Re: [algogeeks] output

2013-12-09 Thread Tamanna Afroze
I got some other outputs.. when line 6 isn't commented i got 3 1 2 3, i m
using turbo c++ compiler..


On Fri, Dec 6, 2013 at 8:17 AM, pawan yadav pawan1991ya...@gmail.comwrote:

 Hi All,

 I'm not able to get output of following c program :

 #includestdio.h
  main()
  {
  int a[] ={ 1,2,3,4,5,6,7};
  char c[] = {'a','x','h','o','k'};
  //printf(%u   %u\n, a[3], a[0]);  line 6
  printf(%d %d %d %d \n, (a[3]-a[0]));
  }

 If line 6 is commented, output :

 3 1562814827 1869117537 0

 Confusion : why is there 4 output?   (a[3]-a[0]) should give only one.

 if line 6 is not commented, output :

 1554221244   1554221232
 3 1554221232 1309214001 64



 Can anybody please explain why/how these outputs are coming?

 Thanks,
 Pawan.

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Re: [algogeeks] output

2013-12-09 Thread Tamanna Afroze
i think because of operator the program is working differently... also
there is four data value print operation..


On Mon, Dec 9, 2013 at 2:34 AM, Tamanna Afroze afroze...@gmail.com wrote:

 I got some other outputs.. when line 6 isn't commented i got 3 1 2 3, i m
 using turbo c++ compiler..


 On Fri, Dec 6, 2013 at 8:17 AM, pawan yadav pawan1991ya...@gmail.comwrote:

 Hi All,

 I'm not able to get output of following c program :

 #includestdio.h
  main()
  {
  int a[] ={ 1,2,3,4,5,6,7};
  char c[] = {'a','x','h','o','k'};
  //printf(%u   %u\n, a[3], a[0]);  line 6
  printf(%d %d %d %d \n, (a[3]-a[0]));
  }

 If line 6 is commented, output :

 3 1562814827 1869117537 0

 Confusion : why is there 4 output?   (a[3]-a[0]) should give only one.

 if line 6 is not commented, output :

 1554221244   1554221232
 3 1554221232 1309214001 64



 Can anybody please explain why/how these outputs are coming?

 Thanks,
 Pawan.

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[algogeeks] output

2013-12-06 Thread pawan yadav
Hi All,

I'm not able to get output of following c program :

#includestdio.h
 main()
 {
 int a[] ={ 1,2,3,4,5,6,7};
 char c[] = {'a','x','h','o','k'};
 //printf(%u   %u\n, a[3], a[0]);  line 6
 printf(%d %d %d %d \n, (a[3]-a[0]));
 }

If line 6 is commented, output :

3 1562814827 1869117537 0

Confusion : why is there 4 output?   (a[3]-a[0]) should give only one.

if line 6 is not commented, output :

1554221244   1554221232
3 1554221232 1309214001 64



Can anybody please explain why/how these outputs are coming?

Thanks,
Pawan.

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[algogeeks] Output

2012-11-24 Thread rajesh pandey
void dosomething(int num)
{
int mask=~(15-1);
int res=nummask;
printf(%d,res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}

please explain  the logic behind the output.

Thanks,
Rajesh  

-- 




Re: [algogeeks] Output

2012-11-24 Thread Rushiraj Patel
As arithmetic operator has higher precedence than shifting operator , mask
will have 5th bit zero from left.

So it will deduct 16 from the input if 5th bit is set in the binary
representation of number.
so it will deduct 16 from 56 and 127..but not from 64

But its  just the procedural thing meaning i don't know..


On Sat, Nov 24, 2012 at 2:15 PM, rajesh pandey rajesh.pandey.i...@gmail.com
 wrote:

 void dosomething(int num)
 {
 int mask=~(15-1);
  int res=nummask;
 printf(%d,res);
 }
 int main()
 {
 dosomething(56);
 dosomething(64);
 dosomething(127);
  return 0;
 }

 please explain  the logic behind the output.

 Thanks,
 Rajesh

 --




-- 




Re: [algogeeks] output of the program with explanation

2012-11-07 Thread vishwa
let me keep it simple

 y is integer pointer pointing to address 20 .. x=20

y+7 will point to the addressy + ( size(int) * 7) i.e  50 here
/*y is integer pointer*/

On Tue, Nov 6, 2012 at 11:45 AM, Rahul Kumar Patle 
patlerahulku...@gmail.com wrote:

 because difference is of 30 bytes..
 and integer takes 4 byte...
 it is representing that there are 7 int blocks between the address x and y
 output will be same as 7 for 31, 30, 29, 28.

 2012/11/6 rajesh pandey rajesh.pandey.i...@gmail.com

 *int *x ,int *y;
 x=(int *) 50;
 y=(int *)20;
 coutx-yendl;

 why the output is 7.*

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[algogeeks] output of the program with explanation

2012-11-05 Thread rajesh pandey
*int *x ,int *y;
x=(int *) 50;
y=(int *)20;
coutx-yendl;

why the output is 7.*

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Re: [algogeeks] output of the program with explanation

2012-11-05 Thread rahul patil
its because it is integer pointer subtraction, So  subtraction  result will
be divided by integer size.

so 30/4 = 7.

2012/11/6 rajesh pandey rajesh.pandey.i...@gmail.com

 *int *x ,int *y;
 x=(int *) 50;
 y=(int *)20;
 coutx-yendl;

 why the output is 7.*

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[algogeeks] output

2012-07-25 Thread jatin
 anybdy has basic trie implementation (insertion and printing) ?
o/p
1)
main()
{
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf(%s\n,p2);
} ...it's giving me empty string 
 
2)
i=5;
printf(%d,i++ * i++);
o/p and also tell the reason?

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[algogeeks] output C

2012-02-25 Thread Ravi Ranjan
#include stdio.h
#include stdlib.h

#define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0]))

  #define PrintInt(expr) printf(%s:%d\n,#expr,(expr))

int main(int argc, char *argv[])
{

  /* The powers of 10 */
  int pot[] = {
  0001,
  0010,
  0100,
  1000
  };
  int i;

  for(i=0;iSIZEOF(pot);i++)
   PrintInt(pot[i]);

  system(PAUSE);
  return 0;
}


howz dat output come plz explain??

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Re: [algogeeks] output C

2012-02-25 Thread atul anand
 0001,
 0010,
 0100,
these number are represented in octal ..so u r getting decimal of the same.
1000 - this is a decimal value;

preceding number by 0 means you are representing it in octal format

similarly preceding 0x means representing in hexa format.

On Sun, Feb 26, 2012 at 3:38 AM, Ravi Ranjan ravi.cool2...@gmail.comwrote:

 #include stdio.h
 #include stdlib.h

 #define SIZEOF(arr) (sizeof(arr)/sizeof(arr[0]))

   #define PrintInt(expr) printf(%s:%d\n,#expr,(expr))

 int main(int argc, char *argv[])
 {

   /* The powers of 10 */
   int pot[] = {
   0001,
   0010,
   0100,
   1000
   };
   int i;

   for(i=0;iSIZEOF(pot);i++)
PrintInt(pot[i]);

   system(PAUSE);
   return 0;
 }


 howz dat output come plz explain??

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[algogeeks] output expalnation?

