In reply to Axil Axil's message of Wed, 9 Jul 2014 18:50:12 -0400: Hi, [snip] >Because the molecular mass of Hydrogen is 1gram/mole, there is 1 mole of >hydrogen in 1 gram of hydrogen atoms. For every mole, there are 6.02*10^23 >atoms so in 1 gram of hydrogen there are 6.02*10^23 hydrogen atoms (in >scientific notation) this is equal to 602000000000000000000000 hydrogen >atoms. > > > >If the gas envelop capacity of the reactor is one liter and is operating at >a pressure of 3 bar then > > > >1 mole of an ideal gas = 22.4 liters at one bar >1 mole of H2 = 2.016 grams >2.016 g / 22.4 liters= 0.09 g per liter at one bar > > > >At 3 bar, there is .27 g of hydrogen in the gas envelope > > > >The number of hydrogen atoms is therefore > > >.27 g * 602000000000000000000000 hydrogen atoms/g = >162540000000000000000000 hydrogen atoms more or less > >Please complete the Miles chemical energy calculation.
1) Is gas in the envelope at the start the only source of Hydrogen, or is replaced from a bottle during the course of the experiment? 2) Is there any hydride of another metal present (e.g. Lanthanum)? 3) Was the Ni powder saturated with H during the initial pressurization? 4) Was any Hydrogen left in the envelope after the experiment? BTW if the actual amount of Hydrogen used is as you stated, then the energy release / H atom for 43000 kWh is about 6 MeV / H atom, which would obviously be nuclear in origin. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
