A 1-2 second radiation burst in a detector is the 'norm' for capture of a cosmic ray in lead!
-----Original Message----- From: Bob Cook [mailto:frobertc...@hotmail.com] Sent: Friday, March 11, 2016 2:05 PM To: vortex-l Subject: [Vo]:Re: Bremsstrahlung experimental note Axil-- Bremsstrahlung radiation is due to inelastic scattering of electrons as they pass through matter. There are no resonances. The radiations occurs as a result of an electron changing direction as a result of the electric field it is passing through. This change in direction (acceleration) saps energy from the kinetic energy of the free electron and distributes that energy as electromagnetic radiation equivalent to the loss of kinetic energy of the electron. The spectrum is random photons because the distance and charge of particles being encountered by an energetic electron is random. Thus the forces on the electron, whether due to other lattice electrons or positive charges in the lattice are random in magnitude. Landau distributions of the energy of photons do not apply to free electrons unless they are at relativistic velocities and have an effective mass like a proton, pion, alpha or other heavy particle. What do you consider is the likely mechanism producing the "Landau distribution" you suggest? Specifically, what particles are involved in the generation of the spectrum? Bob Cook -----Original Message----- From: Axil Axil Sent: Friday, March 11, 2016 10:19 AM To: vortex-l Subject: Re: [Vo]: Bremsstrahlung experimental note The seconds long MFMP X-ray burst is smooth and demonstrates no resonance energy peaks caused by the interaction of electrons with matter. The MFMP burst is strictly a release of photons in a random energy distribution. A Landau distribution is what we are seeing in the MFMP radiation plot. It is the release of energy by particles based on a random release process. This is seen when a particle gives up its kinetic energy to a thin film as the particles interact randomly with the matter in the thin film. If SPPs are releasing their energy based on a random timeframe and/or based on a random accumulation amount, a Landau distribution of energy release will be seen. You might see a Landau distribution if there is a random mixing of both low energy photons (infrared) and high energy photons (gamma's from the nucleus); Such mixing is produced by Fano resonance, where an SPPs are being fed by both infrared photon pumping and nuclear based gamma photon absorption. On Fri, Mar 11, 2016 at 1:05 PM, Axil Axil <janap...@gmail.com> wrote: > Electrons may have nothing to do with the x-ray radiation. > > The radiation could be produced by photon based quasiparticles. > > The LENR reaction might start with Surface Plasmon Polaritons > initiated nuclear reactions and then after thermalization, the decay > of those SPPs. When the SPPs decay, they release their energy content > as photons of varng energies, > > After a second or two, a Bose condensate of these SPPs form and the > energy of the photons are released as hawking radiation which is > thermal. > > The radiation seen only lasts for a second. > > In LENR we get either high energy radiation (x-rays) or heat; not > both. This is based on the temperature of the reactor. A cold reactor > produces X-Rays because of weak SPP pumping.. > > The SPP absorbs nuclear binding energy and stores it in a whispering > gallery wave (WGW) in a dark mode. The energy is stored inside the WGW > until the WGW goes to a bright mode when the SPP decays. This > conversion from dark mode to bright mode happens in a random > distribution. > > When the temperature is raised over a thermal conversion limit, a BEC > is formed where the stored nuclear binding energy is released from the > SPP BEC as hawking radiation which is thermal. > > On Fri, Mar 11, 2016 at 12:34 PM, Bob Cook <frobertc...@hotmail.com> > wrote: >> The effectiveness of the SS can at stopping any high energy electrons >> that cause Bremsstrahlung would depend upon the thickness of the can >> (or >> alumina) >> and the energy of the incident electrons. I think the loss of energy >> per scattering event is proportional to Z ^2 for the nucleus that is >> doing the scattering. Al at Z=13 and with Fe at Z=26 the intensity >> of the Bremsstrahlung signal would be about a factor of 4 different. >> The mean length of the path of an electron is a good parameter to >> know for any given substance (basically its density) vs the incident >> energy of the electron. >> Shielding engineering curves provide this information I believe. Iron >> being significantly more dense than Al2O3 would be much better at >> slowing electrons and thus producing Bremsstrahlung IMHO. >> >> At high electron energies the change of direction of the electron >> going through SS can would be less than for a low energy electron. >> For slow electrons scattering can significantly change the direction >> of an incident electron such that all Bremsstrahlung would be emitted >> from the material that stopped the electron. >> >> I think with a SS can present in the system vs no can and only >> Alumina stopping the electrons, one would expect to see a more >> intense signal at high energy compared to the spectrum from the Alumina >> reactor chamber. >> The >> absorption of the EM Bremsstrahlung by the respective media would >> also have to be considered. Neither Alumina nor SS may transmit some >> of the Bremsstrahlung spectrum very well. Thus the effective >> shielding of the EM radiation considering a distributed source would >> have to be evaluated for the resulting high energy EM and the signal >> intensity corrected accordingly. >> The cut off at the high energy spectrum will be a useful value to >> know to understand the maximum energy of the electron source. This may >> provide >> information about the reaction producing the electrons. The change of >> the >> intensity of the Bremsstrahlung signal as a function of the magnetic >> field would also provide information as to whether or not the lattice >> orientation >> of the nano fuel was important. One might expect that the electrons >> being >> produced by the respective LENR reaction would produced in some >> preferred direction. >> >> Bob Cook >> From: Bob Higgins >> Sent: Friday, March 11, 2016 6:09 AM >> To: vortex-l@eskimo.com >> Subject: [Vo]: Bremsstrahlung experimental note >> >> I don't know if other Vorts thought of this already... but I had a >> minor epiphany regarding the radiation that MFMP measured in GS5.2. >> We identified this radiation tentatively as bremsstrahlung. This has >> certain implications. Bremsstrahlung requires that the high speed >> electrons impact on a high atomic mass element so as to be >> accelerated/decelerated quickly to produce the radiation. It could >> be that the stainless steel can that contained the fuel was an >> important component in seeing the bremsstrahlung. >> Without the can, there would still be the Ni for the electrons to >> hit, but the Ni is covered with light atomic mass Li. If the >> electrons were to strike alumina (no fuel can present), I don't think >> there would be nearly as much bremsstrahlung because alumina is >> comprised of light elements. >> >> Thus, the stainless steel can for the fuel may be an important >> component for seeing the bremsstrahlung. >> >> Bob Higgins
