User and permissions/grants - HELP!
Hi, I just installed MySQL version 4 and as usual, trying to set up users and grant permissions is a nightmare. I followed the instructions in the MySQL manual and granted permissions to a user, like below: GRANT ALL PRIVILEGES ON *.* TO [EMAIL PROTECTED] IDENTIFIED BY '12345678' WITH GRANT OPTION; GRANT ALL PRIVILEGES ON *.* TO newuser@% IDENTIFIED BY '12345678' WITH GRANT OPTION; I can log in with this user, but I can't do anything (i.e. create a database). There is also no mysql database (there is though if I log in as root). So what am I doing wrong.? TIA -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Sorting question
Hi, I have a database with 5 teams and each team has 'n' categories and each category has 5 sub-categories. i.e TeamOne = Ottawa, Category 1 = Player Name, Sub-Categories = Goals, assists, ppg, gwg, points. Team0ne Category 1 Sub 1 Sub 2 Sub 3 Sub 4 Sub 5 Category 2 Sub 1 Sub 2 Sub 3 Sub 4 Sub 5 Etc. From the examples above I am trying to add the all the sub-categories together for each category for each team in descending order. To put it simpler - I want a total of all the goals scored for each team and display them in descending order. I have been able to put a query together that gets me the totals, but I can not get them in decending order. The query below is in a for loop in PHP and cycles through each team and does give me the totals, just not in descending order (actually the order is the way they are numbered in the database); $query = select team.name, sum(goals) from roster join reference join team where team.idn=reference.idn and reference.idp=roster.idp and position = 'F' and team.idn = 1 group by team.name; Now the query here may not be the problem, but the way the for loop works, but any help is appreciated. TIA -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Select Limit question
This is probably easy, but I just can't to put my finger on it. I have a list of numbers (i.e. 1 to 175) and I want to do a select statement to get the highest number. I have tried the limit thing but not getting the right output. Can someone shed some light on this? TIA -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
MySQL query problems
Hi,
Not sure if the problem here is PHP or MySQL, but here we go. I am
trying to do two queries on a database - one after the other, but the
second one never seems to get executed. The two queries are identical
except for two variables. I have checked my form and they are correct
and are being sent to the PHP script the way they should be.
The variables are $playerto, $playerfrom, $nameto, $namefrom. The 'TO'
query is the one that doesn't work.
Here is my code. Any help is appreciated.
if ($namefrom != $nameto) {
if ($playerfrom != $playerto) {
include(2004server.inc);
if($error) {
include(trades-input.php);
exit;
}
$query1 = select manager.idn, manager.total,
roster.idp, position, points from roster join reference
join manager where manager.idn=reference.idn and
reference.idp=roster.idp and manager.idn like '$namefrom' and
roster.idp like '$playerfrom';
$result1 = mysql_query($query1) or $mysqlerror =
mysql_error();
if ($mysqlerror) {
$error = $d_base_error$email_error;
include(trades-input.php);
exit;
}
$line = mysql_fetch_row($result1);
mysql_free_result($result1);
$query2 = select manager.idn, manager.total,
roster.idp, position, points from roster join reference
join manager where manager.idn=reference.idn and
reference.idp=roster.idp and manager.idn like '$nameto' and
roster.idp like '$playerto';
$result2 = mysql_query($query2) or $mysqlerror =
mysql_error();
if ($mysqlerror) {
$error = $d_base_error$email_error;
include(trades-inputs.php);
exit;
}
$row = mysql_fetch_array($result2);
mysql_free_result($result2);
}
}
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RE: MySQL query problems
Since the first query works, the second one should also work as it is
virtually the same. It is querying the same database using the exact
same query. The only difference is the variable names passed to it by
the form.
i.e.
$playerfrom may = Hossa
$playerto may = Alfredsson
$namefrom may = Bill
$nameto may = John
If I change the from and the to values to the opposite of the above
example I get the same thing. The second query does not work (which
works if I use it as the first query). Even if I use the exact same
query for both - the second one will not work.
Hope this makes sense.
-Original Message-
From: Jef S [mailto:[EMAIL PROTECTED]
Sent: July 16, 2003 12:50 PM
To: [EMAIL PROTECTED]
Subject: RE: MySQL query problems
Have you checked the query in an editor to see if they are working? Just
substitute known values in the place of the variables you are using.
