It seems hasty to say that "Because of the Linux algorithm for using swap, a VDISK used for swap even a little will eventually be used completely". That's the same as saying a linux swap area used even a little will eventually be used completely. Why would linux do that? That's not what my SLES9 guests do.
Now that the swap topic's open again: What is the basis for advising z/VM VDISK users to have a hierarchy of multiple linux swap areas of increasing sizes? Are there feature(s) of the swapping algorithm that make that hierarchy principle optimal? -------------------------------------------------------- This e-mail, including any attachments, may be confidential, privileged or otherwise legally protected. It is intended only for the addressee. If you received this e-mail in error or from someone who was not authorized to send it to you, do not disseminate, copy or otherwise use this e-mail or its attachments. Please notify the sender immediately by reply e-mail and delete the e-mail from your system. -----Original Message----- From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] On Behalf Of Rob van der Heij Sent: Monday, December 03, 2007 3:56 AM To: IBMVM@LISTSERV.UARK.EDU Subject: Re: Is 275GB of VDISK stupid? <snip> Because of the Linux algorithm for using swap, a VDISK used for swap even a little will eventually be used completely. So you need to prepare for all of these disks to end up in z/VM paging space. If you see z/VM page in your VDISK on a constant basis, you should look at making the VDISK smaller. Rob -- Rob van der Heij Velocity Software, Inc http://velocitysoftware.com/
