Re: adding file upload to existing form
How about if you show us your form code. On May 17, 10:55 pm, mike mwu...@gmail.com wrote: hmm... but if I add the input type file, when I call the save method in the action, it tries to persist the object to the database and I get a sql error On May 8, 10:52 pm, Trevor Fitzgerald fitzt...@gmail.com wrote: You can do it by properly setting the encoding type of the form, then creating an input with type of file. On the action page, print_r $_FILES to see if it's working correctly. It should have uploaded the file to /tmp. Then use PHP's move_uploaded_file to put it where you want it. Save the new path and filename in the database. There are quite a few tutorials around for file uploads but hopefully that will point you in the right direction. You won't need to create a separate model or anything. On Fri, May 8, 2009 at 10:26 PM, mike mwu...@gmail.com wrote: I want to add a file upload to an existing form. I want to save the file somewhere in the file system, and maybe save a reference to it in the database. seems simple enough, but all the examples I've found aren't exactly what I want. I don't want to create a whole different model for the file upload. Can someone point me in the right direction. Thanks. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Safari 4 Keeps Logging Me Out....
Which platform? I've been using Safari 4 on Mac OS X (10.4.11) for a month or two now with no issues. I'm using database sessions for both development and production and have yet to be logged out unexpectedly. Which browsers/versions do you have working? On May 17, 2:05 am, Kyle Decot kdec...@gmail.com wrote: I'm not sure if anyone else is experiencing this problem but Safari 4 keeps logging me out. Sometimes it won't do it for almost 10 minutes and then other times it will do it immediately after logging in. Any ideas on how to fix this? I'm using DB for sessions by the way but have tried PHP and cake and am getting the same results. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
My Views Folder can't be detected
I try to create something part by part. When I try to check that part, the message The requested URL was not found on this server. If you entered the URL manually please check your spelling and try again. appeared in my browser.. for example : I create a blog. I save view.thml in /views/posts/. I use xampp 1.6.7. Is my server goes wrong? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Safari 4 Keeps Logging Me Out....
I'm using Mac 10.5.7 I can't remember my app logging me out like this in the past. It just started doing this about a month ago. I'm afraid it's something that I modified, added or deleted from my code but I've changed so much stuff lately, I'm not sure where to begin looking. Any ideas on what I can do to diagnose the problem? On May 17, 10:15 pm, ChicagoPlanesTrains myronhay...@gmail.com wrote: Which platform? I've been using Safari 4 on Mac OS X (10.4.11) for a month or two now with no issues. I'm using database sessions for both development and production and have yet to be logged out unexpectedly. Which browsers/versions do you have working? On May 17, 2:05 am, Kyle Decot kdec...@gmail.com wrote: I'm not sure if anyone else is experiencing this problem but Safari 4 keeps logging me out. Sometimes it won't do it for almost 10 minutes and then other times it will do it immediately after logging in. Any ideas on how to fix this? I'm using DB for sessions by the way but have tried PHP and cake and am getting the same results. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Safari 4 Keeps Logging Me Out....
Oh, I didn't see that you had asked which browsers I had working. I've tested it on the following w/ no problems: Firefox 3 (mac) Camino 1.6 (mac) Safari 3 (mac) On May 18, 2:14 am, Kyle Decot kdec...@gmail.com wrote: I'm using Mac 10.5.7 I can't remember my app logging me out like this in the past. It just started doing this about a month ago. I'm afraid it's something that I modified, added or deleted from my code but I've changed so much stuff lately, I'm not sure where to begin looking. Any ideas on what I can do to diagnose the problem? On May 17, 10:15 pm, ChicagoPlanesTrains myronhay...@gmail.com wrote: Which platform? I've been using Safari 4 on Mac OS X (10.4.11) for a month or two now with no issues. I'm using database sessions for both development and production and have yet to be logged out unexpectedly. Which browsers/versions do you have working? On May 17, 2:05 am, Kyle Decot kdec...@gmail.com wrote: I'm not sure if anyone else is experiencing this problem but Safari 4 keeps logging me out. Sometimes it won't do it for almost 10 minutes and then other times it will do it immediately after logging in. Any ideas on how to fix this? I'm using DB for sessions by the way but have tried PHP and cake and am getting the same results. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Notice (8): Undefined property: CakeErrorController::$js_vars
Notice (8): Undefined property: CakeErrorController::$js_vars [APP/
app_controller.php, line 103]
Code
{
$this-set('meta_for_layout', Configure::read('meta'));
$this-set('js_vars_for_layout', $this-js_vars);
AppController::beforeRender() - APP/app_controller.php, line 103
Controller::render() - CORE/cake/libs/controller/controller.php, line
701
ErrorHandler::__outputMessage() - CORE/cake/libs/error.php, line 377
ErrorHandler::missingController() - CORE/cake/libs/error.php, line 176
Object::dispatchMethod() - CORE/cake/libs/object.php, line 119
ErrorHandler::__construct() - CORE/cake/libs/error.php, line 120
Object::cakeError() - CORE/cake/libs/object.php, line 204
Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 148
require - APP/webroot/index.php, line 90
[main] - APP/index.php, line 25
help please ???
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Re: passing arrays as arguments
CakePHP has the function a, which is an alias of array: http://api.cakephp.org/file/basics.php#function-a Is that along the lines of what you're looking at? On Sun, May 17, 2009 at 8:11 PM, Bysa amin...@gmail.com wrote: On May 17, 8:00 pm, Marcelo Andrade mfandr...@gmail.com wrote: On Sun, May 17, 2009 at 10:46 AM, Bysa amin...@gmail.com wrote: wasn't it a good way to have a small mark for it (like jquery)? for example making array(arg1,arg2) -- _(arg1,arg2)? This is not possible because the _() function already exists and is used to gettext i18n. Best regards. -- MARCELO DE F. ANDRADE Belem, PA, Amazonia, Brazil Linux User #221105 http://mfandrade.wordpress.com thanks for reply but i said that as an example. i know it used, the reason was just to clear my mean. there is a unused and small name in php and cake for sure so that we could use it for array passing, or for example make cake to parse a string like [arg1,arg2], i don't know look on it as an idea am i still wrong? thanks anyway --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: How manage triple relation between Model in CAKEPHP?
I describe you my situation: My model is : Teams, Template and Format The triple relation can be expressed in this way: Each team has access to a set of pairs template-format. A template can be associated with some format. In the table relative to this triple relation I have: id team-id format-id template-id Then I have the models : Team,Format,Template On 16 Mag, 13:54, j0n4s.h4rtm...@googlemail.com j0n4s.h4rtm...@googlemail.com wrote: Like this?: Message HasOne User (From) Message HasOne ToUser (To) Message HasOne CcUser (Copy) In message.php: var $belongsTo = array( 'User' = array( 'className' = 'User', 'foreignKey' = 'user_id', 'conditions' = '', 'fields' = '', 'order' = '' ), 'ToUser' = array( 'className' = 'User', 'foreignKey' = 'reciever_user_id', 'conditions' = '', 'fields' = '', 'order' = '' ), 'CcUser' = array( 'className' = 'User', 'foreignKey' = 'cc_user_id', 'conditions' = '', 'fields' = '', 'order' = '' ) ); Else, maybe polymorphic behavior might help. Not sure what you want to achieve. On May 15, 6:36 pm, byqsri marco.rizze...@gmail.com wrote: I haven't understand . Can you make me and example? Many Thanks On 15 Mag, 17:56, AD7six andydawso...@gmail.com wrote: On May 15, 5:32 pm, marco.rizze...@gmail.com marco.rizze...@gmail.com wrote: Hi I have three model that have a triple relation between them. How can I manage this triple relation between Model in CAKEPHP? via belongsTo, hasMany and a model for each table - the usual way. hth, AD --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Launched a new cake app
Did you use signUpText as a msgid in your language files? I had this previously when using generic labels for language strings, and the corresponding language file for the environment set in the visitors web browser was not available. You can solve this problem by setting the default language - I've got the code to achieve this somewhere - ping me back if you would like it and I'll have a look for it. On Sun, May 17, 2009 at 6:52 PM, Miles J mileswjohn...@gmail.com wrote: @Faza - Yes I do the designs and code :p @Eber - Weird! My friend in austria had the same problem, I wonder how I can fix it. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Running a Controller Function from the Console
Hello, I was just wondering how we can run a function of a controller using the console. Like normal PHP Scripts we can run the scripts using the following syntax: [COMMAND PROMPT] php test.php Thanks, Muhammad Ammad Saleem --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Warning (2): Cannot modify header information - headers already sent by
Check for whitespaces in app_controller and the other controllers.This was caused from copy-paste. Think i may helped! Cheers 2009/5/18 Braydenstyles brayden.sty...@gmail.com Warning (2): Cannot modify header information - headers already sent by (output started at /Users/braydenstyles/Sites/app/ app_controller.php:112) [CORE/cake/libs/controller/controller.php, line 587] Code | Context $status = Location: http://localhost/beta_users/login; header - [internal], line ?? Controller::header() - CORE/cake/libs/controller/controller.php, line 587 Controller::redirect() - CORE/cake/libs/controller/controller.php, line 568 AppController::checkAuth() - APP/app_controller.php, line 269 AppController::beforeFilter() - APP/app_controller.php, line 141 UsersController::beforeFilter() - APP/controllers/ users_controller.php, line 49 Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 228 Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 213 Object::requestAction() - CORE/cake/libs/object.php, line 102 include - APP/views/layouts/default.ctp, line 246 View::_render() - CORE/cake/libs/view/view.php, line 654 View::renderLayout() - CORE/cake/libs/view/view.php, line 451 View::render() - CORE/cake/libs/view/view.php, line 384 Controller::render() - CORE/cake/libs/controller/controller.php, line 744 ErrorHandler::__outputMessage() - CORE/cake/libs/error.php, line 377 ErrorHandler::missingController() - CORE/cake/libs/error.php, line 176 Object::dispatchMethod() - CORE/cake/libs/object.php, line 119 ErrorHandler::__construct() - CORE/cake/libs/error.php, line 120 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: last_login update
Yeah Andy i tried this but still nothing.Dunno what else i have to do.Thx
anyway for your idea!
2009/5/18 andy andy.baugh...@gmail.com
I may be wrong, but I believe '$this-Auth-user()' would look for the
function 'user()' within Auth rather than an array value. Have you
tried '$this-Auth-user['id']' before calling saveField?
On May 17, 5:43 am, paulos nikolo paulitosthe...@gmail.com wrote:
Still nothing Faza.I am wondering if i have to do something else to get
it
work.I think -- if ($this-Auth-user()) doesnt seem to work.If i erase
this line cake save the last_login but in a new row.
2009/5/16 Faza f...@ansi.pl
This is the code I'm using, works 100%.
function login() {
$this-layout = 'login';
if ($this-Auth-user()) {
$this-User-id = $this-Auth-user('id');
$this-User-saveField('last_visit', 'now()');
$gr =
$this-User-Group-findById($this-Auth-user('group_id'));
$this-Session-write('Auth.User.group',
$gr['Group']['name']);
$this-Session-write('Auth.User.password', );
$this-redirect($this-Auth-redirect());
}
}
Paulos23 pisze:
Hi Cake people,
I have spent much time in make this work but nothing.I am using auth
which is working ok and i want to update the last_login field in
users
table.But i can't.Most of my attempts lead to create a new row in
table with an empty user contained the updated field.I have read all
of the previous posts here but nothing help me.Can you tell me if I
do something wrong.Here i put my code:
app_controller:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-loginAction = array('controller' =
'users',
'action'
= 'login');
$this-Auth-logoutRedirect = array('controller' =
'users',
'action' = 'login');
$this-Auth-loginRedirect = array('controller' =
'users',
'action'
= 'index');
$this-Auth-loginError=__('Invalid username or
password',true);
$this-Auth-authorize='controller';
}
function isAuthorized(){
return true;
}
}
users_controller: login action
function login() {
$this-layout ='user_login';
if ( $this-Auth-user() ) {
$user = $this-Auth-user();
$this-User-id =
$this-Auth-user('id');
//$user['User']['last_login'] = date ( 'Y-m-d
H:i:s' );
$this-User-saveField('last_login',
date('Y-m-d
H:i:s'));
//$this-User-save('$user');
//$this-User-last_login =
date(Y-m-d H:i:s);
}
}
When i have if ( $this-Auth-user() ) {
$user = $this-Auth-user();
in my code nothing happened.If i comment it then the new row will be
added.
Any help would be so nice!
ty in advance,Paulos
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Router params problem
// routes.php
Router::connect('/:productType/:category/:season',
array('controller' = 'products', 'action' = 'index', 'season'
= null),
array('pass' = array('productType', 'category', 'season')));
// view:
echo $html-link('', array('controller' = 'products', 'action'
= 'index','productType' = $productType, 'category' =
$category));
// result:
a href=/Anvelope Noi/Scutere/:season/
// desired result:
a href=/Anvelope Noi/Scutere/
I need desired result, instead i get result ? Why is that ?
