Dyslexia rules ko? In your illustration I count 4 holes and 1 slot (made of 2 holes), so if a slot is not a hole there are 4 holes? ________________________________ From: John Dammeyer <jo...@autoartisans.com> Sent: Sunday, September 18, 2022 5:49 PM To: 'Enhanced Machine Controller (EMC)' <emc-users@lists.sourceforge.net> Subject: Re: [Emc-users] missing tooth index questions..
Much easier to visualize if you use less holes I think? I first made 6 holes and then laid out two arcs and created a longer slot from two of the holes. I count 5 holes and 5 spaces between the holes. Are you sure you actually cut 100 holes? John Dammeyer > -----Original Message----- > From: Sam Sokolik [mailto:samco...@gmail.com] > Sent: September-18-22 1:51 PM > To: Enhanced Machine Controller (EMC) > Subject: [Emc-users] missing tooth index questions.. > > I have a optical encoder from a mouse running on an emco encoder wheel (100 > holes). I cut out the metal between 2 holes. I think that would be > considered one missing tooth... I have the encoder scale set to 100 and > the missing tooth set to 1 > > I have a little comp that sets the index enable to true whenever it is > false. > > Looking at the halscope screen shot - it only counts to 98.. I would think > it would count from 0 to 99. You can see the gap is seen - but I think > there should be an extra count in there.. > > (I could be not understanding it too) > > ps - if I set the missing teeth to 2 - it will not trigger (like it doesn't > see the gap then which seems correct) > > thanks! > sam _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users
