[snip]
I would like to implement an XML-RPC server (a script of course) that
keeps the value of certain variables between the different invocations
of the script.
[/snip]
Could you store them in a file? Maybe a database.
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[snip]
Ok, here we go.
I would like to implement an XML-RPC server (a script of course) that
keeps the value of certain variables between the different invocations
of the script.
I think that it should be possible, but I don't know where to start
(none of the search in internet gave me a
Jay Blanchard wrote:
[snip]
Ok, here we go.
I would like to implement an XML-RPC server (a script of course) that
keeps the value of certain variables between the different invocations
of the script.
I think that it should be possible, but I don't know where to start
(none of the search in
If you're trying to prevent hitting the database then just cache the
page result and store it as a temporary html file. Then serve the
temporary file whenever people visit (and update every 15 minutes).
Jason
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[mailto:[EMAIL PROTECTED]
Sent: Thursday, May 27, 2004 11:17 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Keep PHP variable values between script calls - XML RPC
Ok, here we go.
I would like to implement an XML-RPC server (a script of course) that
keeps the value of certain variables between
[mailto:[EMAIL PROTECTED]
Inviato: venerdì 14 maggio 2004 8.24
A: [EMAIL PROTECTED]
Oggetto: [PHP] variable passing using URL
hello list,
I have a problem in passing variables using URLs.
I have a link from a PHP 'Page One' and passing some variables thru
URL.
This link should now open another
, and it seemed to fix the problem. I also upgraded to php 4.3.5
and have not seen the problem since.
Thanks again everyone!
Regards,
Geoff Varosky
-Original Message-
From: Ben Ramsey [mailto:[EMAIL PROTECTED]
Sent: Monday, April 05, 2004 3:58 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: Weird
My first thought is that some dynamic code on this page has an error.
Typical like this :
input type=var value=?=$var?'
^^
Or maby a quote is missing? Looking at your examples it looks like there are
different parts of the HTML code comming
Public Key - http://gvarosky.conversent.net/gvarosky.txt
-Original Message-
From: Kim Steinhaug [mailto:[EMAIL PROTECTED]
Sent: Monday, April 05, 2004 6:04 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Weird variable issue encountered... help needed!
My first thought is that some dynamic
On Monday 05 April 2004 22:46, [EMAIL PROTECTED] wrote:
Thank you all for your ideas so far, however, I ahve gone through all my
code, and cannot seem to find the culprit.
I believe it is a known bug with a particular old version of PHP, try using
the latest.
--
Jason Wong - Gremlins
From: Jason Wong [EMAIL PROTECTED]
On Monday 05 April 2004 22:46, [EMAIL PROTECTED] wrote:
Thank you all for your ideas so far, however, I ahve gone through all my
code, and cannot seem to find the culprit.
I believe it is a known bug with a particular old version of PHP, try
using
the
Hmm.. Are there any PHP settings that only applies to that vhost? Can you
please try to run PHP as CGI few tries.. If the input is corrupt, that
_could_ be caused by the Apache2 which accutually is marked as
experimental... Basicly, this would get currupt?
(wierd-var-test.php)
?
One problem
wrong
form action=wierd-var-test.php?action=post
right
form action=wierd-var-test.php method=post
?action is a variable with a value of post
-Blake
DvDmanDT wrote:
Hmm.. Are there any PHP settings that only applies to that vhost? Can you
please try to run PHP as CGI few tries.. If
Is this what your are trying to do?
?php
$var = $_POST['var'];
if($var)
var_dump($_REQUEST);
else
{
?
form action=index.php method=post
input type=text name=var
input type=submit
/form
?
}
?
DvDmanDT wrote:
I agree. I believe the default FORM METHOD is GET.
One problem
wrong
form action=wierd-var-test.php?action=post
right
form action=wierd-var-test.php method=post
?action is a variable with a value of post
-Blake
DvDmanDT wrote:
Hmm.. Are there any PHP settings that only applies to
Accutually, I intented ?action=post, and if($action=='post'), just forgot to
add method=post.. :p
--
// DvDmanDT
MSN: dvdmandt¤hotmail.com
Mail: dvdmandt¤telia.com
Blake Schroeder [EMAIL PROTECTED] skrev i meddelandet
news:[EMAIL PROTECTED]
One problem
wrong
form
Just don't use register globals and use if ($_POST) instead of
if($action=='post') so you don't have to include that ?action=post in
the query string of your action.
