I am using 'spstere' for polar stereo graphic projection over Antarctica.
The specifications llcrnrlat, llcrnrlon etc are specified in a python
module. When I am doing it over north pole it is okay. But in South pole
the latitude circles are not appearing. Can anyone tell where is the fault?
Sourav Chatterjee
September 11,
2013 3:48 AMI am using 'spstere' for polar
stereo graphic projection over Antarctica. The specifications llcrnrlat,
llcrnrlon etc are specified in a python module. When I am doing it over
north pole it is okay. But in South pole the latitude
Hello Paul,
Sorry for the late reply I have been away for a couple of days. Thanks for
filing the issue, I would very much appreciate it if you manage to track it
down.
Luke
On Tue, Jan 17, 2012 at 1:47 AM, Paul Hobson pmhob...@gmail.com wrote:
Luke,
I don't have an answer to your question,
Hello
I sent this email just after Christmas and would appreciate it if anyone
has any suggestions. I am unsure if I have missed a parameter or should I
file a bug?
Thanks
Luke
-- Forwarded message --
From: Luke Jennings ubuntujenk...@googlemail.com
Date: Mon, Dec 26, 2011 at
Hello,
I am plotting polar graphs for a university project, the data is
confidential but I based the work on this example
http://matplotlib.sourceforge.net/examples/pylab_examples/polar_demo.html
and fortunately
the same problem occurs with this. If you take that code and change the
last four
Dear Forum,
I want to send the polar grid lines (circles and radial lines) behind the
plot. How can I do that? I tried other options but unable to do so. Here, I
am taking matplotlib example. Please get back to me on this.
Thanks!!!
Example: polar_demo.py
import matplotlib
import numpy as np
I am using a workaround now. But that is a hackery solution.
Before plotting my data I convert it to dBs and limit it to the lowest value
I want to display. Then I plot it using a regular polar plot with a custom
formatting function that sets the tick labels with respect to the data
offset.
Ben,
I should have mentioned that I already tried that. When I set the rscale to
'log' the plot crashes when zooming or mpl cannot even create it.
Maybe some example code will help:
from numpy import arange, sin, pi, cos, ones
from matplotlib.backends.backend_tkagg import
Small update:
I tried the very same code with MPL 1.0.1 and Python 2.5.0 on Linux 64 and
Python 2.5.4 on Win32 and it runs w/o throwing any exceptions there!
But: the behaviour is still not that what I expected. Still these issues are
remaining:
- the smallest magnitude (center magnitude in
On Thu, Feb 17, 2011 at 4:12 AM, Stephan Markus zw...@web.de wrote:
Small update:
I tried the very same code with MPL 1.0.1 and Python 2.5.0 on Linux 64 and
Python 2.5.4 on Win32 and it runs w/o throwing any exceptions there!
But: the behaviour is still not that what I expected. Still
Hi,
I am trying to display some complex values in a polar plot. Displaying
linear magnitude vs. angle - of course - works without any issues. But I'd
rather display the logarithmic magnitute vs. angle. Since the data for the
radius gets negative then, it'll be wrapped around / rotated by 180deg
On Wed, Feb 16, 2011 at 9:16 AM, Stephan Markus zw...@web.de wrote:
Hi,
I am trying to display some complex values in a polar plot. Displaying
linear magnitude vs. angle - of course - works without any issues. But I'd
rather display the logarithmic magnitute vs. angle. Since the data for
2010/8/20 Michael Droettboom md...@stsci.edu:
Yeah, it's my issue, but I'm not happy with fixing it. Currently,
matplotlib forces the xticks (i.e., the theta ticks) to be at sensible
values via .set_xticks() and .set_xlabels() (projections/polar.py).
I'm coding a matplotlib extension package
On 08/19/2010 05:53 PM, Friedrich Romstedt wrote:
2010/8/19 Michael Droettboommd...@stsci.edu:
On 08/18/2010 06:03 PM, Friedrich Romstedt wrote:
Is the attached issue with a plain polar axes already fixed? I never
encountered this before. 344 degrees happens to be 6.0 rad. I'm
On Fri, Aug 20, 2010 at 8:33 AM, Michael Droettboom md...@stsci.edu wrote:
On 08/19/2010 05:53 PM, Friedrich Romstedt wrote:
2010/8/19 Michael Droettboommd...@stsci.edu:
On 08/18/2010 06:03 PM, Friedrich Romstedt wrote:
Is the attached issue with a plain polar axes already fixed? I
On 08/18/2010 06:03 PM, Friedrich Romstedt wrote:
2010/8/18 Michael Droettboommd...@stsci.edu:
This bug (that the r-axis labels are in the wrong place) should now be fixed
in r8651. This doesn't, unfortunately, address the original question about
annular plots.
