In the case where a positron and electron annihilate each other the conservation of momentum requires that the two photons be emitted in exact opposition and with exactly the same energy. Perhaps it is possible to assume that if the two opposing photons are observed then a process of this type occurs.
Dave -----Original Message----- From: Kevin O'Malley <kevmol...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Thu, Apr 4, 2013 8:07 pm Subject: Re: [Vo]:A pile of clues... should be obvious by now! On Thu, Apr 4, 2013 at 10:33 AM, MarkI-ZeroPoint <zeropo...@charter.net> wrote: Why, in some nuclear interactions, do two gammas go shooting off in OPPOSITE directions??? Where is the physical model that explains the REASON for these basic observations??? ***Here's the physical model I proposed here on Vortex when you look at a balloon popping in slow motion, it does not initially emit its energy in all directions at the first microsecond. Its release of energy goes in the direction that the penetration came from initially. If the balloon pop were due to 2 balloons banging together forcefully, the initial release would be right where the 2 balloons collided. Similarly, when 2 atoms collide and fuse, I think their energy release is not 360 degrees, but is perpendicular to the direction of the plane where the 2 atoms meet. It is initially in only 1 direction, not all directions. That release of energy will have a high degree of probability due to its geometry of initial direction, to be directly in the path of atoms on the lattice. But in hot fusion, those 50,000 balloons all slam into each other at varying different angles, leaving the impression that the initial energy release is initially 360 degrees rather than in one direction. http://www.mail-archive.com/vortex-l@eskimo.com/msg76597.html
