Hi
I want to describe my understanding for low feed system.
I will use direct drive mounting and that mean 5 revolutions for 1 inch of
travel per minute.
5 revolution times 360 degree is 1800 degree per 1 inch per minute.
0.0001 travel per minute means system will have 1.8 degree per minute.
My system generate 8192 pulses per quadrate so 4 times 8192 =32768pulses
per 360 degree of revolution.
So, if I divide 32768 by 360 I will have pulses per 1 degree of
revolution, = 91 pulse per degree.
For 1.8 degree per minute I will have 1.8x91= 163.84 pulses per minute.
Finally, in the case of feed 0.0001 inch per minute I will have 163.84
pulses per minute.
Per second it will be 163.84/60 = 2.731 pulses per second.
So, is this enough pulses?
If I put 1250 K encoder, will it solve the problem on the way in obtaining
stable 0.0001 per minute feed?

Is 1250 K pulse is it per rev or it is per 90degree or revolution?
Thanks
Aram


> Hi Aram,
> I did find a high res encoder at 1250K counts/rev. I'm not really
> certain that is ppr or in quadrature.
>
> Price is in the $1000 range.
>
> http://www.opticalencoder.com/pdf/CP-850-950-HHC.pdf
>
> Dave
>
> On Apr 22, 2008, at 11:09 AM, [EMAIL PROTECTED] wrote:
>
>> Hi
>> I have 3 questions.
>> First if to make motor work on very low feed – 0.001 per minute
>> need only
>> high resolution encoder than may be needed belt reduction to the
>> encoder
>> shaft only, to get more pulses and not to whole motor shaft. Is this
>> correct?
>> Second, what is reasonable low feed with direct drive to motors
>> that have
>> 8192x4 puls per revolution?
>> Third, how much those encoder, with 2 250 000 lines, may cost ?
>> Thanks
>> Aram
>>
>>
>>> [EMAIL PROTECTED] wrote:
>>>> Hi
>>>> I want to build system to tool grinder and that means that my system
>>>> should behave stable on very low RPM.
>>>> Minimum PRM 0.0001 per minute. I want to use direct drive with ball
>>>> screw
>>>> 5 rev per inch or 1 rev for 5 mm in case of metric system.
>>>> My motors have 8192 pulse per ….. it takes 4x8192 per revolution.
>>>> It is
>>>> AG
>>>> industrial from servo dynamics.
>>>> Any fundamentals ideas?
>>>> Should I use higher resolution encoder?
>>> If you really need .0001 Rev/Minute, that is 32768 counts *
>>> .0001 = 3.3 encoder counts/MINUTE, or 18 seconds between each
>>> encoder count.  You can't get smooth motion like that.  Of
>>> course, .0001 RPM x 5 TPI on the screw is a movement rate of
>>> .00002 IPM.  Do you truly need it this slow?
>>>
>>> To get smooth motion, you really want an encoder count rate of
>>> maybe 15 counts/second, or even better, 60.  So, for 15 cts/sec
>>> at .0001 RPM, you need 15 * 60 * 10000 = 9 000 000 counts/rev,
>>> or 2 250 000 pulses/rev.  This will be a pretty expensive
>>> encoder.  (Multiply by 4 for 60 counts/sec.)
>>>
>>> Jon
>>>
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