John
Thanks a lot for all your help and that you spending time on this.
If anyone else need the source code:
(additions: column number in every column header, renamed column
headers)
[code]
?php $sortable = array('id' = 'sort_none', 'hardware_unit_id' =
'sort_none', 'description' = 'sort_none');
Well, I don't know at which position in the source code, i have to
reset it.
I would reset with this source code: $sortCssClass = 'sort_none';
I think, i need to know, which column header is clicked and then i
have to reset all others.
Could you give me a last hint please?
Thanks!
Check out the
Thank you for making an example!
But in my case, i have more than one column to make sortable. In your
example, when i click on one table header to sort, all table headers
show the same arrow, what is wrong :/
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Hmm, should it be easy to reset the sort direction?
I don't know at which position in the source code, i have to reset it.
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Hello again and thanks.
I got an arrow in my column header. But its every time (asc or desc)
the same arrow, so i think, the paginate source code is still wrong.
My problem is still, that i dont know how to combine two classes in
one paginate function.
[code dont works]
?php echo
John
Thanks a lot for all your help.
In your example, is the cake.generic.css file the original?
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Hello and sry that i have to ask again.
But i dont know, what the correct syntax for the pagination is.
At the moment i have:
[code]
?php echo $paginator-sort(array('asc' ='id v', 'desc' ='id ^'),
'id'); ?
[/code]
How do i get class definitions inside?
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Okay, thats the reason. I have to much standard definitions in the
cake.generic.css. It would take me to much time to change all this.
But inspite of this, i used some of your definitions! :-)
I'm new to CSS (and also to CakePHP), so some source code was very
usefull for me.
Thanks a lot for all
Hello again and thanks.
I got an arrow in my column header. But its every time (asc or desc)
the same arrow, so i think, the paginate source code is still wrong.
My problem is still, that i dont know how to combine two classes in
one paginate function.
[code dont works]
?php echo
Hello again and thanks.
I got an arrow in my column header. But its every time (asc or desc)
the same arrow, so i think, the paginate source code is still wrong.
My problem is still, that i dont know how to combine two classes in
one paginate function.
[code dont works]
?php echo
Okay, its done.
Firefox solution:
[code]
.input
{
width:45em;
float:none;
}
.input label
{
width:25%;
float:left;
}
.input input
{
width:50%;
}
[/code]
Internet Explorer 8 solution:
[code]
.input
{
width:45em;
float:none;
}
.input label
{
width:25%;
float:none;
}
.input
Addition:
[code]
uarr;
[/code]
also works. But also _not_ inside the paginate source code.
Any ideas?
Thanks if someone can help!
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John
Hello,
thank you. I had a similar idea. But how do i code this?
[my css code]
#input
{
float:left;
}
[/code]
[view code]
echo $form-input('db_field', array('label' = 'Label', 'maxLength' =
'20%', 'div' = array('id' = 'input')));
[/code]
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Hello again John,
this outputs a strange sign:
Seems like its the arrows hex code.
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Thanks. It works when i write:
[code]
?php echo '#x2191;' ?
[/code]
But _NOT_ with paginate:
[code]
?php echo $paginator-sort(array('asc' ='id v', 'desc' ='id
#x2191'), 'id');
[/code]
What's wrong there?
Regards.
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Hello John,
thank you very much!
With this code, it looks like in the following screenshot:
[code]
.input
{
width:45em;
float:left;
}
.input label
{
width:25%;
float:left;
}
.input input
{
width:75%;
float:left;
}
.input input[type=checkbox]
{
float: none;
width:
Do I understand you correctly, that you don't want the other fields
(name, index, status, etc.) to have the label aligned horizontally
with the input field?
I want, that fields like Name or Duplex look equal to fields like
VLAN or Uplink.
That means, the i want the label on the left and next
Hello,
when i create my automagic form elements, they look like:
label // --- new line
empty text field
Can i disable this word wrap?
Thanks!
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You received this message because
Hello,
my charset is set to UTF-8.
But how do i output a UTF-8 sign inside PHP?
For example an arrow (U+2191) in a table cell:
[code]
th?php echo $paginator-sort(array('asc' ='id U+2193', 'desc'
='id U+2191'), 'id'); ?/th
[/code]
regards and thanks!
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Another addition:
When i only insert the image, without the $html-link, it works in
internet explorer 8.
[code works but without link]
?php echo $html-image(edit.png, array(alt = Editieren)); ?
