In reply to Horace Heffner's message of Tue, 12 Apr 2011 15:38:07 -0800: Hi, [snip] > >On Apr 12, 2011, at 3:22 PM, mix...@bigpond.com wrote: > >> In reply to Horace Heffner's message of Tue, 12 Apr 2011 13:41:19 >> -0800: >> Hi, >> [snip] >>> This roughly 0.8 MeV energy comes from the kinetic energy of the >>> electron, which is the same high value it had in the very small >>> deflated state >> >> The kinetic energy of the electron in the deflated state comes from >> the >> potential energy it had relative to the proton in the non-deflated >> state. Since >> the total mass energy of a Hydrogen atom is short of the energy >> required to form >> a neutron by 800 keV, that is still so in the deflated state. IOW >> the kinetic >> energy of the electron is 800 keV less than would be needed to form >> a neutron. >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/Project.html >> > >Not true. The kinetic energy of the electron in the deflated state >can be around 1 MeV.
That what I just said ;) (Well 7-800 keV anyway). My point was, that this still isn't enough to create a free neutron, because the kinetic energy was subtracted from the ponderable mass of the H atom. IOW it's not 'extra'. However it's not necessary to create a free neutron anyway, because the neutron required will be in a nucleus, and neutrons in nuclei weigh less than free neutrons anyway (by about 5-10 MeV/c^2, depending on the nucleus). >In that case the potential energy is about -1 >MeV. Upon fusion with Ni, the kinetic energy in that case remains >initially at 1 MeV, but, due to the suddenly present 28 extra Ni >nucleus charges, the potential energy is reduced to -29 Mev, and the >net potential plus kinetic energy is reduced by 28 MeV. This loss of >potential energy does not prevent electron capture of the now >energetically trapped electron, if it occurs very fast, because that >electron still has the kinetic energy necessary. I think it is also >true that nuclear heat may prolong the ability of the electron to >both radiate and be captured. Nuclear heat to which I refer is >provided by zero point energy, in a manner as described here: > >http://mtaonline.net/~hheffner/NuclearZPEtapping.pdf > >in which I estimate the nuclear temperature for Ni to be 1.02 MeV. >This then provides a method of capturing zero point energy. > >Best regards, > >Horace Heffner >http://www.mtaonline.net/~hheffner/ > > > Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