Jef
-Original Message-
From: C. Reeve [mailto:[EMAIL PROTECTED]
Sent: Wednesday, July 16, 2003 10:16 AM
To: [EMAIL PROTECTED]
Subject: MySQL query problems
Hi,
Not sure if the problem here is PHP or MySQL, but here we go. I am
trying to do two queries on a database - one after the other, but the
second one never seems to get executed. The two queries are identical
except for two variables. I have checked my form and they are correct
and are being sent to the PHP script the way they should be.
The variables are $playerto, $playerfrom, $nameto, $namefrom. The 'TO'
query is the one that doesn't work.
Here is my code. Any help is appreciated.
if ($namefrom != $nameto) {
if ($playerfrom != $playerto) {
include(2004server.inc);
if($error) {
include(trades-input.php);
exit;
}
$query1 = select manager.idn, manager.total,
roster.idp, position, points from roster join reference
join manager where manager.idn=reference.idn and
reference.idp=roster.idp and manager.idn like '$namefrom' and
roster.idp like '$playerfrom';
$result1 = mysql_query($query1) or $mysqlerror =
mysql_error();
if ($mysqlerror) {
$error = $d_base_error$email_error;
include(trades-input.php);
exit;
}
$line = mysql_fetch_row($result1);
mysql_free_result($result1);
$query2 = select manager.idn, manager.total,
roster.idp, position, points from roster join reference
join manager where manager.idn=reference.idn and
reference.idp=roster.idp and manager.idn like '$nameto' and
roster.idp like '$playerto';
$result2 = mysql_query($query2) or $mysqlerror =
mysql_error();
if ($mysqlerror) {
$error = $d_base_error$email_error;
include(trades-inputs.php);
exit;
}
$row = mysql_fetch_array($result2);
mysql_free_result($result2);
}
}
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http://lists.mysql.com/[EMAIL PROTECTED]
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What's up with this GATOR crap?
Hi, I have noticed recently that every time I go to the MySQL manual page I get prompted to install Gator spyware. If MySQL condones or is going to use spyware, I may have to consider using another database. This may sound extreme, but I do not condone the use of spyware in any form and would hope that others feel the same way. Comments -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Fw: Help, Insert not working.
Would you care to elaborate on that - Using PHP there is no error or return
code - it just goes along happily saying the record was inserted. If there
is a way to do this, please explain.
TIA
- Original Message -
From: gerald_clark [EMAIL PROTECTED]
To: C. Reeve [EMAIL PROTECTED]
Cc: MySQL List [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 9:32 AM
Subject: Re: Fw: Help, Insert not working.
Try reading your return codes.
You got a duplicate key error that you were ignoring.
C. Reeve wrote:
I got it - stupid me has a unique field that I wasn't using in the test
script I was using - so every I tried to add an entry this field was a
duplicate and as such did not add the record. Is there a way to put
something in so mysql would tell me this - 2 hours pissing around for an
oversight.
TIA
- Original Message -
From: C. Reeve [EMAIL PROTECTED]
To: MySQL List [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 1:47 AM
Subject: Help, Insert not working.
Can anyone explain why this isn't working? It will not input the info
into
the database.
$db = mysql_connect($serverhost, $serveruser, $serverpass);
mysql_select_db($database_name);
The variables in the above two rows are correct - I can do selects and
it
works fine.
This is the data to be inserted and they are there
echo BR.$entered_email;
echo BR.$entered_passwd;
echo BR.$name;
Nothing happens.
mysql_query (INSERT INTO userdata (email, passwd, firstname, alias)
VALUES
('$entered_email','$entered_passwd','$name','Hello'));
TIA
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Help, Insert not working.
Can anyone explain why this isn't working? It will not input the info into
the database.
$db = mysql_connect($serverhost, $serveruser, $serverpass);
mysql_select_db($database_name);
The variables in the above two rows are correct - I can do selects and it
works fine.
This is the data to be inserted and they are there
echo BR.$entered_email;
echo BR.$entered_passwd;
echo BR.$name;
Nothing happens.
mysql_query (INSERT INTO userdata (email, passwd, firstname) VALUES
('$entered_email','$entered_passwd','$name'));
TIA
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Fw: Help, Insert not working.