[\code]
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Addition:
I'm really sorry but i forgot my self defined css... :(
So this works for Firefox:
[code]
?php echo $html-link('Edit', array(controller = 'dns_names',
action = edit, $dns_name['Dnsname']['id']), array('class' =
'edit', title = Editieren), null, false); ?
[/code]
And when i remove:
cricket
Also thanks to you. It dont works in both browsers. Dont know why.
Anyway... i decided that i dont use CSS for this. I got it working so
far but i still have one problem.
[this code works (without the CSS class, but its okay]
?php echo $html-image(edit.png, array(alt = Editieren, 'url'
=
The solution was an empty array
[dynamic code]
?php echo $html-link($html-image(delete.png, array(alt =
Löschen)), array(controller = $contr, action = delete,
$row[$class]['id']), array(), sprintf(__($deleteQuestion, true),
$row[$class]['id']), null, false); ?
[/code]
Really thanks a lot to
Hello,
i want to show an element in a table cell.
[element code]
?php echo $html-link($html-image(edit.png, array(alt =
Editieren)), array(controller = $contr, action = edit,
$row[$class]['id']), array('class' = 'edit', title = Editieren),
false); ?
[/code]
[code in view]
td?php echo
Hello,
thanks for the suggestion.
I just compared it. The source code is the same.
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To post
sure :-)
[HTML Code for the table cell:]
tda href=/dns_names/edit/1 class=edit title=Editierenlt;img
src=quot;/img/edit.pngquot; alt=quot;Editierenquot; /gt;/a /
td
[/code]
Addition: When i copy the element outside the table, it works fine.
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cricket
Do you mean the code should be:
[code]
?php echo $html-link($html-image(edit.png, array(alt =
Editieren)), array(controller = $contr, action = edit,
$row[$class]['id']), array('class' = 'edit', title = Editieren),
null, false); ?
[/code]
Then it creates the following
[html source code:]
Yes, i see it.
When i copy the element outside the table, it works fine.
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To post to this
Hello again and really thank you cricket and John!
OK. Copy the HTML source and paste it directly into the view and see
if the image link are accessible inside the table.
Same as before. When i substitute the variables it works fine in
Firefox but _not_ in Internet Explorer :/
Check out the
Ok. I made it working.
[controller code]
function view($temp, $value)
{
$this-set('persons', $this-paginate('Person', array('Person.'.
$temp = $value)));
}
[/code]
[view code for one table cell (in this example the table cell for
column forename)]
?php $value= $row['Person']['forename'];
Hello,
how can i pass a variable from a view to the associated controller? I
need this because i want to reload the view with other values for
paginate.
I'd like to do this inside html-link. The two variables are named
value and temp.
temp should contain the database field in the suitable form,
Martin
Thank you for helping me!
When i do what you suggest, i see the special chars. (echo 'áéíóúñ£
€';)
But, in your message, i dont see this characters. i only see it in the
e-mail, which i get when someone put a message here.
Greetings.
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Martin, cricket
Hello,
Assume you are using mysql -- yes
1) Make sure you have add this to database.php default array
config:'encoding' = 'utf8' -- done
2) Make sure the table collation is utf (could be uft8_general_ci) --
done
3) Make sure the table is empty --
Martin, cricket
Thanks for your help. The problem is solved. I made failures with the
editor.
I opened every file and choose UTF-8 without BOM and thought, that
at this point, the file is UTF-8 converted. This is wrong.
I have to open every file and use Convert to UTF-8 without BOM.
Sorry for
Hello,
instead of umlauts, i see only signs on my website. I think the
problem occurs because i developed with Windows 7 with a tool which is
not UTF-8 compatible and later, i moved the needed files to Ubuntu. To
solve this, i downloaded the Notepad++ Editor. Then i opened all files
and checked
John
Thank you very much.
It works when i change the first code line to:
[code]
$rowCount = $this-Location-Room-find(
[/code]
Also thanks for the possibility of using Counter-Cache.
Is counter-cache also working (counting) when i insert my data the
first time via MySQL (with INSERT)?
Greetings
Great! Thanks again! :-)
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To
Hello,
With this code, my problem is solved.
[CODE]
script type=text/javascript
function toggleColumn(table, column) {
for (var i = 0; i table.rows.length; i++){
if (table.rows[i].cells.length column){
var cell = table.rows[i].cells[column];
Thanks cricket.
Another addition, i someone else has a similar problem.
