RE: 5-4-3 rule [7:65140]

Tiongster wrote: > > Hi to all pros, > > I would like to ask a very simple which is also very confusing. > If I > connected three hubs together have I break a 5-4-3 rule? No, 3 hubs connected together does not break the 5-4-3 "rule." > But I > don't > think I have break the 5-4-3 rule because

Re: 5-4-3 rule [7:65140]

the rule is 5 hubs 4 segments and only 3 populated segments but the above only applies to 10base x the hall problem is the the round trip propagation that cannot exceed 512bit time, so for a 10base x, the maximun roud trip should be 51.2microsecs or less, other wise problems will manifest, by being

RE: 5-4-3 rule segment definition for 10BaseT [7:46439]

Well here is a start: the 5-4-3 rule reffers to 5 segments 4 repeaters 3 populated segments Pierre-Alex Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=46667&t=46439 -- FAQ, list archives, and subscription info: http://www

Re: 5-4-3 rule

Thanks everybody. Tang - Original Message - From: "Dusty Harper" <[EMAIL PROTECTED]> To: "caifeng tang" <[EMAIL PROTECTED]>; "Cisco" <[EMAIL PROTECTED]> Sent: Sunday, October 08, 2000 10:48 PM Subject: RE: 5-4-3 rule > 5 segments separ

RE: 5-4-3 rule

just recovered from some old archives hp this topics seems to come back periodically. Good that I saved my original reply from a few months back: The answer has to do with the IEEE 802.3 standards. There are actually two models how to calculate a "valid" ethernet network. Model 1: Simp

Re: 5-4-3 rule

> caifeng tang wrote: > > hi, guy > Please tell what is 5-4-3 rule mean ? > Thanks Starting the days of coaxial ethernet (10Base2/10Base5) there was a limitation per subnet of : * five cable segments, connected by * four repeaters, but only * three segments coule be populated. This ha

RE: 5-4-3 Rule

ginal Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Reinhold Fischer Sent: Tuesday, August 29, 2000 3:41 PM To: Hitesh Pathak (CSD-BBYRO-RTSG) Cc: 'Suresh Uniyal'; '[EMAIL PROTECTED]' Subject: RE: 5-4-3 Rule Sorry, you are wrong ;) the rule defines

RE: 5-4-3 Rule

Sorry, you are wrong ;) the rule defines that you canNOT have more than 5 segments with 4 repeaters and NO more than 3 segments can be populatet. hth, Reinhold -- Reinhold Fischer CCNP/SCSA/HP Certified Consultant for Network Management On Tue, 29 Aug 2000, Hitesh Pathak (CS

RE: 5-4-3 Rule

Is the rule applies to Bus topology only or applicable for any topologies ? -SU > -Original Message- > From: Hitesh Pathak (CSD-BBYRO-RTSG) [SMTP:[EMAIL PROTECTED]] > Sent: Tuesday, August 29, 2000 5:24 AM > To: 'Suresh Uniyal' > Cc: '[EMAIL PROTECT

RE: 5-4-3 Rule

Title: RE: 5-4-3 Rule Woo hoo! I found one I can answer! Let's see, it's used with Ethernet, in that there can be 5 segments, four repeaters/hubs, but only three can have stations attached. If you've studied how routers work, it is not a logical subnet such at one made by IP

RE: 5-4-3 Rule

esday, August 29, 2000 8:45 AM To: Croyle, James; 'Suresh Uniyal'; Cisco (E-mail) Subject: RE: 5-4-3 Rule This rule is really no longer accurate. To truly find out if your network is within spec, you need to figure the round trip bit delay per segment and device. the 5-4-3 rule is about

RE: 5-4-3 Rule

, Net+, I-Net+   Compaq Computer Corp. NACSC/NSU V: 317-598-9928 F: 317-598-9949   -Original Message- From: Croyle, James [mailto:[EMAIL PROTECTED]] Sent: Tuesday, August 29, 2000 5:48 AM To: 'Suresh Uniyal'; Cisco (E-mail) Subject: RE: 5-4-3 Rule There is a basic rule of thumb

RE: 5-4-3 Rule

It defines a general networking setup like if u have a single network then it should have 5 segments , 4 repeaters & out of 5 segments atleast 3 should be populated ie. on 3 segments you should have some node connected. group , pls correct me if I'm wrong. HP > -Original Message- > From

RE: 5-4-3 Rule

There is a basic rule of thumb to follow with 10 Mbps Ethernet networks. It is commonly known as the 5-4-3 rule and represents the following Ethernet limitations : 5 4 3 Maximum 5 Segments 4 Repeaters 3 Populated Segments Jim C avec CC alphabet soup. =) -Original Message- From: Sure

RE: 5-4-3 Rule

The answer has to do with the IEEE 802.3 standards. There are actually two models how to calculate a "valid" ethernet network for 10Base2/5. Model 1: Simplified model widely known as 5-4-3 rule. Model 2: Calculation of Roundtrip delay (<576 bit times) and Interframe Gap shrinkage (50 bit times) I

Re: 5-4-3 Rule

The part about three populated segments is based on 10base-2/5 and doesn't apply to current designs using UTP and hubs/switches. So, for the modern world its the 5-4 rule. JOE CCNP, CCDP, and a few other things... CCIE Lab - May 27/28 ""Cisco man"" <[EMAIL PROTECTED]> wrote in message [EMAIL P