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Strange cakePHP
hi guys... a view days ago as far as i know, my code ran well
i try to set a variable in custom app_controller class
$this-set('Auth',$this-Auth-user());
i did this because i plan to use that variable in views.
mybe like print_r($Auth)
now my code display warning that says..
*Notice* (8) javascript:void(0);: Undefined variable: Auth
[*APP\views\users\login.ctp*, line *3*]
does anyone know how to solve this problem?
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---
I Don't Know Who/What I Am Yet, But I Know Who/What I Am Not!
--
Marojahan M.T. Sigiro
maroja...@gmail.com
GTalk : marojahan
Y! : ojak_s
http://ojakaja.com
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2 before_filter function
hi all,, what i have to do, so both my before_filter function that found in xxx_controller and app_controller executed? -- --- I Don't Know Who/What I Am Yet, But I Know Who/What I Am Not! -- Marojahan M.T. Sigiro maroja...@gmail.com GTalk : marojahan Y! : ojak_s http://ojakaja.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: passing arrays as arguments
argh i think yes it is. i wonder why i didnt seen anyone use it when they were passing the argument, and used the array() instead. thanks for show me this. On May 18, 11:53 am, Richard rclay...@gmail.com wrote: CakePHP has the function a, which is an alias of array:http://api.cakephp.org/file/basics.php#function-a Is that along the lines of what you're looking at? On Sun, May 17, 2009 at 8:11 PM, Bysa amin...@gmail.com wrote: On May 17, 8:00 pm, Marcelo Andrade mfandr...@gmail.com wrote: On Sun, May 17, 2009 at 10:46 AM, Bysa amin...@gmail.com wrote: wasn't it a good way to have a small mark for it (like jquery)? for example making array(arg1,arg2) -- _(arg1,arg2)? This is not possible because the _() function already exists and is used to gettext i18n. Best regards. -- MARCELO DE F. ANDRADE Belem, PA, Amazonia, Brazil Linux User #221105 http://mfandrade.wordpress.com thanks for reply but i said that as an example. i know it used, the reason was just to clear my mean. there is a unused and small name in php and cake for sure so that we could use it for array passing, or for example make cake to parse a string like [arg1,arg2], i don't know look on it as an idea am i still wrong? thanks anyway --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: 2 before_filter function
Hello Marojahan, Monday, May 18, 2009, 12:11:02 PM, you wrote: what i have to do, so both my before_filter function that found in xxx_controller and app_controller executed? Put parent::beforeFilter(); in your WhateverController beforeFilter method, then the beforeFilter of AppController is called. -- Paul --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Not fully understanding associations. Id showing instead of name.
Yes it's a varchar and I utilised bake, I've got it working now by setting recursive to 2 and amending the views to use the other models field, I just wondered if there was a more efficient way of doing it as I should imagine it is a common thing to do, but if not, not to worry - thanks for the replies! On May 16, 12:59 pm, j0n4s.h4rtm...@googlemail.com j0n4s.h4rtm...@googlemail.com wrote: Is the name field a varchar255 not null or tinytext? Try using cake bake to create your starting environment and work from there On May 15, 5:38 pm, number9 xpozit...@gmail.com wrote: Actually I tried displayfield earlier when I was searching, but it didn't work, presumably because: The model will use name or title, by default. and I am trying to output name (so it should be doing that anyway). On May 15, 4:33 pm, number9 xpozit...@gmail.com wrote: OK, so I tried setting recursive to two again (didn't work earlier) and it worked! Is there a better method to do this for future reference as it seems to place a bit of a load of the database... On May 15, 4:12 pm, number9 xpozit...@gmail.com wrote: Hi all, Apologies for this newbish question, I've searched for hours trying to resolve this with no joy so would appreciate it if you could point me in the right direction. I'm trying to setup a simple website (my first cakephp project, having become OKish at PHP/MYSQL). Basically there are three models so far, posts, categories and sites (all of the databases follow cake naming conventions, with id as PK, name and _id for FKs. Posts belong to categories. Posts also belong to sites. Categories, and sites have one post. I have used cake bake to generate the controllers and views. /posts/ works great, and it shows everything by name, the add works great in terms of the relationships. The problem I am having is, when I go to /categories/, it brings up posts under that category and the category and site are showing up as numbers rather than name (in the view they are category_id, and site_id). I can get the category name to show up OK (because I think that table is mapped). What I don't understand is why the name is not showing in place of the _id like everwhere else. How can I output database fields in another model. It is probably something really simple, but I'm getting used to the cake way of thinking. Is it that the relationship is wrong? The query at the bottom shows the names are being selected. Thanks in advance --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
httpsocket and xml
Hi people, I am wonder if there is an example of using httpsocket and xml.In my app i want to have a page with a search textfield (and search button) as well as a page with the results which i receive in XML format.In particular i want to put a destination (town,country) and from this site http://www.geonames.org/export/ws-overview.html i want to take the xml results and appear them in my results page.As it is sensible i want to parse the receiver xml results. Any help woulb be nice! Paulos --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: last_login update
If you print_r($this-Auth), what keys/values are included in the
array?
On May 18, 4:09 am, paulos nikolo paulitosthe...@gmail.com wrote:
Yeah Andy i tried this but still nothing.Dunno what else i have to do.Thx
anyway for your idea!
2009/5/18 andy andy.baugh...@gmail.com
I may be wrong, but I believe '$this-Auth-user()' would look for the
function 'user()' within Auth rather than an array value. Have you
tried '$this-Auth-user['id']' before calling saveField?
On May 17, 5:43 am, paulos nikolo paulitosthe...@gmail.com wrote:
Still nothing Faza.I am wondering if i have to do something else to get
it
work.I think -- if ($this-Auth-user()) doesnt seem to work.If i erase
this line cake save the last_login but in a new row.
2009/5/16 Faza f...@ansi.pl
This is the code I'm using, works 100%.
function login() {
$this-layout = 'login';
if ($this-Auth-user()) {
$this-User-id = $this-Auth-user('id');
$this-User-saveField('last_visit', 'now()');
$gr =
$this-User-Group-findById($this-Auth-user('group_id'));
$this-Session-write('Auth.User.group',
$gr['Group']['name']);
$this-Session-write('Auth.User.password', );
$this-redirect($this-Auth-redirect());
}
}
Paulos23 pisze:
Hi Cake people,
I have spent much time in make this work but nothing.I am using auth
which is working ok and i want to update the last_login field in
users
table.But i can't.Most of my attempts lead to create a new row in
table with an empty user contained the updated field.I have read all
of the previous posts here but nothing help me.Can you tell me if I
do something wrong.Here i put my code:
app_controller:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-loginAction = array('controller' =
'users',
'action'
= 'login');
$this-Auth-logoutRedirect = array('controller' =
'users',
'action' = 'login');
$this-Auth-loginRedirect = array('controller' =
'users',
'action'
= 'index');
$this-Auth-loginError=__('Invalid username or
password',true);
$this-Auth-authorize='controller';
}
function isAuthorized(){
return true;
}
}
users_controller: login action
function login() {
$this-layout ='user_login';
if ( $this-Auth-user() ) {
$user = $this-Auth-user();
$this-User-id =
$this-Auth-user('id');
//$user['User']['last_login'] = date ( 'Y-m-d
H:i:s' );
$this-User-saveField('last_login',
date('Y-m-d
H:i:s'));
//$this-User-save('$user');
//$this-User-last_login =
date(Y-m-d H:i:s);
}
}
When i have if ( $this-Auth-user() ) {
$user = $this-Auth-user();
in my code nothing happened.If i comment it then the new row will be
added.
Any help would be so nice!
ty in advance,Paulos
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Re: Strange cakePHP
Hey,
if you want to use Auth info in your views it is very simple.
Try this in your view: pr($session-read('Auth.User')); //assuming User is
your login model, otherwise try pr($session-read('Auth'));
Hope you find this handy,
Faifas
On Mon, May 18, 2009 at 12:59, Marojahan M.T. Sigiro maroja...@gmail.comwrote:
hi guys... a view days ago as far as i know, my code ran well
i try to set a variable in custom app_controller class
$this-set('Auth',$this-Auth-user());
i did this because i plan to use that variable in views.
mybe like print_r($Auth)
now my code display warning that says..
*Notice* (8): Undefined variable: Auth [*APP\views\users\login.ctp*, line *3*]
does anyone know how to solve this problem?
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GTalk : marojahan
Y! : ojak_s
http://ojakaja.com
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Re: My Views Folder can't be detected
in cakephp the view has extension .ctp.. you should put the view in /view/posts/view.ctp On Mon, May 18, 2009 at 5:26 AM, eantz eantz.z...@gmail.com wrote: I try to create something part by part. When I try to check that part, the message The requested URL was not found on this server. If you entered the URL manually please check your spelling and try again. appeared in my browser.. for example : I create a blog. I save view.thml in /views/posts/. I use xampp 1.6.7. Is my server goes wrong? -- pietro --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Poll: what do you hate about CakePHP?
Hey,
actually the most annoying thing is that we cannot download separate parts
of Cake. It would be cool if advanced users could choose what do they need
for their project, just like mootools made in their download page. I
certainly understand that this is just *wishful thinking* because Cake's
core uses nearly everything :x
Anyway, upload component would be totally usable!
Also, switching from scriptaculous + prototype to jQuery would be awesome.
People would create and share plugins, which means that our lovely community
would become even bigger and ADmad would be even more mad (sorry AD :x)
Enjoy,
Faifas
On Sat, May 16, 2009 at 06:00, Brendon Kozlowski brendon...@hotmail.comwrote:
Thought of another one.
Paginate settings, and paginate call. Why do they have the same
name? When learning how Cake works, although it's proper OOP to do
so, it's a bit confusing to see:
$this-paginate = array('contain' = 'User');
$this-set('posts', $this-paginate());
I think it would be clearer (from a name the variable what it is
type of coding style) to use something like:
$this-paginateOptions = array('contain' = 'User');
Every time I see $this-paginate when skimming through code, I
immediately see the method, completely forgetting it's also a
property. I hate that. ;)
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Re: last_login update
it prints this AuthComponent Object ( [_loggedIn] = [components] = Array ( [0] = Session [1] = RequestHandler ) [authenticate] = [authorize] = controller [ajaxLogin] = [userModel] = User [userScope] = Array ( ) [fields] = Array ( [username] = username [password] = password ) [sessionKey] = Auth.User [actionPath] = [loginAction] = Array ( [controller] = users [action] = login ) [loginRedirect] = Array ( [controller] = users [action] = index ) [logoutRedirect] = Array ( [controller] = users [action] = login ) [object] = [loginError] = Invalid username or password [authError] = You are not authorized to access that location. [autoRedirect] = 1 [allowedActions] = Array ( [0] = display [1] = index [2] = add ) [actionMap] = Array ( [index] = read [add] = create [edit] = update [view] = read [remove] = delete [create] = create [read] = read [update] = update [delete] = delete ) [data] = [params] = Array ( [pass] = Array ( ) [named] = Array ( ) [controller] = users [action] = login [plugin] = [form] = Array ( ) [url] = Array ( [url] = users/login ) ) [_methods] = Array ( [1] = index [2] = view [3] = add [4] = delete [5] = edit [6] = change_status [7] = login [8] = logout ) [_log] = [enabled] = 1 [Session] = SessionComponent Object ( [__active] = 1 [__started] = 1 [__bare] = 0 [valid] = 1 [error] = [_userAgent] = 99eaa36d863fae669cb83f33c1ad01af [path] = /my_cake/index.php [lastError] = [security] = high [time] = 1242649223 [sessionTime] = 1242649233 [watchKeys] = Array ( ) [id] = [_log] = [host] = localhost [enabled] = 1 [cookieLifeTime] = 0 ) [RequestHandler] = RequestHandlerComponent Object ( [ajaxLayout] = ajax [enabled] = 1 [__responseTypeSet] = [params] = Array ( ) [__requestContent] = Array ( [javascript] = text/javascript [js] = text/javascript [json] = application/json [css] = text/css [html] = Array ( [0] = text/html [1] = */* ) [text] = text/plain [txt] = text/plain [csv] = Array ( [0] = application/vnd.ms-excel [1] = text/plain ) [form] = application/x-www-form-urlencoded [file] = multipart/form-data [xhtml] = Array ( [0] = application/xhtml+xml [1] = application/xhtml [2] = text/xhtml ) [xhtml-mobile] = application/vnd.wap.xhtml+xml [xml] = Array ( [0] = application/xml [1] = text/xml ) [rss] = application/rss+xml [atom] = application/atom+xml [amf] = application/x-amf [wap] = Array ( [0] = text/vnd.wap.wml [1] = text/vnd.wap.wmlscript [2] = image/vnd.wap.wbmp ) [wml] = text/vnd.wap.wml [wmlscript] = text/vnd.wap.wmlscript [wbmp] = image/vnd.wap.wbmp [pdf] = application/pdf [zip] = application/x-zip [tar] = application/x-tar ) [__acceptTypes] = Array ( [0] = text/html [1] =
Re: Poll: what do you hate about CakePHP?
