I think this is incorrect.
I think it is 3.8 grams total retained in the body.
Dan
Silver Smith wrote:
Thanks for the input. So is the following summary accurate?
For Pure water (DH2O) 1ml (cc) of DH20 = 1g of mass
ppm = parts per million usually stated as unit mass/unit mass
Since pure water is 1g:1ml we can state CS/EIS as a concentration of
mass/unit volume
For 10 ppm CS/EIS 1ml DH2O has 1 ug of Silver in it or 10mg
silver per liter.
For 20 ppm CS/EIS 1ml DH2O has 2 ug of Silver in it or 20mg
silver per liter.
There are 1000ug in a mg and 1000mg in a gram
Therefore, if it estimated that it would take 3800mg of silver/day to
cause argyria you would have to drink:
380,000 ml or 12,667 ounces or 99 gallons of 10ppm CS/EIS to risk it. OR
190,000 ml or 6,334 ounces or 49.5 gallons of 20ppm CS/EIS to risk it.
On 5/23/07, *Silver Smith* <cag....@gmail.com
<mailto:cag....@gmail.com>> wrote:
I was reading some info on Argyria and came across the following
statement, "The amount of silver required to develop Argyria is
estimated to be 3.8 grams per day"
I have two questions about that statement.
1. If you are drinking a 10ppm "concentration" of CS/EIS, how many
ounces or milliliters (ml) of the 10ppm CS/EIS would you have to
drink to reach the 3.8 grams for a day.
2. How many days would you need to drink it to "get it" (argyria)?
I need a bit of help fully understanding what we mean in terms of
concentration when we use ppm as the "unit of concentration". I
understand that ppm = parts per million. I assume that would be
"parts of silver" per some unit of volume (water)? In the clinical
lab we measure concentration of analytes in the blood in mg/dl or
ug/dl......etc. So would ppm be microgram (ug-1millionth of a gram)
per some volume of water? What would the volume of water be?
Thanks,
SS
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