Horace, you have succeeded in steering me away from using the DiFiore et all
proposals for anything other than demonstrating the break in isotropy. In
re-reading their paper it appears they are trying to quantify the opposing
net gravitational force for the entire structure of layered cavities. By
building on that false premise I was shooting myself in the foot, The
calculated Casimir force is much higher and up converts the ratio of
short/long vacuum fluctuations curving space-time proportionally. I intend
to put the standard Casimir formula for non ideal metals into a spreadsheet
so I can compare the results between normal Casimir spacing and reduced
spacing for fractional radii (home repairs are delaying me). Whether you
subscribe to hydrino, relativistic or other scenario the narrowest possible
plate spacing is reduced by a factor of 137 assuming Bourgoin's math is
correct. I seem to recall the narrowest dimensions mentioned for a Casimir
force was approximately 10 atoms wide so I would model the minimal spacing
at 10x Bohr diameter/137 making the opening too small for even a single
"normal" atom. I realize there are some modifications to how the boundary
fields of the plates add in very close proximity. I haven't actually read
the Lifshitz work yet to see if this will come into play before the minimum
1/137 orbital radius proposed by Bourgoin is achieved. I also think a
temperature coefficient will need to be considered based on the difference
between Mills' results using a reactor and the slow results of Arata using
just Hydrogen and Pd nano materials at room temperature. 

Best Regards
Fran

For two large, neutral, parallel conducting plates separated by a distance z
in vacuum attract each other with the force per unit area
                                    P(z) =F(z) / S = -(pi^2 * reduced h * c)
/ (240* z^3) 
 Here reduced h is the reduced Planck constant, c is the velocity of light,
and S is the area of the plates.

-----Original Message-----
From: Horace Heffner [mailto:hheff...@mtaonline.net] 
Sent: Sunday, October 04, 2009 5:23 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:megalith levitation


On Oct 3, 2009, at 5:06 PM, Frank wrote:
>  The spatial confinement combined with the equivalence boundary
> suggests the 10E-14 newtons of acceleration calculated by DiFiore  
> et all is
> a vector wholly on the time axis -no trig portions of the spatial  
> axis, the
> force was ignored as inconsequential but I suggest the confinement  
> allows
> heat energy to contribute to the vector and without a relief valve of
> combustion could lead to a thermal runaway where H1 and H2 states  
> oscillate
> by virtue of a Pd like opposition to diatomic formation but here in  
> the
> cavity a high velocity version of this property that immediately  
> tears apart
> H2 restoring monatomic energy levels.

Fran,

I had decided to leave you with your fantasies, but I just can't help  
myself!  I have to make one more try at getting some common sense  
with regard to DiFiore at al.

The 10^-14 newtons is a *force*, not an acceleration.

DiFiore at all state: "... to increase the total force and obtain  
macroscopic dimensions, Nl = 10^6 layers can be used, each having a  
diameter of 35 cm, and thickness of 100 nm, for a total thickness of  
about 10 cm."

This is a device of volume Pi * (35 cm/2)^2 * (10 cm) = 550 cm^3.  It  
is a device comprised of layers of SiO2 and aluminum. The combined  
density is about 2.65 g/cm^3, so the weight is about (2.65 g/cm^3)* 
(550 cm^3) = 1.46 kg.

If you ignore the much more massive power supply required, the  
maximum acceleration that can be obtained is:

    a = f/m = (10^-14 N)/(1.46 kg) = 6.8x10^-15 m/s^2

This is true no matter how big you build you engine. Suppose you  
wanted to use such a 10^-14 newton device to provide thrust for a  
modest 1000 kg space craft. We have:

   a = f/m = (10^-14 N)/(1000 kg) = 10^-17 m/s^2

Acceleration does not have an exponential effect on velocity.  It has  
a linear effect on velocity. In fact, if we accelerate for t seconds  
we obtain a velocity of:

    v = a * t

Suppose we want to see how long it takes for the space craft to go  
from 0 to 60 mph, to see what kind of hot rod we have.  Think it can  
do it in 10 seconds?  Let's see:

    t = v/a = (60 mph)/(10^-17 m/s^2)

      = (96.5 km/h)/(10^-17 m/s^2)

      = (26.8 m/s)/(10^-17 m/s^2)

      = 2.68 x 10^18 seconds

      = 8.49 x 10^10 years

which is older than the age of the known universe.

Hopefully I haven't made a simple mistake.  Please check my work.

The acceleration provided by (10^-14 N)/(1.46 kg), i.e. 6.8x10^-15 m/ 
s^2, can not produce any practical effects. It cannot provide useful  
velocities in a century, nor can it be engineered to provide useful  
kinetic energy or forces.  Applied to an atom, it certainly can not  
provide enough energy in a lifetime to ionize the atom.

Best regards,

Horace Heffner
http://www.mtaonline.net/~hheffner/




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