Is the attached
2010/8/19 Michael Droettboom md...@stsci.edu:
On 08/18/2010 06:03 PM, Friedrich Romstedt wrote:
Is the attached issue with a plain polar axes already fixed? I never
encountered this before. 344 degrees happens to be 6.0 rad. I'm on
svn 8626.
How are you creating that graph? By default,
Hi all,
Is it possible to create a polar plot, where the lower
bound of the radius is larger than zero ?
I would like to plot an annulus.
Any pointer would be appreciated.
Thanks in advance
Nils
On Wed, Aug 18, 2010 at 8:03 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
Hi all,
Is it possible to create a polar plot, where the lower
bound of the radius is larger than zero ?
I would like to plot an annulus.
Any pointer would be appreciated.
Thanks in advance
On Wed, 18 Aug 2010 08:51:31 -0500
Benjamin Root ben.r...@ou.edu wrote:
On Wed, Aug 18, 2010 at 8:03 AM, Nils Wagner
nwag...@iam.uni-stuttgart.dewrote:
Hi all,
Is it possible to create a polar plot, where the lower
bound of the radius is larger than zero ?
I would like to plot an
On 08/18/2010 09:51 AM, Benjamin Root wrote:
On Wed, Aug 18, 2010 at 8:03 AM, Nils Wagner
nwag...@iam.uni-stuttgart.de mailto:nwag...@iam.uni-stuttgart.de
wrote:
Hi all,
Is it possible to create a polar plot, where the lower
bound of the radius is larger than zero ?
I
2010/8/18 Michael Droettboom md...@stsci.edu:
This bug (that the r-axis labels are in the wrong place) should now be fixed
in r8651. This doesn't, unfortunately, address the original question about
annular plots.
Is the attached issue with a plain polar axes already fixed? I never
On Wed, Aug 18, 2010 at 10:03 PM, Nils Wagner
nwag...@iam.uni-stuttgart.de wrote:
I would like to plot an annulus.
With mpl_toolkits.axisartist, it is possible to make an axes of annulus.
But, the resulting axes is not fully compatible with the original
matplotlib axes. Most of the tick-related
Hi Armin,
Thanks, I added it to the mplot3d examples.
Cheers,
Reinier
On Thu, Mar 18, 2010 at 3:46 PM, Armin Moser
armin.mo...@student.tugraz.at wrote:
Hi,
you can create your supporting points on a regular r, phi grid and
transform them then to cartesian coordinates:
from
at implementing this. You will find the mplot3d
code pretty straightforward. (And a lot smaller than you might expect).
-Ben
-Original Message-
From: klukas [mailto:klu...@wisc.edu]
Sent: Wednesday, March 17, 2010 4:34 PM
To: matplotlib-users@lists.sourceforge.net
Subject: [Matplotlib-users
The code below works perfectly. I think this should be included as an
mplot3d codex. I'll look into what's required to submit a new example
to the documentation.
Thanks Armin!
|| Jeff Klukas, Research Assistant, Physics
|| University of Wisconsin -- Madison
|| jeff.klu...@gmail |
Hi,
you can create your supporting points on a regular r, phi grid and
transform them then to cartesian coordinates:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib
import numpy as np
from matplotlib import cm
from matplotlib import pyplot as plt
step = 0.04
maxval = 1.0
fig =
I'm guessing this is currently impossible with the current mplot3d
functionality, but I was wondering if there was any way I could generate a
3d graph with r, phi, z coordinates rather than x, y, z?
The point is that I want to make a figure that looks like the following:
Thank you very much. You have just made me a much happier grad student.
I hope this answer gets added to the FAQ!
