Thanks for all your help. The way I understand it now is that with multiple
vlans using different root bridges, you can have different vlans splitting
the bandwidth - some going in one direction, some in the other. But if one
link goes down, STP will then shift all to the good link. This gives you
some load balancing and also redundancy. It looks like you need to go to
layer 3 switching to do any load balancing other than this. And
etherchannel is another option for aggregating bandwidth. But someone said
with etherchannel using 4 full duplex 100 mbp ports will not give 800 mbps
of throughput? I always thought that in theory that was the case?? Since
the data is transmitted on different wire pairs, if the sender and receiver
transmit at the same time, why isn't 800 mbps possible????
Thanks again !!
""Peter Van Oene"" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Per my other post, STP prevents looping traffic in general, not simply
broadcasts.
>
> Pete
>
>
> *********** REPLY SEPARATOR ***********
>
> On 2/19/2001 at 6:50 AM Kenneth wrote:
>
> >Jason is right. This will defeat the purpose of Spanning Tree of creating
a
> >single path to a destination. The primary reason this was designed was to
> >prevent broadcast loops.
> >
> >If you want to force it to use 2 paths to one destination, use
> >port-channelling which statically load-balances traffic going out of two
> >ports. Statically meaning it creates a list of source-destination MAC
> >address pairs and these pair will communicate from a specific port
> >configured to be part of the port-channel. This is in contrary to Dynamic
> >load-balancing where each packet will go out of each port of the
> >port-channel.
> >
> >With this in mind, if 4 ports are configured for 100 Mbps full-duplex
> >port-channels, this doesn't mean it provides an 800Mbps link.
> >
> >
> >
> >
> >"AndyD" <[EMAIL PROTECTED]> wrote in message
> >96p2uk$rt5$[EMAIL PROTECTED]">news:96p2uk$rt5$[EMAIL PROTECTED]...
> >> Spanning tree is supposed to choose the one best switched path. But if
> >you
> >> set up two equal cost paths, will it use both? Is there a way to force
it
> >> to use the bandwidth from both paths?
> >>
> >> Thanks!
> >>
> >>
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