User: xrambous
Date: 2008-08-14 19:13:44+0000
Modified:
   cs/po/helpcontent2/source/text/scalc/01.po

Log:
 

File Changes:

Directory: /cs/po/helpcontent2/source/text/scalc/
=================================================

File [changed]: 01.po
Url: 
http://cs.openoffice.org/source/browse/cs/po/helpcontent2/source/text/scalc/01.po?r1=1.329&r2=1.330
Delta lines:  +3 -4
-------------------
--- 01.po       2008-08-14 02:50:29+0000        1.329
+++ 01.po       2008-08-14 19:13:41+0000        1.330
@@ -7,8 +7,8 @@
 "Project-Id-Version: 01\n"
 "Report-Msgid-Bugs-To: 
http://qa.openoffice.org/issues/enter_bug.cgi?subcomponent=ui&comment=&short_desc=Localization%20issue%20in%20file%3A%20helpcontent2/source/text/scalc/01.oo&component=l10n&form_name=enter_issue\n";
 "POT-Creation-Date: 2008-06-04 09:15+0200\n"
-"PO-Revision-Date: 2008-08-14 04:49+0200\n"
-"Last-Translator: Kristyna Kitzbergerova <[EMAIL PROTECTED]>\n"
+"PO-Revision-Date: 2008-08-14 21:14+0200\n"
+"Last-Translator: Adam Rambousek <[EMAIL PROTECTED]>\n"
 "Language-Team: Czech <[EMAIL PROTECTED]>\n"
 "MIME-Version: 1.0\n"
 "Content-Type: text/plain; charset=UTF-8\n"
@@ -20797,9 +20797,8 @@
 msgstr "Příklad"
 
 #: 04060185.xhp#par_id3156067.54.help.text
-#, fuzzy
 msgid "<item type=\"input\">=STANDARDIZE(11;10;1)</item> returns 1. The value 
11 in a normal distribution with a mean of 10 and a standard deviation of 1 is 
as much above the mean of 10, as the value 1 is above the mean of the standard 
normal distribution."
-msgstr "<item type=\"input\">=STANDARDIZE(11;10;1)</item> vrátí 1."
+msgstr "<item type=\"input\">=STANDARDIZE(11;10;1)</item> vrátí 1. Hodnota 
11 v normálním rozložení s průměrem 10 a standardní odchylkou 1 je nad 
průměrem 10, stejně jako je hodnota 1 nad průměrem standardního 
normálního rozložení."
 
 #: 04060185.xhp#bm_id3157986.help.text
 msgid "<bookmark_value>NORMSINV 
function</bookmark_value><bookmark_value>normal distribution;inverse of 
standard</bookmark_value>"




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