What about create a true poll for it?
First create a poll for all suggestions, after create a poll to vote on that
suggestions and voilá =)
Henrique Machado
2009/5/18 Aivaras faifas1...@gmail.com
Hey,
actually the most annoying thing is that we cannot download separate parts
of Cake. It would be cool if advanced users could choose what do they need
for their project, just like mootools made in their download page. I
certainly understand that this is just *wishful thinking* because Cake's
core uses nearly everything :x
Anyway, upload component would be totally usable!
Also, switching from scriptaculous + prototype to jQuery would be awesome.
People would create and share plugins, which means that our lovely community
would become even bigger and ADmad would be even more mad (sorry AD :x)
Enjoy,
Faifas
On Sat, May 16, 2009 at 06:00, Brendon Kozlowski
brendon...@hotmail.comwrote:
Thought of another one.
Paginate settings, and paginate call. Why do they have the same
name? When learning how Cake works, although it's proper OOP to do
so, it's a bit confusing to see:
$this-paginate = array('contain' = 'User');
$this-set('posts', $this-paginate());
I think it would be clearer (from a name the variable what it is
type of coding style) to use something like:
$this-paginateOptions = array('contain' = 'User');
Every time I see $this-paginate when skimming through code, I
immediately see the method, completely forgetting it's also a
property. I hate that. ;)
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Embed image in HTML mail tgrought Email component
Hello! How can I embed image in HTML mail send trough Email component? Regards Andraž --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Auth-logout() doesn't logout a user?
Hello,
I have a debug code that prints out values of
$this-Auth-user('id')
$this-Auth-user('name')
inside a controller's beforeRender().
When I login, it shows that I'm logged in as a person.
However, when I logout, it shows that I'm still logged in as the
person I was logged in.
This only happens with users who are not in the admin group.
I think I'm making very novice mistake here with login/out
implementation.
Can someone help me or suggest what could have gone wrong in my
implementation?
Thanks
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Re: retrieving data from another table
What name are you trying to get? Looks like you have Style.name
already available in your result.
If there is a Gender.name you are trying to see you can set the
recursive to a higher number before the find:
$this-Style-recursive = 2;
Or use the Containable behavior as mentioned above.
On May 17, 5:22 pm, justclint justcl...@gmail.com wrote:
Im pulling the data successfully but Im trying to get the name value
as opposed to the id value in a separate table.
When I do debug I get this:
(
[Product] = Array
(
[id] = 21
[color_id] = 3
[image_thumb] = aw_ls_black.png
[price] = 27.95
[shipping_price] = 5.00
[style_id] = 1
)
[Style] = Array
(
[id] = 1
[name] = All Weather Longsleeve Compression Shirt
[gender_id] = 2
[category_id] = 2
[material_id] = 2
[application_id] = 2
For sake of example I will just reference the gender_id. I need it to
show the name not the id.
I have the following tables/models.
Products
Styles
Genders
Product Model:
class Product extends AppModel {
var $name = 'Product';
var $belongsTo = array(
'Style' = array(
'className' = 'Style',
'foreignKey' = 'style_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
);
}
Styles Model:
class Style extends AppModel {
var $name = 'Style';
var $belongsTo = array(
'Gender' = array(
'className' = 'Gender',
'foreignKey' = 'gender_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Category' = array(
'className' = 'Category',
'foreignKey' = 'category_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Material' = array(
'className' = 'Material',
'foreignKey' = 'material_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Application' = array(
'className' = 'Application',
'foreignKey' = 'application_id',
'conditions' = '',
'fields' = '',
'order' = ''
)
);
}
Gender Model:
var $name = 'Gender';
var $hasMany = array(
'Style' = array(
'className' = 'Style',
'foreignKey' = 'gender_id',
'dependent' = false,
'conditions' = '',
'fields' = '',
'order' = '',
'limit' = '',
'offset' = '',
'exclusive' = '',
'finderQuery' = '',
'counterQuery' = ''
)
);
}
?
The page im trying to get this on is my product view page. Action
looks like this:
function view($id = null) {
if (!$id) {
$this-Session-setFlash(__('Invalid Product.',
true));
$this-redirect(array('action'='index'));
}
$this-set('product', $this-Product-read(null, $id));
}
Ive been playing with this for hours and I just cant seem to get it.
If you need more info, please dont hesitate to ask.
Your help is greatly appreciated.
Thanks!
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Re: Auth-logout() doesn't logout a user?
nvm.
I found what I did wrong.
I forgot to allow 'logout'.
Also, for my ACL tables, it let admin to do anything, whereas other
users were limited.
Problem solved :)
On May 18, 6:17 am, Brian Lee brianleeu...@gmail.com wrote:
Hello,
I have a debug code that prints out values of
$this-Auth-user('id')
$this-Auth-user('name')
inside a controller's beforeRender().
When I login, it shows that I'm logged in as a person.
However, when I logout, it shows that I'm still logged in as the
person I was logged in.
This only happens with users who are not in the admin group.
I think I'm making very novice mistake here with login/out
implementation.
Can someone help me or suggest what could have gone wrong in my
implementation?
Thanks
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TreeBehaviour questions
I am using the tree behaviour in conjunction with the jQuery tree at www.jstree.com to create a admin interface for a forum that allows multiple and unlimited subforums. It is working quite well. The only problem is that jstree doesn't tell you how far a node has been moved, but rather gives a reference node and tells you if the item was moved after, before or inside the reference node (Inside meaning it is now a subnode, after meaning that it moved upwards and before meaning downwards). My problem is how do I calculate the distance between two nodes (With the same parent id) if I only know what the two nodes are? Currently I am calculating the difference in lft values between the nodes, but it does not always give correct values. So, what is the recommended method for calculating the distance between two nodes in a MPTT tree? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: TreeBehaviour questions
On May 18, 4:12 pm, Walther waltherl...@gmail.com wrote:
I am using the tree behaviour in conjunction with the jQuery tree
atwww.jstree.comto create a admin interface for a forum that allows
multiple and unlimited subforums.
It is working quite well.
The only problem is that jstree doesn't tell you how far a node has
been moved, but rather gives a reference node and tells you if the
item was moved after, before or inside the reference node (Inside
meaning it is now a subnode, after meaning that it moved upwards and
before meaning downwards).
My problem is how do I calculate the distance between two nodes (With
the same parent id) if I only know what the two nodes are? Currently I
am calculating the difference in lft values between the nodes, but it
does not always give correct values.
the lft and rght values alone do not give you the info you're looking
for.
So, what is the recommended method for calculating the distance
between two nodes in a MPTT tree?
$difference = $Model-find('count', array('conditions' = array
('parent_id' = $thisone, 'lft BETWEEN' = array($first['lft'], $last
['lft'])));
style.
hth,
AD
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CAKEPHP UNDEFINED VARIABLE
Hello, I get an error undefined variable $left_content. This variable has been defined in beforeFilter() of app_controller.php. In beforeFilter(), the code is: $this-set(left_content,$left_content); Somehow the variable is not passed on to the view files.. Any clues?? Thanks, Bharani _ Hotmail® goes with you. http://windowslive.com/Tutorial/Hotmail/Mobile?ocid=TXT_TAGLM_WL_HM_Tutorial_Mobile1_052009 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: need to show debug only if admin - Configure::write('debug', 3); only if admin logged in
Try reversing it. debug:3 in the core and turn it off beforeRender if
you're NOT admin.
On May 17, 4:41 pm, JamesF usaexportexpe...@gmail.com wrote:
hello all, i love cakephp's built in table that shows the sql queries
that are running. my site is now live but i need a way to check under
the hood without disrupting my users.
here is what i put in the beforeRender function of my app_controller:
function beforeRender(){
if ($this-Auth-user('role') == 'admin'){
Configure::write('debug', 2);
} else {
//
}
i have Configure::write('debug', 0) set in my core.php
now this pulls up that sql table thing at the bottom of the screen but
it is EMPTY. it says (default) 0 query took ms.
anyone have a solution?
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Re: Safari 4 Keeps Logging Me Out....
What is Session.checkAgent set to in your app/config/core.php? If it's true, try setting it to false. I believe this has helped with random log-out. Not sure if these were browser specific, but it might just do the trick. Good luck! Any ideas on what I can do to diagnose the problem? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
'or' in paginate() where clause?
Hi all,
Is it possible use 'or' in the conditions resulting from a call to
paginate? I have tried a whole load of variations (based on conditions
that work in a call to find('all'), but to no avail.
Thanks in advance,
Toby
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Re: 'or' in paginate() where clause?
On May 18, 5:26 pm, toby1kenobi toby.math...@gmail.com wrote:
Hi all,
Is it possible use 'or' in the conditions resulting from a call to
paginate?
resulting? How are you getting paginate to give you conditions.
I have tried a whole load of variations (based on conditions
that work in a call to find('all'), but to no avail.
like what.
AD
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Re: 'or' in paginate() where clause?
Thanks for the quick response! I was just about to follow up that post
and say that it's almost working, but not quite (and maybe the error
is mine).
Here's (a slightly simplified version of) my code:
$findParams = array(
'or' = array(
'MyItem.parent_content_item_id' = $myId,
'MyParentItem.id' = $anotherId,
'MyParentItem.id' = $yetAnotherId
));
$myItems = $this-paginate(null, $findParams);
This is returning results that satisfy the first and third 'or'
conditions, but not the second one ('MyParentItem.id' = $anotherId).
Am I missing something daft?
Toby
On May 18, 4:28 pm, AD7six andydawso...@gmail.com wrote:
On May 18, 5:26 pm, toby1kenobi toby.math...@gmail.com wrote:
Hi all,
Is it possible use 'or' in the conditions resulting from a call to
paginate?
resulting? How are you getting paginate to give you conditions.
I have tried a whole load of variations (based on conditions
that work in a call to find('all'), but to no avail.
like what.
AD
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Re: CAKEPHP UNDEFINED VARIABLE
Hello, 1. NO NEED TO WRITE LIKE THIS IN THE SUBJECT 2. Are you overriding your beforeFilter() in your other controllers? If true, are you calling parent::beforeFilter()? If not, do it now. 3. If step no.2 didn't help, did you try calling debug($this- viewVars) in your view to see what's going on there? On May 18, 4:41 pm, lakers fan lakersfa...@msn.com wrote: Hello, I get an error undefined variable $left_content. This variable has been defined in beforeFilter() of app_controller.php. In beforeFilter(), the code is: $this-set(left_content,$left_content); Somehow the variable is not passed on to the view files.. Any clues?? Thanks, Bharani _ Hotmail® goes with you.http://windowslive.com/Tutorial/Hotmail/Mobile?ocid=TXT_TAGLM_WL_HM_T... --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: TreeBehaviour questions
I think I might have just found a bug, or the condition is not
formated correctly.
CakePHP doesn't handle the between operator correctly (Converts it to
`lft BETWEEN` IN ('19', '1') instead of `lft` BETWEEN` '19' AND '1').
On May 18, 4:37 pm, AD7six andydawso...@gmail.com wrote:
On May 18, 4:12 pm, Walther waltherl...@gmail.com wrote:
I am using the tree behaviour in conjunction with the jQuery tree
atwww.jstree.comtocreate a admin interface for a forum that allows
multiple and unlimited subforums.
It is working quite well.
The only problem is that jstree doesn't tell you how far a node has
been moved, but rather gives a reference node and tells you if the
item was moved after, before or inside the reference node (Inside
meaning it is now a subnode, after meaning that it moved upwards and
before meaning downwards).
My problem is how do I calculate the distance between two nodes (With
the same parent id) if I only know what the two nodes are? Currently I
am calculating the difference in lft values between the nodes, but it
does not always give correct values.
the lft and rght values alone do not give you the info you're looking
for.
So, what is the recommended method for calculating the distance
between two nodes in a MPTT tree?
$difference = $Model-find('count', array('conditions' = array
('parent_id' = $thisone, 'lft BETWEEN' = array($first['lft'], $last
['lft'])));
style.
hth,
AD
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Re: TreeBehaviour questions
Nope, no bug.
To use between you type BETWEEN ? AND ? and not just BETWEEN.
Thanks for the help AD7six!
On May 18, 5:44 pm, Walther waltherl...@gmail.com wrote:
I think I might have just found a bug, or the condition is not
formated correctly.
