ike to go 3D, and the symmetry of our system would allow to
>> use a 2D cylindrical grid (r,z) - with zero flux at z=0 and z=L (and
>> r=0), and either Dirichlet/zero flux at r=R. Looking at the mailing list
>> archive and GitHub, it appears that cylindrical coordinates are at the
hive and GitHub, it appears that cylindrical coordinates are at the
> moment not working properly (missing factor)
Yes, that's correct. Sorry about that.
> Is this still the case?
>
> If so, I will start with a simple 3D Cartesian mesh, and then perhaps
> move to more adapted meshes
recipients of list <fipy@nist.gov>
Betreff: Re: Gradient in cylindrical coordinates
Also, note that the "leastSquaresGrad" doesn't have this issue:
https://gist.github.com/wd15/fc34ccb2e57602fc6f9bea96d8160f4a#file-untitled-ipynb
See,
https://www.ctcms.nist.gov/fipy/fipy/generated/fip
Leyton -
A compressible flow example contribution would be most welcome! Please submit a
[pull request](https://github.com/usnistgov/fipy/pulls) and we'll work with you
to get it integrated and released.
[don't hesitate to ask if you need help making the pull request]
- Jon
> On Jan 5, 2018,
Fipy Team,
>>
>>
>>
>> First of all I would like to thank you for your amazing work! I love working
>> with fipy.
>>
>>
>>
>> I have a problem when I calculate the gradient of my variable in cylindrical
>> coordinates. You can s
at 7:23 PM, Munoz Leyton
<leyton.mu...@hirtenberger.com> wrote:
> Dear Fipy Team,
>
>
>
> First of all I would like to thank you for your amazing work! I love working
> with fipy.
>
>
>
> I have a problem when I calculate the gradient of my variable in cylindrical
&g
The Volume for a 2D mesh is the area of the cell. The Volume for a
1D mesh isthe length of the cell.
The CylindricalGrid2D represents a wedge that subtends 1 rad.
Ah, I see now. Thank you for the clarification!
For what I want to do, I have actually found that the following few lines
On Tue, Jun 19, 2012 at 1:04 PM, Jonathan Guyer gu...@nist.gov wrote:
On Jun 19, 2012, at 12:20 PM, Kendall Boniface wrote:
I am having a bit of trouble manipulating a 2D cylindrical mesh and was
wondering if anyone has any helpful advice?
mesh = CylindricalGrid2D(dx=dx, dy=dy, nx=nx,
On Jun 20, 2012, at 11:20 AM, Kendall Boniface wrote:
I'm a bit confused about the getCellVolumes() function. Since I am using the
2D cylindrical grid, I assume it isn't actually giving me volumes so to
speak. I've manually played around with some of my numbers and can't seem to
figure
Hello again,
I am having a bit of trouble manipulating a 2D cylindrical mesh and was
wondering if anyone has any helpful advice?
I want a mesh that is 1.5 meters in the z direction and has an inner radius
of 0.0046 m and an outer radius of 0.00635 m (to model the wall of a pipe).
This is what I
On Jun 19, 2012, at 12:20 PM, Kendall Boniface wrote:
I am having a bit of trouble manipulating a 2D cylindrical mesh and was
wondering if anyone has any helpful advice?
mesh = CylindricalGrid2D(dx=dx, dy=dy, nx=nx, ny=ny) + ((0.0046,),)
print mesh.getCellCenters()
I want the z axis
I pasted the gmsh commands into a file and ran gmsh on it. It threw a
weird error
** On entry to DGESVD parameter number 6 had an illegal value
What error did you get? Did you adapt the gmsh commands from
somewhere? Maybe we could work from that and check that those commands
work
On Jan 19, 2007, at 10:51 PM, Matt Koch wrote:
Rejected message: sent to fipy@nist.gov by [EMAIL PROTECTED] follows.
Reason for rejection: sender not subscribed.
---
Hi Jonathan,
I have to deal with both a
to do it
in the case of cylindrical coordinates
it to avoid making changes to the discretization of the equations. I
believe (needs to be confirmed) that changing the
cell volumes and face areas does in fact allow you to use cartesian
discretization with cylindrical coordinates.
As far as my
are talking
about a 3D model then. No need to talk about cylindrical coordinates
then, simply model an arbitrary shape (such as a cylinder) in
rectangular 3D space? The question then is, how well will a mesh
approximate curved surfaces? Plus, no matter how thin the slice in 3D, a
computational
theta) of the slice?
Exactly.
We really are talking about a 3D model then. No need to talk about
cylindrical coordinates then, simply model an arbitrary shape (such
as a cylinder) in rectangular 3D space?
Not exactly. The slice of pie will only be one cell deep. It's only a
sliver of pie
, but it is a little too advanced
for me.
This exchange discusses wedge shaped meshes that are a requirement
for faking cylindrical coordinates using
Cartesian discretization. If you want to solve a 2D cylindrical
problem, you need to create a 3D wedge shaped mesh.
This may be possible in gmsh
.
This exchange discusses wedge shaped meshes that are a requirement for
faking cylindrical coordinates using
Cartesian discretization. If you want to solve a 2D cylindrical
problem, you need to create a 3D wedge shaped mesh.
This may be possible in gmsh and then you can use the Gmsh importer to
read
in order to switch on
cylindrical coordinates? From the above entry, I am almost guessing that
one would have to implement their own divergences and such in
cylindrical coordinates by adding the radius in proper places of the
divergences and such in rectangular coordinates? That can't be right
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