--
Randolph Fritz
design machine group, architecture department, university of washington
rfr...@u.washington.edu -or- rfritz...@gmail.com
On 2010-03-02 18:23:24 -0800, Jae-Joon
On Wed, Mar 3, 2010 at 4:09 PM, R Fritz rfr...@u.washington.edu wrote:
Thank you very much. You have just made me a much happier grad student.
I hope this answer gets added to the FAQ!
Make us much happier developers :-)
Do you have any link to an example plot?
I googled it but not much luck.
Is it like a polar plot without the bottom half?
Regards,
-JJ
On Tue, Mar 2, 2010 at 1:48 AM, R Fritz rfr...@u.washington.edu wrote:
I'd like to be able to generate type C photometry plots with
matplotlib. The standard
You can see an example on the second page of
http://lightolier.com/MKACatpdfs/8011.PDF. Scroll down. The plot is
next to the table titled, candlepower summary. It's a quadrant
rather than a full circle, and it's clipped to a box, but it's still a
polar plot.
The only problem I have with
The current implementation of PolarAxes does not support that.
However, you can workaround this easily using a custom axes.
In http://matplotlib.sourceforge.net/examples/pylab_examples/polar_demo.html
Instead of
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True, axisbg='#d5de9c')
use
I'd like to be able to generate type C photometry plots with
matplotlib. The standard co-ordinate system for these has 0 degrees at
the bottom (nadir) of the plot, with values increasing
counterclockwise. Is there anyway I can transform the co-ordinates that
matplotlib uses to do this?
--
Hi Giovanni,
Radar plots haven't been added to the core functionality of
matplotlib, but there's an example of a custom radar chart class on
the mpl website:
http://matplotlib.sourceforge.net/examples/api/radar_chart.html
Best,
-Tony
On Oct 17, 2009, at 9:33 AM, Giovanni Bacci wrote:
Hi all. I'd like to know if it's possible to obtain a radar plot like
this: http://code.google.com/intl/en/apis/chart/types.html#radar (the
filled one, with cht=rs) with matplotlib. I'm using matplotlib version
0.98.5
Thanks,
Giovanni
Dear Jae-Joon,
Your workaround worked perfectly! Thanks a lot!
Cheers,
Bartosz
--
Come build with us! The BlackBerryreg; Developer Conference in SF, CA
is the only developer event you need to attend this year.
Thanks. I think you're right, Jae-Joon. I've committed a slightly
simplified version of your patch on the 0.99 branch and trunk.
Mike
Jae-Joon Lee wrote:
Thanks for reporting the problem.
I can reproduce this error in the svn trunk.
My diagnosis is that this is because the clip mask is
Dear all,
I have a problem with exporting polar plots to SVG. When attached to
axes which are not centered in the figure, the content (grids, data,
etc.) seems not to be shifted correctly with the axes. However, when I
plot it directly to the screen or export to PNG everything is fine.
Here is
Thanks for reporting the problem.
I can reproduce this error in the svn trunk.
My diagnosis is that this is because the clip mask is not correctly
set, i.e., the mask path is not properly flipped in the svg backend.
I was able to solve this particular problem using the attached patch.
But, i'm
Hi, I'm new to matplotlib and in need to draw a single impulse on a polar
plot, but don't know how to do it, so i just draw a line using
pylab.polar([0,0],[0,100],'g-')
but when i draw shorter lines or
pylab.polar([0,0],[0,0],'g-')
i get the whole plot filled with green color, instead of a
azerith wrote:
Hi, I'm new to matplotlib and in need to draw a single impulse on a polar
plot, but don't know how to do it, so i just draw a line using
pylab.polar([0,0],[0,100],'g-')
but when i draw shorter lines or
pylab.polar([0,0],[0,0],'g-')
i get the whole plot filled with green
I'm not able to see a difference between the two methods here:
from pylab import *
import numpy as np
r = np.arange(0, 3.0, 0.01)
theta = 2*np.pi*r
fig = figure()
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True)
ax.plot(theta, r)
show()
polar(theta, r)
show()
Can you provide a standalone
Hi all,
I have been trying both ways of plotting polar and found that they behave
differently?
Is it just me?
I have sets of theta and R to plot, and when I plotted in console using
polar() it produces different plot (!) than when I used ax.plot() from my
application. I compared this with the
The grid line will reappear if you set high enough resolution.
plt.subplot(111, polar=True, resolution=100)
This should be filed as a bug, though.