2011-09-26 Thread Ratan
#includestdio.h
int main()
{
int a=1;
switch(a)
{
 int b=6;
case 1:
printf(b is %d,b);
break;
default:
printf(b is %d:,b);
break;
}
return 0;
}

can any1 explain the o/p of this program...





Thanxs n Regards
-- 
Ratan Modi

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Re: [algogeeks] output expalnation?

2011-09-26 Thread sukran dhawan
compile time error... except case labels nothing else will be executed in
case of switch statements... so definition of b will not be executed.so
compilation error

On Tue, Sep 27, 2011 at 6:28 AM, Ratan success.rata...@gmail.com wrote:

 #includestdio.h
 int main()
 {
int a=1;
switch(a)
{
 int b=6;
case 1:
 printf(b is %d,b);
break;
default:
printf(b is %d:,b);
break;
}
 return 0;
 }

 can any1 explain the o/p of this program...





 Thanxs n Regards
 --
 Ratan Modi

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Re: [algogeeks] output expalnation?

2011-09-26 Thread gaurav yadav
b=6 will not execute..

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Re: [algogeeks] output expalnation?

2011-09-26 Thread Ratan
On ideone.com its showing compiler error and on ubuntu garbage value
of b gets as the result...

On Tue, Sep 27, 2011 at 10:21 AM, gaurav yadav
gauravyadav1...@gmail.com wrote:
 b=6 will not execute..

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Allahabad

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[algogeeks] output

2011-09-13 Thread Rajeshwar Patra
http://codepad.org/erdnF74M

can anyone explain the output ???

-- 
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*MCA final year,*
*Nit Durgapur*

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Re: [algogeeks] output

2011-09-13 Thread kumar raja
main(){printf(%s,printf(samsung)+fun());}fun(){return electronic;}

The printf is a function which returns the number of printed
characters , and scanf is a function
which returns the number of inputs scanned .

So after printing samsung it returns 7. fun() is returning a pointer
to the constant string
electronic , so it is like 7[electronic]

so the %s prints that string from the 7th index onwards till end .

So output is nic

so the total output is samsungnic
but i dont know why it is exiting with some error code..



On 13 September 2011 10:51, Rajeshwar Patra rajeshwarpa...@gmail.comwrote:

 http://codepad.org/erdnF74M

 can anyone explain the output ???

 --
 *Rajeshwar Patra,*
 *MCA final year,*
 *Nit Durgapur*

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10it60...@iitkgp.ac.in
7797137043.
09491690115.

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Re: [algogeeks] output

2011-09-13 Thread Ishan Aggarwal
int main(){printf(%s,printf(samsung)+fun());return 0;}fun(){return
electronic;}




On Tue, Sep 13, 2011 at 11:28 PM, kumar raja rajkumar.cs...@gmail.comwrote:

 main(){printf(%s,printf(samsung)+fun());}fun(){return electronic;}

 The printf is a function which returns the number of printed characters , and 
 scanf is a function
 which returns the number of inputs scanned .

 So after printing samsung it returns 7. fun() is returning a pointer to the 
 constant string

 electronic , so it is like 7[electronic]

 so the %s prints that string from the 7th index onwards till end .

 So output is nic

 so the total output is samsungnic

 but i dont know why it is exiting with some error code..



 On 13 September 2011 10:51, Rajeshwar Patra rajeshwarpa...@gmail.comwrote:

 http://codepad.org/erdnF74M

 can anyone explain the output ???

 --
 *Rajeshwar Patra,*
 *MCA final year,*
 *Nit Durgapur*

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 Regards
 Kumar Raja
 M.Tech(SIT)
 IIT Kharagpur,
 10it60...@iitkgp.ac.in
 7797137043.
 09491690115.

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Re: [algogeeks] output

2011-09-13 Thread Kunal Patil
@Kumar: +1

@Kumar  Rajeshwar: ExitFailure is outputted because main is expected to
return something which is not done in your case. Just add return 0; at the
end of main to get expected output.

On Tue, Sep 13, 2011 at 11:33 PM, Ishan Aggarwal 
ishan.aggarwal.1...@gmail.com wrote:

 int main()
 {printf(%s,printf(samsung)+fun());
 return 0;}fun(){return electronic;}




 On Tue, Sep 13, 2011 at 11:28 PM, kumar raja rajkumar.cs...@gmail.comwrote:

 main(){printf(%s,printf(samsung)+fun());}fun(){return electronic;}

 The printf is a function which returns the number of printed characters , 
 and scanf is a function
 which returns the number of inputs scanned .

 So after printing samsung it returns 7. fun() is returning a pointer to 
 the constant string


 electronic , so it is like 7[electronic]

 so the %s prints that string from the 7th index onwards till end .

 So output is nic

 so the total output is samsungnic


 but i dont know why it is exiting with some error code..



 On 13 September 2011 10:51, Rajeshwar Patra rajeshwarpa...@gmail.comwrote:

 http://codepad.org/erdnF74M

 can anyone explain the output ???

 --
 *Rajeshwar Patra,*
 *MCA final year,*
 *Nit Durgapur*

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 Regards
 Kumar Raja
 M.Tech(SIT)
 IIT Kharagpur,
 10it60...@iitkgp.ac.in
 7797137043.
 09491690115.

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[algogeeks] Output question

2011-08-22 Thread vartika
#includestdio.h
#includestring.h
int main()
{
 typedef union
 {
  int a;
  char b[10];
  float c;
 }
 Union;

 Union x,y = {100};
 x.a = 50;
 strcpy(x.b,hello);
 x.c = 21.50;

 printf(Union x : %d %s %f \n,x.a,x.b,x.c );
 printf(Union y :%d %s%f \n,y.a,y.b,y.c);
 return 0;
}

Someone pls explain the output

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Re: [algogeeks] Output question

2011-08-22 Thread sagar pareek
U should know that union's elements share memory alloted through the largest
data type like in this case 10 bytes is alloted and is shared by all the
union elements.

So in union x :- last element modified is c, so that's why it is printing
garbage values for int and char[] elements...
actually if u convert float value in binary then u will see that what's its
actual integer value is? same case for char[]

in union y : last modified element is integer thats y it is printing 100 for
integer... ascii value of 'd' is 100 thats y printing 'd' for char[] and
0.000 for float

On Mon, Aug 22, 2011 at 4:53 PM, vartika vartika.aggarwa...@gmail.comwrote:

 #includestdio.h
 #includestring.h
 int main()
 {
  typedef union
  {
  int a;
  char b[10];
  float c;
  }
  Union;

  Union x,y = {100};
  x.a = 50;
  strcpy(x.b,hello);
  x.c = 21.50;

  printf(Union x : %d %s %f \n,x.a,x.b,x.c );
  printf(Union y :%d %s%f \n,y.a,y.b,y.c);
  return 0;
 }

 Someone pls explain the output

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Re: [algogeeks] Output question

2011-08-22 Thread Abhishek
+1 to sagar.
@vartika: if you don't know the concept of Union then understanding this 
program will be quite lenghty, because it will involve lot of calculation. 
try to check some simple examples, like:

union a
{
int a;
char c;
};
int main()
{
 union a xy;
 xy.a=65;
 printf(%c,xy.c);
 xy.c=65;
 printf( %d,xy.a);
return 0;
}

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[algogeeks] Output?? Why??

