I think we have hit the posting limit for this topic, so I'll just finish with 
this remark: the maximum power transfer between a power amplifier and its load 
will occur when the source and load impedances are complex conjugates (this can 
be seen using the voltage divider equation and some differential calculus). In 
the case of a purely resistive load, this reduces down to the source and load 
resistances being equal.

73,
Matt VK2RQ

> On 1 Aug 2014, at 8:24 am, Per-Tore Aasestrand <p...@ieee.org> wrote:
> 
> Hi list,
> 
> Isn't an RF transmitter or PA actually more like a current generator? Its
> internal resistance is kept low in order to reduce internally dissipated
> power, with consequent reduction in efficiency. It is usually designed to
> work efficiently into 50 ohms.
> 
> It is important to know the difference between these two statements:
> (A) The transmitter has a 50 ohm output impedance.
> (B) The transmitter is designed to work into a 50 ohm load
> 
> A transmitter will be able to put its rated power into a 50 ohm load, but
> this says nothing about its output impedance. That is why I don't think
> conjugate matching will be appropriate.
> 
> (Hope this is not getting too much OT now)
> 
> Per-Tore / LA7NO
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