On 2/20/2025 9:48 PM, Quentin Anciaux wrote:
Brent,
The key point is that a branch isn’t a single, discrete unit—it’s a
coarse-grained structure emerging from decoherence.
It must emerge from the thing measured; from a discrete result. There's
no mechanism for creating a "coarse grained structure".
The fact that a branch has "only one result" is an approximation
because, in reality, the wavefunction remains a superposition of
countless micro-branches.
But they all agree on the measurement result; otherwise they would be a
branch.
What we call "a branch" is just a region where interference is
negligible,
?? It's interference that eliminates the superposition of different
results.
but within that, there are still subtler partitions based on amplitude.
Yes, observer instances are in orthogonal branches, but the
partitioning isn’t uniform.
Why not? What mechanism, defined in what equation makes them not
uniform, i.e. one per result. I know you would like there to be
mechanism, but that doesn't make it so; and it certainly doesn't make
the Schroedinger equation that mechanism.
The measure of a branch corresponds to the number of observer
instances experiencing that outcome,
So if I perform an experiment in from a Superbowl crowd my results will
be more probable than those in undergrad lab on the 3rd floor of the
physics building.
not to the number of distinct sequences. This means that instead of
"one observer per branch," there are exponentially more copies of an
observer in high-amplitude branches than in low-amplitude ones.
The difference is subtle but crucial: If you assume one observer per
branch, you get branch counting and no Born rule. But if you recognize
that branches are not discrete and observer instances scale with
measure, you naturally recover Born probabilities.
Do you? Let's see you do that math.
Brent
--
You received this message because you are subscribed to the Google Groups
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion visit
https://groups.google.com/d/msgid/everything-list/3d482f4c-901e-47b7-890f-0769ebd6f2e5%40gmail.com.