2011-08-17 Thread noobcoder
#includestdio.h
int main()
{
  char arr[5] = geeks;
  printf(%s, arr);
  getchar();
  return 0;
}

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Re: [algogeeks] output

2011-08-12 Thread sukran dhawan
macro has not been terminated and it has so many errors

On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo manis...@gmail.com wrote:

  output of the program?

 #define prn(a) printf(%d,a)
 #define print(a,b,c) prn(a), prn(b), prn(c)
 #define max(a,b) (a

 main()
 {
 int x=1, y=2;
 print(max(x++,y),x,y);
 print(max(x++,y),x,y);
 }

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Re: [algogeeks] output

2011-08-12 Thread Avenged
this is the question :

#includestdio.h
#define prn(a) printf(%d,a)
#define print(a,b,c) prn(a), prn(b), prn(c)
#define max(a,b) (ab?a:b)

int main()
{
int x=1, y=2;
print(max(x++,y),x,y);
print(max(x++,y),x,y);
return 0;
}

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Re: [algogeeks] output

2011-08-12 Thread Anil Arya
Answer=:  32

On Fri, Aug 12, 2011 at 8:05 PM, Avenged nitee...@gmail.com wrote:

 this is the question :

 #includestdio.h
 #define prn(a) printf(%d,a)
 #define print(a,b,c) prn(a), prn(b), prn(c)
 #define max(a,b) (ab?a:b)

 int main()
 {
 int x=1, y=2;
 print(max(x++,y),x,y);
 print(max(x++,y),x,y);
 return 0;
 }

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[algogeeks] output

2011-08-11 Thread manvir siyo
 output of the program?

#define prn(a) printf(%d,a)
#define print(a,b,c) prn(a), prn(b), prn(c)
#define max(a,b) (a

main()
{
int x=1, y=2;
print(max(x++,y),x,y);
print(max(x++,y),x,y);
}

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Re: [algogeeks] output

2011-08-11 Thread Anika Jain
this code has so many errors

On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo manis...@gmail.com wrote:

  output of the program?

 #define prn(a) printf(%d,a)
 #define print(a,b,c) prn(a), prn(b), prn(c)
 #define max(a,b) (a

 main()
 {
 int x=1, y=2;
 print(max(x++,y),x,y);
 print(max(x++,y),x,y);
 }

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Re: [algogeeks] output

2011-08-11 Thread mani walia
this is the question in de shaw written test

On Thu, Aug 11, 2011 at 11:48 PM, Anika Jain anika.jai...@gmail.com wrote:

 this code has so many errors

 On Thu, Aug 11, 2011 at 11:36 PM, manvir siyo manis...@gmail.com wrote:

  output of the program?

 #define prn(a) printf(%d,a)
 #define print(a,b,c) prn(a), prn(b), prn(c)
 #define max(a,b) (a

 main()
 {
 int x=1, y=2;
 print(max(x++,y),x,y);
 print(max(x++,y),x,y);
 }

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Re: [algogeeks] output?

2011-08-10 Thread Arun Vishwanathan
@sandeep: so the statement becomes if(ch=0) since printf returns integer
0...whats does this mean now actually?0 is ascii for NULL and so ch is
assinged to null? I am slightly confused..

On Tue, Aug 9, 2011 at 7:04 PM, SANDEEP CHUGH sandeep.aa...@gmail.comwrote:

 @all sorry i give wrong explanation by mistake..:P :P

 printf()  returns no if characters.. in this case returns 0 . which is
 assigned to ch

 so in ch 0 is stored and 0 is the ascii value of null character
 when we using ch in --- if (ch) -- it will reduce to if(0) -- as 0 is the
 ascii value of null character

 so the output it doesn't matter


 On Tue, Aug 9, 2011 at 10:28 PM, Dipankar Patro dip10c...@gmail.comwrote:

 o/p:
 It doesn't matter

 Reason:
 printf() returns the number of characters printed to screen.
 since printf() will return 0, hence the *else* is selected.


 On 9 August 2011 22:25, siddharth srivastava akssps...@gmail.com wrote:



  On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 It doesn't matter




 what will b the output??

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[algogeeks] output help

2011-08-09 Thread Rohit Srivastava
#includestdio.h
#includeconio.h

int main()
{
struct value
{
int bit1:1;
int bit3:4;
int bit4:4;
}bit={1,2,2};
printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
getche();
return 0;
}
 the above code gives output : -1 2 2
any idea why???

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Re: [algogeeks] output help

2011-08-09 Thread aditi garg
I think it is because bit1 is only 1 bit fwide and whn u initialize it to
1,since MSB is 1 it treats it as a negative integer...Plz correct me if i am
wrong...

On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava access2ro...@gmail.comwrote:

 #includestdio.h
 #includeconio.h

 int main()
 {
 struct value
 {
 int bit1:1;
 int bit3:4;
 int bit4:4;
 }bit={1,2,2};
 printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
 getche();
 return 0;
 }
  the above code gives output : -1 2 2
 any idea why???

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Re: [algogeeks] output help

2011-08-09 Thread sanjay ahuja
Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
treated as int (signed). Thus lower order bit of bit3 which is 2, are
0010 which is 2
try with
1) int bit3:2, output will be -2
2) unsigned int bit3:2, output will be 2.

I hope it is cleared now

On 8/9/11, Rohit Srivastava access2ro...@gmail.com wrote:
 #includestdio.h
 #includeconio.h

 int main()
 {
 struct value
 {
 int bit1:1;
 int bit3:4;
 int bit4:4;
 }bit={1,2,2};
 printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
 getche();
 return 0;
 }
  the above code gives output : -1 2 2
 any idea why???

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Re: [algogeeks] output help

2011-08-09 Thread Rohit Srivastava
hey guys thanks got it!!


On Tue, Aug 9, 2011 at 12:49 PM, sanjay ahuja sanjayahuja.i...@gmail.comwrote:

 Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
 treated as int (signed). Thus lower order bit of bit3 which is 2, are
 0010 which is 2
 try with
 1) int bit3:2, output will be -2
 2) unsigned int bit3:2, output will be 2.

 I hope it is cleared now

 On 8/9/11, Rohit Srivastava access2ro...@gmail.com wrote:
  #includestdio.h
  #includeconio.h
 
  int main()
  {
  struct value
  {
  int bit1:1;
  int bit3:4;
  int bit4:4;
  }bit={1,2,2};
  printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
  getche();
  return 0;
  }
   the above code gives output : -1 2 2
  any idea why???
 
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Re: [algogeeks] output help

2011-08-09 Thread dinesh bansal
On a little-endian machine, bit structure will be represented as:

 0x00 00 00 45

which is bit.bit4 = 0010 (2 in decimal) bit.bit3 = 0010 (2 in decimal)
bit.bit1 = 1 (1 in decimal)

since bit.bit1 exists at the rightmost position, while displaying data as
integer, compiler just repeats the same bit to all the remaining positions
making it 0x (-1). You can confirm it while setting bit.bit1 to 0

-Dinesh Bansal

On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava access2ro...@gmail.comwrote:

 #includestdio.h
 #includeconio.h

 int main()
 {
 struct value
 {
 int bit1:1;
 int bit3:4;
 int bit4:4;
 }bit={1,2,2};
 printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
 getche();
 return 0;
 }
  the above code gives output : -1 2 2
 any idea why???

