External Email - Use Caution Hi Doug,
For the first question, you answered "It is unusual, though it should work". Could you please briefly describe the way FS used to permute (based on my notation v0, v1, ... vn)? Or, the usual way to permute? The way I described seems to be the only way I can think of. Looking forward to your help here. Thanks a lot! Xiao Douglas N. Greve <https://www.mail-archive.com/search?l=freesurfer@nmr.mgh.harvard.edu&q=from:%22Douglas+N.+Greve%22> Thu, 23 Jul 2020 07:37:13 -0700 <https://www.mail-archive.com/search?l=freesurfer@nmr.mgh.harvard.edu&q=date:20200723> On 7/21/2020 11:45 AM, Xiaojiang Yang wrote: External Email - Use Caution Hi Doug, For your questions: 1. "Not sure what you mean by in the ROI. Are you trying to permute across space? That generally does not work because the points are not exchangeable across space." By "In the ROI", I mean for all vertices listed in the label file. Here, I am talking about a test subject and n control subjects, they are all considered in the same reference subject space - fsaverage. A ROI is defined by a label file for the subject fsaverage. So, I am comparing the test subject and control group on the same ROI region, vertex by vertex. I want to permute points in the test subject and points in all subjects in control groups. I am not talking about permuting vertex locations; I am talking about permuting values (thickness in my case) from subjects on each vertex. For example, for vertex i, I have one value (v0) from test subject, and n values (v1, v2,...vn) from control subjects: test subject control subjects v0 v1, v2, ...... vn One way of permutation would be: test subject control subjects v1 v0, v2, ...... vn Is this a reasonable way to do permutation? It is unusual, though it should work. 2. "Not sure. You cannot discriminate between the groups when you are doing permutation" By doing the permutation many (say 1000) times, I want to get the probability distribution of the sampling (observed or test) data inside the ROI area, so that I can decide if I should reject or accept null hypothesis based on cluster-wise significance level. What problems do you think I have in this idea? That should work. I'm not sure what my original concern was Thanks a lot! On 7/21/2020 1:12 AM, Xiaojiang Yang wrote: External Email - Use Caution Dear FS experts, Instead of using mri_glmfit-sim, I am trying to implement a customized multiple comparison correction algorithm using permutation. Before I implement my own, I want to make sure my permutation idea is correct. So I was looking at how mri_glmfit-sim does the permutation. The link here http://freesurfer.net/fswiki/FsTutorial/MultipleComparisonsV6.0Perm has <http://freesurfer.net/fswiki/FsTutorial/MultipleComparisonsV6.0Perm%C2%A0has> a simple description for how to do permutation, but I don't quite understand the 1st step: Permute the design matrix. To me, permute the design matrix means permute the matrix rows here, but still hard to understand why permuting matrix rows does the trick. This is pretty standard in permutation. I think Tom Nichols has some basic tutorials on how permutations work. Anyway, I will not use any design matrix in my customized implementation, so it does not matter for now. My problem can be described as follows: if I have a ROI (a label file) on fsaverage, and I have a test subject and a group of control subjects whose thickness values on every vertex in this label are all known. (The test subject and control subjects are all using fsaverage reference space). I want to compare this test subject's thickness within the ROI to a control group of subjects (within the same ROI). This is a multiple-comparison problem, so I want to use permutation to get less FP rate. My question is: How do I permute the test subject's points and control subjects' points in ROI? Not sure what you mean by in the ROI. Are you trying to permute across space? That generally does not work because the points are not exchangeable across space. My understanding is that: for each point in the label, I randomly re-assign all (1+n) values from (1+n) subjects to these (n+1) subjects (where n is the number of subjects in control group). And when all points in the label are done, this is only 1 permutation. I will need at least 1000 times of permutation to get the comparison statistics. Is my understanding right? Not sure. You cannot discriminate between the groups when you are doing permutation Thank you! Xiao _______________________________________________ Freesurfer mailing listfreesur...@nmr.mgh.harvard.eduhttps://mail.nmr.mgh.harvard.edu/mailman/listinfo/freesurfer
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