I guess the current default for resolution is 1. I think this was to
enable to draw a straight line in polar projection. However, my guess
is that it
Hello,
in version 0.98.5.2 the polar plot still has a problem with negativ angles.
The polarplot is drawing a circle when the angle changes from negativ to
positiv (e.g. from -0.01 to +0.01).
But in What new in 0.98.4
(http://matplotlib.sourceforge.net/users/whats_new.html) I can read:
Fix
To emulate the current behavior (which doesn't try to interpolate
between points) you can pass resolution=1 to the polar command. But I
agree with Eric -- it sounds like updating my resolve this issue.
Mike
Eric Firing wrote:
Ng, Enrico wrote:
The rotation and resetting of the labels
01, 2009 2:14 AM
To: Ng, Enrico
Subject: Re: [Matplotlib-users] Polar plotting clockwise and rotated
With mpl from svn (and using ipython -pylab), the following works:
rr = rand(36)
r = np.hstack((rr, [rr[0]]))
theta = linspace(0, 2*pi, 37)
polar(theta, r)
Eric
The rotation and resetting of the labels isn't a big issue.
The issues is when I reverse the direction. Matplotlib seems to only
want to plot in an anti-clockwise direction. I can transform the data
to be backwards so that it looks ok, however when it tries to connect
the start and end points,
Ng, Enrico wrote:
The rotation and resetting of the labels isn't a big issue.
The issues is when I reverse the direction. Matplotlib seems to only
want to plot in an anti-clockwise direction. I can transform the data
to be backwards so that it looks ok, however when it tries to connect
the
Hi Enrico,
I'm afraid that this functionality is missing in matplotlib, but I'm not an
expert so there is still hope that this can be easily achieved.
A work around, that comes to my mind is resetting the label values using an
idea from another mail on this list
( thetagrids( range(0,360,45),
I've been trying to figure out how to do this for a while. I need to
make polar plots which go around clockwise and have 0deg on top (north)
instead of on the side (east). How can this be done?
--
Stay on top of
I recommend you to use the Wedge class in matplotlib.patches.
from matplotlib.patches import Wedge
# draw a wedge in the axes coordinate. (0.5, 0.5) in axes coordinate
corresponds to (0,0) in polar coordinate.
trans = ax.transAxes
center, R = (0.5, 0.5), 0.5
twopi=360.
pie1 = Wedge(center, R, 0,
Hi, i'm wondering if there is an easy way to fill the background in a polar
graph with a specific color. If I were making a pie graph, it'd be
something like: pie([70,20,10]), where the first 70% is green, the next 20,
yellow, and the last 10, red. I've been experimenting with polar graphs
I made a little more progress, but i'm not sure i'm doing this the right way.
Suggestions?
from pylab import *
import numpy as np
#generate random temperature data
snp=[]
for i in range(0,65):
snp.append(np.random.randint(35,122))
#hide the labels. I don't want them.
rc('xtick',
mcdevitts wrote:
Hello,
I've been trying to implement a smith chart like a previous gentlemen on the
list and have run into a similar problem. When my angle value goes from -pi
to pi I get an extraneous circle from the interpolation. From the previous
posts, I am under the impression that
Laurent Mychkine wrote:
hi,
I'm using polar bars to plot windroses. Since the 0.98.5 version i have
some issues with the plots.
The 0° bar is not displayed in the good way. This bar is
located between -0.26 radian and 0.26 radian but it is printed
counterclockwise.
It was working perfectly with
Hello,
I've been trying to implement a smith chart like a previous gentlemen on the
list and have run into a similar problem. When my angle value goes from -pi
to pi I get an extraneous circle from the interpolation. From the previous
posts, I am under the impression that this is a known issue
hi,
I'm using polar bars to plot windroses. Since the 0.98.5 version i have
some issues with the plots.
The 0° bar is not displayed in the good way. This bar is
located between -0.26 radian and 0.26 radian but it is printed
counterclockwise.
It was working perfectly with matplotlib version
Hi All -
is there any way to make a polar plot with the center of the plot
*not* set to 0? I tried resetting ylim, but that just changes the grid
laid over the plot, not the location of the markers.