CakePHP doesn't handle the between operator correctly (Converts it to
`lft BETWEEN` IN ('19', '1') instead of `lft` BETWEEN` '19' AND '1').
On May 18, 4:37 pm, AD7six andydawso...@gmail.com wrote:
On May 18, 4:12 pm, Walther waltherl...@gmail.com wrote:
I am using the tree behaviour in conjunction with the jQuery tree
atwww.jstree.comtocreatea admin interface for a forum that allows
multiple and unlimited subforums.
It is working quite well.
The only problem is that jstree doesn't tell you how far a node has
been moved, but rather gives a reference node and tells you if the
item was moved after, before or inside the reference node (Inside
meaning it is now a subnode, after meaning that it moved upwards and
before meaning downwards).
My problem is how do I calculate the distance between two nodes (With
the same parent id) if I only know what the two nodes are? Currently I
am calculating the difference in lft values between the nodes, but it
does not always give correct values.
the lft and rght values alone do not give you the info you're looking
for.
So, what is the recommended method for calculating the distance
between two nodes in a MPTT tree?
$difference = $Model-find('count', array('conditions' = array
('parent_id' = $thisone, 'lft BETWEEN' = array($first['lft'], $last
['lft'])));
style.
hth,
AD
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Re: Poll: what do you hate about CakePHP?
Here's another interesting kick in the Matt Groening.
Inability to use FormHelper::error() to show our own errors on the
fly, i.e. $form-error('Arse.biscuits', 'A pair of women's knickers is
missing'); regardless of whether I'm using a model to create a form or
not.
Workaround:
$form-validationErrors['Arse']['biscuits'] = 'Dancing like a mad
eejit is not an allowed action';
echo $form-error('Arse.biscuits');
But why?? Form error should be looking for an validation error message
only if I didn't provide one as a param. Am I the only one who finds
that logical?
On May 18, 2:27 pm, Henrique Machado henri@gmail.com wrote:
What about create a true poll for it?
First create a poll for all suggestions, after create a poll to vote on that
suggestions and voilá =)
Henrique Machado
2009/5/18 Aivaras faifas1...@gmail.com
Hey,
actually the most annoying thing is that we cannot download separate parts
of Cake. It would be cool if advanced users could choose what do they need
for their project, just like mootools made in their download page. I
certainly understand that this is just *wishful thinking* because Cake's
core uses nearly everything :x
Anyway, upload component would be totally usable!
Also, switching from scriptaculous + prototype to jQuery would be awesome.
People would create and share plugins, which means that our lovely community
would become even bigger and ADmad would be even more mad (sorry AD :x)
Enjoy,
Faifas
On Sat, May 16, 2009 at 06:00, Brendon Kozlowski
brendon...@hotmail.comwrote:
Thought of another one.
Paginate settings, and paginate call. Why do they have the same
name? When learning how Cake works, although it's proper OOP to do
so, it's a bit confusing to see:
$this-paginate = array('contain' = 'User');
$this-set('posts', $this-paginate());
I think it would be clearer (from a name the variable what it is
type of coding style) to use something like:
$this-paginateOptions = array('contain' = 'User');
Every time I see $this-paginate when skimming through code, I
immediately see the method, completely forgetting it's also a
property. I hate that. ;)
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Installation Problem: CakePHP 1.2.3.8166 on CENTOS and database.php
Hello all, I'm having a little trouble with a particular installation of cake (1.2.3.8166) I have it running fine on my windows machine but on my Centos machine I get a strange error when renaming the database.php.sample to database.php The messages appear but the wrapper and any associated bits an pieces fail to load (including the validity of the db connection), no errors in the logs - I'm stumped. Anyone else has this problem? Cheers Joel --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
PHP array for use in javascript
Hej all! I've been trying to find a solution for this, and maybe I'm approaching it wrong. This is the case: For my site I need make graphs out of data in a table. I have picked JQuery FLOT for making the graphs. However, FLOT needs data in a jQuery array build like: [[xaxis, yaxis] [xaxis, yaxis] [xaxis, yaxis]]; and then calls the plot graph function in FLOT to build it. These functions (With the array currently hardcoded) are in my project in a seperate .js file I load in my view. However, When I get into my controller and get the relevant data, and pass it to the view using Cake's Set, how can I get that (PHP)array converted and passed to the javascript (.js file) that builds the graph? Has anybody any expierience or idea's with this? And if there are graphing libraries that allow for on-the-fly graphs from a database, that work better with Cake, please tell me! Now it's not to late to switch! Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Custom php.ini and .htaccess
Hi guys!
I using a custom php configuration on dreamhost and works fine with
standalone php files.
But i can't get it working with cakephp(Cakephp works fine without the
custom php.ini but i need it to increase te max upload size)
The thing is when i try to use the custom config with mod_rewrite I get
a internal error.
in my .htaccess i have:
---
IfModule mod_rewrite.c
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php?url=$1 [QSA,L]
/IfModule
Options ExecCGI
AddHandler php5-cgi .php
Action php5-cgi /php5/php5.cgi
---
And the errors is:
--
Internal Server Error
The server encountered an internal error or misconfiguration and was
unable to complete your request.
Please contact the server administrator, webmas...@domain.com and inform
them of the time the error occurred, and anything you might have done
that may have caused the error.
More information about this error may be available in the server error log.
Additionally, a 500 Internal Server Error error was encountered while
trying to use an ErrorDocument to handle the request.
--
And in the log get:
--
Request exceeded the limit of 10 internal redirects due to probable
configuration error. Use 'LimitInternalRecursion' to increase the limit
if necessary. Use 'LogLevel debug' to get a backtrace.
--
Probably is an error in the .htaccess config, but I can't solved it...
any ideas?
Thanks a lot and sorry by mi english...
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Update related model data
Hi, Before I start: creating a user with an email gives no problem, but updating a user, gives a validation error: 'email left blank'. I have this array and I want to save the updated data Array ( [User] = Array ( [firstname] = data[User][firstname] [lastname] = data[User][lastname] [address] = data[User][address] [zip_code] = dat [city] = data[User][city] [country_id] = 149 [gender] = 2 [age] = 55 ) [Email] = Array ( [0] = Array ( [email] = vin...@zonnet.nl ) ) ) I do the following things to update it: $this-User-read(null, $this-authUser['User']['id']); $this-User-Email-save($this-data) $this-User-save($this- data); I couldn't even get saveAll method to work well. The user saves well, but the email gives a validation error, that it is empty (cannot be left blank). The relationship is as follows: user has many emails. What am I doing wrong? Cake thinks, the email is left blank, but in fact it isn't. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: need to show debug only if admin - Configure::write('debug', 3); only if admin logged in
That might be undesirable since any notices or errors before
beforeRender will be in his output.
@JamesF:
Did you put the if-clause at the top of beforeFilter or at the bottom?
Your if will return false if Auth has not had a chance to do it's
thing. Check that you did NOT put it before Auth initializes.
(you will probably be missing the user table slq in your output in
this case but the rest should be there)
On May 18, 4:53 pm, nurvzy nur...@gmail.com wrote:
Try reversing it. debug:3 in the core and turn it off beforeRender if
you're NOT admin.
On May 17, 4:41 pm, JamesF usaexportexpe...@gmail.com wrote:
hello all, i love cakephp's built in table that shows the sql queries
that are running. my site is now live but i need a way to check under
the hood without disrupting my users.
here is what i put in the beforeRender function of my app_controller:
function beforeRender(){
if ($this-Auth-user('role') == 'admin'){
Configure::write('debug', 2);
} else {
//
}
i have Configure::write('debug', 0) set in my core.php
now this pulls up that sql table thing at the bottom of the screen but
it is EMPTY. it says (default) 0 query took ms.
anyone have a solution?
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Re: CAKEPHP UNDEFINED VARIABLE
It's the underscores that are doing it; this has bitten me before.
Have a look at the source for Controller::set().
Try:
$this-set(compact('left_content'), false);
This is essentially the same as doing:
$this-set(array('left_content' = $left_content), false);
By passing in an array as the first param and also using a dummy param
in 2nd place, you aoid having Inflector munge your variable name.
On Mon, May 18, 2009 at 10:41 AM, lakers fan lakersfa...@msn.com wrote:
Hello,
I get an error undefined variable $left_content. This variable has been
defined in beforeFilter() of app_controller.php. In beforeFilter(), the code
is:
$this-set(left_content,$left_content);
Somehow the variable is not passed on to the view files.. Any clues??
Thanks,
Bharani
Hotmail® goes with you. Get it on your BlackBerry or iPhone.
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Re: Router params problem
Maybe it's because you're not passing 'season' to $html-link(), even
if null. Because it's defined in the route, I'll bet that the reverse
routing is thrown off when it's missing from the link creation.
On Mon, May 18, 2009 at 5:38 AM, Bogdan I. Bursuc
bogdanbursu...@gmail.com wrote:
// routes.php
Router::connect('/:productType/:category/:season',
array('controller' = 'products', 'action' = 'index', 'season'
= null),
array('pass' = array('productType', 'category', 'season')));
// view:
echo $html-link('', array('controller' = 'products', 'action'
= 'index','productType' = $productType, 'category' =
$category));
// result:
a href=/Anvelope Noi/Scutere/:season/
// desired result:
a href=/Anvelope Noi/Scutere/
I need desired result, instead i get result ? Why is that ?
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Re: PHP array for use in javascript
Hi, Try looking at JavascriptHelper::object() http://api.cakephp.org/class/javascript-helper#method-JavascriptHelperobject It will help you render a javascript object of any data you have in php. ...or just parse out your data to a string yourself and set it as a javascript variable. (= use php to dynamically create a hard-coded javascript array) On May 18, 6:10 pm, Céryl c.a.h.wilt...@student.tue.nl wrote: Hej all! I've been trying to find a solution for this, and maybe I'm approaching it wrong. This is the case: For my site I need make graphs out of data in a table. I have picked JQuery FLOT for making the graphs. However, FLOT needs data in a jQuery array build like: [[xaxis, yaxis] [xaxis, yaxis] [xaxis, yaxis]]; and then calls the plot graph function in FLOT to build it. These functions (With the array currently hardcoded) are in my project in a seperate .js file I load in my view. However, When I get into my controller and get the relevant data, and pass it to the view using Cake's Set, how can I get that (PHP)array converted and passed to the javascript (.js file) that builds the graph? Has anybody any expierience or idea's with this? And if there are graphing libraries that allow for on-the-fly graphs from a database, that work better with Cake, please tell me! Now it's not to late to switch! Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Forcing user to access her data only
So, here is how my application works: 1. I have users (just like any other apps) 2. I have courses that each user can create Upon login, user will view the list of courses that she created. I got that to work. However, now the problem is, I don't know the simple, neat way to block user from accessing classes that she did not create. For instance, Bob created courses that have IDs of 1, 2, 3. Jane has courses with IDs of 4, 5, 6. How do I stop Bob from doing something like localhost/courses/view/4 (trying to view Jane's course)? and prevent Jane from doing the same for Bob's courses? I am sure that there is very neat way to do it, because this is a problem often comes up when developing web applications. I just want to know the CakePHP way of doing this. Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: PHP array for use in javascript
You could use the JavascriptHelper to create the array, or any other block of JS code. On Mon, May 18, 2009 at 12:10 PM, Céryl c.a.h.wilt...@student.tue.nl wrote: Hej all! I've been trying to find a solution for this, and maybe I'm approaching it wrong. This is the case: For my site I need make graphs out of data in a table. I have picked JQuery FLOT for making the graphs. However, FLOT needs data in a jQuery array build like: [[xaxis, yaxis] [xaxis, yaxis] [xaxis, yaxis]]; and then calls the plot graph function in FLOT to build it. These functions (With the array currently hardcoded) are in my project in a seperate .js file I load in my view. However, When I get into my controller and get the relevant data, and pass it to the view using Cake's Set, how can I get that (PHP)array converted and passed to the javascript (.js file) that builds the graph? Has anybody any expierience or idea's with this? And if there are graphing libraries that allow for on-the-fly graphs from a database, that work better with Cake, please tell me! Now it's not to late to switch! Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Forcing user to access her data only
You can either use ACL or, simpler, just check the User.id when
fetching the courses. You can either fetch the course by ID, then
check its user_id matches $this-Auth-user('id') (if you're using
Auth). Or, use find() instead of read() and add another condition:
'Course.id' = $id,
'Course.user_id' = $this-Auth-user('id')
On Mon, May 18, 2009 at 1:03 PM, Brian Lee brianleeu...@gmail.com wrote:
So, here is how my application works:
1. I have users (just like any other apps)
2. I have courses that each user can create
Upon login, user will view the list of courses that she created.
I got that to work.
However, now the problem is, I don't know the simple, neat way to
block user from accessing classes that she did not create. For
instance, Bob created courses that have IDs of 1, 2, 3. Jane has
courses with IDs of 4, 5, 6. How do I stop Bob from doing something
like localhost/courses/view/4 (trying to view Jane's course)? and
prevent Jane from doing the same for Bob's courses?