Dvdmandt wrote:
Accutually, I intented ?action=post, and if($action=='post'), just forgot to
add method=post.. :p
--
Regards,
It's not the same thing. When an variable references an object then you
can change either the original object or the new variable and you will
be changing the *same* object, not a new one. Maybe this example helps?
?php
class test {
function test($val) {
global
My question is actually regarding the line $myref = $this;. The
author states that this is a reference to the class/object itself. Isn't
this like saying outside the class $myref = new test;? What would be
the point of referring to itself inside the class in this manner?
Thanks for your
Jason, thanks. Yes, I understand your example here very well. My
question actually had more to do with understanding what value was added
to the class by $myref = $this;. Perhaps it is some misunderstanding
I have of classes but, since a class is just a pattern and not an
actual, usable
Dear my friends...
I want to make an alert which can display a value from the database.
I am meaning :
how can I pass a value of a variable from PHP into JavaScript alert (
alert($Firstname, $LastName and $Address);
Is it possible
Hey,
I have stored the name of a function as a variable. I have then passed the
variable to another function as follows:
//put function name in a variable
$contentfunction = newsadmincontent();
//pass variable to another function
Html_content($contentfunction);
//function is:
function
On Mon, 2003-12-22 at 12:36, Carey Baird wrote:
Hey,
I have stored the name of a function as a variable. I have then passed the
variable to another function as follows:
//put function name in a variable
$contentfunction = newsadmincontent();
//pass variable to another function
try eval($contentfunction);
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December 2003 19:43
To: Carey Baird
Cc: php-gen
Subject: Re: [PHP] evaluating a variable
On Mon, 2003-12-22 at 12:36, Carey Baird wrote:
Hey,
I have stored the name of a function as a variable. I have then passed the
variable to another function as follows:
//put function name in a variable
[snip]
Eval ($contentfunction); gave me a parse error:
Parse error: parse error in
/home/pickled/public_html/main/inc/html.php(145)
: eval()'d code on line 1
[/snip]
try to add a semicolon to the end of the variable $contentfunction =
newsadmincontent();;
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PHP General Mailing List (http
On Mon, 2003-12-22 at 12:43, Carey Baird wrote:
Eval ($contentfunction); gave me a parse error:
Parse error: parse error in /home/pickled/public_html/main/inc/html.php(145)
: eval()'d code on line 1
$$contentfunction didnt output anything
Any other ideas?
What are you trying to do
Carey Baird wrote:
Hey,
I have stored the name of a function as a variable. I have then passed the
variable to another function as follows:
//put function name in a variable
$contentfunction = newsadmincontent();
Take off the parenthesis...
$contentfunction = 'newsadmincontent';
To call the
On Mon, 2003-12-22 at 13:09, John W. Holmes wrote:
Carey Baird wrote:
Hey,
I have stored the name of a function as a variable. I have then passed the
variable to another function as follows:
//put function name in a variable
$contentfunction = newsadmincontent();
Take off the
If you change the name of the data field to something[] then the
$_POST['something'] will be an array containing your data
The code you have will result in 2 fields (one hidden one normal) with
the same name ($i), this will cause lots of problems
It is not a good idea to give form fields
thx Mike that works :-)
thx also to the others for their help :-))
Christian
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Hi there,
I'm sure this is an easy fix, but how do you either prevent users from being
able to input in a field or make it so that it doesn't affect the code?
Thanks in advance,
Dimitri Marshall
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--- Dimitri Marshall [EMAIL PROTECTED] wrote:
how do you either prevent users from being able to input in a
field or make it so that it doesn't affect the code?
Can you give an example of affecting the code? You can store spaces in
variables just fine.
Chris
=
Chris Shiflett -
Sorry, what I mean is...
I have a field in a form where users input text.
If the user inputs something like: Hi there, this is a quote and you
should know it.
Then only... Hi there, get's inserted because of the double quotes.
Is that more clear?
Dimitri Marshall
Chris Shiflett [EMAIL
Hello Dimitri,
Wednesday, December 3, 2003, 3:28:19 AM, you wrote:
DM I'm sure this is an easy fix, but how do you either prevent users from being
DM able to input in a field or make it so that it doesn't affect the code?
Assuming you mean the double quote marks, and not a blank space, use
Try using htmlentities() to convert the characters to the html entities
that can be stored and displayed.
http://www.php.net/htmlentities
Jason
Dimitri Marshall wrote:
Sorry, what I mean is...
