Hi Harold,
I'm not sure about \t in the replace box, but \n has a different meaning
depending on whether it's in the find or replace box. In find, it's a
'soft' carriage return, one added by pressing 'shift-enter'. In replace,
it's a hard carriage return, or paragraph mark. To find a paragraph
mark, you use $. For instance, if you're looking for the word 'zebra' at
the end of a paragraph, you'd search for 'zebra.$'. An extra line is ^$.
That's a paragraph with nothing in it.
tc
Harold Drabkin wrote:
After looking at some posts and pages on regular expressions, I think
I might have a bug
I can use \t to find tab characters;
\r, which is suppose to be a carriage return, does nothing
\n finds nothing.
AND
If a try to say replace anything with a \t (that is, \t is now in the
replace rather than the find box), does nothing.
the only time \t works is if it is in the find box.
I'm using OO 2.1, Mac tiger (X11 ).
So if find all \p and replace with \t is suppose to work with regular
expression checked, then I have a bug.
hjd
Anthony Chilco wrote:
Harold Drabkin wrote:
How would I represent searching for all instances of two carriage
returns and replacing them with one?
find = ^$
replace = nothing
Or replacing all tabs with a carriage return.
find = \t
replace = \n
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