To the best of my understanding, the x-ray burst happens once at startup of a reactor run that can last for months.
On Fri, Mar 11, 2016 at 5:40 PM, Russ George <russ.geo...@gmail.com> wrote: > A 1-2 second radiation burst in a detector is the 'norm' for capture of a > cosmic ray in lead! > > -----Original Message----- > From: Bob Cook [mailto:frobertc...@hotmail.com] > Sent: Friday, March 11, 2016 2:05 PM > To: vortex-l > Subject: [Vo]:Re: Bremsstrahlung experimental note > > Axil-- > > Bremsstrahlung radiation is due to inelastic scattering of electrons as > they pass through matter. There are no resonances. The radiations occurs > as a result of an electron changing direction as a result of the electric > field it is passing through. This change in direction (acceleration) saps > energy from the kinetic energy of the free electron and distributes that > energy as electromagnetic radiation equivalent to the loss of kinetic > energy of the > electron. The spectrum is random photons because the distance and charge > of particles being encountered by an energetic electron is random. Thus > the forces on the electron, whether due to other lattice electrons or > positive charges in the lattice are random in magnitude. > > Landau distributions of the energy of photons do not apply to free > electrons unless they are at relativistic velocities and have an effective > mass like a proton, pion, alpha or other heavy particle. > > What do you consider is the likely mechanism producing the "Landau > distribution" you suggest? Specifically, what particles are involved in > the generation of the spectrum? > > Bob Cook > > -----Original Message----- > From: Axil Axil > Sent: Friday, March 11, 2016 10:19 AM > To: vortex-l > Subject: Re: [Vo]: Bremsstrahlung experimental note > > The seconds long MFMP X-ray burst is smooth and demonstrates no resonance > energy peaks caused by the interaction of electrons with matter. The MFMP > burst is strictly a release of photons in a random energy distribution. > > A Landau distribution is what we are seeing in the MFMP radiation plot. It > is the release of energy by particles based on a random release process. > This is seen when a particle gives up its kinetic energy to a thin film as > the particles interact randomly with the matter in the thin film. > > If SPPs are releasing their energy based on a random timeframe and/or > based on a random accumulation amount, a Landau distribution of energy > release will be seen. > > You might see a Landau distribution if there is a random mixing of both > low energy photons (infrared) and high energy photons (gamma's from the > nucleus); > > Such mixing is produced by Fano resonance, where an SPPs are being fed by > both infrared photon pumping and nuclear based gamma photon absorption. > > > > On Fri, Mar 11, 2016 at 1:05 PM, Axil Axil <janap...@gmail.com> wrote: > > Electrons may have nothing to do with the x-ray radiation. > > > > The radiation could be produced by photon based quasiparticles. > > > > The LENR reaction might start with Surface Plasmon Polaritons > > initiated nuclear reactions and then after thermalization, the decay > > of those SPPs. When the SPPs decay, they release their energy content > > as photons of varng energies, > > > > After a second or two, a Bose condensate of these SPPs form and the > > energy of the photons are released as hawking radiation which is > > thermal. > > > > The radiation seen only lasts for a second. > > > > In LENR we get either high energy radiation (x-rays) or heat; not > > both. This is based on the temperature of the reactor. A cold reactor > > produces X-Rays because of weak SPP pumping.. > > > > The SPP absorbs nuclear binding energy and stores it in a whispering > > gallery wave (WGW) in a dark mode. The energy is stored inside the WGW > > until the WGW goes to a bright mode when the SPP decays. This > > conversion from dark mode to bright mode happens in a random > > distribution. > > > > When the temperature is raised over a thermal conversion limit, a BEC > > is formed where the stored nuclear binding energy is released from the > > SPP BEC as hawking radiation which is thermal. > > > > On Fri, Mar 11, 2016 at 12:34 PM, Bob Cook <frobertc...@hotmail.com> > > wrote: > >> The effectiveness of the SS can at stopping any high energy electrons > >> that cause Bremsstrahlung would depend upon the thickness of the can > >> (or > >> alumina) > >> and the energy of the incident electrons. I think the loss of energy > >> per scattering event is proportional to Z ^2 for the nucleus that is > >> doing the scattering. Al at Z=13 and with Fe at Z=26 the intensity > >> of the Bremsstrahlung signal would be about a factor of 4 different. > >> The mean length of the path of an electron is a good parameter to > >> know for any given substance (basically its density) vs the incident > >> energy of the electron. > >> Shielding engineering curves provide this information I believe. Iron > >> being significantly more dense than Al2O3 would be much better at > >> slowing electrons and thus producing Bremsstrahlung IMHO. > >> > >> At high electron energies the change of direction of the electron > >> going through SS can would be less than for a low energy electron. > >> For slow electrons scattering can significantly change the direction > >> of an incident electron such that all Bremsstrahlung would be emitted > >> from the material that stopped the electron. > >> > >> I think with a SS can present in the system vs no can and only > >> Alumina stopping the electrons, one would expect to see a more > >> intense signal at high energy compared to the spectrum from the > Alumina reactor chamber. > >> The > >> absorption of the EM Bremsstrahlung by the respective media would > >> also have to be considered. Neither Alumina nor SS may transmit some > >> of the Bremsstrahlung spectrum very well. Thus the effective > >> shielding of the EM radiation considering a distributed source would > >> have to be evaluated for the resulting high energy EM and the signal > >> intensity corrected accordingly. > >> The cut off at the high energy spectrum will be a useful value to > >> know to understand the maximum energy of the electron source. This may > provide > >> information about the reaction producing the electrons. The change of > >> the > >> intensity of the Bremsstrahlung signal as a function of the magnetic > >> field would also provide information as to whether or not the lattice > >> orientation > >> of the nano fuel was important. One might expect that the electrons > >> being > >> produced by the respective LENR reaction would produced in some > >> preferred direction. > >> > >> Bob Cook > >> From: Bob Higgins > >> Sent: Friday, March 11, 2016 6:09 AM > >> To: vortex-l@eskimo.com > >> Subject: [Vo]: Bremsstrahlung experimental note > >> > >> I don't know if other Vorts thought of this already... but I had a > >> minor epiphany regarding the radiation that MFMP measured in GS5.2. > >> We identified this radiation tentatively as bremsstrahlung. This has > >> certain implications. Bremsstrahlung requires that the high speed > >> electrons impact on a high atomic mass element so as to be > >> accelerated/decelerated quickly to produce the radiation. It could > >> be that the stainless steel can that contained the fuel was an > >> important component in seeing the bremsstrahlung. > >> Without the can, there would still be the Ni for the electrons to > >> hit, but the Ni is covered with light atomic mass Li. If the > >> electrons were to strike alumina (no fuel can present), I don't think > >> there would be nearly as much bremsstrahlung because alumina is > >> comprised of light elements. > >> > >> Thus, the stainless steel can for the fuel may be an important > >> component for seeing the bremsstrahlung. > >> > >> Bob Higgins > > >