I got it - stupid me has a unique field that I wasn't using in the test
script I was using - so every I tried to add an entry this field was a
duplicate and as such did not add the record. Is there a way to put
something in so mysql would tell me this - 2 hours pissing around for an
oversight.
TIA
- Original Message -
From: C. Reeve [EMAIL PROTECTED]
To: MySQL List [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 1:47 AM
Subject: Help, Insert not working.
Can anyone explain why this isn't working? It will not input the info into
the database.
$db = mysql_connect($serverhost, $serveruser, $serverpass);
mysql_select_db($database_name);
The variables in the above two rows are correct - I can do selects and it
works fine.
This is the data to be inserted and they are there
echo BR.$entered_email;
echo BR.$entered_passwd;
echo BR.$name;
Nothing happens.
mysql_query (INSERT INTO userdata (email, passwd, firstname, alias)
VALUES
('$entered_email','$entered_passwd','$name','Hello'));
TIA
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Remote Administration
Hi, How would I go about setting up remote administration of MySQL. MySQL is running on Windows 2000 and I will be connecting from Windows XP. I saw something in the MySQL docs about using an SSH client like Secure CRT, but it loses me at the linking OBDC. Any help on this or another similar way to do remote administration is appreciated.. - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Part Mysql part PHP question....
Hi, I have a hockey database with players names in it and I want to be able to update their stats one after the other. To be more clear - when the page is first entered I want the first players name to automatically appear showing his current stats (this will be in a form). Then you can update the record and write it back to the database, then the next player will show up with his stats showing, and the process continues until all the players have been done. Setting up the database and forms is no problem, but I'm not sure how I would keep count of what player has been done so the next one automatically appears (and if there should be a power failure orWindows crashes, or whatever else - I want the process to start at the last player being updated - I don't want to have to start again from player one). I'm not sure if this is more a PHP or MySQL question - or both - so I have sent it to both lists. Thanks C. Reeve - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Using SUM in a select statement.
Hi, Not sure how to explain this - but here is what I need. I have a hockey pool database with three tables - one has the players and their stats, one has the team owner, and the 3rd is the reference file that ties the two together. I want to be able to do a query for all the players on a particular team that are forwards and get a grand total of all their points. I already have a query that does something similar, but it just displays the individual players stats. Example: Team 1PlayerPosition GoalsPoints *Bob Bonk F 2250 HossaF3341 Total5591 This is what I want to achieve - and then the same for the rest of the teams. *This is my query that get the individual players points. $query = select team.name, player, position, gp, goals, ppg, gwg, shg, ass, pm, shots, pim, points from roster join reference join team where team.idn=reference.idn and reference.idp=roster.idp and team.idn = '$team' and position like '$position' order by points desc; TIA - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: Using SUM in a select statement.
Hmm, after seeing this it looks as if the way I have it is a lot simpler and easier to handle. Currently I just put them in a PHP array and sum the array. Thanks for the input. - Original Message - From: Tore Bostrup [EMAIL PROTECTED] To: MySQL List [EMAIL PROTECTED] Sent: Sunday, March 02, 2003 1:12 PM Subject: Re: Using SUM in a select statement. What you are looking for appears to be report layout. Keep in mind that SQL will only return multiple rows, all with the same columns populated. To even get close to what you want, you can create a query that returns: TeamOwner, Player, Position, Goals, Points And then your application can massage it into the output format you want. A query to return BOTH detail information on players AND summary information on owners would have to be a union of two queries - one returning the player information and the other returning owner summary information (UNION requires version 4.0): SELECT O.OwnerName, 1 as SortOrder, P.Player, P.Position, Goals, Points FROM owners as O INNER JOIN teamplayers as T ON O.OwnerID = T.OwnerID INNER JOIN players as P ON T.PlayerID = P.PlayerID UNION SELECTO.OwnerName, 2 as SortOrder, 'Total' as Player, P.Position, Sum(Goals) as Goals, Sum(Points) as Points FROM owners as O INNER JOIN teamplayers as T ON O.OwnerID = T.OwnerID INNER JOIN players as P ON T.PlayerID = P.PlayerID GROUP BY O.OwnerName, SortOrder, Player, P.Position ORDER BY O.OwnerName, SortOrder, Player, P.Position Based on this, it is basically a question of suppressing repeated values of OwnerName. Adjust the query to match your actual situation. If you are using version 3.23, AFAIK you'll either have to use two separate queries or calculate the totals