In reply to OrionWorks - Steven Vincent Johnson's message of Thu, 26 May 2011 14:48:52 -0500: Hi, [snip] >From Axel > >> If you need an exact number, the start temperature is not >> that high. In the Sweden test, the water temperature was >> pushed up to 60C by the external heater before the reaction >> became gainful. >> >> The internal heater was also in action. So my guess is that >> the temperature of the hydrogen envelope was above 100C but >> hot much above it. > >Axel, > >So far you are you are the only individual within the Vort Collective who >has come close to answering what I thought was a very simple question. You >offered up a speculated lower limit temperature value! Thank you for your >input! :-) > >To clarify, this thread was not trying to elicit discussion pertaining to >what kinds of theoretical mechanisms might be involved in generating Rossi's >e-Cat heat. I was simply trying to get a ball-park thermal range for which >the Rossi "chain" reaction is speculated to operate within. I'm puzzled that >few on this list seem capable of (or perhaps willing to) answer this >question. > >In my original question I asked: If the Rossi reaction can be sustained >below 400 C, by how much below 400 C. Axel, you mention (according to the >Sweden tests) the reaction might be sustainable as low as 60 - 100 C. That >sounds incredibly low to me! Anybody disagree? Just wondering. > >Can anyone offer up reasons as to why in order to initiate the Rossi >reaction the temperature has to at first be increased (via external means) >up to around 400 C. But then, once the reaction has been initiated, >sustainable thermal temperature values can then be reduced significantly - >possibly down to 60 C - 100 C. The physics behind such a significant >reduction in temperature values where the Rossi reaction is alleged to >remain sustainable strikes me as being somewhat hard to believe.
What makes you think it has to be 400 C to start? (I have no idea what it needs to be, and as long as the actual mechanism remains unknown, I think it's anybody's guess.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html