Thanks --
Ariel
Hi all,
Does anyone know if it's possible to make the polar plot look like a
12- or 24-hr clockface? I.e. 0 (or 12) at the top rather than the
right, and labelled in 12ths (or 24ths) instead of degrees?
Thanks,
G
Hi all,
If I run the attached example I obtain no polar plots, but
a view like plot(t,r_1) - for what reason ?
Nils
python -i test_subplot_polar.py --verbose-helpful
$HOME=/home/nwagner
CONFIGDIR=/home/nwagner/.matplotlib
/usr/lib/python2.4/site-packages/matplotlib/__init__.py:662:
On Tue, Dec 2, 2008 at 11:07 AM, Nils Wagner
[EMAIL PROTECTED]wrote:
Hi all,
If I run the attached example I obtain no polar plots, but a view like
plot(t,r_1) - for what reason ?
You need to specify polar=True to the subplot commands. Try this:
from pylab import subplot, polar, linspace,
On Tue, 2 Dec 2008 11:14:48 -0600
Ryan May [EMAIL PROTECTED] wrote:
On Tue, Dec 2, 2008 at 11:07 AM, Nils Wagner
[EMAIL PROTECTED]wrote:
Hi all,
If I run the attached example I obtain no polar plots,
but a view like
plot(t,r_1) - for what reason ?
You need to specify polar=True to the
On Tue, Dec 2, 2008 at 11:27 AM, Nils Wagner
[EMAIL PROTECTED]wrote:
Thank you very much !
It would be nice to have that information in the docstring
Done.
The next inquiry is related to xticks.
I have added
xticks(linspace(0,2*pi,24,endpoint=False))
The difference between consecutive
The next inquiry is related to xticks.
I have added
xticks(linspace(0,2*pi,24,endpoint=False))
The difference between consecutive xticks is varying between 14 and 16
degrees.
The following works around the roundoff for me:
xticks(linspace(0, 360, 24, endpoint=False) * pi/180.)
Ryan
--
Ryan May wrote:
On Tue, Dec 2, 2008 at 11:27 AM, Nils Wagner
[EMAIL PROTECTED] mailto:[EMAIL PROTECTED]
wrote:
Thank you very much !
It would be nice to have that information in the docstring
Done.
Thanks for updating the docstring. I actually saw this as a usability
bug and
Michael Droettboom wrote:
Thanks for updating the docstring. I actually saw this as a usability
bug and have come up with a patch such that polar() (et al) will
*replace* the current axes with a polar plot if it isn't already polar.
This is (from the user's perspective) similar to how,
I've committed both of these things. The subplot()/polar() change seems
tricky, so it may produce some breakage even though the regression
tests are passing. Please let me know if you see anything strange
after this change.
Mike
Ryan May wrote:
Michael Droettboom wrote:
Thanks for
Hi all,
If I run the attached example I get
python -i test_polar.py --verbose-helpful
$HOME=/home/nwagner
matplotlib data path
/usr/lib/python2.4/site-packages/matplotlib/mpl-data
loaded rc file /home/nwagner/matplotlibrc
matplotlib version 0.98.3
verbose.level helpful
interactive is False
It says:
You are using unicode and latex, but have not enabled the matplotlib
'text.latex.unicode' rcParam.
Does setting text.latex.unicode to True resolve the issue?
Maybe that message should be made more prominent -- it currently is only
displayed when verbose is turned on, but it really is
and
makes doing any kind of processing of axis labels more difficult).
Ted
-Original Message-
From: Michael Droettboom [mailto:[EMAIL PROTECTED]
Sent: Tuesday, November 25, 2008 12:25 PM
To: Nils Wagner
Cc: matplotlib-users@lists.sourceforge.net
Subject: Re: [Matplotlib-users] polar
use get_majorticklocs() and get an array of floats.
Cheers,
Mike
Ted
-Original Message-
From: Michael Droettboom [mailto:[EMAIL PROTECTED]
Sent: Tuesday, November 25, 2008 12:25 PM
To: Nils Wagner
Cc: matplotlib-users@lists.sourceforge.net
Subject: Re: [Matplotlib-users] polar
On Tue, Nov 25, 2008 at 2:40 PM, Drain, Theodore R
[EMAIL PROTECTED] wrote:
Michael,
I think the issue is that there is no Unicode in the script that was attached
- it's just a simple polar call so the user isn't really Unicode.
