The 59Cu explanation seems to be nonsensical, at least with the
conventional reaction explanation implied below, because (1) it does
not explain the presence of gram quantities of observable copper (due
to the 1.36 minute half-life of 59Cu), (2) the huge flux of 0.5 MeV
gammas from positron annihilation would be a major risk to the
observers, and proof positive of nuclear reaction, eliminating the
need to measure heat, (3) the logarithmic tail-off of positron
emission, even given the 1.36 m half-life, should be readily
detectable for a long time after power off, (4) and the presence of
gram quantities of Ni59, with 76000 y half-life for EC, should be
readily detectable in the ash via auger electrons or x-rays.
On Jan 22, 2011, at 3:46 AM, Peter Gluck wrote:
Thank you, now everything depend on-Cu is real, or not!
Peter
On Sat, Jan 22, 2011 at 12:25 AM, <mix...@bigpond.com> wrote:
In reply to Peter Gluck's message of Fri, 21 Jan 2011 19:31:09 +0200:
Hi,
[snip]
>That device working for 6 months has produced approx. 50,000
kWhours heat.
>Can this be explained by the reaction of transmutation of Ni to Cu?
>Considering first 300 grams of nichel...? Rossi can tell how much
>Ni is uesd - if he will. Am important rough energy balance anyway.
>Peter
[snip]
If all Ni isotopes react equally, and 2/3 of Ni is Ni-58, and we
assume single
proton fusion, then the primary reaction would be:
Ni-58 + H -> Cu-59 + 3.42 MeV
which then decays rapidly via positron decay according to
Cu-59 -> Ni-59 + e+ + neutrino + 4.8 MeV (however a considerable
portion of this
will be lost via neutrinos; say 1/2?).
so the total reaction energy is 3.42 + 2.4 = 5.82 MeV / Ni-58.
2/3 *50000 kWh / 6 MeV = 1.2E23 Ni-58 reactions, which is 12 gm
Ni-58, or about
18 gm Ni altogether (assuming the other isotopes all yield about
the same amount
of energy / atom). So quite within the realm of possibility.
OTOH, if he had 300 gm of Ni, and 1/3 was converted to Cu, then
that represents
considerably more energy, and one has to wonder where it all went?
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/Project.html
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