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Re: [algogeeks] output help

2011-08-09 Thread SANDEEP CHUGH
i dnt get it.. any better explanation..

On Tue, Aug 9, 2011 at 1:13 PM, dinesh bansal bansal...@gmail.com wrote:

 On a little-endian machine, bit structure will be represented as:

  0x00 00 00 45

 which is bit.bit4 = 0010 (2 in decimal) bit.bit3 = 0010 (2 in decimal)
 bit.bit1 = 1 (1 in decimal)

 since bit.bit1 exists at the rightmost position, while displaying data as
 integer, compiler just repeats the same bit to all the remaining positions
 making it 0x (-1). You can confirm it while setting bit.bit1 to 0

 -Dinesh Bansal


 On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava 
 access2ro...@gmail.comwrote:

 #includestdio.h
 #includeconio.h

 int main()
 {
 struct value
 {
 int bit1:1;
 int bit3:4;
 int bit4:4;
 }bit={1,2,2};
 printf(%d %d %d\n,bit.bit1,bit.bit3,bit.bit4);
 getche();
 return 0;
 }
  the above code gives output : -1 2 2
 any idea why???

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 The Law of Win says, Let's not do it your way or my way; let's do it the
 best way.

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[algogeeks] output?

2011-08-09 Thread tech rascal
#includestdio.h
int main()
{
char ch;
if((ch=printf()))
printf(it matters);
else
printf(it doesn't matter);
return 0;
}


what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread aditi garg
it doesnt matter

On Tue, Aug 9, 2011 at 10:20 PM, tech rascal techrascal...@gmail.comwrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 what will b the output??

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Undergraduate Student
Electronics  Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi

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Re: [algogeeks] output?

2011-08-09 Thread Jayanthi shravan
  it matters..
On Tue, Aug 9, 2011 at 10:20 PM, tech rascal techrascal...@gmail.comwrote:




 what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread tech rascal
explanation??

On Tue, Aug 9, 2011 at 10:24 PM, aditi garg aditi.garg.6...@gmail.comwrote:

 it doesnt matter

 On Tue, Aug 9, 2011 at 10:20 PM, tech rascal techrascal...@gmail.comwrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 what will b the output??

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 Electronics  Communication Divison
 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
 New Delhi


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Re: [algogeeks] output?

2011-08-09 Thread siddharth srivastava
On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


It doesn't matter




 what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread Varun Jakhoria
it doesn't matter

On Tue, Aug 9, 2011 at 10:24 PM, Jayanthi shravan
jayanthisra...@gmail.com wrote:

   it matters..
 On Tue, Aug 9, 2011 at 10:20 PM, tech rascal techrascal...@gmail.com
 wrote:



 what will b the output??

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...it's only about 0's  1's

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Re: [algogeeks] output?

2011-08-09 Thread Amol Sharma
printf returns the numbers of character printed and here it prints nothing
i.e. 0 characters hence returns 0

and hence it doesnt matter gets printed
--


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Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Tue, Aug 9, 2011 at 10:25 PM, tech rascal techrascal...@gmail.comwrote:

 explanation??


 On Tue, Aug 9, 2011 at 10:24 PM, aditi garg aditi.garg.6...@gmail.comwrote:

 it doesnt matter

 On Tue, Aug 9, 2011 at 10:20 PM, tech rascal techrascal...@gmail.comwrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 what will b the output??

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 Undergraduate Student
 Electronics  Communication Divison
 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
 New Delhi


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Re: [algogeeks] output?

2011-08-09 Thread Dipankar Patro
o/p:
It doesn't matter

Reason:
printf() returns the number of characters printed to screen.
since printf() will return 0, hence the *else* is selected.

On 9 August 2011 22:25, siddharth srivastava akssps...@gmail.com wrote:



 On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 It doesn't matter




 what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread SANDEEP CHUGH
it doesn't matter

On Tue, Aug 9, 2011 at 10:25 PM, siddharth srivastava
akssps...@gmail.comwrote:



 On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 output wud be : It doesn't matter


reason:  in the printf() --- this will return null character and assign
it to ch and null character has ascii value 0

so statement reduces to

if(0)

rest u knw..







 what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread siddharth srivastava
my bad..that I didn't notice = (assumed it to be ==)

On 9 August 2011 22:28, SANDEEP CHUGH sandeep.aa...@gmail.com wrote:

 it doesn't matter

 On Tue, Aug 9, 2011 at 10:25 PM, siddharth srivastava akssps...@gmail.com
  wrote:



 On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 output wud be : It doesn't matter


 reason:  in the printf() --- this will return null character and assign
 it to ch and null character has ascii value 0

 so statement reduces to

 if(0)

 rest u knw..







 what will b the output??

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Re: [algogeeks] output?

2011-08-09 Thread SANDEEP CHUGH
@all sorry i give wrong explanation by mistake..:P :P

printf()  returns no if characters.. in this case returns 0 . which is
assigned to ch

so in ch 0 is stored and 0 is the ascii value of null character
when we using ch in --- if (ch) -- it will reduce to if(0) -- as 0 is the
ascii value of null character

so the output it doesn't matter

On Tue, Aug 9, 2011 at 10:28 PM, Dipankar Patro dip10c...@gmail.com wrote:

 o/p:
 It doesn't matter

 Reason:
 printf() returns the number of characters printed to screen.
 since printf() will return 0, hence the *else* is selected.


 On 9 August 2011 22:25, siddharth srivastava akssps...@gmail.com wrote:



 On 9 August 2011 22:20, tech rascal techrascal...@gmail.com wrote:

 #includestdio.h
 int main()
 {
 char ch;
 if((ch=printf()))
 printf(it matters);
 else
 printf(it doesn't matter);
 return 0;
 }


 It doesn't matter




 what will b the output??

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[algogeeks] output help

2011-08-07 Thread Kamakshii Aggarwal
#includestdio.h
int main()
{
   typedef static int *i;
  static int j;
  i a = j;
  printf(%d, *a);
  getchar();
  return 0;
}

what is the error in the code?
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Re: [algogeeks] output help

2011-08-07 Thread Amol Sharma
using typedef u define the static keyword as int
and the statement static int j thus becomes
int int j

hence the compiler gives the error multiple storage class in declaration
specifiers

--


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Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 #includestdio.h
 int main()
 {
typedef static int *i;
   static int j;
   i a = j;
   printf(%d, *a);
   getchar();
   return 0;
 }

 what is the error in the code?
 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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Re: [algogeeks] output help

2011-08-07 Thread aseem garg
typedef doesn't declare an instance of a variable, it declares a type (type
alias actually),

static is a qualifier you apply to an instance, not a type, so you can use
static when you use the type, but not when you define the type.
Aseem



On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 #includestdio.h
 int main()
 {
typedef static int *i;
   static int j;
   i a = j;
   printf(%d, *a);
   getchar();
   return 0;
 }

 what is the error in the code?
 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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Re: [algogeeks] output help

2011-08-07 Thread Kamakshii Aggarwal
got it...thanks

On Mon, Aug 8, 2011 at 12:39 AM, aseem garg ase.as...@gmail.com wrote:

 typedef doesn't declare an instance of a variable, it declares a type (type
 alias actually),

 static is a qualifier you apply to an instance, not a type, so you can use
 static when you use the type, but not when you define the type.
 Aseem



 On Mon, Aug 8, 2011 at 12:29 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 #includestdio.h
 int main()
 {
typedef static int *i;
   static int j;
   i a = j;
   printf(%d, *a);
   getchar();
   return 0;
 }

 what is the error in the code?
 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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[algogeeks] OUTPUT????

