Give me an example of a network where layer two has no broadcasts please...
----- Original Message -----
From: Jack Yu <[EMAIL PROTECTED]>
Newsgroups: groupstudy.cisco
To: <[EMAIL PROTECTED]>
Sent: Sunday, February 18, 2001 1:58 PM
Subject: Re: Equal cost switching
> Actually, the main reason to eliminate multiple paths is because of
> broadcast at layer 2. Lay 2 devices have to this forward broadcast, and
> multiple paths to a single destination will cause broadcast storm. Layer 3
> devices do not have this problem only because they do not forward
broadcast,
> they either read it or drop it. So if there is a network with no layer 2
> broadcast, you do not need spanning tree at all. Of course, you can also
> disable it when you are sure there is no duplicated path exists.
>
> Regards,
> Jack
>
>
>
>
> ""Groupstudy"" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Spanning Tree's job is to eliminate multiple paths to a single
> destination.
> > If it finds more than one path it will put one of them into blocking
mode
> to
> > ensure a loop free path. Remember, Spanning Tree runs at layer two and
> has
> > no concept bandwidth. If you need to setup equal cost paths to a
certain
> > destination, you will need to do it at layers above layer two.
> >
> > Pick up a copy of Radia Perlmans 'Interconnections' second edition.
Radia
> > is the primary authority on the Spanning Tree algorithm, she will
> enlighten
> > you. This is also good solid study for deeper networking knowledge.
> >
> > ----- Original Message -----
> > From: AndyD <[EMAIL PROTECTED]>
> > Newsgroups: groupstudy.cisco
> > To: <[EMAIL PROTECTED]>
> > Sent: Sunday, February 18, 2001 8:58 AM
> > Subject: Equal cost switching
> >
> >
> > > Spanning tree is supposed to choose the one best switched path. But
if
> > you
> > > set up two equal cost paths, will it use both? Is there a way to
force
> it
> > > to use the bandwidth from both paths?
> > >
> > > Thanks!
> > >
> > >
> > > _________________________________
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>
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