At 07:33 PM 12/26/2012, David Roberson wrote:
Abd, time is supposed to be dilated for the probe ship from our
perspective as it approaches the black hole event boundary.
Yes, it would be. However,time is dilated for muons that are
travelling close to c, but they don't "slow down." They are
travelling close to c! The muon decay clock slows down. Not the muon.
I think of it in the following way: On the probe ship one could
place any form of clock that he chooses to keep track of local
time. Let'c choose a laser beam for his clock where he sample the
emission frequency and divides it down to what is needed. Of
course we would be able to compare the final counted down pulse
rate to his heart rate for example.
I believe that the amount of time dilation is exactly the fractional
change in the laser fundamental frequency. The heart of the
spaceman would appear to beat at the exact same ratio. His every
move would be slowed down to us until he freezes when the emission
frequency of the laser becomes zero due to red shift as a limit.
It will take an infinite amount of time from our view point for this to occur.
It would *not* take that time for the spaceship to reach the event
horizon. We'd see the spaceship accelerating, in fact (nothing could
hold it back), and it would redshift, but ... we'd not see it slow
down. We'd see *events on board* slow down.
In fact, imagine the light beam coming to us from the ship. It has a
certain source frequency, so many cycles per second. Suppose the
black holonauts are talking to us, modulated on that beam. As it
approaches the event horizion, the beam would redshift (for us) and
the voices would slow down. It's actually a gravity-induced doppler
shift, plus the velocity shift. To them, nothing special is
happening. But if they are monitoring a beam from us, what would
happen to it? (I can answer this with velocity-induced time dilation,
but haven't much of a clue about the gravity kind, yet.)
