> The trick is getting it nicely
> calibrated, 1 mV/A would be ideal.

Not ideal, really, in that you lose an entire
volt at 1000A, but that might be tolerable.
Your shunt needs to be physically larger so
it won't vaporize as it dissipates the
500*500*0.001=250W of a 500A load.  There's
a reason a 1W resistor is a lot larger than
the usual 1/4" resistor.

Plus, copper has a noticeable temperature
coefficient, if it gets dramatically hot its
resistance will change enough to skew your
results some.

Much longer wire of the 12ga or 10ga persuasion
would survive a lot better.

Consider the lowly toaster rack of the series
glow plug system.  It's only drawing about 50-60A
and look at how big it is.  (It's iron wire,
though.  Not copper, anyway.)

-- Jim


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