I am sure that there is very neat way to do it, because this is a
problem often comes up when developing web applications. I just want
to know the CakePHP way of doing this.
Thanks!
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Re: Forcing user to access her data only
Hi Brian, i assume that each course have an user_id right? so when you
list, edit or view the courses just use a condition to search all the
courses of the current user... ex:
$cond = array('Course.user_id' = $Current_user_id);
$this-set('courses', $this-paginate('Course', $cond));
Brian Lee escribió:
So, here is how my application works:
1. I have users (just like any other apps)
2. I have courses that each user can create
Upon login, user will view the list of courses that she created.
I got that to work.
However, now the problem is, I don't know the simple, neat way to
block user from accessing classes that she did not create. For
instance, Bob created courses that have IDs of 1, 2, 3. Jane has
courses with IDs of 4, 5, 6. How do I stop Bob from doing something
like localhost/courses/view/4 (trying to view Jane's course)? and
prevent Jane from doing the same for Bob's courses?
I am sure that there is very neat way to do it, because this is a
problem often comes up when developing web applications. I just want
to know the CakePHP way of doing this.
Thanks!
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Re: Running a Controller Function from the Console
requestAction should work. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: httpsocket and xml
What have you tried? There a re several examples in the test cases. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
TreeBehaviour Scope
Hi there How does the TreeBehaviour scope work? I imagine that it is meant to allow seperating of trees according to a certain external entity, and thereby allow you to have more then one tree inside a single table. But, it does not look like that is in fact what it is doing. How do you go about creating more then one tree in a single table? In my case I have Categories and Forums. Categories have many forums, and forums can have many nested children forums. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: httpsocket and xml
I didnt try anything yetbut i want some example code to help me start if you know any 2009/5/18 Gwoo gwoo.cake...@gmail.com What have you tried? There a re several examples in the test cases. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: need to show debug only if admin - Configure::write('debug', 3); only if admin logged in
@Martin
even if i remove the conditional and set Configure::write('debug', 2)
in beforeFilter on its own...still no sql is shown. says
(default) 0 query took ms
On May 18, 12:22 pm, Martin Westin martin.westin...@gmail.com wrote:
That might be undesirable since any notices or errors before
beforeRender will be in his output.
@JamesF:
Did you put the if-clause at the top of beforeFilter or at the bottom?
Your if will return false if Auth has not had a chance to do it's
thing. Check that you did NOT put it before Auth initializes.
(you will probably be missing the user table slq in your output in
this case but the rest should be there)
On May 18, 4:53 pm, nurvzy nur...@gmail.com wrote:
Try reversing it. debug:3 in the core and turn it off beforeRender if
you're NOT admin.
On May 17, 4:41 pm, JamesF usaexportexpe...@gmail.com wrote:
hello all, i love cakephp's built in table that shows the sql queries
that are running. my site is now live but i need a way to check under
the hood without disrupting my users.
here is what i put in the beforeRender function of my app_controller:
function beforeRender(){
if ($this-Auth-user('role') == 'admin'){
Configure::write('debug', 2);
} else {
//
}
i have Configure::write('debug', 0) set in my core.php
now this pulls up that sql table thing at the bottom of the screen but
it is EMPTY. it says (default) 0 query took ms.
anyone have a solution?
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Re: retrieving data from another table
Hey Faza and Rick thanks for your reply. Yes, I am trying to get
Gender.name. So what Im trying to do is get my array to show up
something like:
[Product] = Array
(
[id] = 21
[color_id] = 3
[image_thumb] = aw_ls_black.png
[price] = 27.95
[shipping_price] = 5.00
[style_id] = 1
)
[Style] = Array
(
[id] = 1
[name] = All Weather Longsleeve Compression Shirt
[Gender] = Array
(
[gender_id] = 2
[gender_name] = Men
)
[category_id] = 2
[material_id] = 2
[application_id] = 2
*Notice the sub array Gender under Style array
I tried doing the $this-Style-recursive = 1; and $this-Product-
Style-recursive = 1; in my products_controller as shown below but
still not getting the correct results.
function view($id = null) {
if (!$id) {
$this-Session-setFlash(__('Invalid Product.', true));
$this-redirect(array('action'='index'));
}
$this-Style-recursive = 1;
$this-set('product', $this-Product-read(null, $id));
}
And in my product/view Ive tried echo $product['Gender']['name']
$product['Style']['Gender.name'] but obviously its showing as an
unrecognized variable.
Im reading up on the containable right now as I've never used that
behavior before.
Any additional help would be great. Thanks guys!
On May 18, 6:19 am, Rick will...@gmail.com wrote:
What name are you trying to get? Looks like you have Style.name
already available in your result.
If there is a Gender.name you are trying to see you can set the
recursive to a higher number before the find:
$this-Style-recursive = 2;
Or use the Containable behavior as mentioned above.
On May 17, 5:22 pm, justclint justcl...@gmail.com wrote:
Im pulling the data successfully but Im trying to get the name value
as opposed to the id value in a separate table.
When I do debug I get this:
(
[Product] = Array
(
[id] = 21
[color_id] = 3
[image_thumb] = aw_ls_black.png
[price] = 27.95
[shipping_price] = 5.00
[style_id] = 1
)
[Style] = Array
(
[id] = 1
[name] = All Weather Longsleeve Compression Shirt
[gender_id] = 2
[category_id] = 2
[material_id] = 2
[application_id] = 2
For sake of example I will just reference the gender_id. I need it to
show the name not the id.
I have the following tables/models.
Products
Styles
Genders
Product Model:
class Product extends AppModel {
var $name = 'Product';
var $belongsTo = array(
'Style' = array(
'className' = 'Style',
'foreignKey' = 'style_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
);
}
Styles Model:
class Style extends AppModel {
var $name = 'Style';
var $belongsTo = array(
'Gender' = array(
'className' = 'Gender',
'foreignKey' = 'gender_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Category' = array(
'className' = 'Category',
'foreignKey' = 'category_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Material' = array(
'className' = 'Material',
'foreignKey' = 'material_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Application' = array(
'className' = 'Application',
'foreignKey' = 'application_id',
'conditions' = '',
'fields' = '',
'order' = ''
)
);
}
Gender Model:
var $name = 'Gender';
var $hasMany = array(
'Style' = array(
'className' = 'Style',
'foreignKey' = 'gender_id',
'dependent' = false,
'conditions' = '',
'fields' = '',
'order' = '',
'limit' = '',
'offset' = '',
Re: Forcing user to access her data only
But how does this prevent user from accessing a random course?
such as typing localhost/courses/view/123
and hoping to see what he gets for course_id 123.
I know that paginate would restrict what I would like to list;
however, that does not prevent the user from typing the actual url to
access (add, view, delete) the course with some random course number
that he/she did not create.
On May 18, 10:18 am, Gabriel A. Gonzalez gabriel...@gmail.com
wrote:
Hi Brian, i assume that each course have an user_id right? so when you
list, edit or view the courses just use a condition to search all the
courses of the current user... ex:
$cond = array('Course.user_id' = $Current_user_id);
$this-set('courses', $this-paginate('Course', $cond));
Brian Lee escribió:
So, here is how my application works:
1. I have users (just like any other apps)
2. I have courses that each user can create
Upon login, user will view the list of courses that she created.
I got that to work.
However, now the problem is, I don't know the simple, neat way to
block user from accessing classes that she did not create. For
instance, Bob created courses that have IDs of 1, 2, 3. Jane has
courses with IDs of 4, 5, 6. How do I stop Bob from doing something
like localhost/courses/view/4 (trying to view Jane's course)? and
prevent Jane from doing the same for Bob's courses?
I am sure that there is very neat way to do it, because this is a
problem often comes up when developing web applications. I just want
to know the CakePHP way of doing this.
Thanks!
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Re: Forcing user to access her data only
never mind. I get it!
Thanks!
On May 18, 12:05 pm, Brian Lee brianleeu...@gmail.com wrote:
But how does this prevent user from accessing a random course?
such as typing localhost/courses/view/123
and hoping to see what he gets for course_id 123.
I know that paginate would restrict what I would like to list;
however, that does not prevent the user from typing the actual url to
access (add, view, delete) the course with some random course number
that he/she did not create.
On May 18, 10:18 am, Gabriel A. Gonzalez gabriel...@gmail.com
wrote:
Hi Brian, i assume that each course have an user_id right? so when you
list, edit or view the courses just use a condition to search all the
courses of the current user... ex:
$cond = array('Course.user_id' = $Current_user_id);
$this-set('courses', $this-paginate('Course', $cond));
Brian Lee escribió:
So, here is how my application works:
1. I have users (just like any other apps)
2. I have courses that each user can create
Upon login, user will view the list of courses that she created.
I got that to work.
However, now the problem is, I don't know the simple, neat way to
block user from accessing classes that she did not create. For
instance, Bob created courses that have IDs of 1, 2, 3. Jane has
courses with IDs of 4, 5, 6. How do I stop Bob from doing something
like localhost/courses/view/4 (trying to view Jane's course)? and
prevent Jane from doing the same for Bob's courses?
I am sure that there is very neat way to do it, because this is a
problem often comes up when developing web applications. I just want
to know the CakePHP way of doing this.
Thanks!
--~--~-~--~~~---~--~~
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Re: Safari 4 Keeps Logging Me Out....
Awesome! I set it to false an it fixed the problem. Thanks so much! On May 18, 11:03 am, ChicagoPlanesTrains myronhay...@gmail.com wrote: What is Session.checkAgent set to in your app/config/core.php? If it's true, try setting it to false. I believe this has helped with random log-out. Not sure if these were browser specific, but it might just do the trick. Good luck! Any ideas on what I can do to diagnose the problem? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
link TO an image
I'm stuck trying to construct a URL using the html helper that points
to an jpeg sitting in an 'uploads' folder in my webroot folder. I've
tried the following.
$html-link($html-image('/uploads/main_demo.jpg'), array($html-url('/
uploads/main_zoom.jpg', true)), array('title' = 'hello', 'escape' =
false, 'class' = 'mg_main'));
However, this creates the following URL which is obviously broken.
http://mysite/photos/mediagallery/http://mysite/uploads/main_zoom.jpg
When I remove the 'true' option from the $html-url statement I get
this which is also wrong.
http://mysite/photos/mediagallery/uploads/main_zoom.jpg
And then I also noticed that when I go to the following url, Cake asks
for a controller which is of course missing.
http://mysite/uploads/main_zoom.jpg
So how can I just point the browser to this image?
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Syntax errors running console script on production server
I have a working app that runs with no errors on my local machine.
When I upload it to my production server (DreamHost) the app works
fine in the browser, but I have a shell script that I run through the
console that gives me errors on the production server.
The errors I'm getting seem to have to do with class object syntax.
For example - this function declaration in my shell file:
private function _checkRules($text, $author_type, $rules) {
Produces this error
Parse error: syntax error, unexpected T_STRING, expecting
T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /home/jasford/
feedmagnet.com/app/vendors/shells/import.php on line 72
but if I remove the word private from the front of the line it does
not return a syntax error.
Does anyone have any idea what could be going on here? I'm running PHP
5.2.9 locally (Entropy release 7) and PHP 5.2.6 on the remote server.
- Jason
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Datetime difference
Hej all! Since my good advice just ago, I got to another bottleneck. I have a form in which the user selects two times (a start- and an end- time). The form works perfectly and the times get stored in the table as hh:mm:ss. However, I have a 3th row in the database that must hold the elapsed time between the two form-inputted times. I want the computer to calculate this. I figured I must do this in in the controller, I can of course even do after the $this-Model-save() action with a saveField, just before the redirect. However, I cannot seem to find a good example of making that function. I'm not sure how i get my timestamp back from the form, if they are simply substractable and how to store it back in the table. If it makes matters easier, elapsed time can be stored as an integer holding seconds between times in the table, I can probably calculate those back in elapsed minutes/hours in a later view of the table. Any idea's or links to examples of working with Timestamps? It always boggles me! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: How create a unique ACL for multiples apps?
Hi Celso, perhaps I could be wrong, but i think this: GLOBAL DATABASE User Group Aro APP DATABASE aco aros_acos In APP-Model file, the var $useTable is useful. will it work? On 14 maio, 14:38, Celso cels...@gmail.com wrote: How create a unique ACL for multiples apps? Because we have many apps to migrate to CakePHP, these apps actually uses a unique ugly auth for all apps... Thanks, Celso --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: PHP array for use in javascript
Worked almost a charm... Still, I ended up writing a this codeblock to
manually make-up the output the way I want it:
$i=0;
$output = [;
foreach($data as $key=$val){
if ($i != 0) {$output .= , ;}
$output .= [.$key., .$val.];
$i++;
}
$output .= ];
echo $output;
It makes the array look like the string [[x,y],[x,y]...[x,y]] whith
which I used Codeblock to generate the javaCode. Thanks all!
