Because the molecular mass of Hydrogen is 1gram/mole, there is 1 mole of hydrogen in 1 gram of hydrogen atoms. For every mole, there are 6.02*10^23 atoms so in 1 gram of hydrogen there are 6.02*10^23 hydrogen atoms (in scientific notation) this is equal to 602000000000000000000000 hydrogen atoms.
If the gas envelop capacity of the reactor is one liter and is operating at a pressure of 3 bar then 1 mole of an ideal gas = 22.4 liters at one bar 1 mole of H2 = 2.016 grams 2.016 g / 22.4 liters= 0.09 g per liter at one bar At 3 bar, there is .27 g of hydrogen in the gas envelope The number of hydrogen atoms is therefore .27 g * 602000000000000000000000 hydrogen atoms/g = 162540000000000000000000 hydrogen atoms more or less Please complete the Miles chemical energy calculation. On Wed, Jul 9, 2014 at 5:24 PM, <mix...@bigpond.com> wrote: > In reply to Jones Beene's message of Tue, 8 Jul 2014 16:28:32 -0700: > Hi, > [snip] > >However, if hydrogen was added continuously during the long run (as > >expected), then the amount consumed would tell us "volumes" about the > nature > >of the reaction by knowing the thermal output per atom consumed. If it was > >in the range of 200 eV per atom of H2 then we are talking f/H reactions, > and > >if it is MeV range and up, per atom consumed, then we are talking nuclear. > > > >We need to see these results, but according to the sparse record of the > >Hot-Cat, and the fixed amount of starting fuel - then the reaction is most > >likely neither LENR or the hydrino. > > > >In fact, that strange outcome - requiring the mention of a > vacuum/ZPE/Dirac > >source of energy transfer, would be very difficult for all of those PhDs > to > >swallow, and thus responsible for a much longer delay than if the reaction > >can be pinned to nuclear. > > I agree. However lets see the numbers before jumping to conclusions. > > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