I have a field in a form where users input text.
If the user inputs something like: Hi there,
I am trying to do the following:
I have a text file to read in that contains something like The
temperature is $temp
This gets read into an array so that I can parse it out word by word
(the only way I could think to do this, any other ideas are welcome). I
do a test to see whether the first
The temperature is $$temp
Brona
-Original Message-
From: Ian Truelsen [mailto:[EMAIL PROTECTED]
Sent: Sunday, November 30, 2003 9:27 PM
To: php
Subject: [PHP] getting an variable value from an array entry
I am trying to do the following:
I have a text file to read
On Sun, 30 Nov 2003 21:44:50 +0100
Bronislav Klucka [EMAIL PROTECTED] wrote:
The temperature is $$temp
Unfortunately, that is not working for me. I have tried changing it in
the text file, but that just outputs $$temp instead of the value of
$temp. What I have is the array words, for which the
On Sun, Nov 30, 2003 at 01:04:08PM -0800, Ian Truelsen wrote:
On Sun, 30 Nov 2003 21:44:50 +0100
Bronislav Klucka [EMAIL PROTECTED] wrote:
The temperature is $$temp
Unfortunately, that is not working for me. I have tried changing it in
the text file, but that just outputs $$temp instead
On Mon, 1 Dec 2003 00:16:07 +0300
zhuravlev alexander [EMAIL PROTECTED] wrote:
Use eval. http://www.php.net/eval
% cat temp.txt
Temperature $temp degree.
% cat temp.php
?php
$temp = '5';
$filename = ./temp.txt;
$handle = fopen ($filename, r);
$code
* Thus wrote zhuravlev alexander ([EMAIL PROTECTED]):
% cat temp.txt
Temperature $temp degree.
% cat temp.php
?php
$temp = '5';
$filename = ./temp.txt;
$handle = fopen ($filename, r);
$code = fread ($handle, filesize ($filename));
fclose ($handle);
Try:
if (isset($_GET['status']) $_GET['status'] ==0) {
echo Trying;
}
The warning is triggered by the fact that you use a variable that was not
previously defined. Check it before use with isset.
If in php.ini the value error_reporting = E_ALL, it will output warnings.
If you want the
Hello,
I need to test a variable to see if it contains a value or not, and if
not, do something. My php is a little rusty, so which would be better?
if ( !$var )
{ echo do something;}
or
if ( !isset($var )
{ echo do something;}
or are both of those wrong, and if so, how hsoudl I check if a
[snip]
if ( !isset($var )
{ echo do something;}
[/snip]
self answering questions, gotta' love 'em!
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From: Adam Williams [EMAIL PROTECTED]
I need to test a variable to see if it contains a value or not, and if
not, do something.
[snip]
if ( !isset($var )
{ echo do something;}
That's the correct way.
What I am doing is checking a field in an sql table, and if the field is
null, empty,
Adam Williams said the following on 11/12/2003 11:37 AM
Hello,
I need to test a variable to see if it contains a value or not, and if
not, do something. My php is a little rusty, so which would be better?
if ( !$var )
{ echo do something;}
or
if ( !isset($var )
{ echo do something;}
or are
--- Adam Williams [EMAIL PROTECTED] wrote:
I need to test a variable to see if it contains a value or not, and if
not, do something. My php is a little rusty, so which would be better?
This is a good page for understanding how things like isset(), is_null(),
and empty() work:
Frank Tudor wrote:
I have a redirect that if conditions are right it will pass the
user to a new page via $_POST.
I am posting variables in the url and on this next page more
form stuff awaits the user.
If a user submits incorrect stuff in the form is posts to
itself. The url holds
Hi,
Are there any limits on the length a variable or classname may be in
PHP? I was unable to find anything in the manual, and my tests found
that a variable over 2000 characters long still caused no error or problems.
This is important because phpDocumentor 2.0 will be using a database to
Hmmm I _think_ it depends on size_t, which (IIRC) is typically typdef'd as an
unsigned long int. I say that because there are macros (like ZEND_SET_SYMBOL)
that do strlen(name) all over the place. Here's an except from limits.h:
/* Maximum value an `unsigned long int' can hold. (Minimum is 0.)
I got PHP Notice: Undefined variable
Should I define always any var ?? when do I have do define a var??
example if I want to write
?php
if ($_POST['msg'] =='hi')
{
do something ...
}
?