On 18 mei, 19:08, brian bally.z...@gmail.com wrote:
You could use the JavascriptHelper to create the array, or any other
block of JS code.
On Mon, May 18, 2009 at 12:10 PM, Céryl c.a.h.wilt...@student.tue.nl wrote:
Hej all!
I've been trying to find a solution for this, and maybe I'm
approaching it wrong. This is the case:
For my site I need make graphs out of data in a table. I have picked
JQuery FLOT for making the graphs. However, FLOT needs data in a
jQuery array build like:
[[xaxis, yaxis]
[xaxis, yaxis]
[xaxis, yaxis]];
and then calls the plot graph function in FLOT to build it. These
functions (With the array currently hardcoded) are in my project in a
seperate .js file I load in my view.
However, When I get into my controller and get the relevant data, and
pass it to the view using Cake's Set, how can I get that (PHP)array
converted and passed to the javascript (.js file) that builds the
graph?
Has anybody any expierience or idea's with this? And if there are
graphing libraries that allow for on-the-fly graphs from a database,
that work better with Cake, please tell me! Now it's not to late to
switch!
Thanks!
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Re: link TO an image
Do you have a route beginning with 'uploads'? You could just construct
a regular img tag link (ie. without the helper), seeing as you want
to avoid any controllers that Router might think you're pointing to.
On Mon, May 18, 2009 at 3:50 PM, foldiman vi...@vinceallen.com wrote:
I'm stuck trying to construct a URL using the html helper that points
to an jpeg sitting in an 'uploads' folder in my webroot folder. I've
tried the following.
$html-link($html-image('/uploads/main_demo.jpg'), array($html-url('/
uploads/main_zoom.jpg', true)), array('title' = 'hello', 'escape' =
false, 'class' = 'mg_main'));
However, this creates the following URL which is obviously broken.
http://mysite/photos/mediagallery/http://mysite/uploads/main_zoom.jpg
When I remove the 'true' option from the $html-url statement I get
this which is also wrong.
http://mysite/photos/mediagallery/uploads/main_zoom.jpg
And then I also noticed that when I go to the following url, Cake asks
for a controller which is of course missing.
http://mysite/uploads/main_zoom.jpg
So how can I just point the browser to this image?
--~--~-~--~~~---~--~~
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Re: link TO an image
Are you placing the folder upload somewhere in the webroot folder?
If not, you would want to create your upload folder in the webroot
folder. If they are images getting uploaded you might make a folder
structure like:
webroot/img/photos/mediagallery/uploads/
Then your image helper would look something like:
$html-link($html-image('photos/mediagallery/uploads/main_demo.jpg'),
array($html-url('
photos/mediagallery/uploads/main_zoom.jpg')), array('title' =
'hello', 'escape' =
false, 'class' = 'mg_main'));
Hope this helps.
On May 18, 12:50 pm, foldiman vi...@vinceallen.com wrote:
I'm stuck trying to construct a URL using the html helper that points
to an jpeg sitting in an 'uploads' folder in my webroot folder. I've
tried the following.
$html-link($html-image('/uploads/main_demo.jpg'), array($html-url('/
uploads/main_zoom.jpg', true)), array('title' = 'hello', 'escape' =
false, 'class' = 'mg_main'));
However, this creates the following URL which is obviously broken.
http://mysite/photos/mediagallery/http://mysite/uploads/main_zoom.jpg
When I remove the 'true' option from the $html-url statement I get
this which is also wrong.
http://mysite/photos/mediagallery/uploads/main_zoom.jpg
And then I also noticed that when I go to the following url, Cake asks
for a controller which is of course missing.
http://mysite/uploads/main_zoom.jpg
So how can I just point the browser to this image?
--~--~-~--~~~---~--~~
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Re: api.cakephp.org still broken
On Sun, May 17, 2009 at 8:59 PM, Mr-Yellow meisteryel...@gmail.com wrote: They might be, I'm an asshole for sure :-) No need to explain. We get it. Thing is I wasn't the person who decided I wanted to work for fame and recognition. I'm on the cash side of things rather then the open- source side of things, I realise open source people do it for different reasons, but really that's their problem. I can't be held responsible for their being no cash to motivate movement on fixes. So, what are you doing using open source code? BTW, how quickly did MS fix all those problems with IE6? Oh, that's right--they never bothered. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
returning or exiting from methods of controllers
In methods of controllers, there are usually many checks for doing the right thing. For instance, I check if user is accessing the right data. However, I'm wondering what is the best way to return or exit from these methods when errors do occur. I've been using just simple return statement, but is there anything that's more CakePHP-like and follow the framework's design? or is simple return/exit statement good enough? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Syntax errors running console script on production server
I've found a few other posts where people are having similar problems,
but all of them seem to be solving their problems by realizing that
they are running PHP4 on the production server. In my case, I am
definitely running PHP5 - and I don't have any errors using Cake
classes and methods through the browser interface. The issue only
surfaces when I'm running my shell script. In fact - one of my models
is being used by the shell script and a few standard controllers and
it is only throwing an error when run through the shell script.
- Jason
On May 18, 3:15 pm, Jason jasf...@gmail.com wrote:
I have a working app that runs with no errors on my local machine.
When I upload it to my production server (DreamHost) the app works
fine in the browser, but I have a shell script that I run through the
console that gives me errors on the production server.
The errors I'm getting seem to have to do with class object syntax.
For example - this function declaration in my shell file:
private function _checkRules($text, $author_type, $rules) {
Produces this error
Parse error: syntax error, unexpected T_STRING, expecting
T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /home/jasford/
feedmagnet.com/app/vendors/shells/import.php on line 72
but if I remove the word private from the front of the line it does
not return a syntax error.
Does anyone have any idea what could be going on here? I'm running PHP
5.2.9 locally (Entropy release 7) and PHP 5.2.6 on the remote server.
- Jason
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Re: Warning (2): Cannot modify header information - headers already sent by
thanks will search for the white spaces.. cheers B On May 18, 2:04 am, paulos nikolo paulitosthe...@gmail.com wrote: Check for whitespaces in app_controller and the other controllers.This was caused from copy-paste. Think i may helped! Cheers 2009/5/18 Braydenstyles brayden.sty...@gmail.com Warning (2): Cannot modify header information - headers already sent by (output started at /Users/braydenstyles/Sites/app/ app_controller.php:112) [CORE/cake/libs/controller/controller.php, line 587] Code | Context $status = Location:http://localhost/beta_users/login; header - [internal], line ?? Controller::header() - CORE/cake/libs/controller/controller.php, line 587 Controller::redirect() - CORE/cake/libs/controller/controller.php, line 568 AppController::checkAuth() - APP/app_controller.php, line 269 AppController::beforeFilter() - APP/app_controller.php, line 141 UsersController::beforeFilter() - APP/controllers/ users_controller.php, line 49 Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 228 Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 213 Object::requestAction() - CORE/cake/libs/object.php, line 102 include - APP/views/layouts/default.ctp, line 246 View::_render() - CORE/cake/libs/view/view.php, line 654 View::renderLayout() - CORE/cake/libs/view/view.php, line 451 View::render() - CORE/cake/libs/view/view.php, line 384 Controller::render() - CORE/cake/libs/controller/controller.php, line 744 ErrorHandler::__outputMessage() - CORE/cake/libs/error.php, line 377 ErrorHandler::missingController() - CORE/cake/libs/error.php, line 176 Object::dispatchMethod() - CORE/cake/libs/object.php, line 119 ErrorHandler::__construct() - CORE/cake/libs/error.php, line 120 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Datetime difference
You could calculate the time difference on the fly with mysql TIMEDIFF function [http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_timediff] instead of store it in the db And this [http://www.gidnetwork.com/b-16.html] may help to store the time difference. Céryl escribió: Hej all! Since my good advice just ago, I got to another bottleneck. I have a form in which the user selects two times (a start- and an end- time). The form works perfectly and the times get stored in the table as hh:mm:ss. However, I have a 3th row in the database that must hold the elapsed time between the two form-inputted times. I want the computer to calculate this. I figured I must do this in in the controller, I can of course even do after the $this-Model-save() action with a saveField, just before the redirect. However, I cannot seem to find a good example of making that function. I'm not sure how i get my timestamp back from the form, if they are simply substractable and how to store it back in the table. If it makes matters easier, elapsed time can be stored as an integer holding seconds between times in the table, I can probably calculate those back in elapsed minutes/hours in a later view of the table. Any idea's or links to examples of working with Timestamps? It always boggles me! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Content Categorization with CakePHP ?
Hey. I am pretty confused with CakePHP's Tree, I actually do not have a clue how to categorize my content with tree. I tried a few ways, almost did it, but still having trouble with it. Maybe someone could write a tutorial or link me to a tutorial outside cakePHP's bakery. Thankyou. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: retrieving data from another table
Ok, im not sure what I was doing wrong but it was just as simple as
you mentioned. I just added $this-Product-recursive = 2; and viola,
everything was fetched properly.
Thanks a million!
On May 18, 11:55 am, justclint justcl...@gmail.com wrote:
Hey Faza and Rick thanks for your reply. Yes, I am trying to get
Gender.name. So what Im trying to do is get my array to show up
something like:
[Product] = Array
(
[id] = 21
[color_id] = 3
[image_thumb] = aw_ls_black.png
[price] = 27.95
[shipping_price] = 5.00
[style_id] = 1
)
[Style] = Array
(
[id] = 1
[name] = All Weather Longsleeve Compression Shirt
[Gender] = Array
(
[gender_id] = 2
[gender_name] = Men
)
[category_id] = 2
[material_id] = 2
[application_id] = 2
*Notice the sub array Gender under Style array
I tried doing the $this-Style-recursive = 1; and
$this-Product-Style-recursive = 1; in my products_controller as shown
below but
still not getting the correct results.
function view($id = null) {
if (!$id) {
$this-Session-setFlash(__('Invalid Product.',
true));
$this-redirect(array('action'='index'));
}
$this-Style-recursive = 1;
$this-set('product', $this-Product-read(null, $id));
}
And in my product/view Ive tried echo $product['Gender']['name']
$product['Style']['Gender.name'] but obviously its showing as an
unrecognized variable.
Im reading up on the containable right now as I've never used that
behavior before.
Any additional help would be great. Thanks guys!
On May 18, 6:19 am, Rick will...@gmail.com wrote:
What name are you trying to get? Looks like you have Style.name
already available in your result.
If there is a Gender.name you are trying to see you can set the
recursive to a higher number before the find:
$this-Style-recursive = 2;
Or use the Containable behavior as mentioned above.
On May 17, 5:22 pm, justclint justcl...@gmail.com wrote:
Im pulling the data successfully but Im trying to get the name value
as opposed to the id value in a separate table.
When I do debug I get this:
(
[Product] = Array
(
[id] = 21
[color_id] = 3
[image_thumb] = aw_ls_black.png
[price] = 27.95
[shipping_price] = 5.00
[style_id] = 1
)
[Style] = Array
(
[id] = 1
[name] = All Weather Longsleeve Compression Shirt
[gender_id] = 2
[category_id] = 2
[material_id] = 2
[application_id] = 2
For sake of example I will just reference the gender_id. I need it to
show the name not the id.
I have the following tables/models.
Products
Styles
Genders
Product Model:
class Product extends AppModel {
var $name = 'Product';
var $belongsTo = array(
'Style' = array(
'className' = 'Style',
'foreignKey' = 'style_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
);
}
Styles Model:
class Style extends AppModel {
var $name = 'Style';
var $belongsTo = array(
'Gender' = array(
'className' = 'Gender',
'foreignKey' = 'gender_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Category' = array(
'className' = 'Category',
'foreignKey' = 'category_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Material' = array(
'className' = 'Material',
'foreignKey' = 'material_id',
'conditions' = '',
'fields' = '',
'order' = ''
),
'Application' = array(
'className' = 'Application',
'foreignKey' = 'application_id',
'conditions' = '',
'fields' = '',
'order' = ''
)
);
}
Gender Model:
var $name = 'Gender';
var $hasMany = array(
'Style' =
Re: Poll: what do you hate about CakePHP?
You are definitely right indeed.
Faifas
On Mon, May 18, 2009 at 18:54, dr. Hannibal Lecter lecter...@gmail.comwrote:
Here's another interesting kick in the Matt Groening.
Inability to use FormHelper::error() to show our own errors on the
fly, i.e. $form-error('Arse.biscuits', 'A pair of women's knickers is
missing'); regardless of whether I'm using a model to create a form or
not.