It also works without CONTAINABLE. Just keep the associations in the
model and the view code to retrieve and use the following in the
controller:
[code]
var $paginate = array(
'limit' = 50,
Jeremy Burns
Hello again :)
Code in the model of my port-table:
(the $hasOne association from my origionally question was updated to
the association below:)
[code]
public $hasMany = array(
'Port' = array(
'className' = 'Port',
'foreignKey' = 'uplink_id'
)
);
[/code]
I
sure! :-)
[code of model port]
public $belongsTo = array(
'HardwareUnit' = array(
'className' = 'HardwareUnit'
),
'Vlan' = array(
'className' = 'Vlan'
),
'PortEmploymentGroup' = array(
'className' = 'PortEmploymentGroup'
Jeremy
It works with a little modification :) great!!!
The modification is to change ChildPort to ParentPort in the
following code:
[code]
var $paginate = array(
'fields' = array('*'),
'recursive' = 2,
'limit' = 50,
'order' =
I use this in my controller:
[controller code]
var $paginate = array(
'fields' = array('*'),
'recursive' = 2,
'limit' = 50,
'order' = array('Port.hardware_unit_id' = 'asc'),
'contain' = array(
cricket
Again... thanks a lot for your help.
It seems to work. When i debug, i get this:
==
Array
(
[Port] = Array
(
[id] = 1
[hardware_unit_id] = 1
[vlan_id] = 1
[port_employment_group_id] = 3
[uplink_id] =
Jeremy
Thanks! :) That works.
But now, i thought i was ready i noticed another problem.
The debug output above is for a port, which has no value in the field
uplink_id. But the port with id - 3 has value 1 in uplink_id.
So port with id 3 points to port with id 1.
Now, the problem is, that i
On 2 Mrz. 2009, 19:25, mscdex msc...@gmail.com wrote:
On Mar 2, 7:20 am, krishan milepe...@gmail.com wrote:
I usually do this sort of checking in the model validation or in the
delete controller action before the deletion is attempted. Something
like a find('count') or similar method to
Thanks for your help but i still dont get it working. sorry for my bad
knowledge.
In my addModel, i added this line: [code]var $actsAs =
array('Containable');[/code]
In my controller i tryed this to use contain with paginate:
[code]
$this-set('ports', $this-paginate('Port', array('fields' =
logout
Thanks very much for your help! (Also thanks to Miles J.)
All of your recently created code works! :)
I've diceded to take the last one.
The purpose is to toggle (show and dont show) a data row. So i dont
want to follow the link.
Thanks again :)
Greetings.
Check out the new CakePHP
Hello,
I'd like to show the following things in my view (respectively in the
field uplink_id in the view): attribute uplink_id from table ports
with attribute schenker_number from table hardware_units.
My problem are the associations, respectively i don't know the source
code to retrieve the
cricket
Thanks for your answer.
Can i use recursive with pagination too?
I need the pagination because of a sort auomatic in my view.
And despite of debug, i really dont know how to retrive.
I have to go the following way: uplink_id (table ports) - id (table
ports) - hardware_unit_id (table
John
thanks, your idea sounds good.
So i think, i'd like to make the cell content a link and when i click
on it, it should load a view. This view should only show datarows,
with a equal cell (compared with the cell i clicked) inside.
Is that understandable?
[conroller action]
function view()
{
logout
Hello,
when i try this, an error occurs: Parse error: syntax error,
unexpected ')', expecting ',' or ';'
Greetings
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Hello,
i want to isert a mixed Code (javascript and php) into my $html-link,
but i don't know how to do this.
[javascript with php code]
javascript:void(0) onclick=toggleId('?php echo $zeile?');
[end code]
[$html-link code]
?php echo $html-link($html-image(edit.png, array(alt =
edit)), ---think
Thanks but its not working.
the address bar shows only -javascript:;
Greetings.
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Hello,
in a foreach-loop to retrieve my data, i want to check a value from a
field. So i can retrieve only the data, i want.
I tryed:
[code]
foreach ($rows as $row = 'Model.field' = 0):
[/code]
In this example, i only want to retrieve all data-rows from model
Model, which has value 0 in the
Chris
I want to do it in my view.
Thanks a lot, it works great! :)
Thanks thanks thanks! :)
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Hello,
in my view, i have a table with data inside. For example, one column
is named hardware_groups and the content of the cells is something
like: printer, notebook, workstation, and so on.
Is there a simple way to select, for example, only the notebooks?
Hope my problem is understandable.
WebbedIT, Cristian, majna
Thanks a lot! :-)
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Well, i forgot a problem.
Now, i have my global add-function in my appController.
But some add-views have drop-down fields to show the available
foreign-
keys. They additional use this code:
[code]
$this-set('foreignKey', $this-Model1-Model2-find('list'));
[/code]
So, can i extend the
John
Thanks again!!!
