5-4-3 rule

hi, guy Please tell what is 5-4-3 rule mean ? Thanks   Tang

5-4-3 Rule

Hi all, What is 5-4-3 rule? -SU ___ UPDATED Posting Guidelines: http://www.groupstudy.com/list/guide.html FAQ, list archives, and subscription info: http://www.groupstudy.com Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]

5-4-3 Rule

Hi everyone Can someone pls explains the reason behind the limits of 5 segments and why only 3 segments can be populated with nodes? Thanks Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com

Re: 5-4-3 rule

> caifeng tang wrote: > > hi, guy > Please tell what is 5-4-3 rule mean ? > Thanks Starting the days of coaxial ethernet (10Base2/10Base5) there was a limitation per subnet of : * five cable segments, connected by * four repeaters, but only * three segments coule be p

RE: 5-4-3 rule

k. Model 1: Simplified model widely known as 5-4-3 rule. Model 2: Calculation of Roundtrip delay (<576 bit times) and Interframe Gap shrinkage (50 bit times) In model 1, there can be 5 segments connected by 4 repeaters, but only 3 can have stations on them (half duplex mode), the other 2 MUST BE

Re: 5-4-3 rule

Thanks everybody. Tang - Original Message - From: "Dusty Harper" <[EMAIL PROTECTED]> To: "caifeng tang" <[EMAIL PROTECTED]>; "Cisco" <[EMAIL PROTECTED]> Sent: Sunday, October 08, 2000 10:48 PM Subject: RE: 5-4-3 rule > 5 segments separ

OT: 5-4-3 rule

Using the 5-4-3 rule, why can only 3 segments be populated __ Do You Yahoo!? Yahoo! Messenger - Talk while you surf! It's FREE. http://im.yahoo.com/ _ FAQ, list archives, and subscription info:

RE: 5-4-3 Rule

There is a basic rule of thumb to follow with 10 Mbps Ethernet networks. It is commonly known as the 5-4-3 rule and represents the following Ethernet limitations : 5 4 3 Maximum 5 Segments 4 Repeaters 3 Populated Segments Jim C avec CC alphabet soup. =) -Original Message- From

RE: 5-4-3 Rule

inal Message- > From: Suresh Uniyal [SMTP:[EMAIL PROTECTED]] > Sent: Tuesday, August 29, 2000 4:29 PM > To: Cisco (E-mail) > Subject: 5-4-3 Rule > > Hi all, > > What is 5-4-3 rule? > > -SU > > ___ > UPDATED Posting Guidelin

RE: 5-4-3 Rule

This rule is really no longer accurate. To truly find out if your network is within spec, you need to figure the round trip bit delay per segment and device. the 5-4-3 rule is about like the 80/20 rule great for the old days but not for today. Andre' Paree-Huff A+, ASE/LAN, CCNP, MCSE+I

RE: 5-4-3 Rule

esday, August 29, 2000 8:45 AM To: Croyle, James; 'Suresh Uniyal'; Cisco (E-mail) Subject: RE: 5-4-3 Rule This rule is really no longer accurate. To truly find out if your network is within spec, you need to figure the round trip bit delay per segment and device. the 5-4-3 rule is about

RE: 5-4-3 Rule

Title: RE: 5-4-3 Rule Woo hoo! I found one I can answer! Let's see, it's used with Ethernet, in that there can be 5 segments, four repeaters/hubs, but only three can have stations attached. If you've studied how routers work, it is not a logical subnet such at one made by IP

RE: 5-4-3 Rule

nected. > > group , pls correct me if I'm wrong. > > HP > > > -Original Message- > > From: Suresh Uniyal [SMTP:[EMAIL PROTECTED]] > > Sent: Tuesday, August 29, 2000 4:29 PM > > To: Cisco (E-mail) > > Subject:5-4-3 Rule > > >

RE: 5-4-3 Rule

I'm wrong. > > HP > > > -Original Message- > > From: Suresh Uniyal [SMTP:[EMAIL PROTECTED]] > > Sent: Tuesday, August 29, 2000 4:29 PM > > To: Cisco (E-mail) > > Subject:5-4-3

RE: 5-4-3 Rule

his topics seems to come back periodically. Good that I saved my original reply from a few months back: The answer has to do with the IEEE 802.3 standards. There are actually two models how to calculate a "valid" ethernet network. Model 1: Simplified model widely known as 5-4-3 rul

Re: 5-4-3 Rule

The part about three populated segments is based on 10base-2/5 and doesn't apply to current designs using UTP and hubs/switches. So, for the modern world its the 5-4 rule. JOE CCNP, CCDP, and a few other things... CCIE Lab - May 27/28 ""Cisco man"" <[EMAIL PROTECTED]> wrote in message [EMAIL P

RE: 5-4-3 Rule

The answer has to do with the IEEE 802.3 standards. There are actually two models how to calculate a "valid" ethernet network for 10Base2/5. Model 1: Simplified model widely known as 5-4-3 rule. Model 2: Calculation of Roundtrip delay (<576 bit times) and Interframe Gap shrinkage

Re: OT: 5-4-3 rule

>From a document at U Texas: (http://wwwhost.ots.utexas.edu/ethernet/ch13-ora/ch13.html) --Begin Quote--- The "5-4-3" Rule An over-simplified version of the 10 Mbps Model 1 rules, called the "5-4-3" rule, has been circulating

5-4-3 rule [7:65140]

Hi to all pros, I would like to ask a very simple which is also very confusing. If I connected three hubs together have I break a 5-4-3 rule? But I don't think I have break the 5-4-3 rule because I believe the wiring of the hub is a bus circuit which is a segment and with three hubs conn

Re: 5-4-3 rule [7:65140]

being unable to detect collision(csma-cd will fail) ""Tiongster"" a icrit dans le message de news: [EMAIL PROTECTED] > Hi to all pros, > > I would like to ask a very simple which is also very confusing. If I > connected three hubs together have I break a 5-4-3 rule?

RE: 5-4-3 rule [7:65140]

Tiongster wrote: > > Hi to all pros, > > I would like to ask a very simple which is also very confusing. > If I > connected three hubs together have I break a 5-4-3 rule? No, 3 hubs connected together does not break the 5-4-3 "rule." > But I > don't >

5-4-3 rule segment definition for 10BaseT [7:46439]

Hi all, I am unable to find from the archive the discussion on the 5-4-3 rule. What is the definition of a segment for 10BaseT? How can I apply the 5-4-3 rule in a 10BaseT network? I attended a Novell class a few years back and was taught that in the 10BaseT network, it makes use of a

RE: 5-4-3 rule segment definition for 10BaseT [7:46439]

Well here is a start: the 5-4-3 rule reffers to 5 segments 4 repeaters 3 populated segments Pierre-Alex Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=46667&t=46439 -- FAQ, list archives, and subscription in