Workaround:
$form-validationErrors['Arse']['biscuits'] = 'Dancing like a mad
eejit is not an allowed action';
echo $form-error('Arse.biscuits');
But why?? Form error should be looking for an validation error message
only if I didn't provide one as a param. Am I the only one who finds
that logical?
On May 18, 2:27 pm, Henrique Machado henri@gmail.com wrote:
What about create a true poll for it?
First create a poll for all suggestions, after create a poll to vote on
that
suggestions and voilá =)
Henrique Machado
2009/5/18 Aivaras faifas1...@gmail.com
Hey,
actually the most annoying thing is that we cannot download separate
parts
of Cake. It would be cool if advanced users could choose what do they
need
for their project, just like mootools made in their download page. I
certainly understand that this is just *wishful thinking* because
Cake's
core uses nearly everything :x
Anyway, upload component would be totally usable!
Also, switching from scriptaculous + prototype to jQuery would be
awesome.
People would create and share plugins, which means that our lovely
community
would become even bigger and ADmad would be even more mad (sorry AD :x)
Enjoy,
Faifas
On Sat, May 16, 2009 at 06:00, Brendon Kozlowski
brendon...@hotmail.comwrote:
Thought of another one.
Paginate settings, and paginate call. Why do they have the same
name? When learning how Cake works, although it's proper OOP to do
so, it's a bit confusing to see:
$this-paginate = array('contain' = 'User');
$this-set('posts', $this-paginate());
I think it would be clearer (from a name the variable what it is
type of coding style) to use something like:
$this-paginateOptions = array('contain' = 'User');
Every time I see $this-paginate when skimming through code, I
immediately see the method, completely forgetting it's also a
property. I hate that. ;)
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Re: Content Categorization with CakePHP ?
On Mon, May 18, 2009 at 4:52 PM, the...@gmail.com the...@gmail.com wrote: Hey. I am pretty confused with CakePHP's Tree, I actually do not have a clue how to categorize my content with tree. I tried a few ways, almost did it, but still having trouble with it. Maybe someone could write a tutorial or link me to a tutorial outside cakePHP's bakery. Thankyou. Maybe you could explain what kind of data you have, along with at least a *hint* of what you want to do. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Installing CakePHP to mediatemple(dv) issue
Check your apache2 setup has mod_rewrite installed and your directory permissions. If you still have trouble with MT Centos setup I'd suggest asking the MT framework forum as a number of people use Cake on DV. http://wiltonsoftware.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
saveAll Edit - Creates instead of Updating even with passed IDs
This passes the ID for the Promotion properly but not for the
associated title and body:
-
$this-Promotion-id = $id; // Set the IDs so we update rows instead
of creating new ones.
$current = $this-Promotion-find('first', array('conditions' = array
('Promotion.id' = $id),'fields' = array('title_id','body_id')));
$this-Promotion-Title-id = $current['Promotion']['title_id'];
$this-Promotion-Body-id = $current['Promotion']['body_id'];
-
Any ideas?
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Submit/Cancel problem
So, I added a submit and a cancel button to my ajax form and it doesn't matter which you press, it always returns the submit button, not the cancel. The view code has this at the bottom (I stopped using helpers to see if raw HTML would help, it didn't): input name=Submit value=submit type=submit input name=Cancel value=cancel type=submit In the controller (admin_edit) function, I'm dumping out the contents of $this-params['form'] and it always shows Array ( [Submit] = submit ) Even if you press the cancel button. Am I doing something wrong? Thanks! Nancy --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Routing oddities
Hello,
I'm having some problems with my routing, let's go straight to
business:
When accessing this url: http://localhost/somecompany/home
1. With route setup:
Router::connect('/:company/:controller/*');
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*', array(), array
('company' = '[A-Z][a-z][0-9]'));
Result:
Fails, get's routed to /app/controllers/somecompany_controller.php
Question:
Why it fails when I set regexp check to the company parameter?
When accessing this url: http://localhost/somecompany/
1. With route setup:
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*');
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Fails, get's routed to /app/controllers/controller.php
Question:
Why it doesn't take the second route and find to home controller?
Thanks!
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Re: need to show debug only if admin - Configure::write('debug', 3); only if admin logged in
i think what this issue is coming down to is me working off an alias
of my live site and keeping that in debug modethis is probably for
the best since my site is live now and i shouldn't be mucking around
while people are using it.
On May 18, 2:51 pm, JamesF usaexportexpe...@gmail.com wrote:
@Martin
even if i remove the conditional and set Configure::write('debug', 2)
in beforeFilter on its own...still no sql is shown. says
(default) 0 query took ms
On May 18, 12:22 pm, Martin Westin martin.westin...@gmail.com wrote:
That might be undesirable since any notices or errors before
beforeRender will be in his output.
@JamesF:
Did you put the if-clause at the top of beforeFilter or at the bottom?
Your if will return false if Auth has not had a chance to do it's
thing. Check that you did NOT put it before Auth initializes.
(you will probably be missing the user table slq in your output in
this case but the rest should be there)
On May 18, 4:53 pm, nurvzy nur...@gmail.com wrote:
Try reversing it. debug:3 in the core and turn it off beforeRender if
you're NOT admin.
On May 17, 4:41 pm, JamesF usaexportexpe...@gmail.com wrote:
hello all, i love cakephp's built in table that shows the sql queries
that are running. my site is now live but i need a way to check under
the hood without disrupting my users.
here is what i put in the beforeRender function of my app_controller:
function beforeRender(){
if ($this-Auth-user('role') == 'admin'){
Configure::write('debug', 2);
} else {
//
}
i have Configure::write('debug', 0) set in my core.php
now this pulls up that sql table thing at the bottom of the screen but
it is EMPTY. it says (default) 0 query took ms.
anyone have a solution?
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Re: Routing oddities
On Mon, May 18, 2009 at 7:40 PM, doze doze...@gmail.com wrote:
Hello,
I'm having some problems with my routing, let's go straight to
business:
When accessing this url: http://localhost/somecompany/home
1. With route setup:
Router::connect('/:company/:controller/*');
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*', array(), array
('company' = '[A-Z][a-z][0-9]'));
Result:
Fails, get's routed to /app/controllers/somecompany_controller.php
Question:
Why it fails when I set regexp check to the company parameter?
That regexp will catch only a string constructed of a single uppercase
letter, followed by a single lowercase letter, followed by a single
digit. Try:
[A-Za-z0-9]+
This incorporates the 3 character types in a single set.The + says to
match one or more characters.
When accessing this url: http://localhost/somecompany/
1. With route setup:
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*');
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Fails, get's routed to /app/controllers/controller.php
Question:
Why it doesn't take the second route and find to home controller?
That one I'm unsure of as I never use the ':controller' placeholder.
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Re: Syntax errors running console script on production server
Maybe the server has a version 4.x CLI installed as well as a 5.x
Apache module. If you have terminal access, type: php -v
On Mon, May 18, 2009 at 5:11 PM, Jason jasf...@gmail.com wrote:
I've found a few other posts where people are having similar problems,
but all of them seem to be solving their problems by realizing that
they are running PHP4 on the production server. In my case, I am
definitely running PHP5 - and I don't have any errors using Cake
classes and methods through the browser interface. The issue only
surfaces when I'm running my shell script. In fact - one of my models
is being used by the shell script and a few standard controllers and
it is only throwing an error when run through the shell script.
- Jason
On May 18, 3:15 pm, Jason jasf...@gmail.com wrote:
I have a working app that runs with no errors on my local machine.
When I upload it to my production server (DreamHost) the app works
fine in the browser, but I have a shell script that I run through the
console that gives me errors on the production server.
The errors I'm getting seem to have to do with class object syntax.
For example - this function declaration in my shell file:
private function _checkRules($text, $author_type, $rules) {
Produces this error
Parse error: syntax error, unexpected T_STRING, expecting
T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /home/jasford/
feedmagnet.com/app/vendors/shells/import.php on line 72
but if I remove the word private from the front of the line it does
not return a syntax error.
Does anyone have any idea what could be going on here? I'm running PHP
5.2.9 locally (Entropy release 7) and PHP 5.2.6 on the remote server.
- Jason
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Re: Routing oddities
I have done more tests with these and got little bit further, but
still having issues.. Here's the current state:
With these routes:
Router::connect('/:company/:controller/:action/', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/', array('controller' =
'home', 'action' = 'index'));
Router::connect('/:company/', array('controller' = 'home', 'action'
= 'index'));
Following urls work:
localhost/somecompany/
localhost/somecompany/home
localhost/somecompany/home/test -- goes to test() method of
home_controller.php
But action parameters don't work (because they are not being cached by
the routes):
localhost/somecompany/home/test/1 --routes to-- app\controllers
\asd_controller.php
With these routes trying to also catch the parameters for action:
Router::connect('/:company/:controller/:action/*', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/:action/', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/', array('controller' =
'home', 'action' = 'index'));
Router::connect('/:company/', array('controller' = 'home', 'action'
= 'index'));
Following urls work:
localhost/asd/home
localhost/asd/home/test
localhost/asd/home/test/11
But the url:
localhost/asd/
get's routed to a null controller again, e.g. app\controllers
\controller.php
I'll update my progress as I go along, but please anyone post if you
know what's going on!
Thanks.
On May 19, 3:58 am, brian bally.z...@gmail.com wrote:
On Mon, May 18, 2009 at 7:40 PM, doze doze...@gmail.com wrote:
Hello,
I'm having some problems with my routing, let's go straight to
business:
When accessing this url:http://localhost/somecompany/home
1. With route setup:
Router::connect('/:company/:controller/*');
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*', array(), array
('company' = '[A-Z][a-z][0-9]'));
Result:
Fails, get's routed to /app/controllers/somecompany_controller.php
Question:
Why it fails when I set regexp check to the company parameter?
That regexp will catch only a string constructed of a single uppercase
letter, followed by a single lowercase letter, followed by a single
digit. Try:
[A-Za-z0-9]+
This incorporates the 3 character types in a single set.The + says to
match one or more characters.
When accessing this url:http://localhost/somecompany/
1. With route setup:
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*');
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Fails, get's routed to /app/controllers/controller.php
Question:
Why it doesn't take the second route and find to home controller?
That one I'm unsure of as I never use the ':controller' placeholder.
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Re: returning or exiting from methods of controllers
It depends. If the method is not an action, but a private method
called from within the controller (eg. $this-__whatever()) then
returning false is a good idea. It really depends on wht you want from
the method.
If it's an action (ie. called directly through the request) you're
better off setting an error msg--whether in Session-flash() or an
error variable--or redirecting (again, using flash to set a msg).
The usual way to set up an action's flow is to check if $this-data is
empty. If not, this is the 2nd request (a form has been submitted).
Generally, that check can go right at the top. But, in some cases, you
might want to do some checking whether it's the 1st or 2nd request. In
that case, do that first. If it fails, you might want to redirect.
function someAction($id = null)
{
/* this will be run for all requests/submissions
*/
if (!$id)
{
$this-Session-flash('ruh-roh!');
/* processing will stop after the following
*/
$this-redirect('somewhere else');
}
if (!empty($this-data))
{
/* deal with subimtted content
*/
$this-Something-create($this-data);
if ($this-Something-save())
{
/* set a msg and redirect so processing stops
*/
$this-Session-flash('done');
$this-redirect('somewhere else');
}
else
{
/* set error msg but do not redirect so further
* processing can happen further down
*/
$this-Session-flash('ruh-roh again!');
}
}
else
{
/* first request, so grab some data
*/
$this-data = $this-Something-read(null, $id);
}
/* Grab some other data. If save failed for some reason,
* this other data will still be set.
*/
$this-set('foo', $this-Something-Foo-findByBar('bar'));
}
On Mon, May 18, 2009 at 4:58 PM, Brian Lee brianleeu...@gmail.com wrote:
In methods of controllers, there are usually many checks for doing
the right thing.
For instance, I check if user is accessing the right data.
However, I'm wondering what is the best way to return or exit from
these methods when errors do occur. I've been using just simple return
statement, but is there anything that's more CakePHP-like and follow
the framework's design? or is simple return/exit statement good
enough?
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Repopulating a form after an error
When a submitted form fails a validation rule, the form is presented back to the user with their values intact. This is obviously a good thing, as the user doesn't have to fill the whole thing in again. I have a form where I need to compare two of the submitted values to make sure they're not the same. I can't, as far as I know, use a validation rule to compare two fields in the same form. How can I display the form back the user with their values intact? Currently I set a flash message, then redirect back to the form, but the user has to fill the form in again. Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Repopulating a form after an error
Jules, have a look at my reply a moment ago to msg, 'returning or
exiting from methods of controllers'. The reason the form is
redisplayed empty is because you're redirecting. This causes a new
request to be made, so $this-data is empty and FormHelper has nothing
to fill in the form with.
If either validation or save fails, you usually want only to set a
flash msg without doing a redirect. This allows the rest of the action
to be processed, meaning that the form will simply be re-displayed.