You solved it. :)
Here is the code from one of my add-functions, which has a drop-down
field with foreign-key elements.
[code]
function add()
{
parent::add();
$this-set('staffs', $this-HardwareUnit-Staff-find('list'));
$this-set('rooms',
Paul
In my inventory-management, every table/model has the need of an add-
function. The models are, for example: rooms, locations,
hardware_groups, hardware_units, mobile_radio_units, ports ... and so
on.
Furthermore, the add functions are equal to each other, expect, if
there is an foreign-key
Thanks for your answers but i think it's to difficult for me to solve
that.
But thanks a lot!
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John
You only use {$this-modelClass} when you want to use the model
instance.
Thats it. Thanks very much! :)
If someone other wants to use this, here is my final code (add
function in app_controller):
[code]
function add()
{
if(!empty($this-data))
{
John
You only use {$this-modelClass} when you want to use the model
instance.
Thats it. Thanks very much! :)
If someone other wants to use this, here is my final code (add
function in app_controller):
[code]
function add()
{
if(!empty($this-data))
{
Hello again WebbedIT, :-)
i found something in the book and got some simple paginating links
working in my views.
[code]
?php
echo $paginator-link('50', array('limit' = 50));
echo $paginator-link('75', array('limit' = 75));
echo $paginator-link('100', array('limit' = 100));
?
[/code]
Is
Hello again WebbedIT, :-)
i found something in the book and got some simple paginating links
working in my views.
[code]
?php
echo $paginator-link('50', array('limit' = 50));
echo $paginator-link('75', array('limit' = 75));
echo $paginator-link('100', array('limit' = 100));
?
[/code]
Is
John,
Hello and thanks for your help.
Are your controllers only using one model and the models is named the
same as the controller (singular)? If that is so, you don't need to
pass the model, just take your controllers name and Inflect it into a
model name and use that!
Yes, for example i have
Paul,
hmm, it dont works :/
Could you look at the source please?
And should i pass something to the view and write it in the brackets
after function add?
[controller code]
function add()
{
if(!empty($this-data))
{
John, Jon
Thanks a lot for helping me.
Here is my working add-function in the app-controller if someone want
to see an example:
[code]
function add()
{
if(!empty($this-data))
{
if($this-{$this-modelClass}-save($this-data))
Well, i have a continative problem.
Now, i have my global add-function in my appController.
But some add-views have drop-down fields to show the available foreign-
keys.
So how can i extend the concerning controllers with my foreign-key
drop-down field code?
[code]
$this-set('foreignKey',
Well, when i write down the complete add-function again (with
additional foreign-key content) in the controllers, that need this
additional content, it seems to work.
But is it possible, to only add the foreign-key content to the
controllers instead of the complete function?
Check out the new
Hello,
thanks for your help!!!
But with this code, if i copyed it on the right places, i every time
go back to the add view :/
But the destination should be the view where i came from.
Hmm, or it's my mistake. Could you tell me, where i exactly have to
post this code?:
if
Hello,
i'd like to build a global-add function in the appController, so that
all controllers can use it. is that possible?
[App-Controller code:]
function add($modell)
{
if(!empty($this-data))
{
if($this-$modell-save($this-data))
Hello,
How can i redirect to a view, where i came from?
Example:
In view A, i click a button which opens the edit view B
When the user completes the edit action and clicks on save, i want to
redirect to view A.
(with refer, the redirect goes to view B :( )
Thanks a lot, if someone can help!
Hello,
i'd like to manually set the limit-option on the fly in my views.
So, for example, there could be 3 fields with 10, 25 and 50 or a
input field to write the number.
Thanks a lot if someone can help!!!
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Hello,
thanks, but i know this code.
The problem is, that i have to redirect dynamical to the view, where i
came from, because you can access some views from many other views.
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You
Oh sorry, i don't want to edit, i want to add.
I create an inventory management.
When i'm in view hardware units, it's handy to add (via global drop
down menu) a hardware group.
This helps me to save time because without that global drop-down, i
have to go to view hardware groups, then add once,
Hello,
in a complete rendered view, is it possible to blank (hide) columns
and show those again (for example by clicking on column-caption like
paginating)?
Hope my question is understandable.
Thanks very much if someone can help.
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WebbedIT
It works. Thanks a lot! :)
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Miles J
Thank you very much, thats it. :)
If others want to change the output-style, see here:
http://book.cakephp.org/view/44/CakePHP-Core-Configuration-Variables
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Hello,
how can i disable the CakePHP section (in this section are sql
statements) on the bottom of each view?