in your app from the detail data. HTH, Tore. - Original Message - From: C. Reeve [EMAIL PROTECTED] To: MySQL List [EMAIL PROTECTED] Sent: Sunday, March 02, 2003 11:54 AM Subject: Using SUM in a select statement. Hi, Not sure how to explain this - but here is what I need. I have a hockey pool database with three tables - one has the players and their stats, one has the team owner, and the 3rd is the reference file that ties the two together. I want to be able to do a query for all the players on a particular team that are forwards and get a grand total of all their points. I already have a query that does something similar, but it just displays the individual players stats. Example: Team 1PlayerPosition GoalsPoints *Bob Bonk F 2250 HossaF3341 Total5591 This is what I want to achieve - and then the same for the rest of the teams. *This is my query that get the individual players points. $query = select team.name, player, position, gp, goals, ppg, gwg, shg, ass, pm, shots, pim, points from roster join reference join team where team.idn=reference.idn and reference.idp=roster.idp and team.idn = '$team' and position like '$position' order by points desc; TIA - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Testing
Testing - Mysql - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Select question
Hi, I have a database with 3 names in it. In each of these names is 5 categories that have numbers in them. I want to be able to do a select and get the top number from each category for each name and display them from most to least. I have checked all the docs on the select statement, but this is escaping me at the moment. TIA i.e This is what is in the database. Bill 3620504670 John2630324846 Fred8740196242 This is what I want to be able to show: Fred 87 Bill 70 John 48 SPAM bypass: sql, query, queries, smallint - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: Select question
Hi again, After some struggling, I have managed to get the problem below 99% working, the problem now is that I can't get them in descending order. Here is my select statement. $query = select manager.name, position, MAX(goals) from roster join reference join manager where manager.idn=reference.idn and reference.idp=roster.idp and position like 'F' GROUP BY manager.name order by goals desc; Using the example below, this is what I get: Bill 70 John 48 Fred 87 This is what I want: Fred 87 Bill 70 John 48 TIA - Original Message - From: C. Reeve [EMAIL PROTECTED] To: MySQL List [EMAIL PROTECTED] Sent: Friday, February 07, 2003 1:57 PM Subject: Select question Hi, I have a database with 3 names in it. In each of these names is 5 categories that have numbers in them. I want to be able to do a select and get the top number from each category for each name and display them from most to least. I have checked all the docs on the select statement, but this is escaping me at the moment. TIA i.e This is what is in the database. Bill 3620504670 John2630324846 Fred8740196242 This is what I want to be able to show: Fred 87 Bill 70 John 48 SPAM bypass: sql, query, queries, smallint - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: Fw: Problem on WinXP
Nope, same thing - and XP's firewall is not enabled, so this is not an issue. Also, it works on port 3306 fine. When I run a netstat it says it is listening on port 3308 and I get 'mysqld: ready for connections', however, that port is not active. When I scan my PC this port is not open. I can't telnet to it or see it in any other way. Beauford - Original Message - From: miguel solórzano [EMAIL PROTECTED] To: C. Reeve [EMAIL PROTECTED]; MySQL List [EMAIL PROTECTED] Sent: Tuesday, January 14, 2003 3:49 AM Subject: Re: Fw: Problem on WinXP At 01:29 14/01/2003 -0500, C. Reeve wrote: Hi, I just uninstalled and reinstalled and got it to work on port 3306, but I can't get it to work on any other port. As I said, I have changed this in my.ini. Is there something else I should be doing to get this to work on a non-standard port.? Of course: Microsoft Windows 2000 [Versão 5.00.2195] (C) Copyright 1985-1999 Microsoft Corp. c:\mysql\binmysqld --standalone --console --port=3308 mysqld: ready for connections in another DOS screen: Microsoft Windows 2000 [Versão 5.00.2195] (C) Copyright 1985-1999 Microsoft Corp. c:\mysql\binnetstat -a -n Conexões ativas Proto Endereço local Endereço externo Estado TCP0.0.0.0:1350.0.0.0:0 LISTENING TCP0.0.0.0:4450.0.0.0:0 LISTENING TCP0.0.0.0:1025 0.0.0.0:0 LISTENING TCP0.0.0.0:1026 0.0.0.0:0 LISTENING TCP0.0.0.0:1029 0.0.0.0:0 LISTENING TCP0.0.0.0:2523 0.0.0.0:0 LISTENING TCP0.0.0.0:3308 0.0.0.0:0 LISTENING TCP0.0.0.0:3372 0.0.0.0:0 LISTENING TCP0.0.0.0:4873 0.0.0.0:0 LISTENING TCP192.168.0.75:139 0.0.0.0:0 LISTENING If you are having problems on XP, I guess your problem is the the XP's own built fire-wall. -- Regards, __ ___ ___ __ / |/ /_ __/ __/ __ \/ /Miguel Angel Solórzano [EMAIL PROTECTED] / /|_/ / // /\ \/ /_/ / /__ MySQL AB, Fulltime Developer /_/ /_/\_, /___/\___\_\___/ São Paulo - Brazil ___/ www.mysql.com - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Notice: Undefined index:
Hi,
Anyone know why I would be receiving this error in Windows. I have a small
PHP script that accesses a MySQL database and prints out a couple lines.