Because $this-data still contains whatever the user submitted, the
form should contain the data.
As for comparing 2 fields:
var $validate = array(
'field1' = array(
'fieldComparison' = array(
'rule' = array('compareFieldValues', 'field2'),
'message' = 'field1 and field2 are the same!'
)
)
);
function compareFieldValues($field1 = array(), $other_field_name = null)
{
foreach ($field as $key = $value)
{
if ($value === $this-data[$this-name][$other_field_name])
{
return false;
}
else
{
continue;
}
}
return true;
}
On Mon, May 18, 2009 at 9:30 PM, Jules fattyju...@gmail.com wrote:
When a submitted form fails a validation rule, the form is presented
back to the user with their values intact. This is obviously a good
thing, as the user doesn't have to fill the whole thing in again.
I have a form where I need to compare two of the submitted values to
make sure they're not the same. I can't, as far as I know, use a
validation rule to compare two fields in the same form. How can I
display the form back the user with their values intact? Currently I
set a flash message, then redirect back to the form, but the user has
to fill the form in again.
Thanks
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Re: Routing oddities
Got it to work finally!! These are the final routes:
Router::connect('/:company/:controller/:action', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/:action/*', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller', array('controller' =
'home', 'action' = 'index'));
Router::connect('/:company', array('controller' = 'home', 'action'
= 'index'));
All I needed to do is to change the two first routes other way down.
Sweet!
Thanks for all the help and especially the great guys at #cakephp!!
Now to a next adventure.. :)
On May 19, 4:29 am, doze doze...@gmail.com wrote:
I have done more tests with these and got little bit further, but
still having issues.. Here's the current state:
With these routes:
Router::connect('/:company/:controller/:action/', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/', array('controller' =
'home', 'action' = 'index'));
Router::connect('/:company/', array('controller' = 'home', 'action'
= 'index'));
Following urls work:
localhost/somecompany/
localhost/somecompany/home
localhost/somecompany/home/test -- goes to test() method of
home_controller.php
But action parameters don't work (because they are not being cached by
the routes):
localhost/somecompany/home/test/1 --routes to-- app\controllers
\asd_controller.php
With these routes trying to also catch the parameters for action:
Router::connect('/:company/:controller/:action/*', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/:action/', array('controller'
= 'home', 'action' = 'index'));
Router::connect('/:company/:controller/', array('controller' =
'home', 'action' = 'index'));
Router::connect('/:company/', array('controller' = 'home', 'action'
= 'index'));
Following urls work:
localhost/asd/home
localhost/asd/home/test
localhost/asd/home/test/11
But the url:
localhost/asd/
get's routed to a null controller again, e.g. app\controllers
\controller.php
I'll update my progress as I go along, but please anyone post if you
know what's going on!
Thanks.
On May 19, 3:58 am, brian bally.z...@gmail.com wrote:
On Mon, May 18, 2009 at 7:40 PM, doze doze...@gmail.com wrote:
Hello,
I'm having some problems with my routing, let's go straight to
business:
When accessing this url:http://localhost/somecompany/home
1. With route setup:
Router::connect('/:company/:controller/*');
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*', array(), array
('company' = '[A-Z][a-z][0-9]'));
Result:
Fails, get's routed to /app/controllers/somecompany_controller.php
Question:
Why it fails when I set regexp check to the company parameter?
That regexp will catch only a string constructed of a single uppercase
letter, followed by a single lowercase letter, followed by a single
digit. Try:
[A-Za-z0-9]+
This incorporates the 3 character types in a single set.The + says to
match one or more characters.
When accessing this url:http://localhost/somecompany/
1. With route setup:
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Works ok, get's routed to /app/controllers/home_controller.php
2. With route setup:
Router::connect('/:company/:controller/*');
Router::connect('/:company/*', array('controller' = 'home'));
Result:
Fails, get's routed to /app/controllers/controller.php
Question:
Why it doesn't take the second route and find to home controller?
That one I'm unsure of as I never use the ':controller' placeholder.
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How would I hide and default a foreign field in a relationship
I'm creating an application with the following two tables: posts: - id - title - body comments: - id - post_id - comment I was able to bake this app and all the links are working. Now I would like to customize the app so that, when a comment is added from the post: - the post id (list) is not showing in the comment view - the post id gets saved when the comment is saved - the comment gets redirected to the post the comment originated from after saving Any source code samples to assist with these issues would be greatly appreciated. Jorge --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: How would I hide and default a foreign field in a relationship
On Mon, May 18, 2009 at 10:22 PM, Jorge Garifuna garif...@gmail.com wrote:
I'm creating an application with the following two tables:
posts:
- id
- title
- body
comments:
- id
- post_id
- comment
I was able to bake this app and all the links are working. Now I would
like to customize the app so that, when a comment is added from the
post:
- the post id (list) is not showing in the comment view
Just delete it from your view. Bake creates very generic views and,
unless you change the templates, you'll generally need to clean them
up somewhat.
- the post id gets saved when the comment is saved
$form-hidden('Comment.post_id')
Depending on how you're doing things, you may need to do:
$form-hidden('Comment.post_id', array('value' = $post_id))
... that's if you've set the $post_id var.
- the comment gets redirected to the post the comment originated from
after saving
$this-redirect(
array(
'controller' = 'Post',
'action' = 'view',
$post_id
)
);
Or, if you don't want the 'view' part in the URL, you might want
something like this:
$this-redirect(
array(
'controller' = 'Post',
'action' = 'view',
'id' = $post_id
)
);
In which case your route would be:
Router::connect(
'/posts/:id',
array('controller' = 'posts', 'action' = 'view'),
array('id' = '[0-9]+', 'pass' = array('id'))
);
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Re: Notice (8): Undefined property: CakeErrorController::$js_vars
It is obvious - no js_vars found in error controller class!
If you add new properties to controllers do not forget to define them
in AppController definition. Same for models. Same for helpers.
Otherwise you see such error.
On May 18, 2:22 pm, Braydenstyles brayden.sty...@gmail.com wrote:
Notice (8): Undefined property: CakeErrorController::$js_vars [APP/
app_controller.php, line 103]
Code
{
$this-set('meta_for_layout', Configure::read('meta'));
$this-set('js_vars_for_layout', $this-js_vars);
AppController::beforeRender() - APP/app_controller.php, line 103
Controller::render() - CORE/cake/libs/controller/controller.php, line
701
ErrorHandler::__outputMessage() - CORE/cake/libs/error.php, line 377
ErrorHandler::missingController() - CORE/cake/libs/error.php, line 176
Object::dispatchMethod() - CORE/cake/libs/object.php, line 119
ErrorHandler::__construct() - CORE/cake/libs/error.php, line 120
Object::cakeError() - CORE/cake/libs/object.php, line 204
Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 148
require - APP/webroot/index.php, line 90
[main] - APP/index.php, line 25
help please ???
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Re: Repopulating a form after an error
Thank you Brian, I wasn't aware that you could write a custom validation function. However, I've tried both methods, and am still having the same problem. In both cases, the form comes back with fresh data in it. I have confirmed that the custom validation rule is firing. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Installation Problem: CakePHP 1.2.3.8166 on CENTOS and database.php
what version of PHP is the centos machine running ? have you got all the required .htaccess files and mod_rewrite installed in apache2 ? - http://wiltonsoftware.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Application setup where each customer has own database
Hello,
Just to let you know that I got this setup working.. Thank you very
very much for the help.
I'll write up some article about the setup as I think it can help
somebody other some day.
Thanks!
On May 18, 6:44 am, Dr. Loboto drlob...@gmail.com wrote:
How do you define a link between Models that are not in the same
database? Will Cake check the useDbConfig from the employee
model automatically?
Ordinal association. Cake will load associated model and get all
necessary info from it.
how can I make it work with urls like:
www.domain.com/company1/controller/action
www.domain.com/company2/controller/action
Read about routing again and test it yourself. Looks like something
like this may help you:
Router::connect(
'/:company/:controller/:action/*', // company name, then
controller
name, then action name, then any params
array (), // nothing to specify - controller and action already
pointed
array ('company' = 'a-zA-Z0-9') // regexp for company name check
(also can be omitted, I think)
);
But it may also require explicit map non company-specific URLs before
this rule. Also there can be problems... And will be definitely...
Search this group for named params and prefix routing (_after_ you
check how it works yourself).
On May 15, 11:18 pm,dozedoze...@gmail.com wrote:
Thanks a lot for the answer! That kind of database selection is indeed
perfect for me and much simpler.. don't have to do any custom db
drivers. Thanks again!
I have couple questions though, as this is the first time I'm using
CakePHP and don't know much about it yet.
1. Can I link tables between database configs?
Yes, but Cake will always run separate queries, no any joins.
How do you define a link between Models that are not in the same
database? I know that with useDbConfig I can tell CakePHP that which
database to use for the model, but when I'm creating a link from users
to employees table for example, how can I tell CakePHP that the
employees table is in the other database? Or do I need to tell that
even? Will Cake check the useDbConfig from the employee model
automatically?
E.g. would this simply work:
class User extends AppModel {
var $useDbConfig = 'commondb';
var $name = 'User';
var $hasOne = 'Employee';
}
class Employee extends AppModel {
var $useDbConfig = 'companydb';
var $name = 'Employee';
}
// get employee object from the user object
$employee = $user-Employee;
Then to another question...
You can determine and save database name by something like this (I
assume that routing with param 'company' is used):
I tried to read about the routing in CakePHP, but I didn't quite get
it.. so how can I make it work with urls like:
www.domain.com/company1/controller/actionwww.domain.com/company2/cont...
and take that first part of the url out to save as db name (with
Configure::write like you pointed out) and then use the rest of the
url to navigate normally to the controller / action. I could do it in
the app/webroot/index.php before the $url parameter is passed to the
dispatcher, but I'm guessing that would be the wrong way to do it. Can
I do it with the routing somehow?
These might be quite trivial things for more advanced CakePHP users,
but for me as a newbie, I haven't quite grasped the idea yet..
I'm definitely going to do some write up of the whole setup.
On May 15, 5:44 am, Dr. Loboto drlob...@gmail.com wrote:
1. Can I link tables between database configs?
Yes, but Cake will always run separate queries, no any joins.
2. How to automate the database table selection?
Method on link you provided looks too complex for your situation. If
each company have own databases with completely same structure, the
only thing you need to do for company specific models is to select
appropriate DB config.
You can determine and save database name by something like this (I
assume that routing with param 'company' is used):
class AppController extends Controller {
function constructClasses() {
// Save company name when we already know it but before
models are
created
Configure::write(
'companyDB',
!empty($this-params['company']) ?
$this-params['company'] : false
);
parent::constructClasses();
}
}
Mark all company-specific models like this:
class CompanyProfile extends AppModel {
var $specific = true;
}
And have such AppModel:
class AppModel extends Model {
var $specific = false;
function __construct($id = false, $table = null, $ds = null) {
if ($this-specific) {
// Get saved company/database name
$dbName =
can i use integer in model name
How can i use table raw_06 and model can anyone help me --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Poll: what do you hate about CakePHP?
+1 with Matt Curry on this: Remove Model::recursive. All find calls would return just the model and if you wanted associated models you HAVE TO use Containable. - Built in functionality for custom find types. Right now there are some nice hacks that you can put into your AppModel to define your own custom find types but this should work out of the box. - The MEIO upload behavior (or something like it) could be added to the core. That behavior has greatly simplified managing uploads for me and is quite flexible. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Submit/Cancel problem
Please show the code in which you create the buttons, together with the surrounding form code! Then we may be able to assist you :) John On May 19, 2:11 am, Nancy nancy.milli...@gmail.com wrote: So, I added a submit and a cancel button to my ajax form and it doesn't matter which you press, it always returns the submit button, not the cancel. The view code has this at the bottom (I stopped using helpers to see if raw HTML would help, it didn't): input name=Submit value=submit type=submit input name=Cancel value=cancel type=submit In the controller (admin_edit) function, I'm dumping out the contents of $this-params['form'] and it always shows Array ( [Submit] = submit ) Even if you press the cancel button. Am I doing something wrong? Thanks! Nancy --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Submit/Cancel problem
Use reset or button NOT submit type for the cancel button. input name=Cancel value=cancel type=reset or input name=Cancel value=cancel type=button Nancy escribió: So, I added a submit and a cancel button to my ajax form and it doesn't matter which you press, it always returns the submit button, not the cancel. The view code has this at the bottom (I stopped using helpers to see if raw HTML would help, it didn't): input name=Submit value=submit type=submit input name=Cancel value=cancel type=submit In the controller (admin_edit) function, I'm dumping out the contents of $this-params['form'] and it always shows Array ( [Submit] = submit ) Even if you press the cancel button. Am I doing something wrong? Thanks! Nancy --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