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[EMAIL PROTECTED]
Nabil:
I got PHP Notice: Undefined variable
Should I define always any var ?? when do I have do define a var??
example if I want to write
?php
if ($_POST['msg'] =='hi')
{
do something ...
}
?php
if (!isset($_POST['msg'])) die(No message!);
if ($_POST['msg'] == 'hi
Message -
From: nabil [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, October 04, 2003 3:45 PM
Subject: [PHP] PHP Notice: Undefined variable
I got PHP Notice: Undefined variable
Should I define always any var ?? when do I have do define a var??
example if I want to write
?php
Simply lower your error reporting level. If you do not have access to your
php.ini (not everyone does), then can you can amend this directive in either
.htaccess or even on a per script basis by using the error_reporting()
function like so.
error_reporting(2039);
(Equivalent to E_ALL ~E_NOTICE)
Andrew Chernyack wrote:
I recommend the next variant
if ($_POST[msg] ==hi)
Why?
I've created an html file with form's action parameter as info.php that
contains phpinfo().
The result was
PHP_SELF /~adolf/info.php
_POST[a] dv fdsvz
_SERVER[CONTENT_LENGTH] 10
You see, _POST[a]
I'm new at OO and still a newbie at PHP despite hacking away at it for a
while (admittedly off and on). I'm creating a signup form for alumni of our
department, and I'm trying to verify that they have not signed up previously
before allowing their data to be inserted. Trouble has ensued! :)
In
= select id, fname from contact_info where email = '$email';
Hope that helps!
-Original Message-
From: Kirk Babb [mailto:[EMAIL PROTECTED]
Sent: Saturday, October 04, 2003 5:28 PM
To: [EMAIL PROTECTED]
Subject: [PHP] returning a variable from a class function? plus other probs
I'm new
A couple of things...
$conxn = mysql_connect('localhost','root','redtail.7') or fail(Could
not connect: .mysql_error());
Create a script inc.mysqlconnect.php that connects and selects and
require_once() it on all of your files that need to connect to the
database. This will save
Dan,
Thanks so much for the help - I learned a lot from your reply. I'll chew on
this a while and go from there. BTW- yes, that really was my user and pwd
up until now! Dumb now I realize, thanks for pointing that out. I've
created a new root pwd, and created a user with access only to the
* Thus wrote Dan Anderson ([EMAIL PROTECTED]):
$chk = Select id, fname from contact_info where email = . $email;
You need to quote the email. So perhaps the following would be more
appropriate:
$chk = SELECT id, fname FROM contact_info WHERE email = \{$email}\;
Using ' is prefered IIRC, and also escaping all the data before sending
it to the database:
Hmmm. Perhaps Emacs isn't converting from Unicode to ASCII properly?
::shrugs:: I just know sometimes my queries don't work if I use ' .
-Dan
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PHP General Mailing List (http://www.php.net/)
To
up until now! Dumb now I realize, thanks for pointing that out. I've
created a new root pwd, and created a user with access only to the alumni
If you want to be super secure you should create several users. Once
for SELECTing, one for INSERTing, etc. Juggling resource handles gets
tricky
The user I created can only INSERT, SELECT, DELETE, UPDATE using the GRANT
option from the mysql cmd line. I'll have to start checking my data per
yours and Curt's responses.
Sounds like I should remove the DELETE option from that user and create a
second user with DELETE permission.
-Kirk
* Thus wrote Dan Anderson ([EMAIL PROTECTED]):
Using ' is prefered IIRC, and also escaping all the data before sending
it to the database:
Hmmm. Perhaps Emacs isn't converting from Unicode to ASCII properly?
::shrugs:: I just know sometimes my queries don't work if I use ' .
I just
:[EMAIL PROTECTED]
Sent: Tuesday, August 26, 2003 4:00 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] problem passing variable between forms.
- Original Message -
From: Angelo Zanetti [EMAIL PROTECTED]
I have a form in which I have a table with dynamic checkboxes
From: Angelo Zanetti [EMAIL PROTECTED]
therefore I can register this variable on the same page as the checkboxes?
So therefore is it posssible for php to determine which checkboxes have
been
selected (or are the ones that are selected added to the array)?
The ones that are selected are added
On Sun, Sep 21, 2003 at 03:01:41PM -0400, Rich Fox wrote:
: Eugene Lee [EMAIL PROTECTED] wrote:
:
: If I have a block of text saved in an external text file, e.g.:
:
: All {$badstuff} and no {$goodstuff} makes {$name} a dull {$type}.