This works fine in LinuxI have searched google and found many users with
the same problem, but not one solution.
TIA
Notice: Undefined index: lastname in E:\IIS Webs\index.php on line 29
?
PRINT HTML;
PRINT HEAD;
PRINT TITLEADDRESSES/title;
PRINT /HEAD;
PRINT BODY BGCOLOR=white TEXT=#00 LINK=#FF VLINK=#66
aLINK=#FF;
mysql_pconnect(127.0.0.1:3308, user, pass) or
die(could not connect);
mysql_select_db(address);
$query = SELECT lastname, firstname, city FROM data;
$result = mysql_query ($query);
while ($line = mysql_fetch_row($result)) {
echo BR.$line['lastname'];
echo BR.$line['firstname'];
echo BR.$line['city'].BR;
}
?
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Problem on WinXP
Hi, I just installed MySQL on my WinXP box and not sure what's going on. The server starts (or so it says it does) but I get an error saying I can't connect to localhost. Not sure what else to say. I have included some info below (note that I changed the port to 3308 in my.ini as Linux Mysql is using 3306 - although using 3306 does nothing for Windows). A scan of my Windows machine shows that neither of these ports are open. I am also behind a Linksys router and have forwarding directed to Windows on port 3308. Any info is appreciated. I have done some searches on this error and have not come up with anything that works. TIA D:\Language\MySQL 3.23\binnet start mysql The MySql service is starting. The MySql service was started successfully. D:\Language\MySQL 3.23\binmysqladmin create dbtest mysqladmin: connect to server at 'localhost' failed error: 'Can't connect to MySQL server on 'localhost' (10061)' Check that mysqld is running on localhost and that the port is 3306. You can check this by doing 'telnet localhost 3306' D:\Language\MySQL 3.23\binmysql ERROR 2003: Can't connect to MySQL server on 'localhost' (10061) [mysqld] basedir=D:/Language/MySQL 3.23 #bind-address=192.168.1.100 datadir=D:/Language/MySQL 3.23/data #language=D:/Language/MySQL 3.23/share/your language directory #slow query log#= #tmpdir#= port=3308 #set-variable=key_buffer=16M [WinMySQLadmin] Server=D:/Language/MySQL 3.23/bin/mysqld-nt.exe user=xxx password=xxx QueryInterval=10 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Fw: Problem on WinXP
Hi, I just uninstalled and reinstalled and got it to work on port 3306, but I can't get it to work on any other port. As I said, I have changed this in my.ini. Is there something else I should be doing to get this to work on a non-standard port.? TIA - Original Message - From: C. Reeve [EMAIL PROTECTED] To: MySQL List [EMAIL PROTECTED] Sent: Tuesday, January 14, 2003 12:54 AM Subject: Problem on WinXP Hi, I just installed MySQL on my WinXP box and not sure what's going on. The server starts (or so it says it does) but I get an error saying I can't connect to localhost. Not sure what else to say. I have included some info below (note that I changed the port to 3308 in my.ini as Linux Mysql is using 3306 - although using 3306 does nothing for Windows). A scan of my Windows machine shows that neither of these ports are open. I am also behind a Linksys router and have forwarding directed to Windows on port 3308. Any info is appreciated. I have done some searches on this error and have not come up with anything that works. TIA D:\Language\MySQL 3.23\binnet start mysql The MySql service is starting. The MySql service was started successfully. D:\Language\MySQL 3.23\binmysqladmin create dbtest mysqladmin: connect to server at 