That is my fear Jones. A photon has a large energy to momentum ratio as compared to an electron. I would expect to see Compton reflection of the high energy gamma as it collides with electrons. It is very presumptuous to assume that the gammas will be absorbed quickly. Does anyone see how both energy and momentum can be conserved during a collision between a high energy gamma and any number of electrons?
I suppose that one can look back at the point of origin of the gamma and mentally reverse the process. In that case the nucleus recoiled with much less energy than the gamma while it by definition had to conserve momentum. Perhaps a large cloud of coupled electrons that scattered in every direction carrying off portions of the energy might be able to absorb the total energy. The random directions of the dispersion cloud of electrons could balance the momentum portion of the equation if a miracle occurred. Now I know I am a heretic with an overactive imagination! Dave -----Original Message----- From: Jones Beene <jone...@pacbell.net> To: vortex-l <vortex-l@eskimo.com> Sent: Thu, Apr 4, 2013 7:04 pm Subject: RE: [Vo]:A pile of clues... should be obvious by now! The problem with such ahigh energy gamma hitting an electron is that the total mass-energy of thetarget is only 2-3% of the mass-energy of the driver. This slight impediment doesnot even slow the gamma down very much. There could possibly be pair-productionbut to imagine that the re-emission was all infrared would probably mean thatmomentum could not be conserved. How could it? From:David Roberson Has anyone looked to see that momentum is conserved in theseprocesses? Dave -----OriginalMessage----- From: mixent >More disinformation. There is no possibility of nano-sized sites stopping >gamma radiation. This requires thick lead shielding. ..I have often wondered if an electron that is within the wavelength of a gamma (i.e. a "near field" energy transfer) might absorb the energy as kinetic energy. For a 23.8 MeV gamma the wavelength is 52 fm. For a Mills' Hydrino this is too small for even the smallest Hydrino, however if my version is correct, then it should be possible for f/H with a p > 32.
