Brent, That assumes a strict one-to-one mapping between observers and branches, which is exactly what’s in question. If the wavefunction remains a superposition of infinite branches, then what we call a "branch" is just a coarse-grained partition, not a fundamental unit.
If we allow infinite superposition, partitioning the multiverse by amplitude isn’t the same as naive branch counting. It’s closer to a measure-based weighting, where high-amplitude outcomes have exponentially more observer instances—not more branches, but more weight within the structure. If you assume one observer per branch, you assume what you want to prove: that measure plays no role. But if measure defines how often an observer finds themselves in a given state, it naturally leads to the Born rule without naive branch counting. Quentin Le jeu. 20 févr. 2025, 00:43, Brent Meeker <[email protected]> a écrit : > > > On 2/19/2025 12:20 AM, Quentin Anciaux wrote: > > Brent, > > Yes, and that’s exactly the problem—Gleason’s theorem doesn’t apply to > two-dimensional Hilbert spaces, which means it doesn’t universally derive > the Born rule. So if MWI fails for not deriving the Born rule, then > standard QM faces the same issue unless you introduce additional > postulates. > > Branch counting doesn’t work, but my example isn’t branch counting—it’s > asymmetric duplication, where observer distribution follows measure, > > Observer distribution is only one observer per branch; the observers can't > see each other. So N observers implies N branches. It's mathematically > equivalent to branch counting. > > Brent > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion visit > https://groups.google.com/d/msgid/everything-list/4ef93cce-f418-4a4d-9de3-15c189722d76%40gmail.com > <https://groups.google.com/d/msgid/everything-list/4ef93cce-f418-4a4d-9de3-15c189722d76%40gmail.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/everything-list/CAMW2kAowEqs4qoj4oOME4dOEMzSM95%2Br--784pO48sfSzQDOSA%40mail.gmail.com.