'localhost' failed error: 'Can't connect to MySQL server on 'localhost' (10061)' Check that mysqld is running on localhost and that the port is 3306. You can check this by doing 'telnet localhost 3306' D:\Language\MySQL 3.23\binmysql ERROR 2003: Can't connect to MySQL server on 'localhost' (10061) [mysqld] basedir=D:/Language/MySQL 3.23 #bind-address=192.168.1.100 datadir=D:/Language/MySQL 3.23/data #language=D:/Language/MySQL 3.23/share/your language directory #slow query log#= #tmpdir#= port=3308 #set-variable=key_buffer=16M [WinMySQLadmin] Server=D:/Language/MySQL 3.23/bin/mysqld-nt.exe user=xxx password=xxx QueryInterval=10 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: MySQL and PHP question
Thanks for the info. I tried using mysql_free_result() and mysql_close($db)
and opening the DB again for the second query with the same results. I
haven't tried using a different variable for $result.
- Original Message -
From: Steve Yates [EMAIL PROTECTED]
To: MySQL List [EMAIL PROTECTED]
Sent: Wednesday, December 18, 2002 1:32 AM
Subject: Re: MySQL and PHP question
On Wed, 18 Dec 2002 22:54:53 -0500, C. Reeve wrote:
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
$num1 = $line['number'];
}
Loop through the result and return the value from the last row?
Did you want select sum(number) as SubTotal1 from table1 where
userid=$user1?
$query select number from table2 where userid=$user2;
$result = mysql_query($query) or die(Query failed);
You re-used the same variable $result. Offhand I would try
using a second variable, and/or using mysql_free_result() in between.
- Steve Yates
- My hard disk is full! Maybe I'll try this message section thing.
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$Variables and Select statements
Hi,
From the code below $wk gets the values (w1, w2, w3, etc.) as it goes
through the 'for' loop. w1, w2, etc. are also colums in the table manager.
What I can't figure out is why the select statement fails (no error, just no
data) when I use $wk as apposed to hardcoding w1, w2, etc. Is this possible
or am I missing something?
Note: the colums w1, w2, etc contain numbers which I am trying to select.
TIA
$db = mysql_connect(xx,xx,xx);
mysql_select_db(database);
echo TABLE ALIGN=center WIDTH=200 BORDER=0TR\n;
for ($i = 1; $i 26; $i++) {
$wk = w$i;
echo TR Width=200TD ALIGN=center COLSPAN=2BWeek
.$i./B/TD/TR\n;
echo TR Width=200TD COLSPAN=2HR SIZE=5/TD/TRTR\n;
echo TR WIDTH=100TD ALIGN=leftBName/B/TDTD
ALIGN=rightBPoints/B/TD;
echo TR Width=100TD/TD/TR\n;
$query = select name, $wk from manager order by $wk desc;
$result = mysql_query($query) or die(Query failed);
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo TR WIDTH=150TD ALIGN=left.$line['name']./TDTD
ALIGN=right.$line['$wk']./TD;
}
echo TR Width=200TD COLSPAN=2HR SIZE=5/TD/TR\n;
}
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Re: $Variables and Select statements
Thanks for the information, I will try that in this situation, however, I
have done this in other select statements and it has worked fine. I will
follow-up in the PHP list if I still have problems.
Please note also that since I assumed this was a MySQL problem I posted it
to this group. Since these two programs are so closely interlinked, it is
hard for us newbies to tell where the problem may lie. I have in the past
posted a question to both groups as I wasn't sure of it either. These lists
are for those that know and those that don't and both have to be tolerant of
the other.