:
: after reading the text into a string, is there a way
Sorry, we have a Eugene Lee at my aikido school and it's such an unusual
name I thought you might be him.
Eugene Lee [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Sun, Sep 21, 2003 at 03:01:41PM -0400, Rich Fox wrote:
: Eugene Lee [EMAIL PROTECTED] wrote:
:
: If I have a
That's not Eugene from the dojo is it?
Rich
Eugene Lee [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
If I have a block of text saved in an external text file, e.g.:
All {$badstuff} and no {$goodstuff} makes {$name} a dull {$type}.
after reading the text into a string, is there
Hi,
I'm having trouble evaluating a dynamic variable. I want to check if the
variable $_POST[resolutions$i] is an empty string, as you'll see from the
code. However, every way I've tried to check the variable so far (including
empty() and eval()) always returns a null value, even when the variable
[snip]
I'm having trouble evaluating a dynamic variable. I want to check if the
variable $_POST[resolutions$i] is an empty string, as you'll see from
the
code. However, every way I've tried to check the variable so far
(including
empty() and eval()) always returns a null value, even when the
this worked for me.
?
$entries = 20;
for ($i=1; $i=$entries; $i++) {
if(isset($_POST[resolutions$i]) $_POST[resolutions$i] !==
''){
echo Hello $ibr /;
}
}
?
html
body
form method=POST
input type=hidden name=resolutions1 value=etefgtE /
input type=hidden name=resolutions3
Steve Goodman mailto:[EMAIL PROTECTED]
on Tuesday, September 02, 2003 12:54 PM said:
Can someone
recommend a way to reliably evaluate this variable?
1. (not positive on this point so correct me if I'm wrong) you shouldn't
compare with !==. Instead us !=.
2. What does the following do?
Chris W. Parker
on Tuesday, September 02, 2003 1:29 PM said:
1. (not positive on this point so correct me if I'm wrong) you
shouldn't compare with !==. Instead us !=.
Ok, turns out I'm wrong on that. I guess I should go look it up!!
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PHP General Mailing List (http://www.php.net/)
To
singular, not plural. Thanks for the
help everyone
.
-Original Message-
From: Chris W. Parker [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 02, 2003 3:29 PM
To: Stephen Goodman; [EMAIL PROTECTED]
Subject: RE: [PHP] evaluating dynamic variable
Steve Goodman mailto:[EMAIL PROTECTED
From: Stephen Goodman [EMAIL PROTECTED]
When I run the code you've attached, with $i iterating up to 3, I get
three 'empty!', even if $resolution1 should be 'not empty!'. It seems
like the $i in $_POST[resolutions.$i] is not getting parsed into a
value, and php is looking for a key
HI all
I have a form in which I have a table with dynamic checkboxes, they are in a
checkbox array ( name = chk[]...), I pass this variable to the next page
using POST I receive the variable and use it, no problem, but then when I
try to pass it to the next form in the URL (using an A HREF:
a
- Original Message -
From: Angelo Zanetti [EMAIL PROTECTED]
I have a form in which I have a table with dynamic checkboxes, they are in
a
checkbox array ( name = chk[]...), I pass this variable to the next page
using POST I receive the variable and use it, no problem, but then when I
I have a form in which I have a table with dynamic checkboxes, they are in a
checkbox array ( name = chk[]...), I pass this variable to the next page
using POST I receive the variable and use it, no problem, but then when I
try to pass it to the next form in the URL (using an A HREF:
a
--- Angelo Zanetti [EMAIL PROTECTED] wrote:
I pass this variable to the next page using POST I receive the
variable and use it, no problem, but then when I try to pass it
to the next form in the URL (using an A HREF:
a href='confirmrequest.php?requested= . $chk . ' )
...
My
Hi php-general,
I'm thinking of how I could store the content of a String-variable a) in a
Variable to be passed to other functions b) in a Database (MySQL) too . The content is
html-code (with
tags and style code (css)).
The point is that I'm making myself a kind
of CMS, and I want to edit a
I'm not sure what you're asking but...
Using htmlentities() and undohtmlentities() (look up the real functions)
to data going into and out of your database will allow you to store it
without getting lots of errors...
mySQL storage (even TEXT and BLOB types) can't be larger then so many
bytes
Jason Giangrande [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
When registered globals is set to off this does not effect the $PHP_SELF
variable right? In other words I should be able to call $PHP_SELF with
out having to do this $_SERVER['PHP_SELF'], right?
