Hi Axil a couple of quick questions? Was it confirmed the pulse was only a few seconds? I thought they only spotted it in the spectrum at the end of longer session but are not sure exactly when and how long it lasted once initiated?
I have been trying to find papers and references on high energy gamma absorption by SPP... I suppose your dark mode plasmons could you point me to a reference? Also Does it require degenerate matter to form or some other method? I know you have circulated a lot of documents and background on the broader ideas about SPP but is there is one you recommend that specifically on these points? Thanks Stephen > On 11 mrt. 2016, at 23:16, Axil Axil <janap...@gmail.com> wrote: > > Something must produce those electrons and that something (Alpha. beta} > produces EMF energy at a well defined gamma level. > > Bright mode release of "photons" from SPPs when they decay...before an SPP > BEC becomes active. > >> On Fri, Mar 11, 2016 at 5:05 PM, Bob Cook <frobertc...@hotmail.com> wrote: >> Axil-- >> >> Bremsstrahlung radiation is due to inelastic scattering of electrons as they >> pass through matter. There are no resonances. The radiations occurs as a >> result of an electron changing direction as a result of the electric field >> it is passing through. This change in direction (acceleration) saps energy >> from the kinetic energy of the free electron and distributes that energy as >> electromagnetic radiation equivalent to the loss of kinetic energy of the >> electron. The spectrum is random photons because the distance and charge >> of particles being encountered by an energetic electron is random. Thus the >> forces on the electron, whether due to other lattice electrons or positive >> charges in the lattice are random in magnitude. >> >> Landau distributions of the energy of photons do not apply to free electrons >> unless they are at relativistic velocities and have an effective mass like a >> proton, pion, alpha or other heavy particle. >> >> What do you consider is the likely mechanism producing the "Landau >> distribution" you suggest? Specifically, what particles are involved in the >> generation of the spectrum? >> >> Bob Cook >> >> -----Original Message----- From: Axil Axil >> Sent: Friday, March 11, 2016 10:19 AM >> To: vortex-l >> Subject: Re: [Vo]: Bremsstrahlung experimental note >> >> The seconds long MFMP X-ray burst is smooth and demonstrates no >> resonance energy peaks caused by the interaction of electrons with >> matter. The MFMP burst is strictly a release of photons in a random >> energy distribution. >> >> A Landau distribution is what we are seeing in the MFMP radiation >> plot. It is the release of energy by particles based on a random >> release process. This is seen when a particle gives up its kinetic >> energy to a thin film as the particles interact randomly with the >> matter in the thin film. >> >> If SPPs are releasing their energy based on a random timeframe and/or >> based on a random accumulation amount, a Landau distribution of energy >> release will be seen. >> >> You might see a Landau distribution if there is a random mixing of >> both low energy photons (infrared) and high energy photons (gamma's >> from the nucleus); >> >> Such mixing is produced by Fano resonance, where an SPPs are being fed >> by both infrared photon pumping and nuclear based gamma photon >> absorption. >> >> >> >>> On Fri, Mar 11, 2016 at 1:05 PM, Axil Axil <janap...@gmail.com> wrote: >>> Electrons may have nothing to do with the x-ray radiation. >>> >>> The radiation could be produced by photon based quasiparticles. >>> >>> The LENR reaction might start with Surface Plasmon Polaritons >>> initiated nuclear reactions and then after thermalization, the decay >>> of those SPPs. When the SPPs decay, they release their energy content >>> as photons of varng energies, >>> >>> After a second or two, a Bose condensate of these SPPs form and the >>> energy of the photons are released as hawking radiation which is >>> thermal. >>> >>> The radiation seen only lasts for a second. >>> >>> In LENR we get either high energy radiation (x-rays) or heat; not >>> both. This is based on the temperature of the reactor. A cold reactor >>> produces X-Rays because of weak SPP pumping.. >>> >>> The SPP absorbs nuclear binding energy and stores it in a whispering >>> gallery wave (WGW) in a dark mode. The energy is stored inside the WGW >>> until the WGW goes to a bright mode when the SPP decays. This >>> conversion from dark mode to bright mode happens in a random >>> distribution. >>> >>> When the temperature is raised over a thermal conversion limit, a BEC >>> is formed where the stored nuclear binding energy is released from the >>> SPP BEC as hawking radiation which is thermal. >>> >>> >>>> On Fri, Mar 11, 2016 at 12:34 PM, Bob Cook <frobertc...@hotmail.com> wrote: >>>> The effectiveness of the SS can at stopping any high energy electrons that >>>> cause Bremsstrahlung would depend upon the thickness of the can (or >>>> alumina) >>>> and the energy of the incident electrons. I think the loss of energy per >>>> scattering event is proportional to Z ^2 for the nucleus that is doing the >>>> scattering. Al at Z=13 and with Fe at Z=26 the intensity of the >>>> Bremsstrahlung signal would be about a factor of 4 different. The mean >>>> length of the path of an electron is a good parameter to know for any given >>>> substance (basically its density) vs the incident energy of the electron. >>>> Shielding engineering curves provide this information I believe. Iron >>>> being significantly more dense than Al2O3 would be much better at slowing >>>> electrons and thus producing Bremsstrahlung IMHO. >>>> >>>> At high electron energies the change of direction of the electron going >>>> through SS can would be less than for a low energy electron. For slow >>>> electrons scattering can significantly change the direction of an incident >>>> electron such that all Bremsstrahlung would be emitted from the material >>>> that stopped the electron. >>>> >>>> I think with a SS can present in the system vs no can and only Alumina >>>> stopping the electrons, one would expect to see a more intense signal at >>>> high energy compared to the spectrum from the Alumina reactor chamber. The >>>> absorption of the EM Bremsstrahlung by the respective media would also have >>>> to be considered. Neither Alumina nor SS may transmit some of the >>>> Bremsstrahlung spectrum very well. Thus the effective shielding of the EM >>>> radiation considering a distributed source would have to be evaluated for >>>> the resulting high energy EM and the signal intensity corrected >>>> accordingly. >>>> The cut off at the high energy spectrum will be a useful value to know to >>>> understand the maximum energy of the electron source. This may provide >>>> information about the reaction producing the electrons. The change of the >>>> intensity of the Bremsstrahlung signal as a function of the magnetic field >>>> would also provide information as to whether or not the lattice orientation >>>> of the nano fuel was important. One might expect that the electrons being >>>> produced by the respective LENR reaction would produced in some preferred >>>> direction. >>>> >>>> Bob Cook >>>> From: Bob Higgins >>>> Sent: Friday, March 11, 2016 6:09 AM >>>> To: vortex-l@eskimo.com >>>> Subject: [Vo]: Bremsstrahlung experimental note >>>> >>>> I don't know if other Vorts thought of this already... but I had a minor >>>> epiphany regarding the radiation that MFMP measured in GS5.2. We >>>> identified >>>> this radiation tentatively as bremsstrahlung. This has certain >>>> implications. Bremsstrahlung requires that the high speed electrons impact >>>> on a high atomic mass element so as to be accelerated/decelerated quickly >>>> to >>>> produce the radiation. It could be that the stainless steel can that >>>> contained the fuel was an important component in seeing the bremsstrahlung. >>>> Without the can, there would still be the Ni for the electrons to hit, but >>>> the Ni is covered with light atomic mass Li. If the electrons were to >>>> strike alumina (no fuel can present), I don't think there would be nearly >>>> as >>>> much bremsstrahlung because alumina is comprised of light elements. >>>> >>>> Thus, the stainless steel can for the fuel may be an important component >>>> for >>>> seeing the bremsstrahlung. >>>> >>>> Bob Higgins >