Beauford
- Original Message -
From: Basil Hussain [EMAIL PROTECTED]
To: C. Reeve [EMAIL PROTECTED]; MySQL List
[EMAIL PROTECTED]
Sent: Wednesday, December 18, 2002 11:57 AM
Subject: RE: $Variables and Select statements
Hi,
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo TR WIDTH=150TD
ALIGN=left.$line['name']./TDTD
ALIGN=right.$line['$wk']./TD;
}
Here is your problem. Your are indeed substituting $wk into the query
correctly, but when you go to output the result rows you are not.
You should simply remove the quote marks from:
$line['$wk']
so that it is:
$line[$wk]
PHP does not interpret variable names in single-quoted strings - only in
double-quoted strings. With your current code, PHP is only looking for an
array element called '$wk', which doesn't exist!
In future, may I suggest you that post questions like this to the PHP
mailing list, as this is nothing to do with MySQL.
Regards,
Basil Hussain
---
Internet Developer, Kodak Weddings
E-Mail: [EMAIL PROTECTED]
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MySQL and PHP question
Hi, Why is it that I can not use two mysql queries in the same PHP file. I have tried to do this several times trying to put my site together and have had nothing but problems. The recent one is this: I use a SELECT statement to get some info from a table, then I modify that info and use an UPDATE statement to update another table. The update does not work (all variables used by PHP contain the proper values as does the info selected from the table). I get no errors as it appears the update worked, but the table was not updated. I have also found that I can not do two select statements in the same PHP file, as the second one will not contain any data . The query does not fail, there is just no data. Any info is appreciated. TIA - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: MySQL and PHP question
I've since deleted the code and did it another way. The code however went
something like this. This is just a mock up (there is more being selected
etc and there are some joins, but the syntax is exact).
So what happens is the select statement with $user1 in it gets the proper
values (the first one in the example), the other one doesn't, but if I
change $user1 and $user2 around the second select will get the values.
So on the surface it sounds like a problem with $user2, but I have run
extensive tests and $user2 gets the proper values (they both come from a
form).
In another project I am doing, I tried a similar feat with totally different
values and got the same results. This time I was trying to do one SELECT and
one UPDATE.
If anyone has any ideas it would be appreciated. Also, if there is a better
way to do the following this would also be appreciated.
$query select number from table1 where userid=$user1;
$result = mysql_query($query) or die(Query failed);
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
$num1 = $line['number'];
}
$query select number from table2 where userid=$user2;
$result = mysql_query($query) or die(Query failed);
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
$num2 = $line['number'];
}
$total = $num1 + $num2;
mysql_query(UPDATE table3 SET total = '$total' WHERE userid=$user);
TIA
- Original Message -
From: Steve Yates [EMAIL PROTECTED]
To: MySQL List [EMAIL PROTECTED]
Sent: Tuesday, December 17, 2002 5:12 PM
Subject: Re: MySQL and PHP question
On Wed, 18 Dec 2002 16:05:35 -0500, C. Reeve wrote:
I can not use two mysql queries in the same PHP file
Please post code snippets, this is possible.
- Steve Yates
- Burger Borg: We do it our way; yours is irrelevant.
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Select / Calculate question
Hi, I have one table with an id1 column and a number column, these numbers correspond to another table with an id2 column and a name column and a total column. I also have a reference table with ties the two together (an id1 and id2 column). I want to be able to select all numbers in the first table that correspond to the name in the second column and add them together and place them in the total column of the second table, but whatever I have done has failed. Can anyone suggest a way of doing this? TIA Table1Table2Reference id1 number id2nametotalid1id2 1101John 6011 1202Mary 9022 130etc. etc. 240 250 etc. (MySQL, Query) - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
What is wrong with this Alter statement?
From the MySQL Manual: ALTER TABLE tbl_name MODIFY [COLUMN] create_definition [FIRST | AFTER column_name] I have also tried CHANGE instead of MODIFY. My Statement: alter table manager change column w1 decimal(8,2) not null after moves; The problem is the AFTER statement, if I omit it I have no problem. Now I'm probably reading this wrong but in any event I need my columns to be in a certain order and their not. Without deleting them and re-adding them (and the data) - how do I get them in the order I need? i.e w1, w2, w3, w4 .. w25 not w13, w21, w2, w9 w4, w1. (I have no idea how they even got messed up as I created them in order. Up arrow, change number, up arrow, change numberetc, etc. I'm ranting, but this is really ticking me. TIA - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