Thanks a lot!
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Guillermo
No, i'd like something like a pop-up warning window, which says: are
you sure you want to delete?.
Is this possible with an image-link?
[code]
?php echo $html-image(delete.png, array(alt = delete,
'url' = array('controller' = 'hardware_units', 'action' = 'delete',
'id' =
Hello,
i have a question about some signs. Is the use of this sample
always equal to this 'sample' ?
Thanks!
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arif, paulos
Hello,
i merged your ideas, this code works for me. It is a image, which
links to a view and it outputs a confirm message with the current row
number (id).
I used this for a delete option.
[code]
?php echo $html-link($html-image(delete.png, array(alt =
delete, title = delete)),
Hello all,
i finally got it working!!! :-)
i merged some ideas i found in the google-group, so the following code
works for me. It is an image, which links to a delete-view and it
outputs a confirm message with the current row number (id).
[code]
?php echo $html-link($html-image(delete.png,
Addition: It also would be nice, if the cell width would fit to the
cell content.
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Thanks. Furthermore, is it possible to create only a horizotal line
under each complete data-row?
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Thanks! That works for me:
[code]
style type=text/css
th { white-space:nowrap; }
/style
[/code]
Furthermore, is it possible to create only a horizontal line under
each complete data row?
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.
Mike Karthauser
Brightstorm limited
Tel: 07939252144
On 11 Feb 2010, at 07:19, sebb86 kahlc...@googlemail.com wrote:
Hello,
when i retrieve my data in table-cells, how can i avoid line breaks,
for example in the table header?
[retrieve-code]
!-- table- (column-) captions
Jeremy
Thanks for your answer.
But actually i'd like to create a button (not a button-picture), which
links to a view.
I don't want to add a picture, because every button would have an
other description.
So is this possible to realize or must i create lots of pictures? ;-)
Thanks.
Check out the
Hello all,
thanks for all your answers. After reading all your answers, i've
decided to use a image, which links to a page.
Could someone help me to add a warning-message, e.g. when i delete
something???
Here is my image/link code from the view:
[code]
?php echo $html-image(delete.png,
the session messages var in your layout
On 11 February 2010 11:25, sebb86 kahlc...@googlemail.com wrote:
Hello all,
thanks for all your answers. After reading all your answers, i've
decided to use a image, which links to a page.
Could someone help me to add a warning-message, e.g. when i
Addition:
this works with the $hrml-link but not with $html-image. :-(
[code]
?php echo $html-link('Delete', array('action' = 'delete', 'id' =
$hardware_unit['HardwareUnit']['id']), null, 'Sind sie sicher?'); ?
[/code]
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Hello,
when i retrieve my data in table-cells, how can i avoid line breaks,
for example in the table header?
[retrieve-code]
!-- table- (column-) captions --
table
tr
th?php echo $paginator-sort(array('asc' ='id v', 'desc'
='id ^'), 'id'); ?/th
th.../th
matzehahn
Thanks for this link. Unfortunately this source don't worked with my
edit-function (add worked).
I tryed to change the source, but without success.
BrendonKoz
Thanks also for your help. I tryed some hours to get all this working
but also without success.
Fortunately, i found a
John
That's it. Thanks very much!!! :)
Here is the complete code with columns, if needed:
[code]
!-- table- (column-) captions --
table
tr
th?php echo $paginator-sort(array('asc' ='id v', 'desc'
='id ^'), 'id'); ?/th
th?php echo $paginator-sort(array('asc'
Hello,
in my database, there is a HABTM association between model rooms and
staffs.
In my index-view of staffs, when i retrieve the data, i'd like to
have an extra column for each datarow with all rooms, which belongs to
the current staff(id).
The join table contains room_id and staff_id and is
Hello,
i almost solved my problem, but there is still a little fault. In one
of my views i readout a database cell, with a text inside, e.g. 13.pdf
(13.pdf = document_name).
The little fault is, when i click on the text in the column (e.g.
13.pdf) a download-windows opens and the file i download
Hello,
my table **rooms** contains three fields: //id//, //building_id//
and //room//.
//Building_id// and //room// have to be UNIQUE together, because room
9 is in building 1 only one time but room 9 can also conained in
building 2.
The //building_id// in the view is realized as a drop-down
Hello,
I'd like to show the following things in my view (respectively in the
field uplink_id in the view): attribute uplink_id from table ports
with attribute schenker_number from table hardware_units.
My problem are the associations, respectively i don't know the source
code to retrieve the
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