2011-08-06 Thread SHIVAM AGRAWAL
any1 plz tell me y output of float type of dis prgrm  is zero?

#includestdio.h
#define INT 1
main()
{
struct a
{
int type;
};
struct c
{
int type;
int e;
};
struct b
{
int type;
float f;
};
union
{
struct a n;
struct b nf;
struct c ni;
}all;
all.ni.type=INT;
all.nf.f=10.43;
all.ni.e=1;
printf(%f\n,all.nf.f);
if(all.nf.type==INT)
printf(float value =%2.1f,all.nf.f);
if(all.ni.type==INT)
printf(\ninteger value=%d,all.ni.e);
printf(\n%d %d %d %f,all.ni.type,all.nf.type,all.ni.e,all.nf.f);

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Re: [algogeeks] OUTPUT????

2011-08-06 Thread Ankit Minglani
out put is :
10.375001
float value =10.4
integer value=1
1 1 1 10.37500

what us the problem ?

On Sat, Aug 6, 2011 at 2:19 AM, SHIVAM AGRAWAL shivi...@gmail.com wrote:

 any1 plz tell me y output of float type of dis prgrm  is zero?

 #includestdio.h
 #define INT 1
 main()
 {
 struct a
 {
 int type;
 };
 struct c
 {
 int type;
 int e;
 };
 struct b
 {
 int type;
 float f;
 };
 union
 {
 struct a n;
 struct b nf;
 struct c ni;
 }all;
 all.ni.type=INT;
 all.nf.f=10.43;
 all.ni.e=1;
 printf(%f\n,all.nf.f);
 if(all.nf.type==INT)
 printf(float value =%2.1f,all.nf.f);
 if(all.ni.type==INT)
 printf(\ninteger value=%d,all.ni.e);
 printf(\n%d %d %d %f,all.ni.type,all.nf.type,all.ni.e,all.nf.f);

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Re: [algogeeks] OUTPUT????

2011-08-06 Thread Aditya Virmani
output wud be:
0.00
float value= 00.0
integer value=1
1 1 1 0.00

On Sat, Aug 6, 2011 at 2:49 PM, SHIVAM AGRAWAL shivi...@gmail.com wrote:

 any1 plz tell me y output of float type of dis prgrm  is zero?

 #includestdio.h
 #define INT 1
 main()
 {
 struct a
 {
 int type;
 };
 struct c
 {
 int type;
 int e;
 };
 struct b
 {
 int type;
 float f;
 };
 union
 {
 struct a n;
 struct b nf;
 struct c ni;
 }all;
 all.ni.type=INT;
 all.nf.f=10.43;
 all.ni.e=1;
 printf(%f\n,all.nf.f);
 if(all.nf.type==INT)
 printf(float value =%2.1f,all.nf.f);
 if(all.ni.type==INT)
 printf(\ninteger value=%d,all.ni.e);
 printf(\n%d %d %d %f,all.ni.type,all.nf.type,all.ni.e,all.nf.f);

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[algogeeks] output???

2011-08-05 Thread Rajesh Kumar
program output comes - hi
why??

#includestdio.h
main()
{
float a=0.7;
if(.7 a)
printf(hi\n);
else
printf(hello\n);
}

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Re: [algogeeks] output???

2011-08-05 Thread kartik sachan
the output will be hi

even if u have putted equal to sign there this is becoz 0.7 do not exactly
stored like 0.7 in a but some thing lesser as describe in ASCII format
that's why it is awlays lesser than 0.7

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Re: [algogeeks] output???

2011-08-05 Thread bagaria.ka...@gmail.com
.7 in float is taken like .699 i blv ?

On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan kartik.sac...@gmail.comwrote:

 the output will be hi

 even if u have putted equal to sign there this is becoz 0.7 do not exactly
 stored like 0.7 in a but some thing lesser as describe in ASCII format
 that's why it is awlays lesser than 0.7

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Re: [algogeeks] output???

2011-08-05 Thread sukran dhawan
coz by default all real values are converted to double and it is larger than
float.ie real nos are not stored accurately inside computer memory.so
since double occupies more memory it prints hi

On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal kamakshi...@gmail.comwrote:

 the reason is dat 0.7 is treated as double..therefore double(0.7)
 float(0.7)

 On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan kartik.sac...@gmail.comwrote:

 the output will be hi

 even if u have putted equal to sign there this is becoz 0.7 do not exactly
 stored like 0.7 in a but some thing lesser as describe in ASCII format
 that's why it is awlays lesser than 0.7

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 Kamakshi
 kamakshi...@gmail.com

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Re: [algogeeks] output???

2011-08-05 Thread Rajesh Kumar
Thanks to all

On Fri, Aug 5, 2011 at 8:53 PM, sukran dhawan sukrandha...@gmail.comwrote:

 coz by default all real values are converted to double and it is larger
 than float.ie real nos are not stored accurately inside computer memory.so
 since double occupies more memory it prints hi


 On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal 
 kamakshi...@gmail.comwrote:

 the reason is dat 0.7 is treated as double..therefore double(0.7)
 float(0.7)

 On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan kartik.sac...@gmail.comwrote:

 the output will be hi

 even if u have putted equal to sign there this is becoz 0.7 do not
 exactly stored like 0.7 in a but some thing lesser as describe in ASCII
 format
 that's why it is awlays lesser than 0.7

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 Kamakshi
 kamakshi...@gmail.com

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Re: [algogeeks] output???

2011-08-05 Thread sagar pareek
ha ha
its not like it stores slightly less than actual  :P :P

try this

float a=0.5,b=1.0,c=0.7;

if(0.5==a)
printf(yes a=0.5\n);

if(1.0==b)
printf(yes b=1.0\n);

if(0.7!=c)
printf(Yes c!=0.7\n);

o/p will be
yes a=0.5
yes b=1.0
yes c!=0.7

check it out i will explain it later...
On Fri, Aug 5, 2011 at 9:26 PM, Rajesh Kumar testalgori...@gmail.comwrote:

 Thanks to all


 On Fri, Aug 5, 2011 at 8:53 PM, sukran dhawan sukrandha...@gmail.comwrote:

 coz by default all real values are converted to double and it is larger
 than float.ie real nos are not stored accurately inside computer
 memory.so
 since double occupies more memory it prints hi


 On Fri, Aug 5, 2011 at 8:24 PM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 the reason is dat 0.7 is treated as double..therefore double(0.7)
 float(0.7)

 On Fri, Aug 5, 2011 at 8:20 PM, kartik sachan 
 kartik.sac...@gmail.comwrote:

 the output will be hi

 even if u have putted equal to sign there this is becoz 0.7 do not
 exactly stored like 0.7 in a but some thing lesser as describe in ASCII
 format
 that's why it is awlays lesser than 0.7

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 kamakshi...@gmail.com

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[algogeeks] output

2011-08-05 Thread ranjane
# define swap(a,b) temp=a; a=b; b=temp;
main( )
{
int i, j, temp;
i=5;
j=10;
temp=0;
if( i  j)
swap( i, j );
printf( “%d %d %d”, i, j, temp);
}


On compiling i got ans 10, 0, 0.explain..

