drift out of the reaction zone with a energy of just a few KeV.
With strong EMF
https://www.youtube.com/watch?v=E7ZqBV5iGAc
--
Daniel Rocha - RJ
danieldi...@gmail.com
On Fri, Sep 12, 2014 at 12:23 AM, mix...@bigpond.com wrote:
In that case, why not get specific, and check what would be produced if a
deuteron/neutron/proton were added to the starting material?
Yes, this is something I should do. There's enough data to make it a
little bit of a project, so
Eric Walker eric.wal...@gmail.com wrote:
Why can't free energy companies be like other companies? I feel that the
amount of cloak and dagger and intrigue is overrepresented in this niche.
Yup. I think there are two main reasons:
1. No patent protection.
2. Strange, secretive people.
The
On Fri, Sep 12, 2014 at 7:27 AM, Bob Cook frobertc...@hotmail.com wrote:
It is not to hard to imagine 2 D's or 2 H's inside a face centered cubic
metal matrix reacting at the same time with Ni or Pd nuclei of the same
cell they share.
Just an opinion, but I find it even more unlikely that
On Fri, Sep 12, 2014 at 7:09 AM, Bob Cook frobertc...@hotmail.com wrote:
How does a 6.-- Mev proton give up its energy without some gammas x-rays
showing up?
When a proton ~ 10 MeV travels through a metal, it will interact with
electrons via the Coulomb interaction and, possibly, with lattice
I wrote:
Except for deexcitation gammas arising from inelastic collisions with
lattice sites, the fast proton will give rise to photons on the order of
less than ~ 20 keV.
One exception to this is when the proton collides with another species with
sufficient energy to fuse. Then there may be
Fusion is a two step process. The first step is the tunneling of the one or
more He2 nuclei into the as yet to be realized resultant nucleus. This
process may occur as a superposition of many separate nuclear
events where multiple nuclei tunnel into the resultant nucleus and yet
still be at a
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