Thanks,
Jason
is then displayed,
below which the previous login time should be printed, after which the
variable is deleted.
Yet, PHP seems to delete the variable prior to printing it on the screen,
resulting in the absence of the previous login time, although the command to
delete it from the array is issued AFTER
Has anyone had any success with using variables in a regex shown below??
$foo = 3;
$bar = 4;
preg_match('/^[a-z0-9\-_\.]+\.[a-z0-9]{$foo, $bar}$/', $some_string)
or even
preg_match('/^[a-z0-9\-_\.]+\.[a-z0-9]{' . $foo . ', ' . $bar . '}$/',
$some_string)
but this would work
Gerard Samuel [EMAIL PROTECTED] wrote:
Has anyone had any success with using variables in a regex shown below??
$foo = 3;
$bar = 4;
preg_match('/^[a-z0-9\-_\.]+\.[a-z0-9]{$foo, $bar}$/', $some_string)
You have single quotes, so php wont expand the variables inside.
or even
Curt Zirzow wrote:
Gerard Samuel [EMAIL PROTECTED] wrote:
or even
preg_match('/^[a-z0-9\-_\.]+\.[a-z0-9]{' . $foo . ', ' . $bar . '}$/',
$some_string)
that should work.
Unfortunately it doesn't for some reason. Don't know why.
but you could do this:
$pattern =
Gerard Samuel a écrit:
Curt Zirzow wrote:
Gerard Samuel [EMAIL PROTECTED] wrote:
or even
preg_match('/^[a-z0-9\-_\.]+\.[a-z0-9]{' . $foo . ', ' . $bar .
'}$/', $some_string)
I think, you Forgot, a \ before the $ at the end of the expression...
that should work.
Unfortunately it doesn't
.any clues as to why I can't carry the
variable?
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-Original Message-
From: Ron Allen [mailto:[EMAIL PROTECTED]
Sent: 15 July 2003 10:55
I am using PHP 4.3.0
The way that I usually carry variables from one page to another is
$Unit = ($_GET['Unit']);
This is the page that is referencing it!
?PHP
echo brbr;
$DBName = SIGO;
Dear All,
I need to get results like this.
?
$result = get_executed_php_file_contents.php
?
Looking for some solutions
TM
At 11:31 14-7-03, you wrote:
Dear All,
I need to get results like this.
?
$result = get_executed_php_file_contents.php
?
I use:
ob_start();
include('modules/file.php');
$result=ob_get_contents();
ob_end_clean();
--
PHP General
Hi,
Put a return statement at the end of file
'get_executed_php_file_contents.php' that returns the value you need, then
use:
?
$result = include(get_executed_php_file_contents.php);
?
On 14/7/03 10:31 am, Tariq Murtaza [EMAIL PROTECTED] wrote:
Dear All,
I need to get results like
ways fordoing this. HTH
Haseeb
---Original Message---
From: Ryan Gibson
Date: Monday, July 14, 2003 02:46:01 PM
To: Tariq Murtaza; [EMAIL PROTECTED]
Subject: Re: [PHP] How to get "executed php result" in variable
Hi,
Put a return statement at the e
Alright, I've got an error reporting class with a report() method.
I want to be able to e-mail myself the name of the variable that bombed
out and the line that it was on (as well as the filename) if possible.
Don't really know where to start... looks like this:
function report ($error_var) {
I want to be able to e-mail myself the name of the variable that bombed
out and the line that it was on (as well as the filename) if possible.
Don't really know where to start... looks like this:
You can use PHP's predefined constants in an assertion, and
debug_backtrace().
I can click links and they work but when I enter data in a form and try to send it to
the next php script to process the data, nothing happens. Is there a simple way I can
see what is returning from the browser to see if what I expect is actually getting
there?? I think $_SERVER['QUERY_STRING']
On Monday 30 June 2003 04:38, Sparky Kopetzky wrote:
I can click links and they work but when I enter data in a form and try to
send it to the next php script to process the data, nothing happens. Is
there a simple way I can see what is returning from the browser to see if
what I expect is
OK, I see that I have to use $_POST['user_name'] or can I just use the
variable passed back $user_name which would be a heck of a lot simpler??
Sparky
- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, June 29, 2003 14:56
Subject: Re: [PHP] ARGHHH
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