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Re: [algogeeks] output

2011-08-05 Thread saurabh singh
hint:MACRo is just substituted as it is

On Sat, Aug 6, 2011 at 10:23 AM, ranjane ranjane...@gmail.com wrote:

 # define swap(a,b) temp=a; a=b; b=temp;
 main( )
 {
 int i, j, temp;
 i=5;
 j=10;
 temp=0;
 if( i  j)
 swap( i, j );
 printf( “%d %d %d”, i, j, temp);
 }


 On compiling i got ans 10, 0, 0.explain..

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Re: [algogeeks] output

2011-08-05 Thread saurabh singh
Try compiling with gcc -E filename.c.That will clear everything

On Sat, Aug 6, 2011 at 10:25 AM, saurabh singh saurab...@gmail.com wrote:

 hint:MACRo is just substituted as it is


 On Sat, Aug 6, 2011 at 10:23 AM, ranjane ranjane...@gmail.com wrote:

 # define swap(a,b) temp=a; a=b; b=temp;
 main( )
 {
 int i, j, temp;
 i=5;
 j=10;
 temp=0;
 if( i  j)
 swap( i, j );
 printf( “%d %d %d”, i, j, temp);
 }


 On compiling i got ans 10, 0, 0.explain..

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 MNNIT ALLAHABAD





-- 
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B.Tech (Computer Science)
MNNIT ALLAHABAD

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Re: [algogeeks] output

2011-08-05 Thread loka ranjane
@saurabh:ya got it..thanks

On Sat, Aug 6, 2011 at 10:26 AM, saurabh singh saurab...@gmail.com wrote:
 Try compiling with gcc -E filename.c.That will clear everything

 On Sat, Aug 6, 2011 at 10:25 AM, saurabh singh saurab...@gmail.com wrote:

 hint:MACRo is just substituted as it is

 On Sat, Aug 6, 2011 at 10:23 AM, ranjane ranjane...@gmail.com wrote:

 # define swap(a,b) temp=a; a=b; b=temp;
 main( )
 {
 int i, j, temp;
 i=5;
 j=10;
 temp=0;
 if( i  j)
 swap( i, j );
 printf( “%d %d %d”, i, j, temp);
 }


 On compiling i got ans 10, 0, 0.explain..

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 B.Tech (Computer Science)
 MNNIT ALLAHABAD





 --
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 B.Tech (Computer Science)
 MNNIT ALLAHABAD


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Re: [algogeeks] output

2011-08-05 Thread Pramod Jayswal
when swap is called ,as it is a macro ,before compilation its code is
replaced and the code before compilation bcomes:

 # define swap(a,b) temp=a; a=b; b=temp;
 main( )
 {
 int i, j, temp;
 i=5;
 j=10;
 temp=0;
 if( i  j)

   //code replaced here

 temp=a;   //not executed (false)

   a=b; //a=10(from b=10)
   b=temp;   //b=0 (from temp=0)

 printf( “%d %d %d”, i, j, temp);
 }

 and that is why u get output  10,0,0...



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[algogeeks] OUTPUT PROBLEM

2011-07-30 Thread kartik sachan
#include stdio.h
  void foo(const char **p) { }
  int main(int argc, char **argv)
  {
  foo(argv);
  return 0;
  }

why the above code giving me warning can body explain me??

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Re: [algogeeks] OUTPUT PROBLEM

2011-07-30 Thread Amol Sharma
the warning comes is as

warning: passing argument 1 of ‘foo’ from incompatible pointer type


foo expects a constant char** but it is not the case...hence warning is
displayed...

remove the const keyword.you'll see no warning !!

--


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Computer Science and Engineering
MNNIT Allahabad




On Sat, Jul 30, 2011 at 5:30 PM, kartik sachan kartik.sac...@gmail.comwrote:


 #include stdio.h
   void foo(const char **p) { }
   int main(int argc, char **argv)
   {
   foo(argv);
   return 0;
   }

 why the above code giving me warning can body explain me??

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Re: [algogeeks] OUTPUT PROBLEM

2011-07-30 Thread kartik sachan
*@AMOL *sending a normal pointer to a const pointer doesn't give any warning



why this is giving??

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[algogeeks] Output Help.

2011-07-30 Thread aseem garg
int b=2;b=b++;
b=???

Plz explain..
Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Kamakshii Aggarwal
3.it is same as b=b+1;

On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread aseem garg
@Kamakshi: Run karke dekh leti pehle.  :-/
Aseem



On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 3.it is same as b=b+1;

 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 kamakshi...@gmail.com

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Re: [algogeeks] Output Help.

2011-07-30 Thread aditi garg
it would be undefined...

On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 Kamakshi
 kamakshi...@gmail.com

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NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
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Re: [algogeeks] Output Help.

2011-07-30 Thread Kamakshii Aggarwal
oh sorry,mane galat pad lia..mane sirf b++ dekha...
it is compiler dependent.value of b is changing twice b/w two serial points

On Sun, Jul 31, 2011 at 1:37 AM, aseem garg ase.as...@gmail.com wrote:

 @Kamakshi: Run karke dekh leti pehle.  :-/
 Aseem



 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;

 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread aseem garg
@Aditi: Run karke dekh leti pehle.  :-/
Aseem



On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread vaibhav shukla
concept of sequence points.search wiki

On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Amol Sharma
@aseem output is 3 only...check it once again

http://ideone.com/mWGc5

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On Sun, Jul 31, 2011 at 1:37 AM, aseem garg ase.as...@gmail.com wrote:

 @Kamakshi: Run karke dekh leti pehle.  :-/
 Aseem



 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;

 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread vidushi
@aseem its 3
different on yours ?

On Sun, Jul 31, 2011 at 1:37 AM, aseem garg ase.as...@gmail.com wrote:

 @Kamakshi: Run karke dekh leti pehle.  :-/
 Aseem



 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;

 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Neeraj Gupta
Yes, it's UB.
For such ques, try to run it on ideone.
It will give a warning if any operation is not standard.
http://ideone.com/bJBGl

 http://ideone.com/bJBGl

On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread aseem garg
I am getting 2. .
Aseem



On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta neeraj.gupta...@gmail.comwrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread aseem garg
On Dev CPP.
Aseem



On Sun, Jul 31, 2011 at 1:42 AM, aseem garg ase.as...@gmail.com wrote:

 I am getting 2. .
 Aseem



 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.comwrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Amol Sharma
yup it is undefined and the warning is justified
b=b++ will assign 2 to b then increment b hence 3 is printed
--


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Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta neeraj.gupta...@gmail.comwrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.com wrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 kamakshi...@gmail.com

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Re: [algogeeks] Output Help.

