Hi Hudson,

On Friday 10 February 2006 2:28 pm, Hudson Lacerda wrote:
> Hi Aaron,
>
> Aaron Krister Johnson escreveu:
> > On Wednesday 08 February 2006 6:28 pm, Hudson Lacerda wrote:
> >>For an equal tempered scale, one can:
> >>
> >>- Define the tuning for the base pitches C D E F G A B (pitches C and c
> >>are equivalent mod N, but N doesn't have to be the 2/1 octave);
> >>
> >>- Define the number of steps included in a whole tone (C to D); the
> >>number of steps involved in a specific accidental can be represented by
> >>its ratio numerator.
> >
> > Hi Hudson,
> >
> > The above assumes a regular meantone-type ET (or EDO as they are
> > sometimes called). Sometimes, as in a non-meantone ET like 22-tet or
> > 53-tet, there are two sizes of major 2nd--one for the 9/8 approximation,
> > the other, a smaller major 2nd, representing 10/9.
> >
> > So, the above only works for temperaments that temper out the 81/80
> > syntonic comma (i.e. meantone-family temperaments)
> >
> > Best,
> > Aaron.
>
> Fortunately, I think not. I can agree with that it works *better* for
> meantone-like temperaments. If one uses the suggested notations provided
> by the program scala, there is no such a limitation, although some
> pitches are rather roughly approximated (e.g. E vs. E\ in E22).
>
> For 22-ET using E22 notation, a whole tone is always 4 steps:
>
>    0:          1/1           C          unison, perfect prime
>    1:         54.545 cents   C/   Db
>    2:        109.091 cents   C#\  Db/
>    3:        163.636 cents   C#   D\
>    4:        218.182 cents   D
>    5:        272.727 cents   D/   Eb
>    6:        327.273 cents   D#\  Eb/
>    7:        381.818 cents   D#   E\
>    8:        436.364 cents   E
>    9:        490.909 cents   F
>   10:        545.455 cents   F/   Gb
>   11:        600.000 cents   F#\  Gb/
>   12:        654.545 cents   F#   G\
>   13:        709.091 cents   G
>   14:        763.636 cents   G/   Ab
>   15:        818.182 cents   G#\  Ab/
>   16:        872.727 cents   G#   A\
>   17:        927.273 cents   A
>   18:        981.818 cents   A/   Bb
>   19:       1036.364 cents   A#\  Bb/
>   20:       1090.909 cents   A#   B\
>   21:       1145.455 cents   B
>   22:          2/1           C          octave

Good point--but the question is, how would abcm2ps handle E\? What would the 
accidental look like?

BTW, it would be nice to implement a version of abcm2ps that could do the full 
gamut of 31-equal accidentals....

Cheers,
Aaron.


 
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