@Rahul,
As per my understanding,
In any round P(C is dead) = P(A is alive * A shoots C * A's shot is
accurate) + P(B is alive * B shoots C * B's shot is accurate)
this is to be minimized.
by not shooting at either A or B in 1st chance, how is this probability less
for C?


On Sat, Jan 1, 2011 at 10:43 PM, Salil Joshi <joshi.sali...@gmail.com>wrote:

> @Rahul,
> What purpose is served by wasting the shot? If C shoots at A or B, at least
> some probability that C is dead in future will be reduced.
>
>
>
> On Sat, Jan 1, 2011 at 10:14 PM, RAHUL KUJUR <kujurismonu2...@gmail.com>wrote:
>
>> @snehal:
>> will the shooting take place in increasing order of accuracy of hitting
>> the target and is that at a time only one person can take a shot???
>> if yes then
>> @Salil:
>> my answer would be the same as above. what C will do is that it will first
>> let A and B kill each other first.
>> After C wastes his shot it will be B's turn. B can kill C, but in that
>> case the turn would go to A and he would surely kill B. If B goes after A,
>> then B may hit it or miss it(as its probability of hitting is 50%)
>> If B misses it
>> then
>> it depends on A whom to kill. A may kill B or C. A will try to kill one
>> who is better shooter i.e. B as C is less likely to hit A.
>> If B hits A then we are done. Round 1 is complete(as required in the
>> question) and C survives the first round.
>> Look the problem is not that who gets killed at last but rather what C
>> should fire in the first round obviously to survive(as I understood the
>> problem). It may happen that eventually C gets killed. But what should C
>> shoot in first round to survive.
>>
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>
>
>
> --
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> --------
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> Salil Joshi.
> CSE MTech II, IITB
> A-414, Hostel 12
> +91.9819.442.865
>
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Thanks & Regards
Salil Joshi.
CSE MTech II, IITB
A-414, Hostel 12
+91.9819.442.865


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