2011-07-30 Thread Sanchit Manchanda
I am getting b=2.
Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
it should be 3.
:-\
No warnings in dev cpp.


On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma amolsharm...@gmail.com wrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.comwrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 kamakshi...@gmail.com

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http://iblogmythots.wordpress.com/

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Re: [algogeeks] Output Help.

2011-07-30 Thread Kamakshii Aggarwal
@sanchit:it is undefined..

On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda sanchit...@gmail.comwrote:

 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
 it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma amolsharm...@gmail.comwrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.comwrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
 aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Sanchit Manchanda
I dint get any error, not even warning. it might depend from compiler to
compiler. but yeah it should be undefined.

On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 @sanchit:it is undefined..


 On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda 
 sanchit...@gmail.comwrote:

 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to me
 it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma amolsharm...@gmail.comwrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta neeraj.gupta...@gmail.com
  wrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
 aditi.garg.6...@gmail.comwrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread gaurav gupta
bt y it sud b undefind?

On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda sanchit...@gmail.comwrote:

 I dint get any error, not even warning. it might depend from compiler to
 compiler. but yeah it should be undefined.


 On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 @sanchit:it is undefined..


 On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda 
 sanchit...@gmail.comwrote:

 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to
 me it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma amolsharm...@gmail.comwrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.com wrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg aditi.garg.6...@gmail.com
  wrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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Re: [algogeeks] Output Help.

2011-07-30 Thread Kamakshii Aggarwal
@gaurav:refer the link below
http://c-faq.com/expr/seqpoints.html

On Sun, Jul 31, 2011 at 1:53 AM, gaurav gupta grvgupta...@gmail.com wrote:

 bt y it sud b undefind?


 On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda 
 sanchit...@gmail.comwrote:

 I dint get any error, not even warning. it might depend from compiler to
 compiler. but yeah it should be undefined.


 On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 @sanchit:it is undefined..


 On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda sanchit...@gmail.com
  wrote:

 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to
 me it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma amolsharm...@gmail.comwrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.com wrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
 aditi.garg.6...@gmail.com wrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 Kamakshi
 kamakshi...@gmail.com

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 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
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Re: [algogeeks] Output Help.

2011-07-30 Thread gaurav gupta
thanx kamakshi

On Sun, Jul 31, 2011 at 1:56 AM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:

 @gaurav:refer the link below
 http://c-faq.com/expr/seqpoints.html


 On Sun, Jul 31, 2011 at 1:53 AM, gaurav gupta grvgupta...@gmail.comwrote:

 bt y it sud b undefind?


 On Sun, Jul 31, 2011 at 1:51 AM, Sanchit Manchanda 
 sanchit...@gmail.comwrote:

 I dint get any error, not even warning. it might depend from compiler to
 compiler. but yeah it should be undefined.


 On Sun, Jul 31, 2011 at 1:49 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 @sanchit:it is undefined..


 On Sun, Jul 31, 2011 at 1:47 AM, Sanchit Manchanda 
 sanchit...@gmail.com wrote:

 I am getting b=2.
 Maybe coz we are assigning 2 to b then incrementing b. But still acc to
 me it should be 3.
 :-\
 No warnings in dev cpp.



 On Sun, Jul 31, 2011 at 1:43 AM, Amol Sharma 
 amolsharm...@gmail.comwrote:

 yup it is undefined and the warning is justified
 b=b++ will assign 2 to b then increment b hence 3 is printed

 --


 Amol Sharma
 Third Year Student
 Computer Science and Engineering
 MNNIT Allahabad




 On Sun, Jul 31, 2011 at 1:41 AM, Neeraj Gupta 
 neeraj.gupta...@gmail.com wrote:

 Yes, it's UB.
 For such ques, try to run it on ideone.
 It will give a warning if any operation is not standard.
 http://ideone.com/bJBGl

  http://ideone.com/bJBGl

 On Sun, Jul 31, 2011 at 1:38 AM, aditi garg 
 aditi.garg.6...@gmail.com wrote:

 it would be undefined...

 On Sun, Jul 31, 2011 at 1:34 AM, Kamakshii Aggarwal 
 kamakshi...@gmail.com wrote:

 3.it is same as b=b+1;


 On Sun, Jul 31, 2011 at 1:32 AM, aseem garg 
 ase.as...@gmail.comwrote:

 int b=2;b=b++;
 b=???

 Plz explain..
 Aseem

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 NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
 Sector 3, Dwarka
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 To 

[algogeeks] OUTPUT

2011-07-27 Thread Kamakshii Aggarwal
#includestdio.h
# define MAXROW 3
#define MAXCOL 4


int main()
{
int (*p)[MAXCOL];
p=(int(*)[MAXCOL])malloc(MAXROW*sizeof(*p));
printf(%d %d,sizeof(p),sizeof(*p));

 system(pause);

  return 0;
}

THE O/P IS 4 16.
I am not getting the reason.plss help

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Re: [algogeeks] OUTPUT

2011-07-27 Thread ramya reddy
The system on which u executed this will allocate 4 bytes for int type.
hence sizeof(p) gives 4 bytes and sizeof(*p) will contain 4 such integer
pointers( int *p[4] is the declaration)  which gives 4*4=16 bytes


Regards
Ramya

*Try to learn something about everything and everything about something*

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Re: [algogeeks] output

2011-07-27 Thread Kamakshii Aggarwal
@magesh:so acc to you the code below should give error?
#includestdio.h

int main(int argc,char *argv[])
{
  char const *s=;
 char str[]=hello;
 s=str;
 while(*s){
   printf(%c,*s++);
   }

 system(pause);

  return 0;
}


On Wed, Jul 27, 2011 at 7:12 PM, mageshthegr...@gmail.com wrote:

 ** Its not a const pointer. It is pointer to constant. So only modifying
 the value of s will cause error. For constant to pointer the const has to be
 between * and the keyword

 Sent from BlackBerry® on Airtel
 --
 *From: * Kamakshii Aggarwal kamakshi...@gmail.com
 *Sender: * algogeeks@googlegroups.com
 *Date: *Wed, 27 Jul 2011 19:09:20 +0530
 *To: *algogeeks@googlegroups.com
 *ReplyTo: * algogeeks@googlegroups.com
 *Subject: *[algogeeks] output

 #includestdio.h

 int main(int argc,char *argv[])
 {
  const char *s=;
  char str[]=hello;
  s=str;
  while(*s){
printf(%c,*s++);
}

  system(pause);

   return 0;
 }
 o/p is hello.
 why the above code is running normally even when constant char pointer is
 being incremented...??plss help...
 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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Re: [algogeeks] output

2011-07-27 Thread Kamakshii Aggarwal
@piyush:thanks...i got my mistake

On Wed, Jul 27, 2011 at 7:30 PM, Piyush Sinha ecstasy.piy...@gmail.comwrote:

 char const *s and const char *s are both same...try using char *const s..it
 will give error then


 On Wed, Jul 27, 2011 at 7:21 PM, Kamakshii Aggarwal kamakshi...@gmail.com
  wrote:

 @magesh:so acc to you the code below should give error?
 #includestdio.h

 int main(int argc,char *argv[])
 {
   char const *s=;
  char str[]=hello;
  s=str;
  while(*s){
printf(%c,*s++);
}

  system(pause);

   return 0;
 }


 On Wed, Jul 27, 2011 at 7:12 PM, mageshthegr...@gmail.com wrote:

