The seconds long MFMP X-ray burst is smooth and demonstrates no resonance energy peaks caused by the interaction of electrons with matter. The MFMP burst is strictly a release of photons in a random energy distribution.
A Landau distribution is what we are seeing in the MFMP radiation plot. It is the release of energy by particles based on a random release process. This is seen when a particle gives up its kinetic energy to a thin film as the particles interact randomly with the matter in the thin film. If SPPs are releasing their energy based on a random timeframe and/or based on a random accumulation amount, a Landau distribution of energy release will be seen. You might see a Landau distribution if there is a random mixing of both low energy photons (infrared) and high energy photons (gamma's from the nucleus); Such mixing is produced by Fano resonance, where an SPPs are being fed by both infrared photon pumping and nuclear based gamma photon absorption. On Fri, Mar 11, 2016 at 1:05 PM, Axil Axil <janap...@gmail.com> wrote: > Electrons may have nothing to do with the x-ray radiation. > > The radiation could be produced by photon based quasiparticles. > > The LENR reaction might start with Surface Plasmon Polaritons > initiated nuclear reactions and then after thermalization, the decay > of those SPPs. When the SPPs decay, they release their energy content > as photons of varng energies, > > After a second or two, a Bose condensate of these SPPs form and the > energy of the photons are released as hawking radiation which is > thermal. > > The radiation seen only lasts for a second. > > In LENR we get either high energy radiation (x-rays) or heat; not > both. This is based on the temperature of the reactor. A cold reactor > produces X-Rays because of weak SPP pumping.. > > The SPP absorbs nuclear binding energy and stores it in a whispering > gallery wave (WGW) in a dark mode. The energy is stored inside the WGW > until the WGW goes to a bright mode when the SPP decays. This > conversion from dark mode to bright mode happens in a random > distribution. > > When the temperature is raised over a thermal conversion limit, a BEC > is formed where the stored nuclear binding energy is released from the > SPP BEC as hawking radiation which is thermal. > > On Fri, Mar 11, 2016 at 12:34 PM, Bob Cook <frobertc...@hotmail.com> wrote: >> The effectiveness of the SS can at stopping any high energy electrons that >> cause Bremsstrahlung would depend upon the thickness of the can (or alumina) >> and the energy of the incident electrons. I think the loss of energy per >> scattering event is proportional to Z ^2 for the nucleus that is doing the >> scattering. Al at Z=13 and with Fe at Z=26 the intensity of the >> Bremsstrahlung signal would be about a factor of 4 different. The mean >> length of the path of an electron is a good parameter to know for any given >> substance (basically its density) vs the incident energy of the electron. >> Shielding engineering curves provide this information I believe. Iron >> being significantly more dense than Al2O3 would be much better at slowing >> electrons and thus producing Bremsstrahlung IMHO. >> >> At high electron energies the change of direction of the electron going >> through SS can would be less than for a low energy electron. For slow >> electrons scattering can significantly change the direction of an incident >> electron such that all Bremsstrahlung would be emitted from the material >> that stopped the electron. >> >> I think with a SS can present in the system vs no can and only Alumina >> stopping the electrons, one would expect to see a more intense signal at >> high energy compared to the spectrum from the Alumina reactor chamber. The >> absorption of the EM Bremsstrahlung by the respective media would also have >> to be considered. Neither Alumina nor SS may transmit some of the >> Bremsstrahlung spectrum very well. Thus the effective shielding of the EM >> radiation considering a distributed source would have to be evaluated for >> the resulting high energy EM and the signal intensity corrected accordingly. >> The cut off at the high energy spectrum will be a useful value to know to >> understand the maximum energy of the electron source. This may provide >> information about the reaction producing the electrons. The change of the >> intensity of the Bremsstrahlung signal as a function of the magnetic field >> would also provide information as to whether or not the lattice orientation >> of the nano fuel was important. One might expect that the electrons being >> produced by the respective LENR reaction would produced in some preferred >> direction. >> >> Bob Cook >> From: Bob Higgins >> Sent: Friday, March 11, 2016 6:09 AM >> To: vortex-l@eskimo.com >> Subject: [Vo]: Bremsstrahlung experimental note >> >> I don't know if other Vorts thought of this already... but I had a minor >> epiphany regarding the radiation that MFMP measured in GS5.2. We identified >> this radiation tentatively as bremsstrahlung. This has certain >> implications. Bremsstrahlung requires that the high speed electrons impact >> on a high atomic mass element so as to be accelerated/decelerated quickly to >> produce the radiation. It could be that the stainless steel can that >> contained the fuel was an important component in seeing the bremsstrahlung. >> Without the can, there would still be the Ni for the electrons to hit, but >> the Ni is covered with light atomic mass Li. If the electrons were to >> strike alumina (no fuel can present), I don't think there would be nearly as >> much bremsstrahlung because alumina is comprised of light elements. >> >> Thus, the stainless steel can for the fuel may be an important component for >> seeing the bremsstrahlung. >> >> Bob Higgins