I think Unicode is starting to creep into the source in various
Subject: Re: [Matplotlib-users] polar
Drain, Theodore R wrote:
Michael,
I think the issue is that there is no Unicode in the script that was
attached - it's just a simple polar call so the user isn't really
Unicode.
Polar plots always use Unicode by default for the degree sign
John Hunter wrote:
The problem here appears to be in
matplotlib.projects.polar.ThetaFormatter.__call__, which uses the
degree symbol. I think all we need to do is return the proper tex
string in this case. Michael, does this look right to you:
def __call__(self, x, pos=None):
]
Sent: Tuesday, November 25, 2008 1:06 PM
To: Drain, Theodore R
Cc: matplotlib-users@lists.sourceforge.net
Subject: Re: [Matplotlib-users] polar
Drain, Theodore R wrote:
Michael,
I think the issue is that there is no Unicode in the script that was
attached - it's just
On Tue, Nov 25, 2008 at 3:16 PM, John Hunter [EMAIL PROTECTED] wrote:
If the unicode minus is sufficiently problematic for you, I can add an
rc param. Something like
axis.unicode_minus : True
Added as rc param 'axes.unicode_minus' in svn r6453 with example
examples/api/unicode_minus.py
Hi Tony,
Thank you for the reply, the solutions you propose are fine in this
case. But I'm trying to use the polar plot
as a smith chart for an instrument and there i will receive data that is
unknown but can be something like this:
r = np.transpose(.1+np.arange ( 0 , 0.7 , 0.001))
theta =
On Sep 17, 2008, at 1:59 AM, jan gillis wrote:
Hello,
I have a problem with polar plot, if i run the following code in
matplotlib 0.98.3, polar plot is drawing a extra circle to go from
angle -3.14159265 to angle 3.03753126. Is there a solution for this
problem?
Hi all,
the new polar projection gives me a strange behavour by interpolating
each simple line between two consecutives points. Where I just want
points at specified coordinates and lines connecting them, between each
pairs appears a interpolated line in polar projection with multiple points.
Is it possible to make a chart like this:
http://www.advsofteng.com/images/multiradar_g.png
with matplotlib?
Where can I find some examples?
Thanks a lot.
-
This SF.net email is sponsored by the 2008 JavaOne(SM)
I've been using matplotlib on OSX a bit and was wondering if anyone
had code out there for a polar half-space plot? I created one for
matlab a while back and if there is not one for matplotlib, I would
be happy to offer up my code as a good beginning. It has a good bit
of logic in it to
On 4/30/07, Gonzalo A. de la Vega [EMAIL PROTECTED] wrote:
Hi all,
I'm trying to embed a polar plot into a glade gui. I modified the
mpl_with_glade.py example script to have something to start with. No
problems with normal plot, but when I try to do polar plot, it fails with
the following:
Miles Lubin wrote:
Hi,
I would like to be able to remove the dotted straight lines on the polar
axes, but keep the dotted circular lines (not sure of the technical
names, sorry). I also want to remove the degree measurement labels since
they are not meaningful for the data that I am
Solved the problems, thanks.
Another issue has come up. After looking through
http://matplotlib.sourceforge.net/matplotlib.axes.html#PolarAxes, I see
a get_rmax() function, but there is no corresponding set_rmax(). Using
set_ylim() causes hanging when it attempts to graph, and set_xlim is
Miles Lubin wrote:
Solved the problems, thanks.
Another issue has come up. After looking through
http://matplotlib.sourceforge.net/matplotlib.axes.html#PolarAxes, I see
a get_rmax() function, but there is no corresponding set_rmax(). Using
set_ylim() causes hanging when it attempts to
On Monday 25 December 2006 01:30, Eric Firing wrote:
I don't think so--at least, I have not figured it out after a few
minutes of looking around and trying to understand how things work. I
think polar plotting needs quite a bit of work.
Sorry for hijacking the thread, but a few months ago I
I am a new user of matplotlib and am trying to create a radar or
star plot. I didn't see a convenience function in matplotlib so I am
trying to create it using polar plots.
It would seem straight forward if the fill() function could be used
with polar axes, but my attempts thus far have not
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