 ** Its not a const pointer. It is pointer to constant. So only modifying
 the value of s will cause error. For constant to pointer the const has to be
 between * and the keyword

 Sent from BlackBerry® on Airtel
 --
 *From: * Kamakshii Aggarwal kamakshi...@gmail.com
 *Sender: * algogeeks@googlegroups.com
 *Date: *Wed, 27 Jul 2011 19:09:20 +0530
 *To: *algogeeks@googlegroups.com
 *ReplyTo: * algogeeks@googlegroups.com
 *Subject: *[algogeeks] output

 #includestdio.h

 int main(int argc,char *argv[])
 {
  const char *s=;
  char str[]=hello;
  s=str;
  while(*s){
printf(%c,*s++);
}

  system(pause);

   return 0;
 }
 o/p is hello.
 why the above code is running normally even when constant char pointer is
 being incremented...??plss help...
 --
 Regards,
 Kamakshi
 kamakshi...@gmail.com

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 *+91-7483122727*
 * https://www.facebook.com/profile.php?id=10655377926 NEVER SAY
 NEVER
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Re: [algogeeks] OUTPUT

2011-07-26 Thread kavitha nk
sry sry o/p ll be 0 1 0in the 2nd printf the value ll be evaluated
from rite to left...
so in the 1st printf i's vlue ll be 0 and in the 2nd printf stmt rite
expression is evaluated first and then i value ll be modified in it..
and with hte help of it left one is evaluated...crct me if i'm
wrong..

On 7/26/11, kavitha nk kavithan...@gmail.com wrote:
 ans ll nt be 0 0 2 va???

 On 7/25/11, Puneet Gautam puneet.nsi...@gmail.com wrote:
 @aditi: the %2 in each of these printf statements is redundant coz
 it is 1%2...and % has higher precedence over left or right
 shifts..thats y output of say :

 #includestdio.h
 main()
 {
 int i=1;
 printf(\n%d%d ,i=2,i=1%2);
 return 0;
 }

 is 8 8

 1 gets left shifted twice in i=2, becomes 4
 then i1%2 concludes to i1 as 1%2 is 1 only..
 i1 ,makes i=8 and hence

 8 8 is printed.

 On 7/25/11, Puneet Gautam puneet.nsi...@gmail.com wrote:
 @rajeev: hey...does printf evaluate an expression right to left
 without considering any priority of operators..?
 Pls reply asap..



 On 7/25/11, Puneet Gautam puneet.nsi...@gmail.com wrote:
 @aditi: y dont u try it out urself considering the priorities of
 different operators used here...!!
 that would help...

 On 7/25/11, aditi garg aditi.garg.6...@gmail.com wrote:
 Can u plz elaborate...im not able to understand...

 On Mon, Jul 25, 2011 at 11:04 PM, rajeev bharshetty
 rajeevr...@gmail.comwrote:

 @sameer I think that is right


 On Mon, Jul 25, 2011 at 11:02 PM, sameer.mut...@gmail.com 
 sameer.mut...@gmail.com wrote:

 its because of side effect where value of i is getting changed twice
 in
 a
 single line.
 correct me if i am wrong :)

 *Muthuraj R.
 4TH Year BE.**
 Information Science Dept*
 *PESIT, Bengaluru .
 *




 On Mon, Jul 25, 2011 at 11:01 PM, geek forgeek
 geekhori...@gmail.comwrote:

 y not the output is 3 2  coz on right to left evaluation  of printf
 i
 shud be left shifted by 1 bit wgich shud make it 2 ??


 On Mon, Jul 25, 2011 at 10:28 AM, sameer.mut...@gmail.com 
 sameer.mut...@gmail.com wrote:

 yeah output
  0
 1 1
 *is dis because of side effect? *
 * *
 *
 *
 *Muthuraj R.
 4TH Year BE.**
 Information Science Dept*
 *PESIT, Bengaluru .
 *





 On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan
 deok...@gmail.comwrote:

 run on gcc compiler it would be
 0
 1 1


 On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek
 geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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 *
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Re: [algogeeks] output please

2011-07-25 Thread Arshad Alam
yes I understand, thanks to both of you

On Sun, Jul 24, 2011 at 10:10 PM, rajeev bharshetty rajeevr...@gmail.comwrote:

 value 200 exceeds the char range so -56 , to print 200 try unsigned char .

 On Sun, Jul 24, 2011 at 10:06 PM, Prashant Gupta prashantatn...@gmail.com
  wrote:

 -56


 On Sun, Jul 24, 2011 at 8:15 PM, Arshad Alam alam3...@gmail.com wrote:

 #includestdio.h
 #includeconio.h
 void main()
 {
 char ch=200;
 printf(\n%d,ch);
 getch();
 }

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Re: [algogeeks] output please

2011-07-25 Thread kavitha nk
it is printed in %d format nd not as %ch...

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[algogeeks] OUTPUT

2011-07-25 Thread geek forgeek
1.
#includestdio.h
main()
{
int i=1;
printf(\n%d,i^=1%2);
printf(\n%d %d,i^=1%2,i=1%2);
return 0;
}

output 3 3
hey shudnt the output be 3 2

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Re: [algogeeks] OUTPUT

2011-07-25 Thread Deoki Nandan
run on gcc compiler it would be
0
1 1

On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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*
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Re: [algogeeks] OUTPUT

2011-07-25 Thread aditi garg
@ Deoki : Can u please explain how did dis outcome come?


On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan deok...@gmail.com wrote:

 run on gcc compiler it would be
 0
 1 1


 On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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 *
 *

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Re: [algogeeks] OUTPUT

2011-07-25 Thread rajeev bharshetty
@Deoki Remove the first printf from the program ..
You will get 3 3 . The first printf should be removed .
And about the output as 3 3 it is beacuse of the right to left eval of
printf so i has value 3 after evaluation.

On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan deok...@gmail.com wrote:

 run on gcc compiler it would be
 0
 1 1


 On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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 *
 *

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Re: [algogeeks] OUTPUT

2011-07-25 Thread geek forgeek
ma mistake

code is
#includestdio.h
main()
{
int i=1;
 printf(\n%d %d,i^=1%2,i=1%2);
return 0;
}



On Mon, Jul 25, 2011 at 10:19 AM, Deoki Nandan deok...@gmail.com wrote:

 run on gcc compiler it would be
 0
 1 1

 On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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 *
 *

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Re: [algogeeks] OUTPUT

2011-07-25 Thread sameer.mut...@gmail.com
yeah output
 0
1 1
*is dis because of side effect? *
* *
*
*
*Muthuraj R.
4TH Year BE.**
Information Science Dept*
*PESIT, Bengaluru .
*




On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan deok...@gmail.com wrote:

 run on gcc compiler it would be
 0
 1 1


 On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek geekhori...@gmail.comwrote:

 1.
 #includestdio.h
 main()
 {
 int i=1;
  printf(\n%d,i^=1%2);
  printf(\n%d %d,i^=1%2,i=1%2);
 return 0;
 }

 output 3 3
 hey shudnt the output be 3 2


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 *
 *

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