Tharin,
I am trying to configure both a router and my personal network of 6 (7)
devices. 7 if I count the router; which I do. Does that combination have a
bearing on this?
After 7 years, I was trying to stretch/play a little bit because this is my
2d go-around with high-speed. Perhaps I went too far. I tried to use the
3rd quartile/block of the IP address to define a "server" and a "client
PC." It did not work at all. "Servers" could talk to/see "servers but not
clients. "Clients" could talkto/see "clients" but not "servers". Yes, I
was trying to use the 3rd quartile/block of the IP address to differentiate
"servers" and "clients." Well, no matter.....
OK, I may now back up and re-implement my old plan of using a Class A
network IP address scheme, but use a sub-net mask of 255.255.255.0. This
scheme served me well for the last 7 years.
You did answer my question and confirmed I did have a grasp about the
"sub-net mask" control.
I chose the Class C scheme due to comment here on the list. It just does
not work with my chosen IP address series, but now I know that my chosen IP
address series may be 'out of bounds.'
I will play some more tonight. I will get it to work. More play in
process..........
Thank you. Best/Most Crisp answer so far....... :)
Best,
Duncan
At 16:02 10/29/2007 -0700, you wrote:
There is something like 64 thousand ip addresses in the private
192.168.x.x range. (192.168.0.0 - 192.168.255.255)
The subnet mask will determine the range of IP addresses that will be in
your local network. Your local network being the computers/devices you
have direct access to send data without needing to be handled through a router.
The common and default subnet mask that is used in a SOHO network and on a
Private C class block is 255.255.255.0. This will allow for a total of 254
hosts. This is the default setting for most consumer routers from Linksys,
D-link, Netgear, etc.
If computerA had an ip address of 192.168.0.12 and a subnet mask of
255.255.255.0 it would be able to communicate with the network range of
192.168.0.1-192.168.0.254. If computerB had an IP of 192.168.9.5 and the
same subnet the valid network range would be 192.168.9.1-192.168.9.254. A
ping from
computerA would not reach computerB or vice versa because they are on two
different networks.
Hopefully this crude example shows how the subnet mask determines the ip
range; especially, how that particular subnet mask would restrict your ip
range to whichever block you choose in the third set of numbers.
How did you need to apply this knowledge?? Are you configuring a router or
small network in your home??
DHSinclair <[EMAIL PROTECTED]> wrote:
OK, I now use what I read is the Class C private IP address series.
I use 192.168.2xx.x. I am told that my sub-net mask should
be 255.255.255.0.
If this is true, then should not my chosen 3rd quartile of "2xx" really
be a value 0?
Or, does it really mean that my chosen 3rd quartile is somehow
ignored? Yes, I do recall discussion about this last year, but back
then I was using the Class A private IP series......... :)
Thank you for any/all de-mystification.
Best,
Duncan
